Math worksheet for calculating the area and circumference of circles.
Worksheet titled "Area & Circumference" with nine circles, each labeled with a radius or diameter, and spaces to calculate radius, diameter, area, and circumference.
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Show Answer Key & Explanations
Step-by-step solution for: Circumference, Area, Radius, and Diameter - Circle Worksheets
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Show Answer Key & Explanations
Step-by-step solution for: Circumference, Area, Radius, and Diameter - Circle Worksheets
Let's solve each problem step by step using the formulas for area and circumference of a circle:
- Diameter (d) = 2 × Radius (r)
- Radius (r) = Diameter ÷ 2
- Area (A) = π × r²
- Circumference (C) = 2π × r or π × d
We’ll use π ≈ 3.14 unless otherwise specified.
---
- Given: Radius = 4 ft
- Diameter = 2 × 4 = 8 ft
- Area = π × r² = π × 4² = π × 16 = 16π ft²
- Circumference = 2π × r = 2π × 4 = 8π ft
✔ Answer:
- Radius = 4 ft
- Diameter = 8 ft
- Area = 16π ft²
- Circumference = 8π ft
---
- Given: Radius = 7 cm
- Diameter = 2 × 7 = 14 cm
- Area = π × 7² = π × 49 = 49π cm²
- Circumference = 2π × 7 = 14π cm
✔ Answer:
- Radius = 7 cm
- Diameter = 14 cm
- Area = 49π cm²
- Circumference = 14π cm
---
- Given: Diameter = 14 m
- Radius = 14 ÷ 2 = 7 m
- Area = π × 7² = 49π m²
- Circumference = π × 14 = 14π m
✔ Answer:
- Radius = 7 m
- Diameter = 14 m
- Area = 49π m²
- Circumference = 14π m
---
- Given: Radius = 9 in
- Diameter = 2 × 9 = 18 in
- Area = π × 9² = π × 81 = 81π in²
- Circumference = 2π × 9 = 18π in
✔ Answer:
- Radius = 9 in
- Diameter = 18 in
- Area = 81π in²
- Circumference = 18π in
---
- Given: Diameter = 36 ft
- Radius = 36 ÷ 2 = 18 ft
- Area = π × 18² = π × 324 = 324π ft²
- Circumference = π × 36 = 36π ft
✔ Answer:
- Radius = 18 ft
- Diameter = 36 ft
- Area = 324π ft²
- Circumference = 36π ft
---
- Given: Radius = 5 in
- Diameter = 2 × 5 = 10 in
- Area = π × 5² = π × 25 = 25π in²
- Circumference = 2π × 5 = 10π in
✔ Answer:
- Radius = 5 in
- Diameter = 10 in
- Area = 25π in²
- Circumference = 10π in
---
- Given: Diameter = 30 cm
- Radius = 30 ÷ 2 = 15 cm
- Area = π × 15² = π × 225 = 225π cm²
- Circumference = π × 30 = 30π cm
✔ Answer:
- Radius = 15 cm
- Diameter = 30 cm
- Area = 225π cm²
- Circumference = 30π cm
---
- Given: Radius = 8 mm
- Diameter = 2 × 8 = 16 mm
- Area = π × 8² = π × 64 = 64π mm²
- Circumference = 2π × 8 = 16π mm
✔ Answer:
- Radius = 8 mm
- Diameter = 16 mm
- Area = 64π mm²
- Circumference = 16π mm
---
- Given: Diameter = 25 km
- Radius = 25 ÷ 2 = 12.5 km
- Area = π × (12.5)² = π × 156.25 = 156.25π km²
- Circumference = π × 25 = 25π km
✔ Answer:
- Radius = 12.5 km
- Diameter = 25 km
- Area = 156.25π km²
- Circumference = 25π km
---
| # | Radius | Diameter | Area | Circumference |
|---|--------|----------|------------|----------------|
| 1 | 4 ft | 8 ft | 16π ft² | 8π ft |
| 2 | 7 cm | 14 cm | 49π cm² | 14π cm |
| 3 | 7 m | 14 m | 49π m² | 14π m |
| 4 | 9 in | 18 in | 81π in² | 18π in |
| 5 | 18 ft | 36 ft | 324π ft² | 36π ft |
| 6 | 5 in | 10 in | 25π in² | 10π in |
| 7 | 15 cm | 30 cm | 225π cm² | 30π cm |
| 8 | 8 mm | 16 mm | 64π mm² | 16π mm |
| 9 | 12.5 km| 25 km | 156.25π km²| 25π km |
> 💡 Note: The question asks for exact area and circumference, so we leave answers in terms of π, not decimal approximations.
