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Practice dividing complex numbers and simplifying the results with this free algebra worksheet.

Worksheet for simplifying complex numbers with 8 division problems involving imaginary units.

Worksheet for simplifying complex numbers with 8 division problems involving imaginary units.

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Show Answer Key & Explanations Step-by-step solution for: Rationalize Complex Number Worksheets (printable, online, answers ...
Let's solve each of these complex number division problems by simplifying the expressions. The general method is to multiply the numerator and denominator by the conjugate of the denominator to eliminate the imaginary part in the denominator.

---

1. $\frac{8 + 3i}{-3 + i}$



Step 1: Multiply numerator and denominator by the conjugate of the denominator: $-3 - i$

$$
\frac{8 + 3i}{-3 + i} \cdot \frac{-3 - i}{-3 - i}
$$

Numerator:
$$
(8 + 3i)(-3 - i) = 8(-3) + 8(-i) + 3i(-3) + 3i(-i) = -24 - 8i - 9i - 3i^2
$$
$$
= -24 - 17i - 3(-1) = -24 - 17i + 3 = -21 - 17i
$$

Denominator:
$$
(-3 + i)(-3 - i) = (-3)^2 - (i)^2 = 9 - (-1) = 9 + 1 = 10
$$

Result:
$$
\frac{-21 - 17i}{10} = -\frac{21}{10} - \frac{17}{10}i
$$

Answer: $-\frac{21}{10} - \frac{17}{10}i$

---

2. $\frac{9 + 7i}{1 - 3i}$



Multiply by conjugate $1 + 3i$:

$$
\frac{9 + 7i}{1 - 3i} \cdot \frac{1 + 3i}{1 + 3i}
$$

Numerator:
$$
(9 + 7i)(1 + 3i) = 9(1) + 9(3i) + 7i(1) + 7i(3i) = 9 + 27i + 7i + 21i^2
$$
$$
= 9 + 34i + 21(-1) = 9 + 34i - 21 = -12 + 34i
$$

Denominator:
$$
(1 - 3i)(1 + 3i) = 1^2 - (3i)^2 = 1 - 9(-1) = 1 + 9 = 10
$$

Result:
$$
\frac{-12 + 34i}{10} = -\frac{6}{5} + \frac{17}{5}i
$$

Answer: $-\frac{6}{5} + \frac{17}{5}i$

---

3. $\frac{7 - 7i}{9 - i}$



Multiply by conjugate $9 + i$:

$$
\frac{7 - 7i}{9 - i} \cdot \frac{9 + i}{9 + i}
$$

Numerator:
$$
(7 - 7i)(9 + i) = 7(9) + 7(i) -7i(9) -7i(i) = 63 + 7i - 63i -7i^2
$$
$$
= 63 - 56i -7(-1) = 63 - 56i + 7 = 70 - 56i
$$

Denominator:
$$
(9 - i)(9 + i) = 81 - i^2 = 81 - (-1) = 82
$$

Result:
$$
\frac{70 - 56i}{82} = \frac{35}{41} - \frac{28}{41}i
$$

Answer: $\frac{35}{41} - \frac{28}{41}i$

---

4. $\frac{5 + i}{8 + i}$



Multiply by conjugate $8 - i$:

$$
\frac{5 + i}{8 + i} \cdot \frac{8 - i}{8 - i}
$$

Numerator:
$$
(5 + i)(8 - i) = 5(8) + 5(-i) + i(8) + i(-i) = 40 - 5i + 8i - i^2
$$
$$
= 40 + 3i - (-1) = 40 + 3i + 1 = 41 + 3i
$$

Denominator:
$$
(8 + i)(8 - i) = 64 - i^2 = 64 + 1 = 65
$$

Result:
$$
\frac{41 + 3i}{65} = \frac{41}{65} + \frac{3}{65}i
$$

Answer: $\frac{41}{65} + \frac{3}{65}i$

---

5. $\frac{-10 + i}{-1 + 3i}$



Multiply by conjugate $-1 - 3i$:

$$
\frac{-10 + i}{-1 + 3i} \cdot \frac{-1 - 3i}{-1 - 3i}
$$

Numerator:
$$
(-10 + i)(-1 - 3i) = (-10)(-1) + (-10)(-3i) + i(-1) + i(-3i)
= 10 + 30i - i - 3i^2
$$
$$
= 10 + 29i - 3(-1) = 10 + 29i + 3 = 13 + 29i
$$

