Balancing Chemical Equation | PDF | Hydroxide | Sodium Hydroxide - Free Printable

Let's solve the Balancing Chemical Equations Worksheet step by step and then classify each reaction type.

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🔧 Step 1: Balancing Each Equation

We'll balance each chemical equation by ensuring the number of atoms of each element is equal on both sides.

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#### 1. Zn (s) + AgNO₃ (aq) → Zn(NO₃)₂ (aq) + Ag (s)

- Zn: 1 on left, 1 on right ✔
- Ag: 1 on left, 1 on right → but Ag is produced as solid, and Zn(NO₃)₂ has two NO₃⁻ groups.
- So need 2 AgNO₃ to provide two NO₃⁻ for Zn²⁺.

✔ Balanced:
> Zn (s) + 2AgNO₃ (aq) → Zn(NO₃)₂ (aq) + 2Ag (s)

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#### 2. N₂ (g) + H₂ (g) → NH₃ (g)

- N₂ has 2 N, NH₃ has 1 N → need 2 NH₃
- Then H: 6 H on right → need 3 H₂ on left

✔ Balanced:
> N₂ (g) + 3H₂ (g) → 2NH₃ (g)

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#### 3. NaCl (aq) + AgC₂H₃O₂ (aq) → NaC₂H₃O₂ (aq) + AgCl (s)

- All elements are 1:1 except AgCl precipitates.
- Already balanced as written.

✔ Balanced:
> NaCl (aq) + AgC₂H₃O₂ (aq) → NaC₂H₃O₂ (aq) + AgCl (s)

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#### 4. Mg(OH)₂ (aq) + H₃PO₄ (aq) → H₂O (l) + Mg₃(PO₄)₂ (aq)

- Mg: 2 on left, 3 on right → LCM = 6 → use 3 Mg(OH)₂, 2 Mg₃(PO₄)₂
- Wait: Mg₃(PO₄)₂ has 3 Mg → so need 3 Mg(OH)₂
- PO₄: 1 in H₃PO₄, 2 in Mg₃(PO₄)₂ → need 2 H₃PO₄
- Now H: from 3 Mg(OH)₂ → 6 OH⁻ → 6 H⁺ needed → 2 H₃PO₄ gives 6 H⁺ → perfect
- Water: 6 H and 6 O from OH and H → 6 H₂O

✔ Balanced:
> 3Mg(OH)₂ (aq) + 2H₃PO₄ (aq) → 6H₂O (l) + Mg₃(PO₄)₂ (aq)

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#### 5. HNO₃ (aq) + Ni (s) → Ni(NO₃)₂ (aq) + H₂ (g)

- Ni: 1 on both sides ✔
- NO₃⁻: 2 in Ni(NO₃)₂ → so need 2 HNO₃
- H: 2 H on left → produces H₂ → good

✔ Balanced:
> 2HNO₃ (aq) + Ni (s) → Ni(NO₃)₂ (aq) + H₂ (g)

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#### 6. Ba(HCO₃)₂ (s) → BaCO₃ (s) + H₂O (g) + CO₂ (g)

- Decomposition: bicarbonate breaks down.
- Ba(HCO₃)₂ → BaCO₃ + H₂O + CO₂
- But HCO₃⁻ decomposes: 2 HCO₃⁻ → CO₃²⁻ + H₂O + CO₂
- So one molecule gives: BaCO₃ + H₂O + CO₂

✔ Balanced:
> Ba(HCO₃)₂ (s) → BaCO₃ (s) + H₂O (g) + CO₂ (g)

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#### 7. BaCl₂ (aq) + Na₂SO₄ (aq) → NaCl (aq) + BaSO₄ (s)

- Ba: 1 on both sides
- SO₄: 1 on both
- Na: 2 on left → need 2 NaCl on right
- Cl: 2 on left → 2 on right

✔ Balanced:
> BaCl₂ (aq) + Na₂SO₄ (aq) → 2NaCl (aq) + BaSO₄ (s)

