Area and Perimeter of Composite Figures worksheet with four L-shaped and rectangular figures, requiring calculation of area and perimeter.

Let’s solve each problem step by step. We’ll find the area and perimeter for each composite figure.

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Problem 1:

Figure is an L-shape made of two rectangles.

We can split it into:
- Top rectangle: 10 cm long, 3 cm high → Area = 10 × 3 = 30 cm²
- Bottom right rectangle: 5 cm wide, (7 - 3) = 4 cm high → Area = 5 × 4 = 20 cm²

Total Area = 30 + 20 = 50 cm²

Perimeter: Add all outer sides.

Start from top left and go clockwise:
- Top: 10 cm
- Right side: 7 cm
- Bottom: 5 cm
- Up inner vertical: 4 cm (this is the height of bottom part)
- Left inner horizontal: (10 - 5) = 5 cm? Wait — let’s trace carefully.

Actually, better to list all outer edges:

Top: 10 cm
Right: 7 cm
Bottom: 5 cm
Up on right side of bottom part: 4 cm (since total height is 7, top part is 3, so bottom part height is 4)
Then left along bottom of top part: (10 - 5) = 5 cm? No — wait, the left side of the whole shape is 3 cm down, then there's a step.

Better way: Draw mentally or sketch.

Outer perimeter path:

Start at top-left corner:
→ Right 10 cm
↓ Down 7 cm
← Left 5 cm
↑ Up 4 cm (to meet the inner corner)
← Left 5 cm (because 10 - 5 = 5)
↑ Up 3 cm (back to start)

Wait — that adds up to: 10 + 7 + 5 + 4 + 5 + 3 = 34 cm? But we double-counted?

No — actually, when you go around the outside, you don’t go inside.

Correct outer perimeter:

Imagine walking around the outside:

From top-left:
- Go right 10 cm (top edge)
- Go down 7 cm (right edge)
- Go left 5 cm (bottom edge)
- Go up 4 cm (inner vertical — but this is still outer boundary? Actually no — in an L-shape, the “step” is part of the outer perimeter.

Actually, standard way: For any polygon, add all outer sides.

Label the sides:

Top: 10 cm
Right: 7 cm
Bottom: 5 cm
Left-bottom vertical: 4 cm (from bottom up to the step)
Step-horizontal: 5 cm (leftward, since 10 - 5 = 5)
Left-top vertical: 3 cm (up to close the shape)

So: 10 + 7 + 5 + 4 + 5 + 3 = 34 cm

But let’s verify with another method: The full bounding box would be 10x7 = 70 cm perimeter if solid, but we have a cutout? No — it’s not a cutout, it’s an L-shape.

Alternative: Use grid or count.

Actually, correct perimeter for L-shape like this:

It has 6 sides:

1. Top: 10
2. Right: 7
3. Bottom: 5
4. Inner vertical up: 4 (height of lower part)
5. Inner horizontal left: 5 (width difference: 10 - 5)
6. Left vertical up: 3

Sum: 10+7=17; +5=22; +4=26; +5=31; +3=34 → 34 cm

Yes.

Area: As calculated, 50 cm²

BUT — wait! The instruction says units for area are cm² and perimeter cm — which matches.

However, looking back at the figure: The left side is labeled 3cm, bottom part height is 4cm, so total height 7cm — correct.

Widths: top 10cm, bottom 5cm — so the overhang is 5cm on left? Actually, the figure shows:

Top rectangle: width 10cm, height 3cm
Attached below on the right: a rectangle 5cm wide, 4cm high — so yes, area 30 + 20 = 50 cm²

Perimeter: 34 cm

But let me check online or standard formula — actually, for such shapes, perimeter is sum of all outer edges.

Another way: Imagine extending lines — the perimeter equals the perimeter of the full rectangle minus nothing because it’s convex? No, it’s concave.

Actually, for this L-shape, perimeter is same as if it were a rectangle 10x7, but with a "notch" — but here it’s not a notch, it’s missing a piece on bottom left.

Full rectangle 10x7 would have perimeter 2*(10+7)=34 — oh! Interesting.

In this case, even though it’s L-shaped, the perimeter is the same as the bounding rectangle because the inner corners cancel out.

Is that true?

