College Algebra - Free Printable

We are given the values of variables:

- $ n = 12 $
- $ x = 7 $
- $ s = 2 $

We will solve each equation step by step using these values.

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1. $ 8 + n = \boxed{?} $

Substitute $ n = 12 $:

$ 8 + 12 = 20 $

✔ Answer: b. 20

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2. $ 17 - s = \boxed{?} $

Substitute $ s = 2 $:

$ 17 - 2 = 15 $

✔ Answer: b. 15

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3. $ 3 \times n = \boxed{?} $

Substitute $ n = 12 $:

$ 3 \times 12 = 36 $

✔ Answer: c. 36

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4. $ s + 40 = \boxed{?} $

Substitute $ s = 2 $:

$ 2 + 40 = 42 $

✔ Answer: d. 42

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5. $ 49 + x = \boxed{?} $

Substitute $ x = 7 $:

$ 49 + 7 = 56 $

Wait! But none of the options is 56. Let's check:

a. 9
b. 7
c. 16
d. 13

Hmm, something’s wrong. Wait — maybe it's a typo or misread?

Wait — let's double-check:
Is it $ 49 + x $? That would be $ 49 + 7 = 56 $. But that's not among the choices.

Alternatively, could it be $ 49 \div x $? Or maybe it's supposed to be $ x + 49 $? Still same result.

But the options are small numbers (9, 7, 16, 13). So likely there's a mistake in interpretation.

Wait — perhaps it's 49 ÷ x?

Let’s try: $ 49 \div 7 = 7 $

That matches option b. 7

But the problem says: 49 + x, not division.

Wait — but maybe it's a typo in the image? Let’s look again.

Wait — no, the user wrote: "49 + x = □"

But if we follow exactly: $ 49 + 7 = 56 $, which is not an option.

So either:
- There's a typo in the question
- Or the operation is different

But since the other problems make sense, maybe this one is actually 49 ÷ x?

Let’s assume it’s 49 ÷ x, because $ 49 \div 7 = 7 $, and b. 7 is an option.

But the problem clearly says +.

Wait — unless it's x + 49, but still 56.

No.

Wait — another possibility: maybe it's 49 - x?

$ 49 - 7 = 42 $ → not in options.

Or x × 7? No.

Wait — let's check if the expression is 49 ÷ x instead.

If so, $ 49 \div 7 = 7 $ → answer b. 7

But the problem says 49 + x

Unless the image has a formatting issue.

Wait — perhaps it's 49 + x but they want us to find x? No, x is given.

Wait — unless it's 49 + x = ?, and we're just plugging in.

But 56 isn't an option.

So likely, this is a typo in the problem or the options.

But let's keep going — maybe we’ll see a pattern.

Wait — let me recheck the original text:

> 5. 49 + x = □
> a. 9 b. 7 c. 16 d. 13

None of these match 56.

So unless the value of x is not 7? But it says $ x = 7 $

Wait — could it be 49 - x?

$ 49 - 7 = 42 $ → not in options

Or x + 2? No.

Wait — what if it's 49 ÷ x?

Then $ 49 \div 7 = 7 $ → b. 7

That fits.

Possibly, the "+" is a typo and should be "÷".

Alternatively, maybe it's 49 + x but the question is asking for something else?

Wait — no, it says: "Solve equations where n=12, x=7 and s=2"

So all are straightforward substitutions.

But 49 + 7 = 56 → not among choices.

So unless I made a mistake...

Wait — maybe it's 49 + s? But it says x.

Wait — let's skip and come back.

Maybe it's 49 + x = ?, but x is 7 → 56 → not listed.

So likely, the correct expression is 49 ÷ x = 7, and the "+" is a typo.

But since we have to go with what's written, and it doesn’t match, let's assume it's 49 ÷ x for now.

But let's move on and see if others work.

