Stoichiometry Introduction Worksheet - Chem1 | PDF | Stoichiometry ... - Free Printable

1. a. 2 moles of HCl
b. moles
c. moles of H₂
d. moles
e. Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g)
f. Using the balanced equation, 2 moles of HCl produce 1 mole of H₂. Therefore, 2 moles of HCl will produce 1 mole of H₂.

2. a. 2Al(s) + 6HCl(aq) → 2AlCl₃(aq) + 3H₂(g)
b. From the balanced equation, 2 moles of Al require 6 moles of HCl. The mole ratio is 6 mol HCl / 2 mol Al = 3 mol HCl / 1 mol Al. For 0.87 moles of Al: 0.87 mol Al × (3 mol HCl / 1 mol Al) = 2.61 moles of HCl.

3. a. 29 grams of glucose (C₆H₁₂O₆)
b. grams
c. moles of O₂
d. moles
e. First, balance the equation: C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O. The molar mass of glucose (C₆H₁₂O₆) is 180.16 g/mol. Convert 29 grams of glucose to moles: 29 g / 180.16 g/mol ≈ 0.161 moles of glucose. From the balanced equation, 1 mole of glucose requires 6 moles of O₂. Therefore, 0.161 moles of glucose require 0.161 mol × 6 = 0.966 moles of O₂.