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Perimeter & Area of Semi and Quadrant Circle worksheet | Live ... - Free Printable

Perimeter &  Area of Semi and Quadrant Circle worksheet | Live ...

Educational worksheet: Perimeter & Area of Semi and Quadrant Circle worksheet | Live .... Download and print for classroom or home learning activities.

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Show Answer Key & Explanations Step-by-step solution for: Perimeter & Area of Semi and Quadrant Circle worksheet | Live ...
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To solve the problem, we need to calculate the perimeter and area of the given semicircles and quarter circles. Let's break it down step by step for each shape.

Formulas Needed:


1. Circumference of a full circle: \( C = 2\pi r \)
2. Area of a full circle: \( A = \pi r^2 \)

#### For Semicircles:
- Perimeter: The perimeter of a semicircle is half the circumference of the full circle plus the diameter.
\[
P_{\text{semicircle}} = \pi r + 2r
\]
- Area: The area of a semicircle is half the area of the full circle.
\[
A_{\text{semicircle}} = \frac{1}{2} \pi r^2
\]

#### For Quarter Circles:
- Perimeter: The perimeter of a quarter circle is one-fourth the circumference of the full circle plus twice the radius.
\[
P_{\text{quarter circle}} = \frac{\pi r}{2} + 2r
\]
- Area: The area of a quarter circle is one-fourth the area of the full circle.
\[
A_{\text{quarter circle}} = \frac{1}{4} \pi r^2
\]

Given Data:


- Use \( \pi = 3.142 \)

---

Solutions:



#### Part (a): Semicircle with radius \( r = 3 \) cm
- Perimeter:
\[
P = \pi r + 2r = 3.142 \times 3 + 2 \times 3 = 9.426 + 6 = 15.426 \approx 15.4 \, \text{cm}
\]
- Area:
\[
A = \frac{1}{2} \pi r^2 = \frac{1}{2} \times 3.142 \times 3^2 = \frac{1}{2} \times 3.142 \times 9 = 14.139 \approx 14.1 \, \text{cm}^2
\]

#### Part (b): Quarter Circle with radius \( r = 4 \) cm
- Perimeter:
\[
P = \frac{\pi r}{2} + 2r = \frac{3.142 \times 4}{2} + 2 \times 4 = 6.284 + 8 = 14.284 \approx 14.3 \, \text{cm}
\]
- Area:
\[
A = \frac{1}{4} \pi r^2 = \frac{1}{4} \times 3.142 \times 4^2 = \frac{1}{4} \times 3.142 \times 16 = 12.568 \approx 12.6 \, \text{cm}^2
\]

#### Part (c): Semicircle with diameter \( d = 6 \) cm
- Radius \( r = \frac{d}{2} = \frac{6}{2} = 3 \) cm
- Perimeter:
\[
P = \pi r + 2r = 3.142 \times 3 + 2 \times 3 = 9.426 + 6 = 15.426 \approx 15.4 \, \text{cm}
\]
- Area:
\[
A = \frac{1}{2} \pi r^2 = \frac{1}{2} \times 3.142 \times 3^2 = \frac{1}{2} \times 3.142 \times 9 = 14.139 \approx 14.1 \, \text{cm}^2
\]

#### Part (d): Semicircle with radius \( r = 3.5 \) cm
- Perimeter:
\[
P = \pi r + 2r = 3.142 \times 3.5 + 2 \times 3.5 = 10.997 + 7 = 17.997 \approx 18.0 \, \text{cm}
\]
- Area:
\[
A = \frac{1}{2} \pi r^2 = \frac{1}{2} \times 3.142 \times 3.5^2 = \frac{1}{2} \times 3.142 \times 12.25 = 19.23625 \approx 19.2 \, \text{cm}^2
\]

#### Part (e): Quarter Circle with radius \( r = 2 \) mm
- Perimeter:
\[
P = \frac{\pi r}{2} + 2r = \frac{3.142 \times 2}{2} + 2 \times 2 = 3.142 + 4 = 7.142 \approx 7.1 \, \text{mm}
\]
- Area:
\[
A = \frac{1}{4} \pi r^2 = \frac{1}{4} \times 3.142 \times 2^2 = \frac{1}{4} \times 3.142 \times 4 = 3.142 \approx 3.1 \, \text{mm}^2
\]

#### Part (f): Quarter Circle with radius \( r = 1.5 \) m
- Perimeter:
\[
P = \frac{\pi r}{2} + 2r = \frac{3.142 \times 1.5}{2} + 2 \times 1.5 = 2.3565 + 3 = 5.3565 \approx 5.4 \, \text{m}
\]
- Area:
\[
A = \frac{1}{4} \pi r^2 = \frac{1}{4} \times 3.142 \times 1.5^2 = \frac{1}{4} \times 3.142 \times 2.25 = 1.769625 \approx 1.8 \, \text{m}^2
\]

#### Part (g): Quarter Circle with radius \( r = 7 \) m
- Perimeter:
\[
P = \frac{\pi r}{2} + 2r = \frac{3.142 \times 7}{2} + 2 \times 7 = 10.997 + 14 = 24.997 \approx 25.0 \, \text{m}
\]
- Area:
\[
A = \frac{1}{4} \pi r^2 = \frac{1}{4} \times 3.142 \times 7^2 = \frac{1}{4} \times 3.142 \times 49 = 38.4845 \approx 38.5 \, \text{m}^2
\]

#### Part (h): Quarter Circle with radius \( r = 13 \) m
- Perimeter:
\[
P = \frac{\pi r}{2} + 2r = \frac{3.142 \times 13}{2} + 2 \times 13 = 20.423 + 26 = 46.423 \approx 46.4 \, \text{m}
\]
- Area:
\[
A = \frac{1}{4} \pi r^2 = \frac{1}{4} \times 3.142 \times 13^2 = \frac{1}{4} \times 3.142 \times 169 = 132.66845 \approx 132.7 \, \text{m}^2
\]

---

Final Answers:


\[
\boxed{
\begin{array}{ll}
\text{(a)} & \text{Perimeter: } 15.4 \, \text{cm}, \, \text{Area: } 14.1 \, \text{cm}^2 \\
\text{(b)} & \text{Perimeter: } 14.3 \, \text{cm}, \, \text{Area: } 12.6 \, \text{cm}^2 \\
\text{(c)} & \text{Perimeter: } 15.4 \, \text{cm}, \, \text{Area: } 14.1 \, \text{cm}^2 \\
\text{(d)} & \text{Perimeter: } 18.0 \, \text{cm}, \, \text{Area: } 19.2 \, \text{cm}^2 \\
\text{(e)} & \text{Perimeter: } 7.1 \, \text{mm}, \, \text{Area: } 3.1 \, \text{mm}^2 \\
\text{(f)} & \text{Perimeter: } 5.4 \, \text{m}, \, \text{Area: } 1.8 \, \text{m}^2 \\
\text{(g)} & \text{Perimeter: } 25.0 \, \text{m}, \, \text{Area: } 38.5 \, \text{m}^2 \\
\text{(h)} & \text{Perimeter: } 46.4 \, \text{m}, \, \text{Area: } 132.7 \, \text{m}^2 \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of circle area and perimeter worksheet.
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