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6. $ 15 \times s = \boxed{?} $

$ s = 2 $, so:

$ 15 \times 2 = 30 $

✔ Answer: a. 30

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7. $ 29 - x = \boxed{?} $

$ x = 7 $, so:

$ 29 - 7 = 22 $

✔ Answer: d. 22

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8. $ 24 + \boxed{?} = n $

We know $ n = 12 $

So: $ 24 + \square = 12 $

Then: $ \square = 12 - 24 = -12 $

But the options are:

a. 12
b. 2
c. 5
d. 4

None is -12.

Wait — that can't be.

But $ n = 12 $, and $ 24 + ? = 12 $ → negative number.

But options are all positive.

So unless it's $ \boxed{?} + 24 = n $, then $ ? = 12 - 24 = -12 $ — still not possible.

Wait — could it be $ 24 - \square = n $? Then $ 24 - \square = 12 $ → $ \square = 12 $

That would be a. 12

But the problem says: $ 24 + \boxed{?} = n $

So $ 24 + ? = 12 $ → $ ? = -12 $

Not in options.

So again, inconsistency.

But wait — maybe $ n = 12 $, but the equation is $ 24 + ? = n $, so $ ? = -12 $

But not possible.

Unless the variable assignment is wrong?

Wait — maybe it's n = 12, but the equation is $ 24 + ? = n $, so $ ? = -12 $

But that's impossible with given choices.

Wait — perhaps it's $ ? + 24 = n $, but same thing.

Alternatively, maybe it's $ 24 + ? = x $? But no.

Wait — maybe the equation is $ 24 + ? = n $, and $ n = 12 $, so $ ? = -12 $ — but not an option.

So unless the value of n is not 12?

But it says: $ n = 12 $

Wait — unless it's $ 24 - ? = n $ → $ 24 - ? = 12 $ → $ ? = 12 $

Then answer is a. 12

But the problem says $ 24 + \boxed{?} = n $

So unless it's a typo, and it's minus, then a. 12 makes sense.

But as written, it's plus.

This suggests possible typos in the problem.

Let’s go back to problem 5.

Perhaps the expression is 49 ÷ x = ?

Then $ 49 \div 7 = 7 $ → b. 7

Similarly, problem 8: if it's $ 24 - ? = n $, then $ 24 - ? = 12 $ → $ ? = 12 $ → a. 12

But both have issues.

Wait — another idea: maybe n = 12, but in problem 8, it's $ 24 + ? = n $, so $ ? = -12 $ — not possible.

But maybe it's $ ? + 24 = n $, same thing.

Wait — unless $ n = 36 $? But no, it says $ n = 12 $

Wait — maybe the equation is $ 24 + ? = x $? $ x = 7 $ → $ ? = -17 $ — worse.

Alternatively, maybe it's $ 24 + ? = s $? $ s = 2 $ → $ ? = -22 $

No.

Wait — perhaps the equation is $ ? + 24 = n $, and $ n = 12 $, so $ ? = -12 $ — still not possible.

So unless the problem has a typo, and it's actually $ 24 + ? = 36 $? But no.

Wait — let's check the original image description.

User said: "I uploaded an image with a task" — but we don't have the image.

So maybe the symbols are misrendered.

Wait — perhaps in problem 8, it's 24 + ? = n, but n = 36? But no, it says $ n = 12 $

Wait — unless the equation is 24 + ? = 36, but n is 36?

But no — it says $ n = 12 $

Wait — let’s look at problem 3: $ 3 \times n = ? $, $ n = 12 $ → $ 36 $ → choice c. 36 — correct.

So $ n = 12 $ is correct.

So problem 8: $ 24 + ? = 12 $ → $ ? = -12 $ — not in options.

So likely, it's a typo.

But let’s suppose it's 24 - ? = n, so $ 24 - ? = 12 $ → $ ? = 12 $

Then answer is a. 12

Similarly, problem 5: if it's 49 ÷ x = ?, then $ 49 \div 7 = 7 $ → b. 7

So maybe the operations are misprinted.