Bounding rectangle: 10 cm wide, 7 cm tall → perimeter 2*(10+7)=34 cm — yes!

And our manual count also gave 34 cm — so correct.

Area is less: 50 cm² vs 70 cm² for full rectangle.

So for Problem 1:
Area: 50 cm²
Perimeter: 34 cm

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Problem 2:

Units are mm, but answer boxes say cm² and cm — probably a typo in worksheet, but we'll compute in mm and convert? Or maybe they want numerical value assuming unit conversion? Let's see.

The figure: similar L-shape.

Dimensions:
Left side: 8mm
Top: 6mm
Right side: 6mm
Bottom: 10mm

Split into two rectangles:

Option 1:
- Left rectangle: 6mm wide, 8mm high → area = 48 mm²
- Bottom right rectangle: (10 - 6) = 4mm wide, 6mm high → area = 24 mm²
Total area = 48 + 24 = 72 mm²

But answer box says cm² — so we need to convert.

1 cm = 10 mm, so 1 cm² = 100 mm²

Thus, 72 mm² = 72 / 100 = 0.72 cm²

But that seems messy — perhaps the worksheet meant to keep units consistent? Looking at other problems, they use cm, m, etc., and answer boxes match.

Problem 2 has mm, but answer says cm² and cm — likely a mistake in the worksheet. Probably should be mm² and mm.

But to follow instructions, we must put answer in cm² and cm.

So convert everything to cm first.

Given:
6mm = 0.6 cm
8mm = 0.8 cm
10mm = 1.0 cm
6mm = 0.6 cm (right side)

Now, split figure:

Left rectangle: width 0.6 cm, height 0.8 cm → area = 0.6 * 0.8 = 0.48 cm²

Bottom right rectangle: width (1.0 - 0.6) = 0.4 cm, height 0.6 cm → area = 0.4 * 0.6 = 0.24 cm²

Total area = 0.48 + 0.24 = 0.72 cm²

Perimeter: same as bounding rectangle? Bounding box: width 1.0 cm, height 0.8 cm → perimeter = 2*(1.0 + 0.8) = 3.6 cm

Manual count:

Sides:
Top: 0.6 cm
Right: 0.6 cm (but total height is 0.8, so the right side has two parts? Let's trace.

Start top-left:
→ Right 0.6 cm (top)
↓ Down 0.8 cm (left side? No — left side is 0.8 cm, but after going right 0.6, we go down only partway?

Actually, the figure: from top-left, go right 6mm (0.6cm), then down to the step — how far? The right side is labeled 6mm, so from top-right, down 6mm to the step, then left to the inner corner, then down remaining 2mm? Total height 8mm.

Better: Label points.

Assume coordinates:

Set bottom-left as (0,0)

Then:
- Bottom-right: (10,0) mm
- Top-right: (10,6) mm? But left side is 8mm, so top-left is (0,8)

The shape: from (0,8) to (6,8) to (6,6) to (10,6) to (10,0) to (0,0) to (0,8)? But that would make a different shape.

Standard L-shape for problem 2:

Typically, it's like:

- Full height on left: 8mm
- Full width on bottom: 10mm
- Cut out top-right? No.

From the drawing description: it's an L rotated.

Commonly: the figure has:
- Left vertical: 8mm
- Top horizontal: 6mm
- Then down to a point, then right to 10mm bottom, then up 6mm on right.

So vertices:
Start at top-left (0,8)
→ to (6,8) [top]
↓ to (6,6) [down 2mm? But right side is labeled 6mm, which might be from bottom]

Perhaps the 6mm on right is the height of the right part.

Assume:
The figure consists of:
- A rectangle on left: 6mm wide, 8mm high
- Attached to its bottom-right, a rectangle 4mm wide (10-6), 6mm high — but then the total height on right is 6mm, while left is 8mm, so there's a step up on the right.

So the outer perimeter:

Start at top-left (0,8):
→ right to (6,8) : 6mm
↓ down to (6,6) : 2mm (since from y=8 to y=6)
→ right to (10,6) : 4mm
↓ down to (10,0) : 6mm
← left to (0,0) : 10mm
↑ up to (0,8) : 8mm

Sum: 6 + 2 + 4 + 6 + 10 + 8 = 36 mm

Convert to cm: 36 mm = 3.6 cm

Area: as before, left rect 6*8=48 mm², bottom-right rect 4*6=24 mm², total 72 mm² = 0.72 cm²

But 0.72 cm² is correct numerically.

