Explanation:
We are asked to find what number goes in the box to make each expression a *perfect square trinomial*. A perfect square trinomial looks like:
$$
x^2 + bx + c = (x + d)^2
$$
When you expand $(x + d)^2$, you get:
$$
x^2 + 2dx + d^2
$$
So, for $x^2 + bx + \boxed{?}$ to be a perfect square:
- The middle term is $bx = 2dx$ → so $d = \frac{b}{2}$
- Then the constant term must be $d^2 = \left(\frac{b}{2}\right)^2$
Let’s apply this to problems 9 and 10.
---
Problem 9:
$x^2 + 16x + \boxed{?}$
Here, $b = 16$, so:
$$
d = \frac{16}{2} = 8 \\
\text{Constant term} = d^2 = 8^2 = 64
$$
✔ So the box should be
64.
---
Problem 10:
$x^2 - 3x + \boxed{?}$
Here, $b = -3$, so:
$$
d = \frac{-3}{2} = -\frac{3}{2} \\
\text{Constant term} = d^2 = \left(-\frac{3}{2}\right)^2 = \frac{9}{4}
$$
✔ So the box should be
$\frac{9}{4}$.
Let’s double-check both:
- $x^2 + 16x + 64 = (x + 8)^2$ ✔️
- $x^2 - 3x + \frac{9}{4} = \left(x - \frac{3}{2}\right)^2$ ✔️
Both are perfect squares.
Final Answer:
9. 64
10. $\frac{9}{4}$
Parent Tip: Review the logic above to help your child master the concept of completing the square and quadratic formula worksheet.