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Step-by-step solution for: Completing the square worksheet: Fill out & sign online | DocHub
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Show Answer Key & Explanations
Step-by-step solution for: Completing the square worksheet: Fill out & sign online | DocHub
Let's solve each problem step-by-step using the method of completing the square. We'll also address the last two questions about creating perfect square trinomials.
---
To complete the square for a quadratic equation in the form:
$$
x^2 + bx + c = 0
$$
1. Move constant to the other side:
$$
x^2 + bx = -c
$$
2. Take half of the coefficient of $ x $, square it, and add to both sides:
$$
\left(\frac{b}{2}\right)^2
$$
3. Factor the left side into a perfect square trinomial.
4. Solve by taking square roots.
---
Now, let’s go through each problem.
---
Step 1: Move constant:
$$
x^2 + 8x = 6
$$
Step 2: Half of 8 is 4; square it: $ 4^2 = 16 $. Add to both sides:
$$
x^2 + 8x + 16 = 6 + 16 = 22
$$
Step 3: Factor:
$$
(x + 4)^2 = 22
$$
Step 4: Solve:
$$
x + 4 = \pm\sqrt{22} \Rightarrow x = -4 \pm \sqrt{22}
$$
✔ Answer: $ x = -4 \pm \sqrt{22} $
---
This one is already a perfect square!
$$
x^2 + 6x + 9 = (x + 3)^2 = 0
$$
So,
$$
x + 3 = 0 \Rightarrow x = -3
$$
✔ Answer: $ x = -3 $
---
First, divide entire equation by 2 to make leading coefficient 1:
$$
x^2 - 10x - 32 = 0
$$
Move constant:
$$
x^2 - 10x = 32
$$
Half of -10 is -5; square it: $ (-5)^2 = 25 $. Add to both sides:
$$
x^2 - 10x + 25 = 32 + 25 = 57
$$
Factor:
$$
(x - 5)^2 = 57
$$
Solve:
$$
x - 5 = \pm\sqrt{57} \Rightarrow x = 5 \pm \sqrt{57}
$$
✔ Answer: $ x = 5 \pm \sqrt{57} $
---
Move constant:
$$
x^2 + 16x = -24
$$
Half of 16 is 8; $ 8^2 = 64 $. Add to both sides:
$$
x^2 + 16x + 64 = -24 + 64 = 40
$$
Factor:
$$
(x + 8)^2 = 40
$$
Solve:
$$
x + 8 = \pm\sqrt{40} = \pm 2\sqrt{10} \Rightarrow x = -8 \pm 2\sqrt{10}
$$
✔ Answer: $ x = -8 \pm 2\sqrt{10} $
---
Move constant:
$$
x^2 + 4x = -10
$$
Half of 4 is 2; $ 2^2 = 4 $. Add to both sides:
$$
x^2 + 4x + 4 = -10 + 4 = -6
$$
Factor:
$$
(x + 2)^2 = -6
$$
Solve:
$$
x + 2 = \pm\sqrt{-6} = \pm i\sqrt{6} \Rightarrow x = -2 \pm i\sqrt{6}
$$
✔ Answer: $ x = -2 \pm i\sqrt{6} $ (complex solutions)
---
Move constant:
$$
x^2 + 8x = -7
$$
Half of 8 is 4; $ 4^2 = 16 $. Add to both sides:
$$
x^2 + 8x + 16 = -7 + 16 = 9
$$
Factor:
$$
(x + 4)^2 = 9
$$
Solve:
$$
x + 4 = \pm 3 \Rightarrow x = -4 \pm 3
$$
So:
- $ x = -4 + 3 = -1 $
- $ x = -4 - 3 = -7 $
✔ Answer: $ x = -1 $ or $ x = -7 $
---
Move constant:
$$
x^2 + 24x = 16
$$
Half of 24 is 12; $ 12^2 = 144 $. Add to both sides:
$$
x^2 + 24x + 144 = 16 + 144 = 160
$$
Factor:
$$
(x + 12)^2 = 160
$$
Solve:
$$
x + 12 = \pm\sqrt{160} = \pm\sqrt{16 \cdot 10} = \pm 4\sqrt{10}
\Rightarrow x = -12 \pm 4\sqrt{10}
$$
✔ Answer: $ x = -12 \pm 4\sqrt{10} $
---
Move constant:
$$
x^2 + 4x = 3
$$
Half of 4 is 2; $ 2^2 = 4 $. Add to both sides:
$$
x^2 + 4x + 4 = 3 + 4 = 7
$$
Factor:
$$
(x + 2)^2 = 7
$$
Solve:
$$
x + 2 = \pm\sqrt{7} \Rightarrow x = -2 \pm \sqrt{7}
$$
✔ Answer: $ x = -2 \pm \sqrt{7} $
---
We use the formula: take half of the middle term, square it.
