Let’s go step by step to solve this worksheet.
The task is to write the
chemical formula for each given ionic compound name, and also to write the
name for each given chemical formula.
We’ll do them one at a time.
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Part 1: Write the formula from the name
#### a) magnesium oxide
Magnesium = Mg²⁺
Oxide = O²⁻
Charges balance → MgO
✔ MgO
#### b) calcium sulfide
Calcium = Ca²⁺
Sulfide = S²⁻
Charges balance → CaS
✔ CaS
#### c) aluminum chloride
Aluminum = Al³⁺
Chloride = Cl⁻
Need 3 Cl⁻ to balance 1 Al³⁺ → AlCl
✔ AlCl₃
#### d) sodium bromide
Sodium = Na⁺
Bromide = Br⁻
Balance → NaBr
✔ NaBr
#### e) potassium iodide
Potassium = K⁺
Iodide = I⁻
Balance → KI
✔ KI
#### f) lithium fluoride
Lithium = Li⁺
Fluoride = F
Balance → LiF
✔ LiF
#### g) barium nitrate
Barium = Ba²⁺
Nitrate = NO₃⁻ (polyatomic ion)
Need 2 NO₃⁻ to balance Ba²⁺ → Ba(NO)₂
✔ Ba(NO₃)₂
#### h) ammonium sulfate
Ammonium = NH₄⁺
Sulfate = SO₄²
Need 2 NH₄ to balance SO₄²⁻ → (NH₄)₂SO₄
✔ (NH₄)₂SO₄
#### i) iron(II) phosphate
Iron(II) = Fe²⁺
Phosphate = PO₄³⁻
Find least common multiple of 2 and 3 → 6
So: 3 Fe² (total +6) and 2 PO₄³⁻ (total -6) → Fe₃(PO₄)₂
✔ Fe₃(PO₄)₂
#### j) copper(I) carbonate
Copper(I) = Cu⁺
Carbonate = CO₃²⁻
Need 2 Cu⁺ to balance CO₃²⁻ → Cu₂CO₃
✔ Cu₂CO₃
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Part 2: Write the name from the formula
#### k) AgCl
Ag = silver (usually +1)
Cl = chloride
→ Silver chloride
✔ silver chloride
#### l) ZnO
Zn = zinc (+2)
O = oxide
→ Zinc oxide
✔ zinc oxide
#### m) FeCl₃
Fe here must be +3 because Cl is -1 × 3 = -3 → so Fe³
→ Iron(III) chloride
✔ iron(III) chloride
#### n) PbS
Pb = lead (can be +2 or +4; S is -2 → so Pb²⁺)
→ Lead(II) sulfide
✔ lead(II) sulfide
#### o) SnBr₂
Sn = tin (Br is -1 × 2 = -2 → so Sn²⁺)
→ Tin(II) bromide
✔ tin(II) bromide
#### p) Hg₂Cl₂
This is mercury(I) — note: Hg₂²⁺ is the diatomic ion
Cl is -1 × 2 = -2 → matches Hg₂²⁺
→ Mercury(I) chloride
✔ mercury(I) chloride
#### q) Cr₂O
Cr: let x be charge. 2x + 3(-2) = 0 → 2x = 6 → x = +3
→ Chromium(III) oxide
✔ chromium(III) oxide
#### r) MnSO₄
Mn: SO₄ is -2 → so Mn must be +2
→ Manganese(II) sulfate
✔ manganese(II) sulfate
#### s) Ni(NO₃)₂
Ni: NO₃ is -1 × 2 = -2 → so Ni²⁺
→ Nickel(II) nitrate
✔ nickel(II) nitrate
#### t) Co(OH)
Co: OH is -1 × 3 = -3 → so Co³
→ Cobalt(III) hydroxide
✔ cobalt(III) hydroxide
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Final Answer:
a) MgO
b) CaS
c) AlCl
d) NaBr
e) KI
f) LiF
g) Ba(NO₃)₂
h) (NH₄)₂SO₄
i) Fe₃(PO₄)₂
j) Cu₂CO
k) silver chloride
l) zinc oxide
m) iron(III) chloride
n) lead(II) sulfide
o) tin(II) bromide
p) mercury(I) chloride
q) chromium(III) oxide
r) manganese(II) sulfate
s) nickel(II) nitrate
t) cobalt(III) hydroxide
Parent Tip: Review the logic above to help your child master the concept of chemistry unit 6 worksheet 3.