Binary Coding worksheet for students to practice converting words into binary code.

To solve the problem, we need to convert each letter in the given words into its corresponding binary code. Binary coding for letters typically uses the ASCII (American Standard Code for Information Interchange) system, where each character is represented by a unique 7-bit or 8-bit binary number.

Step-by-Step Solution:

#### 1. BLUE CARDS
The word is "HELLO".

- H: The ASCII value of 'H' is 72.
- Convert 72 to binary: \( 72_{10} = 01001000_2 \)
- E: The ASCII value of 'E' is 69.
- Convert 69 to binary: \( 69_{10} = 01000101_2 \)
- L: The ASCII value of 'L' is 76.
- Convert 76 to binary: \( 76_{10} = 01001100_2 \)
- L: The ASCII value of 'L' is 76.
- Convert 76 to binary: \( 76_{10} = 01001100_2 \)
- O: The ASCII value of 'O' is 79.
- Convert 79 to binary: \( 79_{10} = 01001111_2 \)

So, the binary codes are:
- H: 01001000
- E: 01000101
- L: 01001100
- L: 01001100
- O: 01001111

#### 2. Word "FUTURE"
- F: The ASCII value of 'F' is 70.
- Convert 70 to binary: \( 70_{10} = 01000110_2 \)
- U: The ASCII value of 'U' is 85.
- Convert 85 to binary: \( 85_{10} = 01010101_2 \)
- T: The ASCII value of 'T' is 84.
- Convert 84 to binary: \( 84_{10} = 01010100_2 \)
- U: The ASCII value of 'U' is 85.
- Convert 85 to binary: \( 85_{10} = 01010101_2 \)
- R: The ASCII value of 'R' is 82.
- Convert 82 to binary: \( 82_{10} = 01010010_2 \)
- E: The ASCII value of 'E' is 69.
- Convert 69 to binary: \( 69_{10} = 01000101_2 \)

So, the binary codes are:
- F: 01000110
- U: 01010101
- T: 01010100
- U: 01010101
- R: 01010010
- E: 01000101

#### 3. Word "CANDY"
- C: The ASCII value of 'C' is 67.
- Convert 67 to binary: \( 67_{10} = 01000011_2 \)
- A: The ASCII value of 'A' is 65.
- Convert 65 to binary: \( 65_{10} = 01000001_2 \)
- N: The ASCII value of 'N' is 78.
- Convert 78 to binary: \( 78_{10} = 01001110_2 \)
- D: The ASCII value of 'D' is 68.
- Convert 68 to binary: \( 68_{10} = 01000100_2 \)
- Y: The ASCII value of 'Y' is 89.
- Convert 89 to binary: \( 89_{10} = 01011001_2 \)

So, the binary codes are:
- C: 01000011
- A: 01000001
- N: 01001110
- D: 01000100
- Y: 01011001

#### 4. Word "PIZZA"
- P: The ASCII value of 'P' is 80.
- Convert 80 to binary: \( 80_{10} = 01010000_2 \)
- I: The ASCII value of 'I' is 73.
- Convert 73 to binary: \( 73_{10} = 01001001_2 \)
- Z: The ASCII value of 'Z' is 90.
- Convert 90 to binary: \( 90_{10} = 01011010_2 \)
- Z: The ASCII value of 'Z' is 90.
- Convert 90 to binary: \( 90_{10} = 01011010_2 \)
- A: The ASCII value of 'A' is 65.
- Convert 65 to binary: \( 65_{10} = 01000001_2 \)

So, the binary codes are:
- P: 01010000
- I: 01001001
- Z: 01011010
- Z: 01011010
- A: 01000001

Final Answer:

\[
\boxed{
\begin{array}{ll}
\text{1. HELLO} & \begin{aligned}
H: & 01001000 \\
E: & 01000101 \\
L: & 01001100 \\
L: & 01001100 \\
O: & 01001111
\end{aligned} \\
\text{2. FUTURE} & \begin{aligned}
F: & 01000110 \\
U: & 01010101 \\
T: & 01010100 \\
U: & 01010101 \\
R: & 01010010 \\
E: & 01000101
\end{aligned} \\
\text{3. CANDY} & \begin{aligned}
C: & 01000011 \\
A: & 01000001 \\
N: & 01001110 \\
D: & 01000100 \\
Y: & 01011001
\end{aligned} \\
\text{4. PIZZA} & \begin{aligned}
P: & 01010000 \\
I: & 01001001 \\
Z: & 01011010 \\
Z: & 01011010 \\
A: & 01000001
\end{aligned}
\end{array}
}
\]