Let’s solve each row one by one. We’ll add up the value of the coins in each row to find the total.
First, let’s remember what each coin is worth:
- Penny (copper coin with Lincoln) = 1¢
- Nickel (silver coin with Jefferson) = 5¢
- Dime (small silver coin with Roosevelt) = 10¢
- Quarter (large silver coin with Washington) = 25¢
Now, let’s go row by row:
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Row 1:
Nickel (5¢) + Penny (1¢) + Dime (10¢) = 5 + 1 + 10 =
16¢ → Already given as correct.
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Row 2:
Quarter (25¢) + Penny (1¢) + Dime (10¢) = 25 + 1 + 10 =
36¢
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Row 3:
Quarter (25¢) + Dime (10¢) + Dime (10¢) = 25 + 10 + 10 =
45¢
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Row 4:
Penny (1¢) + Penny (1¢) + Penny (1¢) + Nickel (5¢) = 1 + 1 + 1 + 5 =
8¢
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Row 5:
Nickel (5¢) + Penny (1¢) + Quarter (25¢) + Penny (1¢) = 5 + 1 + 25 + 1 =
32¢
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Row 6:
Quarter (25¢) + Dime (10¢) + Dime (10¢) + Penny (1¢) = 25 + 10 + 10 + 1 =
46¢
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Row 7:
Nickel (5¢) + Nickel (5¢) + Nickel (5¢) + Penny (1¢) = 5 + 5 + 5 + 1 =
16¢
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Row 8:
Penny (1¢) + Quarter (25¢) + Nickel (5¢) + Dime (10¢) = 1 + 25 + 5 + 10 =
41¢
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Final Answer:
Row 2: 36¢
Row 3: 45¢
Row 4: 8¢
Row 5: 32¢
Row 6: 46¢
Row 7: 16¢
Row 8: 41¢
Parent Tip: Review the logic above to help your child master the concept of coins worksheet for 2nd grade.