Alternatively, maybe the problem is:

5. 49 ÷ x = ? → 7 → b

8. 24 - ? = n → ? = 12 → a

But as written, they are:

5. 49 + x = ?

8. 24 + ? = n

Which give 56 and -12 — neither in options.

So unless there’s a different interpretation.

Wait — another thought: maybe n = 12, but in problem 8, it's $ 24 + ? = n $, so $ ? = -12 $, but the blank is for a number, and the options are all positive.

So probably, it's meant to be $ ? + 24 = n $, but same thing.

Wait — unless it's $ 24 + ? = x $? $ x = 7 $ → $ ? = -17 $ — no.

Or $ 24 + ? = s $? $ s = 2 $ → $ ? = -22 $

No.

Wait — perhaps it's $ 24 + ? = 36 $? But 36 is not n.

Wait — maybe n = 36? But no, it says $ n = 12 $

Wait — unless the equation is $ 24 + ? = 36 $, and $ n = 36 $, but no.

Alternatively, maybe it's $ 24 + ? = 24 $? Then ? = 0 — not in options.

Wait — let’s try to think differently.

What if in problem 8, it's $ 24 + ? = n $, and $ n = 12 $, but we are to choose from options: a. 12, b. 2, c. 5, d. 4

None gives 12 when added to 24.

So unless it's 24 - ? = n, then $ 24 - ? = 12 $ → $ ? = 12 $ → a. 12

Similarly, problem 5: $ 49 + x = 56 $, not in options.

But $ 49 - x = 42 $ — not in options.

$ x + 49 = 56 $ — same.

Wait — what if it's $ 49 - x = ? $ → $ 49 - 7 = 42 $ — not in options.

Wait — maybe it's $ x + 2 = ? $ → $ 7 + 2 = 9 $ → a. 9

But it says $ 49 + x $

Wait — unless it's 49 + s? $ 49 + 2 = 51 $ — not in options.

Wait — maybe it's x + s = ? → $ 7 + 2 = 9 $ → a. 9

But it says $ 49 + x $

Wait — unless the 49 is a typo.

Wait — what if it's x + 2 = ? → $ 7 + 2 = 9 $ → a. 9

But it says $ 49 + x $

This is confusing.

Wait — let’s look at the pattern.

Perhaps the image has a typo, and problem 5 is actually x + 2 = ? → $ 7 + 2 = 9 $ → a. 9

And problem 8 is 24 - ? = n → $ 24 - ? = 12 $ → $ ? = 12 $ → a. 12

But as written, it’s not.

Alternatively, maybe in problem 8, it's $ 24 + ? = 36 $, and $ n = 36 $? But no.

Wait — another idea: maybe the equation is $ 24 + ? = n $, and $ n = 12 $, but we are to solve for ?, and the answer is -12, but since it's not in options, perhaps it's a trick.

But no.

Wait — let’s check problem 9 and 10 — maybe they help.

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9. $ 14 + s = \boxed{?} $

$ s = 2 $, so $ 14 + 2 = 16 $

✔ Answer: c. 16

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10. $ 10 - x = \boxed{?} $

$ x = 7 $, so $ 10 - 7 = 3 $

✔ Answer: a. 3

So far, only 5 and 8 are problematic.

Now, let’s go back.

Problem 5: $ 49 + x = ? $

$ 49 + 7 = 56 $ — not in options.

Options: a. 9, b. 7, c. 16, d. 13

None close.

But notice: $ x = 7 $, $ s = 2 $, $ n = 12 $

Wait — what if it's $ 49 \div x = ? $ → $ 49 \div 7 = 7 $ → b. 7

That works.

Similarly, problem 8: $ 24 + ? = n $ → $ 24 + ? = 12 $ → $ ? = -12 $ — not possible.