- Coefficient of $ x $ is 16.
- Half: $ \frac{16}{2} = 8 $
- Square: $ 8^2 = 64 $
So, $ x^2 + 16x + 64 = (x + 8)^2 $
✔ Answer: $ \boxed{64} $
---
- Coefficient of $ x $ is -3.
- Half: $ \frac{-3}{2} $
- Square: $ \left(\frac{-3}{2}\right)^2 = \frac{9}{4} $
So, $ x^2 - 3x + \frac{9}{4} = \left(x - \frac{3}{2}\right)^2 $
✔ Answer: $ \boxed{\frac{9}{4}} $
---
| Problem | Answer |
|--------|--------|
| 1 | $ x = -4 \pm \sqrt{22} $ |
| 2 | $ x = -3 $ |
| 3 | $ x = 5 \pm \sqrt{57} $ |
| 4 | $ x = -8 \pm 2\sqrt{10} $ |
| 5 | $ x = -2 \pm i\sqrt{6} $ |
| 6 | $ x = -1 $ or $ x = -7 $ |
| 7 | $ x = -12 \pm 4\sqrt{10} $ |
| 8 | $ x = -2 \pm \sqrt{7} $ |
| 9 | $ \boxed{64} $ |
| 10 | $ \boxed{\frac{9}{4}} $ |
Let me know if you'd like these written neatly on a printable format!
---
🔷 Completing the Square Method Overview:
To complete the square for a quadratic equation in the form:
$$
x^2 + bx + c = 0
$$
1. Move constant to the other side:
$$
x^2 + bx = -c
$$
2. Take half of the coefficient of $ x $, square it, and add to both sides:
$$
\left(\frac{b}{2}\right)^2
$$
3. Factor the left side into a perfect square trinomial.
4. Solve by taking square roots.
---
Now, let’s go through each problem.
---
1. $ x^2 + 8x - 6 = 0 $
Step 1: Move constant:
$$
x^2 + 8x = 6
$$
Step 2: Half of 8 is 4; square it: $ 4^2 = 16 $. Add to both sides:
$$
x^2 + 8x + 16 = 6 + 16 = 22
$$
Step 3: Factor:
$$
(x + 4)^2 = 22
$$
Step 4: Solve:
$$
x + 4 = \pm\sqrt{22} \Rightarrow x = -4 \pm \sqrt{22}
$$
✔ Answer: $ x = -4 \pm \sqrt{22} $
---
2. $ x^2 + 6x + 9 = 0 $
This one is already a perfect square!
