Math worksheet for converting improper fractions to mixed numbers.
Worksheet titled "Converting Fractions (A)" with exercises to convert improper fractions to mixed numbers.
JPG
500×647
19.7 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #691153
⭐
Show Answer Key & Explanations
Step-by-step solution for: Converting Improper Fractions to Mixed Fractions (A)
▼
Show Answer Key & Explanations
Step-by-step solution for: Converting Improper Fractions to Mixed Fractions (A)
To convert an improper fraction to a mixed number, follow these steps:
1. Divide the numerator (top number) by the denominator (bottom number).
2. The result of the division is your whole number.
3. The remainder becomes the new numerator.
4. The denominator stays the same.
Here are the solutions for each problem on the worksheet, row by row:
Row 1:
* $32 \div 9 = 3$ with a remainder of $5 \rightarrow \mathbf{3 \frac{5}{9}}$
* $67 \div 12 = 5$ with a remainder of $7 \rightarrow \mathbf{5 \frac{7}{12}}$
* $116 \div 15 = 7$ with a remainder of $11 \rightarrow \mathbf{7 \frac{11}{15}}$
* $34 \div 15 = 2$ with a remainder of $4 \rightarrow \mathbf{2 \frac{4}{15}}$
Row 2:
* $25 \div 12 = 2$ with a remainder of $1 \rightarrow \mathbf{2 \frac{1}{12}}$
* $41 \div 6 = 6$ with a remainder of $5 \rightarrow \mathbf{6 \frac{5}{6}}$
* $53 \div 7 = 7$ with a remainder of $4 \rightarrow \mathbf{7 \frac{4}{7}}$
* $25 \div 4 = 6$ with a remainder of $1 \rightarrow \mathbf{6 \frac{1}{4}}$
Row 3:
* $127 \div 15 = 8$ with a remainder of $7 \rightarrow \mathbf{8 \frac{7}{15}}$
* $21 \div 8 = 2$ with a remainder of $5 \rightarrow \mathbf{2 \frac{5}{8}}$
* $15 \div 4 = 3$ with a remainder of $3 \rightarrow \mathbf{3 \frac{3}{4}}$
* $33 \div 10 = 3$ with a remainder of $3 \rightarrow \mathbf{3 \frac{3}{10}}$
Row 4:
* $25 \div 9 = 2$ with a remainder of $7 \rightarrow \mathbf{2 \frac{7}{9}}$
* $38 \div 7 = 5$ with a remainder of $3 \rightarrow \mathbf{5 \frac{3}{7}}$
* $99 \div 10 = 9$ with a remainder of $9 \rightarrow \mathbf{9 \frac{9}{10}}$
* $44 \div 5 = 8$ with a remainder of $4 \rightarrow \mathbf{8 \frac{4}{5}}$
Row 5:
* $53 \div 15 = 3$ with a remainder of $8 \rightarrow \mathbf{3 \frac{8}{15}}$
* $41 \div 8 = 5$ with a remainder of $1 \rightarrow \mathbf{5 \frac{1}{8}}$
* $64 \div 9 = 7$ with a remainder of $1 \rightarrow \mathbf{7 \frac{1}{9}}$
* $57 \div 10 = 5$ with a remainder of $7 \rightarrow \mathbf{5 \frac{7}{10}}$
Row 6:
* $16 \div 7 = 2$ with a remainder of $2 \rightarrow \mathbf{2 \frac{2}{7}}$
* $56 \div 9 = 6$ with a remainder of $2 \rightarrow \mathbf{6 \frac{2}{9}}$
* $21 \div 10 = 2$ with a remainder of $1 \rightarrow \mathbf{2 \frac{1}{10}}$
* $67 \div 8 = 8$ with a remainder of $3 \rightarrow \mathbf{8 \frac{3}{8}}$
Row 7:
* $12 \div 7 = 1$ with a remainder of $5 \rightarrow \mathbf{1 \frac{5}{7}}$
* $83 \div 12 = 6$ with a remainder of $11 \rightarrow \mathbf{6 \frac{11}{12}}$
* $36 \div 7 = 5$ with a remainder of $1 \rightarrow \mathbf{5 \frac{1}{7}}$
* $19 \div 6 = 3$ with a remainder of $1 \rightarrow \mathbf{3 \frac{1}{6}}$
Row 8:
* $13 \div 2 = 6$ with a remainder of $1 \rightarrow \mathbf{6 \frac{1}{2}}$