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#### 8. Al₂(CO₃)₃ (s) → Al₂O₃ (s) + CO₂ (g)

- Carbonate decomposition: CO₃²⁻ → CO₂ + O²⁻
- Al₂(CO₃)₃ has 3 CO₃ → 3 CO₂
- Oxygen: 9 O from CO₃ → 3 CO₂ uses 6 O, Al₂O₃ needs 3 O → total 9 O → matches

✔ Balanced:
> Al₂(CO₃)₃ (s) → Al₂O₃ (s) + 3CO₂ (g)

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#### 9. Ca (s) + H₂O (l) → Ca(OH)₂ (aq) + H₂ (g)

- Ca: 1 on both sides
- H: 2 on left, 2 in Ca(OH)₂ + 2 in H₂ → 4 H → need 2 H₂O
- O: 2 on left → 2 in Ca(OH)₂ → good
- H: 4 H from 2 H₂O → 2 H in Ca(OH)₂ + 2 H in H₂ → good

✔ Balanced:
> Ca (s) + 2H₂O (l) → Ca(OH)₂ (aq) + H₂ (g)

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#### 10. LiHCO₃ (s) → Li₂CO₃ (s) + H₂O (g) + CO₂ (g)

- Left: LiHCO₃ → 1 Li, 1 H, 1 C, 3 O
- Right: Li₂CO₃ has 2 Li → need 2 LiHCO₃
- Then: 2 LiHCO₃ → 2 H, 2 C, 6 O
- Products: Li₂CO₃ (1 C), H₂O (1 O, 2 H), CO₂ (1 C, 2 O)
- Total C: 1+1=2 ✔
- H: 2 → H₂O ✔
- O: 3 from Li₂CO₃ + 1 from H₂O + 2 from CO₂ = 6 ✔

✔ Balanced:
> 2LiHCO₃ (s) → Li₂CO₃ (s) + H₂O (g) + CO₂ (g)

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#### 11. N₂ (g) + O₂ (g) → N₂O₅ (g)

- N₂: 2 N → N₂O₅ has 2 N → good
- O: 5 O on right → need 5/2 O₂ → multiply all by 2

✔ Balanced:
> 2N₂ (g) + 5O₂ (g) → 2N₂O₅ (g)

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#### 12. MgBr₂ (aq) + KOH (aq) → KBr (aq) + Mg(OH)₂ (s)

- Mg: 1 on both
- Br: 2 → need 2 KBr
- K: 2 → need 2 KOH
- OH: 2 → Mg(OH)₂ needs 2 OH → good

✔ Balanced:
> MgBr₂ (aq) + 2KOH (aq) → 2KBr (aq) + Mg(OH)₂ (s)

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#### 13. Mn (s) + CuCl₂ (aq) → Cu (s) + MnCl₂ (s)

- Mn: 1 → 1
- Cu: 1 → 1
- Cl: 2 → 2

✔ Balanced:
> Mn (s) + CuCl₂ (aq) → Cu (s) + MnCl₂ (s)

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#### 14. Zn (s) + S₈ (s) → ZnS (s)

- S₈ has 8 S → need 8 ZnS
- Zn: 8 → need 8 Zn

✔ Balanced:
> 8Zn (s) + S₈ (s) → 8ZnS (s)

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#### 15. NaOH (aq) + H₂SO₄ (aq) → H₂O (l) + Na₂SO₄ (aq)

- Na: 1 on left → 2 on right → need 2 NaOH
- H: 2 from NaOH + 2 from H₂SO₄ = 4 H → H₂O has 2 H → need 2 H₂O
- SO₄: 1 → 1
- O: balanced

✔ Balanced:
> 2NaOH (aq) + H₂SO₄ (aq) → 2H₂O (l) + Na₂SO₄ (aq)

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#### 16. K (s) + H₂O (l) → KOH (aq) + H₂ (g)