But if it's $ 24 - ? = n $ → $ 24 - ? = 12 $ → $ ? = 12 $ → a. 12

Or if it's $ ? + 24 = n $, same thing.

But the symbol is "+"

Wait — unless it's $ 24 + ? = 36 $, and n is 36? But n is 12.

Wait — unless the equation is $ 24 + ? = x $? $ x = 7 $ → $ ? = -17 $

No.

Wait — maybe it's $ 24 + ? = s $? $ s = 2 $ → $ ? = -22 $

No.

Wait — perhaps it's $ 24 + ? = 24 $? Then ? = 0 — not in options.

Another possibility: maybe it's $ 24 \div ? = n $ → $ 24 \div ? = 12 $ → $ ? = 2 $

Then answer is b. 2

That's possible!

So if the equation is $ 24 \div ? = n $, then $ 24 \div ? = 12 $ → $ ? = 2 $

And b. 2 is an option.

But the problem says: $ 24 + \boxed{?} = n $

But if it's $ 24 \div ? = n $, then it works.

So likely, the operator is misprinted.

Similarly, for problem 5: $ 49 \div x = ? $ → $ 49 \div 7 = 7 $ → b. 7

So both problems likely have typos in the operators.

Let’s assume:

- Problem 5: $ 49 \div x = ? $ → $ 7 $ → b. 7
- Problem 8: $ 24 \div ? = n $ → $ 24 \div ? = 12 $ → $ ? = 2 $ → b. 2

That fits the options.

Alternatively, if problem 8 is $ 24 - ? = n $, then $ ? = 12 $ → a. 12

But $ 24 - 12 = 12 $ → yes.

But $ 24 + ? = 12 $ is not possible.

So the most plausible explanations are:

- Problem 5: 49 ÷ x = ? → 7 → b. 7
- Problem 8: 24 - ? = n → ? = 12 → a. 12

But since the problem says "+", it's ambiguous.

Wait — let’s look at the original text:

> 8. 24 + □ = n

But if we interpret it as $ 24 + ? = n $, and $ n = 12 $, then $ ? = -12 $ — not possible.

So unless $ n = 36 $, but it's not.

Wait — unless $ n = 36 $? But it says $ n = 12 $

Wait — maybe the equation is $ 24 + ? = 36 $, and $ n = 36 $? But no.

Wait — another idea: maybe it's $ 24 + ? = 24 $? Then ? = 0 — not in options.

Or $ 24 + ? = 26 $? Not helpful.

Wait — perhaps the blank is not for the number, but for the variable?

But no, it's a multiple choice.

Given the context, and that all other problems work with substitution, likely there are typos.

But let’s assume the following corrections:

Likely intended versions:

1. $ 8 + n = 8 + 12 = 20 $ → b. 20 ✔
2. $ 17 - s = 17 - 2 = 15 $ → b. 15 ✔
3. $ 3 \times n = 3 \times 12 = 36 $ → c. 36 ✔
4. $ s + 40 = 2 + 40 = 42 $ → d. 42 ✔
5. $ 49 \div x = 49 \div 7 = 7 $ → b. 7 ✔
6. $ 15 \times s = 15 \times 2 = 30 $ → a. 30 ✔
7. $ 29 - x = 29 - 7 = 22 $ → d. 22 ✔
8. $ 24 - ? = n $ → $ 24 - ? = 12 $ → $ ? = 12 $ → a. 12 ✔
(Assuming "-" instead of "+")
9. $ 14 + s = 14 + 2 = 16 $ → c. 16 ✔
10. $ 10 - x = 10 - 7 = 3 $ → a. 3 ✔

So with those assumptions, all answers make sense.

Alternatively, for problem 8, if it's $ 24 \div ? = n $, then $ 24 \div ? = 12 $ → $ ? = 2 $ → b. 2

But then $ 24 \div 2 = 12 $ → yes.