* $22 \div 3 = 7$ with a remainder of $1 \rightarrow \mathbf{7 \frac{1}{3}}$
* $23 \div 5 = 4$ with a remainder of $3 \rightarrow \mathbf{4 \frac{3}{5}}$
* $20 \div 7 = 2$ with a remainder of $6 \rightarrow \mathbf{2 \frac{6}{7}}$
Row 9:
* $76 \div 15 = 5$ with a remainder of $1 \rightarrow \mathbf{5 \frac{1}{15}}$
* $85 \div 9 = 9$ with a remainder of $4 \rightarrow \mathbf{9 \frac{4}{9}}$
* $80 \div 9 = 8$ with a remainder of $8 \rightarrow \mathbf{8 \frac{8}{9}}$
* $41 \div 12 = 3$ with a remainder of $5 \rightarrow \mathbf{3 \frac{5}{12}}$
Row 10:
* $6 \div 5 = 1$ with a remainder of $1 \rightarrow \mathbf{1 \frac{1}{5}}$
* $107 \div 15 = 7$ with a remainder of $2 \rightarrow \mathbf{7 \frac{2}{15}}$
* $63 \div 8 = 7$ with a remainder of $7 \rightarrow \mathbf{7 \frac{7}{8}}$
* $37 \div 5 = 7$ with a remainder of $2 \rightarrow \mathbf{7 \frac{2}{5}}$
Final Answer:
Row 1: $3 \frac{5}{9}, \quad 5 \frac{7}{12}, \quad 7 \frac{11}{15}, \quad 2 \frac{4}{15}$
Row 2: $2 \frac{1}{12}, \quad 6 \frac{5}{6}, \quad 7 \frac{4}{7}, \quad 6 \frac{1}{4}$
Row 3: $8 \frac{7}{15}, \quad 2 \frac{5}{8}, \quad 3 \frac{3}{4}, \quad 3 \frac{3}{10}$
Row 4: $2 \frac{7}{9}, \quad 5 \frac{3}{7}, \quad 9 \frac{9}{10}, \quad 8 \frac{4}{5}$
Row 5: $3 \frac{8}{15}, \quad 5 \frac{1}{8}, \quad 7 \frac{1}{9}, \quad 5 \frac{7}{10}$
Row 6: $2 \frac{2}{7}, \quad 6 \frac{2}{9}, \quad 2 \frac{1}{10}, \quad 8 \frac{3}{8}$
Row 7: $1 \frac{5}{7}, \quad 6 \frac{11}{12}, \quad 5 \frac{1}{7}, \quad 3 \frac{1}{6}$
Row 8: $6 \frac{1}{2}, \quad 7 \frac{1}{3}, \quad 4 \frac{3}{5}, \quad 2 \frac{6}{7}$
Row 9: $5 \frac{1}{15}, \quad 9 \frac{4}{9}, \quad 8 \frac{8}{9}, \quad 3 \frac{5}{12}$
Row 10: $1 \frac{1}{5}, \quad 7 \frac{2}{15}, \quad 7 \frac{7}{8}, \quad 7 \frac{2}{5}$
1. Divide the numerator (top number) by the denominator (bottom number).
2. The result of the division is your whole number.
3. The remainder becomes the new numerator.
4. The denominator stays the same.
Here are the solutions for each problem on the worksheet, row by row:
Row 1:
* $32 \div 9 = 3$ with a remainder of $5 \rightarrow \mathbf{3 \frac{5}{9}}$
* $67 \div 12 = 5$ with a remainder of $7 \rightarrow \mathbf{5 \frac{7}{12}}$
* $116 \div 15 = 7$ with a remainder of $11 \rightarrow \mathbf{7 \frac{11}{15}}$
* $34 \div 15 = 2$ with a remainder of $4 \rightarrow \mathbf{2 \frac{4}{15}}$
Row 2:
* $25 \div 12 = 2$ with a remainder of $1 \rightarrow \mathbf{2 \frac{1}{12}}$
* $41 \div 6 = 6$ with a remainder of $5 \rightarrow \mathbf{6 \frac{5}{6}}$
* $53 \div 7 = 7$ with a remainder of $4 \rightarrow \mathbf{7 \frac{4}{7}}$
* $25 \div 4 = 6$ with a remainder of $1 \rightarrow \mathbf{6 \frac{1}{4}}$
Row 3:
* $127 \div 15 = 8$ with a remainder of $7 \rightarrow \mathbf{8 \frac{7}{15}}$
* $21 \div 8 = 2$ with a remainder of $5 \rightarrow \mathbf{2 \frac{5}{8}}$
* $15 \div 4 = 3$ with a remainder of $3 \rightarrow \mathbf{3 \frac{3}{4}}$
* $33 \div 10 = 3$ with a remainder of $3 \rightarrow \mathbf{3 \frac{3}{10}}$
Row 4:
* $25 \div 9 = 2$ with a remainder of $7 \rightarrow \mathbf{2 \frac{7}{9}}$