$$
x^2 + 6x + 9 = (x + 3)^2 = 0
$$
So,
$$
x + 3 = 0 \Rightarrow x = -3
$$
✔ Answer: $ x = -3 $
---
3. $ 2x^2 - 20x - 64 = 0 $
First, divide entire equation by 2 to make leading coefficient 1:
$$
x^2 - 10x - 32 = 0
$$
Move constant:
$$
x^2 - 10x = 32
$$
Half of -10 is -5; square it: $ (-5)^2 = 25 $. Add to both sides:
$$
x^2 - 10x + 25 = 32 + 25 = 57
$$
Factor:
$$
(x - 5)^2 = 57
$$
Solve:
$$
x - 5 = \pm\sqrt{57} \Rightarrow x = 5 \pm \sqrt{57}
$$
✔ Answer: $ x = 5 \pm \sqrt{57} $
---
4. $ x^2 + 16x + 24 = 0 $
Move constant:
$$
x^2 + 16x = -24
$$
Half of 16 is 8; $ 8^2 = 64 $. Add to both sides:
$$
x^2 + 16x + 64 = -24 + 64 = 40
$$
Factor:
$$
(x + 8)^2 = 40
$$
Solve:
$$
x + 8 = \pm\sqrt{40} = \pm 2\sqrt{10} \Rightarrow x = -8 \pm 2\sqrt{10}
$$
✔ Answer: $ x = -8 \pm 2\sqrt{10} $
---
5. $ x^2 + 4x + 10 = 0 $
Move constant:
$$
x^2 + 4x = -10
$$
Half of 4 is 2; $ 2^2 = 4 $. Add to both sides:
$$
x^2 + 4x + 4 = -10 + 4 = -6
$$
Factor:
$$
(x + 2)^2 = -6
$$
Solve:
$$
x + 2 = \pm\sqrt{-6} = \pm i\sqrt{6} \Rightarrow x = -2 \pm i\sqrt{6}
$$
✔ Answer: $ x = -2 \pm i\sqrt{6} $ (complex solutions)
---
6. $ x^2 + 8x + 7 = 0 $
Move constant:
$$
x^2 + 8x = -7
$$
Half of 8 is 4; $ 4^2 = 16 $. Add to both sides:
$$
x^2 + 8x + 16 = -7 + 16 = 9
$$
Factor:
$$
(x + 4)^2 = 9
$$
Solve:
$$
x + 4 = \pm 3 \Rightarrow x = -4 \pm 3
$$
So:
- $ x = -4 + 3 = -1 $
- $ x = -4 - 3 = -7 $
✔ Answer: $ x = -1 $ or $ x = -7 $
---
7. $ x^2 + 24x - 16 = 0 $
Move constant:
$$
x^2 + 24x = 16
$$
Half of 24 is 12; $ 12^2 = 144 $. Add to both sides:
$$
x^2 + 24x + 144 = 16 + 144 = 160
$$
Factor:
$$
(x + 12)^2 = 160
$$
Solve:
$$
x + 12 = \pm\sqrt{160} = \pm\sqrt{16 \cdot 10} = \pm 4\sqrt{10}
\Rightarrow x = -12 \pm 4\sqrt{10}
$$
✔ Answer: $ x = -12 \pm 4\sqrt{10} $
---
8. $ x^2 + 4x - 3 = 0 $
Move constant:
$$
x^2 + 4x = 3
$$
Half of 4 is 2; $ 2^2 = 4 $. Add to both sides:
$$
x^2 + 4x + 4 = 3 + 4 = 7
$$
Factor:
$$
(x + 2)^2 = 7
$$
Solve:
$$
x + 2 = \pm\sqrt{7} \Rightarrow x = -2 \pm \sqrt{7}
$$
✔ Answer: $ x = -2 \pm \sqrt{7} $
---
9. What value completes $ x^2 + 16x + \boxed{\phantom{0}} $ to make a perfect square trinomial?
We use the formula: take half of the middle term, square it.
- Coefficient of $ x $ is 16.
- Half: $ \frac{16}{2} = 8 $
- Square: $ 8^2 = 64 $
So, $ x^2 + 16x + 64 = (x + 8)^2 $
✔ Answer: $ \boxed{64} $
---
10. What value completes $ x^2 - 3x + \boxed{\phantom{0}} $?
- Coefficient of $ x $ is -3.
- Half: $ \frac{-3}{2} $
- Square: $ \left(\frac{-3}{2}\right)^2 = \frac{9}{4} $
So, $ x^2 - 3x + \frac{9}{4} = \left(x - \frac{3}{2}\right)^2 $
✔ Answer: $ \boxed{\frac{9}{4}} $
---
✔ Final Answers Summary:
| Problem | Answer |
|--------|--------|
| 1 | $ x = -4 \pm \sqrt{22} $ |
| 2 | $ x = -3 $ |
| 3 | $ x = 5 \pm \sqrt{57} $ |
| 4 | $ x = -8 \pm 2\sqrt{10} $ |
| 5 | $ x = -2 \pm i\sqrt{6} $ |
| 6 | $ x = -1 $ or $ x = -7 $ |
| 7 | $ x = -12 \pm 4\sqrt{10} $ |
| 8 | $ x = -2 \pm \sqrt{7} $ |
| 9 | $ \boxed{64} $ |
| 10 | $ \boxed{\frac{9}{4}} $ |
Let me know if you'd like these written neatly on a printable format!
Parent Tip: Review the logic above to help your child master the concept of complete the square worksheet.