However, looking at other problems, they use whole numbers, so perhaps the worksheet intends for us to ignore unit conversion and just use the numbers as given, but that would be wrong.

Maybe "cm" in answer box is a typo, and should be "mm". But the instruction says "type in your answer in the boxes provided", and boxes say cm² and cm.

To be safe, I'll compute with mm and convert.

But let's see problem 3 and 4 — they use m and cm, and answer boxes say cm² and cm, so for problem 3, if it's in meters, we need to convert to cm.

This is inconsistent.

For problem 3: dimensions in m, answer in cm² and cm — so we must convert.

Similarly for problem 2.

So for problem 2:

Area = 72 mm² = 72 / 100 = 0.72 cm²

Perimeter = 36 mm = 3.6 cm

But 0.72 and 3.6 are decimals, while others are integers — perhaps acceptable.

Maybe the worksheet expects us to treat the units as is, but that doesn't make sense.

Another possibility: in some contexts, they might want the numerical value without unit conversion, but that would be incorrect.

Let's look at the figure again — perhaps I misread.

In problem 2, the right side is labeled 6mm, bottom 10mm, left 8mm, top 6mm.

If we consider the shape as having:

- Width 10mm, height 8mm, but with a rectangle cut out from top-right of size 4mm x 2mm? Let's calculate area that way.

Full rectangle 10x8 = 80 mm²

Cut out: from top-right, a rectangle of width (10-6)=4mm, height (8-6)=2mm? Because the right side is 6mm high, so from top, it goes down 2mm to the step.

So cut out area = 4 * 2 = 8 mm²

Then area = 80 - 8 = 72 mm² — same as before.

Perimeter: when you cut out a rectangle from corner, the perimeter increases by twice the cut-out dimensions? No.

Original perimeter 2*(10+8)=36 mm

When you cut out a rectangle from corner, you remove two sides but add two new sides of same length, so perimeter unchanged.

In this case, cutting out a 4x2 rectangle from top-right corner: you remove the top 4mm and right 2mm, but add the new inner edges: down 2mm and left 4mm, so net change zero — perimeter remains 36 mm.

Yes, so perimeter is 36 mm = 3.6 cm

Area 72 mm² = 0.72 cm²

So for problem 2:
Area: 0.72 cm²
Perimeter: 3.6 cm

But let's write as fractions or decimals? Probably decimals are fine.

0.72 and 3.6

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Problem 3:

Dimensions in meters, answer in cm² and cm — so convert to cm.

1 m = 100 cm

So:
5m = 500 cm
6m = 600 cm
8m = 800 cm
3m = 300 cm

Figure: L-shape, but oriented differently.

Split into two rectangles:

Option:
- Left rectangle: 5m wide, (6+3)=9m high? Let's see.

From the figure: it's like a backwards L.

Top part: width 5m, height 6m
Bottom part: width (5+8)=13m? No.

Vertices: assume bottom-left (0,0)
→ right to (13,0)? Let's define.

Typically: from left, width 5m for the vertical part, then extends right 8m for the horizontal part, with heights.

The figure shows:
- Left side: from bottom to top, total height 6m + 3m = 9m? But labeled 6m on the vertical part of the L, and 3m on the bottom right.

Standard interpretation:

The shape has:
- A vertical rectangle on left: 5m wide, 9m high? But the label "6m" is on the right side of the top part.

Better: the figure is composed of:
- Top rectangle: 5m wide, 6m high
- Bottom rectangle: (5+8)=13m wide, 3m high — but then they overlap? No.

Actually, it's an L-shape where the stem is on left.

So:
- Left column: 5m wide, total height 6m + 3m = 9m
- But the bottom part extends right 8m beyond the left column.

So the bottom rectangle is 8m wide (extension) and 3m high, attached to the bottom of the left column.

But the left column is 5m wide, 9m high, and the bottom extension is 8m wide, 3m high, attached to the bottom-right of the left column.

So total width = 5 + 8 = 13m
Total height = 9m, but the right part is only 3m high.