Denominator:
$$
(-1 + 3i)(-1 - 3i) = (-1)^2 - (3i)^2 = 1 - 9(-1) = 1 + 9 = 10
$$

Result:
$$
\frac{13 + 29i}{10} = \frac{13}{10} + \frac{29}{10}i
$$

Answer: $\frac{13}{10} + \frac{29}{10}i$

---

6. $\frac{-3 - 5i}{-8 + 3i}$



Multiply by conjugate $-8 - 3i$:

$$
\frac{-3 - 5i}{-8 + 3i} \cdot \frac{-8 - 3i}{-8 - 3i}
$$

Numerator:
$$
(-3 - 5i)(-8 - 3i) = (-3)(-8) + (-3)(-3i) + (-5i)(-8) + (-5i)(-3i)
= 24 + 9i + 40i + 15i^2
$$
$$
= 24 + 49i + 15(-1) = 24 + 49i - 15 = 9 + 49i
$$

Denominator:
$$
(-8 + 3i)(-8 - 3i) = (-8)^2 - (3i)^2 = 64 - 9(-1) = 64 + 9 = 73
$$

Result:
$$
\frac{9 + 49i}{73} = \frac{9}{73} + \frac{49}{73}i
$$

Answer: $\frac{9}{73} + \frac{49}{73}i$

---

7. $\frac{1 + 2i}{5 + i}$



Multiply by conjugate $5 - i$:

$$
\frac{1 + 2i}{5 + i} \cdot \frac{5 - i}{5 - i}
$$

Numerator:
$$
(1 + 2i)(5 - i) = 1(5) + 1(-i) + 2i(5) + 2i(-i) = 5 - i + 10i - 2i^2
$$
$$
= 5 + 9i - 2(-1) = 5 + 9i + 2 = 7 + 9i
$$

Denominator:
$$
(5 + i)(5 - i) = 25 - i^2 = 25 + 1 = 26
$$

Result:
$$
\frac{7 + 9i}{26} = \frac{7}{26} + \frac{9}{26}i
$$

Answer: $\frac{7}{26} + \frac{9}{26}i$

---

8. $\frac{3 + 3i}{9 - i}$



Multiply by conjugate $9 + i$:

$$
\frac{3 + 3i}{9 - i} \cdot \frac{9 + i}{9 + i}
$$

Numerator:
$$
(3 + 3i)(9 + i) = 3(9) + 3(i) + 3i(9) + 3i(i) = 27 + 3i + 27i + 3i^2
$$
$$
= 27 + 30i + 3(-1) = 27 + 30i - 3 = 24 + 30i
$$

Denominator:
$$
(9 - i)(9 + i) = 81 - i^2 = 81 + 1 = 82
$$

Result:
$$
\frac{24 + 30i}{82} = \frac{12}{41} + \frac{15}{41}i
$$

Answer: $\frac{12}{41} + \frac{15}{41}i$

---

Final Answers:



| Expression | Simplified Form |
|----------|------------------|
| $\frac{8 + 3i}{-3 + i}$ | $-\frac{21}{10} - \frac{17}{10}i$ |
| $\frac{9 + 7i}{1 - 3i}$ | $-\frac{6}{5} + \frac{17}{5}i$ |
| $\frac{7 - 7i}{9 - i}$ | $\frac{35}{41} - \frac{28}{41}i$ |
| $\frac{5 + i}{8 + i}$ | $\frac{41}{65} + \frac{3}{65}i$ |
| $\frac{-10 + i}{-1 + 3i}$ | $\frac{13}{10} + \frac{29}{10}i$ |
| $\frac{-3 - 5i}{-8 + 3i}$ | $\frac{9}{73} + \frac{49}{73}i$ |
| $\frac{1 + 2i}{5 + i}$ | $\frac{7}{26} + \frac{9}{26}i$ |
| $\frac{3 + 3i}{9 - i}$ | $\frac{12}{41} + \frac{15}{41}i$ |

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