- K: 1 → 1
- H: 2 on left → 1 in KOH + 2 in H₂ → 3 H → imbalance
- Need 2 K and 2 H₂O → 2 KOH and 1 H₂

Try:
> 2K + 2H₂O → 2KOH + H₂

✔ Balanced:
> 2K (s) + 2H₂O (l) → 2KOH (aq) + H₂ (g)

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#### 17. C₆H₁₂ (l) + O₂ (g) → H₂O (g) + CO₂ (g)

- Combustion of hydrocarbon.
- C₆H₁₂ → 6 CO₂ + 6 H₂O
- H: 12 → 6 H₂O → 12 H ✔
- C: 6 → 6 CO₂ ✔
- O: 6 CO₂ (12 O) + 6 H₂O (6 O) = 18 O → need 9 O₂

✔ Balanced:
> C₆H₁₂ (l) + 9O₂ (g) → 6H₂O (g) + 6CO₂ (g)

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#### 18. KOH (aq) + H₂CO₃ (aq) → H₂O (l) + K₂CO₃ (aq)

- K: 1 → 2 → need 2 KOH
- H: 2 from KOH + 2 from H₂CO₃ = 4 H → 2 H₂O
- CO₃: 1 → 1

✔ Balanced:
> 2KOH (aq) + H₂CO₃ (aq) → 2H₂O (l) + K₂CO₃ (aq)

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#### 19. C₆H₁₂O₆ (l) + O₂ (g) → H₂O (g) + CO₂ (g)

- Glucose combustion
- C₆H₁₂O₆ → 6 CO₂ + 6 H₂O
- C: 6 → 6 ✔
- H: 12 → 6 H₂O ✔
- O: left: 6 (from glucose) + 2×? from O₂
- Right: 6×2 = 12 O in CO₂ + 6×1 = 6 O in H₂O → 18 O
- So need 12 O from O₂ → 6 O₂

✔ Balanced:
> C₆H₁₂O₆ (l) + 6O₂ (g) → 6H₂O (g) + 6CO₂ (g)

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#### 20. Al (s) + S₈ (s) → Al₂S₃ (s)

- Al₂S₃ has 2 Al, 3 S
- S₈ has 8 S → need multiple of 3 and 8 → LCM = 24
- So: 4 Al₂S₃ → 8 Al, 12 S
- S₈ provides 8 S → need 3 S₈ → 24 S
- So 4 Al₂S₃ → 8 Al → need 8 Al

Wait: 4 Al₂S₃ = 8 Al, 12 S → but we need 24 S → so 3 S₈ = 24 S → need more Al

Better:
- Let’s find smallest integers:
- Al₂S₃ → 2 Al, 3 S
- S₈ → 8 S → need 8/3 = 2.66... → scale up
- Multiply Al₂S₃ by 8 → 16 Al, 24 S
- S₈ × 3 → 24 S
- Al → 16 Al

✔ Balanced:
> 16Al (s) + 3S₈ (s) → 8Al₂S₃ (s)

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✔ Final Balanced Equations:

| # | Balanced Equation |
|---|------------------|
| 1 | Zn + 2AgNO₃ → Zn(NO₃)₂ + 2Ag |
| 2 | N₂ + 3H₂ → 2NH₃ |
| 3 | NaCl + AgC₂H₃O₂ → NaC₂H₃O₂ + AgCl |
| 4 | 3Mg(OH)₂ + 2H₃PO₄ → 6H₂O + Mg₃(PO₄)₂ |
| 5 | 2HNO₃ + Ni → Ni(NO₃)₂ + H₂ |
| 6 | Ba(HCO₃)₂ → BaCO₃ + H₂O + CO₂ |
| 7 | BaCl₂ + Na₂SO₄ → 2NaCl + BaSO₄ |
| 8 | Al₂(CO₃)₃ → Al₂O₃ + 3CO₂ |
| 9 | Ca + 2H₂O → Ca(OH)₂ + H₂ |
|10 | 2LiHCO₃ → Li₂CO₃ + H₂O + CO₂ |
|11 | 2N₂ + 5O₂ → 2N₂O₅ |
|12 | MgBr₂ + 2KOH → 2KBr + Mg(OH)₂ |
|13 | Mn + CuCl₂ → Cu + MnCl₂ |
|14 | 8Zn + S₈ → 8ZnS |
|15 | 2NaOH + H₂SO₄ → 2H₂O + Na₂SO₄ |
|16 | 2K + 2H₂O → 2KOH + H₂ |
|17 | C₆H₁₂ + 9O₂ → 6H₂O + 6CO₂ |
|18 | 2KOH + H₂CO₃ → 2H₂O + K₂CO₃ |
|19 | C₆H₁₂O₆ + 6O₂ → 6H₂O + 6CO₂ |
|20 | 16Al + 3S₈ → 8Al₂S₃ |

