Ratio Worksheets - Math Monks - Free Printable

Let's solve each table step by step. The goal is to complete the tables so that each row forms an equivalent ratio to the first row in that table. We'll use proportions and cross-multiplication to find missing values.

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(1) Bees to Ants

Given:
40 bees : 10 ants → Simplify: $ \frac{40}{10} = 4:1 $

So, the ratio of bees to ants is 4:1, meaning for every 4 bees, there is 1 ant.

Now fill in the rest:

- 60 bees → $ \frac{60}{4} = 15 $ ants
- 120 bees → $ \frac{120}{4} = 30 $ ants
- 18 bees → $ \frac{18}{4} = 4.5 $ ants

✔ Answers:
- 60 → 15
- 120 → 30
- 18 → 4.5

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(2) Boys to Girls

Given:
28 boys : 18 girls → Simplify: $ \frac{28}{18} = \frac{14}{9} \approx 1.555... $

So, ratio is $ \frac{14}{9} $. Use this to find missing values.

We can write:
$ \frac{\text{Boys}}{\text{Girls}} = \frac{14}{9} $

So, $ \text{Girls} = \frac{9}{14} \times \text{Boys} $

- 52 boys → $ \frac{9}{14} \times 52 = \frac{468}{14} = 33.428... \approx 33.43 $
- 36 boys → $ \frac{9}{14} \times 36 = \frac{324}{14} = 23.142... \approx 23.14 $
- 82 boys → $ \frac{9}{14} \times 82 = \frac{738}{14} = 52.714... \approx 52.71 $

✔ Answers:
- 52 → 33.43
- 36 → 23.14
- 82 → 52.71

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(3) Tigers to Lions

Given:
34 tigers : 14 lions → $ \frac{34}{14} = \frac{17}{7} \approx 2.4286 $

So, $ \frac{\text{Tigers}}{\text{Lions}} = \frac{17}{7} $

Then, $ \text{Lions} = \frac{7}{17} \times \text{Tigers} $

- 20 tigers → $ \frac{7}{17} \times 20 = \frac{140}{17} \approx 8.24 $
- 66 tigers → $ \frac{7}{17} \times 66 = \frac{462}{17} \approx 27.18 $
- 72 tigers → $ \frac{7}{17} \times 72 = \frac{504}{17} \approx 29.65 $

✔ Answers:
- 20 → 8.24
- 66 → 27.18
- 72 → 29.65

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(4) Roses to Dahlias

Given:
12 roses : 20 dahlias → $ \frac{12}{20} = \frac{3}{5} = 0.6 $

So, $ \frac{\text{Roses}}{\text{Dahlias}} = \frac{3}{5} $

Thus, $ \text{Dahlias} = \frac{5}{3} \times \text{Roses} $

- 48 roses → $ \frac{5}{3} \times 48 = 80 $
- 3 roses → $ \frac{5}{3} \times 3 = 5 $
- 36 roses → $ \frac{5}{3} \times 36 = 60 $

✔ Answers:
- 48 → 80
- 3 → 5
- 36 → 60

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(5) Sheep to Cows

Given:
52 sheep : 60 cows → $ \frac{52}{60} = \frac{13}{15} \approx 0.8667 $

So, $ \frac{\text{Sheep}}{\text{Cows}} = \frac{13}{15} $

Then, $ \text{Cows} = \frac{15}{13} \times \text{Sheep} $

- 39 sheep → $ \frac{15}{13} \times 39 = 15 \times 3 = 45 $
- 26 sheep → $ \frac{15}{13} \times 26 = 15 \times 2 = 30 $
- 78 sheep → $ \frac{15}{13} \times 78 = 15 \times 6 = 90 $

✔ Answers:
- 39 → 45
- 26 → 30
- 78 → 90

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(6) Balloons to Kites

Given:
20 balloons : 50 kites → $ \frac{20}{50} = \frac{2}{5} = 0.4 $

So, $ \frac{\text{Balloons}}{\text{Kites}} = \frac{2}{5} $

Then, $ \text{Kites} = \frac{5}{2} \times \text{Balloons} $

- 40 balloons → $ \frac{5}{2} \times 40 = 100 $
- 36 balloons → $ \frac{5}{2} \times 36 = 90 $
- 60 balloons → $ \frac{5}{2} \times 60 = 150 $

✔ Answers:
- 40 → 100
- 36 → 90
- 60 → 150

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✔ Final Answer Table:

#### (1)
| No. of Bees | No. of Ants |
|-------------|-------------|
| 40 | 10 |
| 60 | 15 |
| 120 | 30 |
| 18 | 4.50 |

#### (2)
| No. of Boys | No. of Girls |
|-------------|--------------|
| 28 | 18 |
| 52 | 33.43 |
| 36 | 23.14 |
| 82 | 52.71 |

#### (3)
| No. of Tigers | No. of Lions |
|---------------|--------------|
| 34 | 14 |
| 20 | 8.24 |
| 66 | 27.18 |
| 72 | 29.65 |

#### (4)
| No. of Roses | No. of Dahlias |
|--------------|----------------|
| 12 | 20 |
| 48 | 80 |
| 3 | 5 |
| 36 | 60 |

#### (5)
| No. of Sheep | No. of Cows |
|--------------|-------------|
| 52 | 60 |
| 39 | 45 |
| 26 | 30 |
| 78 | 90 |

#### (6)
| No. of Balloons | No. of Kites |
|------------------|--------------|
| 20 | 50 |
| 40 | 100 |
| 36 | 90 |
| 60 | 150 |

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✔ Summary:

All ratios are maintained using equivalent fractions. For each table, we used the initial ratio to find missing values via proportion.

Let me know if you'd like a printable version or explanation in simpler terms!