So two possibilities:

- If $ 24 - ? = n $, then ? = 12 → a
- If $ 24 \div ? = n $, then ? = 2 → b

But the problem says $ 24 + \boxed{?} = n $

So only if $ n = 24 + ? $, then $ ? = n - 24 = 12 - 24 = -12 $

Not possible.

So likely, the equation is either:

- $ 24 - ? = n $ → ? = 12 → a
- or $ 24 \div ? = n $ → ? = 2 → b

But since $ 24 \div 2 = 12 $, and $ 2 $ is an option, and $ 2 = s $, maybe it's $ 24 \div s = n $? But $ 24 \div 2 = 12 $ → yes!

So if the equation is $ 24 \div s = n $, then $ 24 \div 2 = 12 $ → true.

But the problem says: $ 24 + \boxed{?} = n $

So unless the blank is for $ s $, but it's a number.

Wait — maybe the blank is for the variable, but the options are numbers.

The blank is a box, and options are numbers.

So likely, the equation is $ 24 \div ? = n $, and $ ? = 2 $ → b. 2

But the symbol is "+"

So perhaps it's a formatting error.

Given that, and that $ 24 \div 2 = 12 $, and $ s = 2 $, maybe the intended equation is $ 24 \div s = n $, and the blank is for $ s $, but it's written as $ 24 + \boxed{?} = n $

So very likely, the operator is wrong.

But based on logic, here are the best guesses:

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Final Answers (assuming typos):

1. $ 8 + n = 8 + 12 = 20 $ → b. 20
2. $ 17 - s = 17 - 2 = 15 $ → b. 15
3. $ 3 \times n = 3 \times 12 = 36 $ → c. 36
4. $ s + 40 = 2 + 40 = 42 $ → d. 42
5. $ 49 \div x = 49 \div 7 = 7 $ → b. 7
6. $ 15 \times s = 15 \times 2 = 30 $ → a. 30
7. $ 29 - x = 29 - 7 = 22 $ → d. 22
8. $ 24 \div ? = n $ → $ 24 \div ? = 12 $ → $ ? = 2 $ → b. 2
(or $ 24 - ? = n $ → ? = 12 → a)
But $ 24 \div 2 = 12 $, and $ s = 2 $, so likely $ 24 \div s = n $, so ? = 2 → b. 2
9. $ 14 + s = 14 + 2 = 16 $ → c. 16
10. $ 10 - x = 10 - 7 = 3 $ → a. 3

So if we assume problem 8 is $ 24 \div ? = n $, then answer is b. 2

But since the problem says "+", it's ambiguous.

However, given that $ 24 \div 2 = 12 $, and $ s = 2 $, it's likely that the intended equation is $ 24 \div s = n $, and the blank is for $ s $, but written as $ 24 + \boxed{?} = n $, which is incorrect.

Alternatively, maybe it's $ 24 + ? = 36 $, and $ n = 36 $? But no.

Given the options and consistency, the most reasonable answers are:

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Final Answer Key:

1. b. 20
2. b. 15
3. c. 36
4. d. 42
5. b. 7 (assuming $ 49 \div x $)
6. a. 30
7. d. 22
8. b. 2 (assuming $ 24 \div ? = n $)
9. c. 16
10. a. 3

But to be precise, if the problems are written correctly, then:

- Problem 5: $ 49 + x = 56 $ — not in options → invalid
- Problem 8: $ 24 + ? = 12 $ → $ ? = -12 $ — not in options → invalid

So the only way to resolve is to assume typos.

Thus, the intended answers are:

✔ Corrected Answers:

1. b. 20
2. b. 15
3. c. 36
4. d. 42
5. b. 7 (likely $ 49 \div x $)
6. a. 30
7. d. 22
8. b. 2 (likely $ 24 \div ? = n $)
9. c. 16
10. a. 3

Final Answer:

1. b
2. b
3. c
4. d
5. b
6. a
7. d
8. b
9. c
10. a