Atomic Structure and Chemical Nomenclature Worksheet with a table of elements and their properties.

Let's solve the Atomic Structure and Chemical Nomenclature Worksheet step by step.

We need to fill in the missing values in the table using the following key relationships:

- Atomic Number (Z) = number of protons
- Mass Number (A) = number of protons + neutrons
- Electrons = protons – charge (for ions), or equal to protons for neutral atoms
- Isotope/Ion Symbol format: $^A_Z\text{X}^{charge}$

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Step-by-step completion:

| Element | Atomic Number (Z) | Mass Number (A) | Protons | Neutrons | Electrons | Isotope/Ion Symbol |
|--------|-------------------|------------------|---------|----------|-----------|---------------------|
| | 6 | | | 6 | 6 | |
| Silicon | | 28 | 14 | | | $^{28}_{14}\text{Si}$ |
| | 26 | 56 | | | 24 | |
| | | | 79 | 118 | 79 | |
| | | | | 61 | 47 | |
| | 82 | | | 125 | 80 | |
| Fluorine | | 19 | 9 | | | $^{19}_9\text{F}^-$ |
| Oxygen | 8 | 16 | | | 10 | |
| | | | 12 | 12 | 10 | |
| | 19 | | | 20 | 18 | |
| Copper | | 64 | | | | $^{64}_{29}\text{Cu}^+$ |
| | 7 | 14 | | | 7 | |
| Hydrogen | | 1 | 1 | | 1 | |
| | | | 11 | 12 | | $^{23}_{11}\text{Na}^-$ |
| | 80 | 201 | | | | |
| | 42 | 96 | | | | |
| | 29 | | | 29 | 35 | |
| | 15 | 31 | | | | |

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Now, let’s fill each row one by one.

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Row 1:

- Z = 6 → Element is Carbon
- Protons = 6
- Neutrons = 6 → A = 6 + 6 = 12
- Electrons = 6 → Neutral atom
- Symbol: $^{12}_6\text{C}$

✔ Completed: Carbon, 12, 6, 6, 6, $^{12}_6\text{C}$

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Row 2: Silicon

- Given: A = 28, Protons = 14 → Z = 14
- Neutrons = A – protons = 28 – 14 = 14
- Electrons = 14 (neutral)
- Symbol given: $^{28}_{14}\text{Si}$ → matches

✔ Completed: 14, 28, 14, 14, 14, $^{28}_{14}\text{Si}$

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Row 3:

- Z = 26 → Iron (Fe)
- A = 56
- Protons = 26
- Neutrons = 56 – 26 = 30
- Electrons = 24 → so it has a charge of +2 (26 – 24 = +2)
- Ion: Fe²⁺ → symbol: $^{56}_{26}\text{Fe}^{2+}$

✔ Completed: Iron, 26, 56, 26, 30, 24, $^{56}_{26}\text{Fe}^{2+}$

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Row 4:

- Protons = 79 → Z = 79 → Gold (Au)
- Neutrons = 118 → A = 79 + 118 = 197
- Electrons = 79 → neutral
- Symbol: $^{197}_{79}\text{Au}$

✔ Completed: Au, 79, 197, 79, 118, 79, $^{197}_{79}\text{Au}$

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Row 5:

- Neutrons = 61
- Electrons = 47 → so protons = 47 (if neutral), but electrons < protons → ion
- But electrons = 47, so if neutral, protons = 47 → Z = 47 → Silver (Ag)
- So protons = 47
- A = protons + neutrons = 47 + 61 = 108
- Charge: 47 – 47 = 0 → neutral? Wait, electrons = 47, protons = 47 → neutral
- So element: Ag, Z = 47, A = 108 → $^{108}_{47}\text{Ag}$

✔ Completed: Ag, 47, 108, 47, 61, 47, $^{108}_{47}\text{Ag}$

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Row 6:

- Z = 82 → Lead (Pb)
- Neutrons = 125 → A = 82 + 125 = 207
- Electrons = 80 → so charge = 82 – 80 = +2 → Pb²⁺
- Symbol: $^{207}_{82}\text{Pb}^{2+}$