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## 🔬 Types of Reactions

The five types of chemical reactions are:

1. Synthesis (Combination)
A + B → AB
Example: 2H₂ + O₂ → 2H₂O

2. Decomposition
AB → A + B
Example: 2H₂O → 2H₂ + O₂

3. Single Replacement (Displacement)
A + BC → AC + B
Example: Zn + 2HCl → ZnCl₂ + H₂

4. Double Replacement (Metathesis)
AB + CD → AD + CB
Example: AgNO₃ + NaCl → AgCl + NaNO₃

5. Combustion
Fuel + O₂ → CO₂ + H₂O (for hydrocarbons)
Example: CH₄ + 2O₂ → CO₂ + 2H₂O

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🔍 Classify Each Reaction:

| # | Type |
|---|------|
| 1 | Single Replacement (Zn replaces Ag) |
| 2 | Synthesis |
| 3 | Double Replacement (precipitation) |
| 4 | Double Replacement (acid-base) |
| 5 | Single Replacement (Ni displaces H) |
| 6 | Decomposition |
| 7 | Double Replacement (precipitation) |
| 8 | Decomposition |
| 9 | Single Replacement (Ca displaces H) |
|10 | Decomposition |
|11 | Synthesis |
|12 | Double Replacement |
|13 | Single Replacement (Mn displaces Cu) |
|14 | Synthesis |
|15 | Double Replacement (acid-base) |
|16 | Single Replacement (K displaces H) |
|17 | Combustion |
|18 | Double Replacement (acid-base) |
|19 | Combustion |
|20 | Synthesis |

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✔ Final Answer Table

#### Types of Reaction (List):

1. Synthesis: A + B → AB
Example: N₂ + 3H₂ → 2NH₃

2. Decomposition: AB → A + B
Example: Ba(HCO₃)₂ → BaCO₃ + H₂O + CO₂

3. Single Replacement: A + BC → AC + B
Example: Zn + 2AgNO₃ → Zn(NO₃)₂ + 2Ag

4. Double Replacement: AB + CD → AD + CB
Example: NaCl + AgC₂H₃O₂ → NaC₂H₃O₂ + AgCl

5. Combustion: Hydrocarbon + O₂ → CO₂ + H₂O
Example: C₆H₁₂ + 9O₂ → 6CO₂ + 6H₂O

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#### Classification of Reactions (1–20):

| # | Type |
|---|------|
| 1 | Single Replacement |
| 2 | Synthesis |
| 3 | Double Replacement |
| 4 | Double Replacement |
| 5 | Single Replacement |
| 6 | Decomposition |
| 7 | Double Replacement |
| 8 | Decomposition |
| 9 | Single Replacement |
|10 | Decomposition |
|11 | Synthesis |
|12 | Double Replacement |
|13 | Single Replacement |
|14 | Synthesis |
|15 | Double Replacement |
|16 | Single Replacement |
|17 | Combustion |
|18 | Double Replacement |
|19 | Combustion |
|20 | Synthesis |

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✔ All equations balanced and classified!
Let me know if you'd like this formatted as a printable worksheet or with explanations per reaction.