Let me know if you'd like decimal versions too!
🔷 Formulas:
- Diameter (d) = 2 × Radius (r)
- Radius (r) = Diameter ÷ 2
- Area (A) = π × r²
- Circumference (C) = 2π × r or π × d
We’ll use π ≈ 3.14 unless otherwise specified.
---
Problem 1
- Given: Radius = 4 ft
- Diameter = 2 × 4 = 8 ft
- Area = π × r² = π × 4² = π × 16 = 16π ft²
- Circumference = 2π × r = 2π × 4 = 8π ft
✔ Answer:
- Radius = 4 ft
- Diameter = 8 ft
- Area = 16π ft²
- Circumference = 8π ft
---
Problem 2
- Given: Radius = 7 cm
- Diameter = 2 × 7 = 14 cm
- Area = π × 7² = π × 49 = 49π cm²
- Circumference = 2π × 7 = 14π cm
✔ Answer:
- Radius = 7 cm
- Diameter = 14 cm
- Area = 49π cm²
- Circumference = 14π cm
---
Problem 3
- Given: Diameter = 14 m
- Radius = 14 ÷ 2 = 7 m
- Area = π × 7² = 49π m²
- Circumference = π × 14 = 14π m
✔ Answer:
- Radius = 7 m
- Diameter = 14 m
- Area = 49π m²
- Circumference = 14π m
---
Problem 4
- Given: Radius = 9 in
- Diameter = 2 × 9 = 18 in
- Area = π × 9² = π × 81 = 81π in²
- Circumference = 2π × 9 = 18π in
✔ Answer:
- Radius = 9 in
- Diameter = 18 in
- Area = 81π in²
- Circumference = 18π in
---
Problem 5
- Given: Diameter = 36 ft
- Radius = 36 ÷ 2 = 18 ft
- Area = π × 18² = π × 324 = 324π ft²
- Circumference = π × 36 = 36π ft
✔ Answer:
- Radius = 18 ft
- Diameter = 36 ft
- Area = 324π ft²
- Circumference = 36π ft
---
Problem 6
- Given: Radius = 5 in
- Diameter = 2 × 5 = 10 in
- Area = π × 5² = π × 25 = 25π in²
- Circumference = 2π × 5 = 10π in
✔ Answer:
- Radius = 5 in
- Diameter = 10 in
- Area = 25π in²
- Circumference = 10π in
---
Problem 7
- Given: Diameter = 30 cm
- Radius = 30 ÷ 2 = 15 cm
- Area = π × 15² = π × 225 = 225π cm²
- Circumference = π × 30 = 30π cm
✔ Answer:
- Radius = 15 cm
- Diameter = 30 cm
- Area = 225π cm²
- Circumference = 30π cm
---
Problem 8
- Given: Radius = 8 mm
- Diameter = 2 × 8 = 16 mm
- Area = π × 8² = π × 64 = 64π mm²
- Circumference = 2π × 8 = 16π mm
✔ Answer:
- Radius = 8 mm
- Diameter = 16 mm
- Area = 64π mm²
- Circumference = 16π mm
---
Problem 9
- Given: Diameter = 25 km
- Radius = 25 ÷ 2 = 12.5 km
- Area = π × (12.5)² = π × 156.25 = 156.25π km²
- Circumference = π × 25 = 25π km
✔ Answer:
- Radius = 12.5 km
- Diameter = 25 km
- Area = 156.25π km²
- Circumference = 25π km
---
✔ Final Answers Summary:
| # | Radius | Diameter | Area | Circumference |
|---|--------|----------|------------|----------------|
| 1 | 4 ft | 8 ft | 16π ft² | 8π ft |
| 2 | 7 cm | 14 cm | 49π cm² | 14π cm |
| 3 | 7 m | 14 m | 49π m² | 14π m |
| 4 | 9 in | 18 in | 81π in² | 18π in |
| 5 | 18 ft | 36 ft | 324π ft² | 36π ft |
| 6 | 5 in | 10 in | 25π in² | 10π in |
| 7 | 15 cm | 30 cm | 225π cm² | 30π cm |
| 8 | 8 mm | 16 mm | 64π mm² | 16π mm |
| 9 | 12.5 km| 25 km | 156.25π km²| 25π km |
> 💡 Note: The question asks for exact area and circumference, so we leave answers in terms of π, not decimal approximations.
Let me know if you'd like decimal versions too!
Parent Tip: Review the logic above to help your child master the concept of circumference worksheets.