* $38 \div 7 = 5$ with a remainder of $3 \rightarrow \mathbf{5 \frac{3}{7}}$
* $99 \div 10 = 9$ with a remainder of $9 \rightarrow \mathbf{9 \frac{9}{10}}$
* $44 \div 5 = 8$ with a remainder of $4 \rightarrow \mathbf{8 \frac{4}{5}}$
Row 5:
* $53 \div 15 = 3$ with a remainder of $8 \rightarrow \mathbf{3 \frac{8}{15}}$
* $41 \div 8 = 5$ with a remainder of $1 \rightarrow \mathbf{5 \frac{1}{8}}$
* $64 \div 9 = 7$ with a remainder of $1 \rightarrow \mathbf{7 \frac{1}{9}}$
* $57 \div 10 = 5$ with a remainder of $7 \rightarrow \mathbf{5 \frac{7}{10}}$
Row 6:
* $16 \div 7 = 2$ with a remainder of $2 \rightarrow \mathbf{2 \frac{2}{7}}$
* $56 \div 9 = 6$ with a remainder of $2 \rightarrow \mathbf{6 \frac{2}{9}}$
* $21 \div 10 = 2$ with a remainder of $1 \rightarrow \mathbf{2 \frac{1}{10}}$
* $67 \div 8 = 8$ with a remainder of $3 \rightarrow \mathbf{8 \frac{3}{8}}$
Row 7:
* $12 \div 7 = 1$ with a remainder of $5 \rightarrow \mathbf{1 \frac{5}{7}}$
* $83 \div 12 = 6$ with a remainder of $11 \rightarrow \mathbf{6 \frac{11}{12}}$
* $36 \div 7 = 5$ with a remainder of $1 \rightarrow \mathbf{5 \frac{1}{7}}$
* $19 \div 6 = 3$ with a remainder of $1 \rightarrow \mathbf{3 \frac{1}{6}}$
Row 8:
* $13 \div 2 = 6$ with a remainder of $1 \rightarrow \mathbf{6 \frac{1}{2}}$
* $22 \div 3 = 7$ with a remainder of $1 \rightarrow \mathbf{7 \frac{1}{3}}$
* $23 \div 5 = 4$ with a remainder of $3 \rightarrow \mathbf{4 \frac{3}{5}}$
* $20 \div 7 = 2$ with a remainder of $6 \rightarrow \mathbf{2 \frac{6}{7}}$
Row 9:
* $76 \div 15 = 5$ with a remainder of $1 \rightarrow \mathbf{5 \frac{1}{15}}$
* $85 \div 9 = 9$ with a remainder of $4 \rightarrow \mathbf{9 \frac{4}{9}}$
* $80 \div 9 = 8$ with a remainder of $8 \rightarrow \mathbf{8 \frac{8}{9}}$
* $41 \div 12 = 3$ with a remainder of $5 \rightarrow \mathbf{3 \frac{5}{12}}$
Row 10:
* $6 \div 5 = 1$ with a remainder of $1 \rightarrow \mathbf{1 \frac{1}{5}}$
* $107 \div 15 = 7$ with a remainder of $2 \rightarrow \mathbf{7 \frac{2}{15}}$
* $63 \div 8 = 7$ with a remainder of $7 \rightarrow \mathbf{7 \frac{7}{8}}$
* $37 \div 5 = 7$ with a remainder of $2 \rightarrow \mathbf{7 \frac{2}{5}}$
Final Answer:
Row 1: $3 \frac{5}{9}, \quad 5 \frac{7}{12}, \quad 7 \frac{11}{15}, \quad 2 \frac{4}{15}$
Row 2: $2 \frac{1}{12}, \quad 6 \frac{5}{6}, \quad 7 \frac{4}{7}, \quad 6 \frac{1}{4}$
Row 3: $8 \frac{7}{15}, \quad 2 \frac{5}{8}, \quad 3 \frac{3}{4}, \quad 3 \frac{3}{10}$
Row 4: $2 \frac{7}{9}, \quad 5 \frac{3}{7}, \quad 9 \frac{9}{10}, \quad 8 \frac{4}{5}$
Row 5: $3 \frac{8}{15}, \quad 5 \frac{1}{8}, \quad 7 \frac{1}{9}, \quad 5 \frac{7}{10}$
Row 6: $2 \frac{2}{7}, \quad 6 \frac{2}{9}, \quad 2 \frac{1}{10}, \quad 8 \frac{3}{8}$
Row 7: $1 \frac{5}{7}, \quad 6 \frac{11}{12}, \quad 5 \frac{1}{7}, \quad 3 \frac{1}{6}$
Row 8: $6 \frac{1}{2}, \quad 7 \frac{1}{3}, \quad 4 \frac{3}{5}, \quad 2 \frac{6}{7}$
Row 9: $5 \frac{1}{15}, \quad 9 \frac{4}{9}, \quad 8 \frac{8}{9}, \quad 3 \frac{5}{12}$
Row 10: $1 \frac{1}{5}, \quad 7 \frac{2}{15}, \quad 7 \frac{7}{8}, \quad 7 \frac{2}{5}$
Parent Tip: Review the logic above to help your child master the concept of change mixed number to improper fraction worksheet.