Here are the step-by-step solutions for the problems on your worksheet.
Top Section: Definitions
*
v stands for
Wave Speed (how fast the wave travels).
*
$\lambda$ (lambda) stands for
Wavelength (distance from crest to crest).
*
f stands for
Frequency (how many waves pass a point per second).
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Problem 1
*
Given: Wavelength ($\lambda$) = 2 m, Frequency ($f$) = 6 Hz.
*
Goal: Find Speed ($v$).
*
Formula: $v = \lambda \times f$
*
Calculation: $2 \text{ m} \times 6 \text{ Hz} = 12 \text{ m/s}$.
Problem 2
*
Given: Frequency ($f$) = 2 Hz, Wavelength ($\lambda$) = 10 m. (Note: Amplitude is extra information not needed for speed).
*
Goal: Find Speed ($v$).
*
Formula: $v = \lambda \times f$
*
Calculation: $10 \text{ m} \times 2 \text{ Hz} = 20 \text{ m/s}$.
Problem 3
*
Given: "Two wavelengths pass a given point each second" means Frequency ($f$) = 2 Hz. "Distance between wave crests" means Wavelength ($\lambda$) = 3 m.
*
Goal: Find Speed ($v$).
*
Formula: $v = \lambda \times f$
*
Calculation: $3 \text{ m} \times 2 \text{ Hz} = 6 \text{ m/s}$.
Problem 4
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Given: Frequency ($f$) = 20 Hz, Speed ($v$) = 340 m/s.
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Goal: Find Wavelength ($\lambda$).
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Formula: $\lambda = v / f$
*
Calculation: $340 \text{ m/s} / 20 \text{ Hz} = 17 \text{ m}$.
Problem 5
*
Given: Frequency ($f$) = 150,000 Hz, Speed ($v$) = 1,500 m/s.
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Goal: Find Wavelength ($\lambda$).
*
Formula: $\lambda = v / f$
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Calculation: $1,500 / 150,000 = 0.01 \text{ m}$.
Problem 6
*
Given: "Waves are 6 m apart" means Wavelength ($\lambda$) = 6 m. "Pass a surfer every 2 s" is the Period ($T$). To find Frequency, we use $f = 1 / T$. So, $f = 1 / 2 = 0.5 \text{ Hz}$.
*
Goal: Find Speed ($v$).
*
Formula: $v = \lambda \times f$
*
Calculation: $6 \text{ m} \times 0.5 \text{ Hz} = 3 \text{ m/s}$.
Final Answer:
Definitions:
* v stands for
Wave Speed
* $\lambda$ stands for
Wavelength
* f stands for
Frequency
1. 12 m/s
2. 20 m/s
3. 6 m/s
4. 17 m
5. 0.01 m
6. 3 m/s
Parent Tip: Review the logic above to help your child master the concept of calculating wave speed worksheet.