✔ Completed: Pb, 82, 207, 82, 125, 80, $^{207}_{82}\text{Pb}^{2+}$

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Row 7: Fluorine

- Given: A = 19, protons = 9 → Z = 9 → F
- Neutrons = 19 – 9 = 10
- Electrons = ? → symbol shows $^{19}_9\text{F}^-$ → charge = -1 → electrons = 9 + 1 = 10
- So electrons = 10

✔ Completed: F, 9, 19, 9, 10, 10, $^{19}_9\text{F}^-$

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Row 8: Oxygen

- Z = 8, A = 16
- Protons = 8
- Neutrons = 16 – 8 = 8
- Electrons = 10 → so charge = 8 – 10 = -2 → O²⁻
- Symbol: $^{16}_8\text{O}^{2-}$

✔ Completed: O, 8, 16, 8, 8, 10, $^{16}_8\text{O}^{2-}$

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Row 9:

- Protons = 12 → Z = 12 → Magnesium (Mg)
- Neutrons = 12 → A = 12 + 12 = 24
- Electrons = 10 → charge = 12 – 10 = +2 → Mg²⁺
- Symbol: $^{24}_{12}\text{Mg}^{2+}$

✔ Completed: Mg, 12, 24, 12, 12, 10, $^{24}_{12}\text{Mg}^{2+}$

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Row 10:

- Z = 19 → Potassium (K)
- Neutrons = 20 → A = 19 + 20 = 39
- Electrons = 18 → charge = 19 – 18 = +1 → K⁺
- Symbol: $^{39}_{19}\text{K}^+$

✔ Completed: K, 19, 39, 19, 20, 18, $^{39}_{19}\text{K}^+$

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Row 11: Copper

- A = 64
- Symbol: $^{64}_{29}\text{Cu}^+$ → so Z = 29 → Cu
- Protons = 29
- Neutrons = 64 – 29 = 35
- Electrons = 29 – 1 = 28 (since +1 charge)
- So electrons = 28

✔ Completed: Cu, 29, 64, 29, 35, 28, $^{64}_{29}\text{Cu}^+$

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Row 12:

- Z = 7 → Nitrogen (N)
- A = 14
- Protons = 7
- Neutrons = 14 – 7 = 7
- Electrons = 7 → neutral
- Symbol: $^{14}_7\text{N}$

✔ Completed: N, 7, 14, 7, 7, 7, $^{14}_7\text{N}$

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Row 13: Hydrogen

- Z = 1, A = 1
- Protons = 1
- Neutrons = 1 – 1 = 0
- Electrons = 1 → neutral
- Symbol: $^1_1\text{H}$

✔ Completed: H, 1, 1, 1, 0, 1, $^1_1\text{H}$

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Row 14:

- Protons = 11 → Z = 11 → Sodium (Na)
- Neutrons = 12 → A = 11 + 12 = 23
- Symbol: $^{23}_{11}\text{Na}^-$ → charge = -1 → electrons = 11 + 1 = 12
- So electrons = 12

✔ Completed: Na, 11, 23, 11, 12, 12, $^{23}_{11}\text{Na}^-$

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Row 15:

- Z = 80 → Mercury (Hg)
- A = 201
- Protons = 80
- Neutrons = 201 – 80 = 121
- Electrons = 80 → neutral
- Symbol: $^{201}_{80}\text{Hg}$

✔ Completed: Hg, 80, 201, 80, 121, 80, $^{201}_{80}\text{Hg}$

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Row 16:

- Z = 42 → Molybdenum (Mo)
- A = 96
- Protons = 42
- Neutrons = 96 – 42 = 54
- Electrons = 42 → neutral
- Symbol: $^{96}_{42}\text{Mo}$

✔ Completed: Mo, 42, 96, 42, 54, 42, $^{96}_{42}\text{Mo}$

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Row 17:

- Z = 29 → Copper (Cu)
- Neutrons = 29 → A = 29 + 29 = 58
- Electrons = 35 → more than protons → anion
- Protons = 29 → charge = 29 – 35 = -6 → Cu⁶⁻ (unusual, but possible in theory)
- But wait: this seems off. Let's double-check.
- Protons = 29 → Z = 29 → Cu
- Neutrons = 29 → A = 58
- Electrons = 35 → charge = 29 – 35 = -6 → Cu⁶⁻
- But such a high charge is rare — possibly a typo?
- But based on data: