- Problem 1a: Hypotenuse = √(7² + 12²) = √(49 + 144) = √193 ≈ 13.9 cm → Cross out "ON"
- Problem 1b: Hypotenuse = √(8² + 15²) = √(64 + 225) = √289 = 17 ft → Cross out "UM"
- Problem 1c: Hypotenuse = √(10² + 10²) = √(100 + 100) = √200 ≈ 14.1 in. → Cross out "E"
- Problem 2: Wire length = √(8² + 5²) = √(64 + 25) = √89 ≈ 9.4 ft → Cross out "B"
- Problem 3: Distance = √(300² + 400²) = √(90,000 + 160,000) = √250,000 = 500 m → Cross out "IT"
- Problem 4a: Legs are 2 cm and 2 cm, hypotenuse = √(2² + 2²) = √8 ≈ 2.8 cm, perimeter = 2 + 2 + 2.8 = 6.8 cm → Cross out "AN"
- Problem 4b: Legs are 2 cm and 3 cm, hypotenuse = √(2² + 3²) = √13 ≈ 3.6 cm, perimeter = 2 + 3 + 3.6 = 8.6 cm → Cross out "ME"
- Problem 5: Distance = √(70² + 40²) = √(4900 + 1600) = √6500 ≈ 80.6 paces → Cross out "T"
- Problem 6: Distance from home to second base = √(60² + 60²) = √7200 ≈ 84.9 ft → Cross out "L"
- Problem 7: Diagonal = √(2² + 1.5²) = √(4 + 2.25) = √6.25 = 2.5 mi; walking along sides = 2 + 1.5 = 3.5 mi; difference = 3.5 - 2.5 = 1 mi → Cross out "D"
Remaining letters: A, M, A, R, T, I, A, N, B, A, N, D → "A MARTIAN BAND"
Parent Tip: Review the logic above to help your child master the concept of bridge to algebra worksheet answers.