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Power Rule for Integration worksheet with ten problems for finding indefinite integrals.

Worksheet titled "Power Rule for Integration" with ten calculus problems involving indefinite integrals of various polynomial and rational functions.

Worksheet titled "Power Rule for Integration" with ten calculus problems involving indefinite integrals of various polynomial and rational functions.

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Show Answer Key & Explanations Step-by-step solution for: Calculus Worksheets | Indefinite Integration for Calculus ...
Let's solve each of these integrals using the Power Rule for Integration.

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🔷 Power Rule for Integration:



For any real number $ n \ne -1 $:

$$
\int x^n \, dx = \frac{x^{n+1}}{n+1} + C
$$

Also, remember:
- The integral of a sum is the sum of the integrals.
- Constants can be factored out.
- For negative exponents: $ \frac{1}{x^n} = x^{-n} $

We'll apply this rule to each problem.

---

1) $ \int (2x - 1)\,dx $



Break it into two parts:

$$
= \int 2x\,dx - \int 1\,dx
= 2 \int x\,dx - \int dx
= 2 \cdot \frac{x^2}{2} - x + C
= x^2 - x + C
$$

Answer: $ x^2 - x + C $

---

2) $ \int (-4x^3 + 36x^2 - 72x)\,dx $



Integrate term by term:

$$
= -4 \int x^3\,dx + 36 \int x^2\,dx - 72 \int x\,dx
= -4 \cdot \frac{x^4}{4} + 36 \cdot \frac{x^3}{3} - 72 \cdot \frac{x^2}{2}
= -x^4 + 12x^3 - 36x^2 + C
$$

Answer: $ -x^4 + 12x^3 - 36x^2 + C $

---

3) $ \int (2x + 3)\,dx $



$$
= 2 \int x\,dx + \int 3\,dx
= 2 \cdot \frac{x^2}{2} + 3x + C
= x^2 + 3x + C
$$

Answer: $ x^2 + 3x + C $

---

4) $ \int \left( \frac{-1}{x^2} \right) dx $



Rewrite: $ \frac{-1}{x^2} = -x^{-2} $

$$
= \int -x^{-2}\,dx = - \int x^{-2}\,dx
= - \cdot \frac{x^{-1}}{-1} + C = x^{-1} + C = \frac{1}{x} + C
$$

Answer: $ \frac{1}{x} + C $

---

5) $ \int \left( \frac{-57}{x^4} \right) dx $



$ \frac{-57}{x^4} = -57x^{-4} $

$$
= -57 \int x^{-4}\,dx = -57 \cdot \frac{x^{-3}}{-3} + C
= 19x^{-3} + C = \frac{19}{x^3} + C
$$

Answer: $ \frac{19}{x^3} + C $

---

6) $ \int \left( \frac{-28}{x^2} \right) dx $



$ = -28 \int x^{-2}\,dx = -28 \cdot \frac{x^{-1}}{-1} + C = 28x^{-1} + C = \frac{28}{x} + C $

Answer: $ \frac{28}{x} + C $

---

7) $ \int \left( \frac{12}{169x^{13}} \right) dx $



Simplify: $ \frac{12}{169} \cdot x^{-13} $

$$
= \frac{12}{169} \int x^{-13}\,dx = \frac{12}{169} \cdot \frac{x^{-12}}{-12} + C
= -\frac{1}{169} x^{-12} + C = -\frac{1}{169x^{12}} + C
$$

Answer: $ -\frac{1}{169x^{12}} + C $

---

8) $ \int \left( \frac{-3}{11x^{11}} \right) dx $



$ = -\frac{3}{11} \int x^{-11}\,dx = -\frac{3}{11} \cdot \frac{x^{-10}}{-10} + C = \frac{3}{110} x^{-10} + C = \frac{3}{110x^{10}} + C $

Answer: $ \frac{3}{110x^{10}} + C $

---

9) $ \int (2x + 5)\,dx $



$$
= 2 \int x\,dx + \int 5\,dx = 2 \cdot \frac{x^2}{2} + 5x + C = x^2 + 5x + C
$$

Answer: $ x^2 + 5x + C $

---

10) $ \int \left( \frac{-10}{133x^9} \right) dx $



$ = -\frac{10}{133} \int x^{-9}\,dx = -\frac{10}{133} \cdot \frac{x^{-8}}{-8} + C = \frac{10}{133 \cdot 8} x^{-8} + C $

$$
= \frac{10}{1064} x^{-8} + C = \frac{5}{532} x^{-8} + C = \frac{5}{532x^8} + C
$$

Answer: $ \frac{5}{532x^8} + C $

---

Final Answers Summary:



| Problem | Answer |
|--------|--------|
| 1) | $ x^2 - x + C $ |
| 2) | $ -x^4 + 12x^3 - 36x^2 + C $ |
| 3) | $ x^2 + 3x + C $ |
| 4) | $ \frac{1}{x} + C $ |
| 5) | $ \frac{19}{x^3} + C $ |
| 6) | $ \frac{28}{x} + C $ |
| 7) | $ -\frac{1}{169x^{12}} + C $ |
| 8) | $ \frac{3}{110x^{10}} + C $ |
| 9) | $ x^2 + 5x + C $ |
| 10) | $ \frac{5}{532x^8} + C $ |

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