Area:
- Left rectangle: 5m * 9m = 45 m²
- Bottom-right rectangle: 8m * 3m = 24 m²
But they overlap? No, because the bottom-right is attached to the side, not overlapping.

Actually, the left rectangle includes the bottom-left part, and the bottom-right is additional.

So total area = area of left part + area of bottom extension.

Left part: 5m wide, from y=0 to y=9m
Bottom extension: from x=5m to x=13m, y=0 to y=3m

So no overlap.

Area = (5*9) + (8*3) = 45 + 24 = 69 m²

Convert to cm²: 1 m² = 10,000 cm², so 69 * 10,000 = 690,000 cm²

Perimeter: let's trace outer edges.

Start at top-left (0,9):
→ right to (5,9) : 5m
↓ down to (5,3) : 6m (since from y=9 to y=3)
→ right to (13,3) : 8m
↓ down to (13,0) : 3m
← left to (0,0) : 13m
↑ up to (0,9) : 9m

Sum: 5 + 6 + 8 + 3 + 13 + 9 = let's calculate: 5+6=11; +8=19; +3=22; +13=35; +9=44 m

Convert to cm: 44 * 100 = 4400 cm

Is this correct? When we go from (5,3) to (13,3), that's the top of the bottom extension, then down to (13,0), then left to (0,0), then up to (0,9).

Yes, and from (0,9) to (5,9) is the top of the left part.

So perimeter 44 m = 4400 cm

Area 69 m² = 690,000 cm²

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Problem 4:

Dimensions in cm, answer in cm² and cm — good.

Figure: L-shape.

Labels:
Left side: 8cm
Bottom: 5cm
Right side: 6cm
Inner horizontal: 4cm

Split into rectangles.

One way:
- Bottom rectangle: 5cm wide, ? high
- Top rectangle: ? wide, 6cm high

Note that the total height on left is 8cm, on right is 6cm, so the difference is 2cm, which is the height of the bottom part on the left.

Also, the inner horizontal is 4cm, which is the width of the top part on the right.

Assume:
The shape has a bottom rectangle and a top rectangle.

Bottom rectangle: width 5cm, height h1
Top rectangle: width w2, height 6cm

From the figure, the top rectangle is shifted right, so its left edge is at x= something.

The inner horizontal segment is 4cm, which is likely the width of the top rectangle.

Also, the total width at bottom is 5cm, at top is more.

From the labels: the right side is 6cm, which is the height of the top part.

The left side is 8cm, so the bottom part height is 8 - 6 = 2cm.

The bottom rectangle is 5cm wide, 2cm high.

The top rectangle: it sits on top of the bottom rectangle, but extends to the right. The inner horizontal is 4cm, which might be the overhang.

Typically, the top rectangle has width such that from the left, it starts after some offset.

The bottom is 5cm wide. The top part has a horizontal segment of 4cm on the right, but that might be the width of the top rectangle.

Assume the top rectangle is 4cm wide? But then where is it placed.

From the figure description: it's like a rectangle with a bite taken out, but usually for L-shape.

Standard way: the figure can be seen as a large rectangle minus a small rectangle, or add two rectangles.

Add two rectangles:

- Left rectangle: 5cm wide, 8cm high? But then the right part is shorter.

Better:
- Bottom rectangle: 5cm wide, 2cm high (since total height 8cm, top part 6cm, so bottom 2cm)
- Top rectangle: width (5 + 4) = 9cm? Because the inner horizontal is 4cm, which is the extension to the right.

The label "4cm" is on the inner horizontal, which is the top of the bottom part or bottom of the top part.

In many such figures, the 4cm is the width of the protrusion.

So, the top rectangle is wider than the bottom.

Specifically, the bottom is 5cm wide, the top extends 4cm to the right, so top width = 5 + 4 = 9cm, height 6cm.

But then the left side: from bottom to top, the left edge is straight, so the top rectangle should be aligned left with the bottom.

So:
- Bottom rectangle: 5cm wide, 2cm high
- Top rectangle: 9cm wide, 6cm high, sitting on top of the bottom rectangle, aligned left.

Then the total height on left is 2 + 6 = 8cm, good.
On right, the bottom part is only 2cm high, top part is 6cm high, so the right side has a step.

The right side label is 6cm, which matches the top part height.

The inner horizontal is 4cm, which is the overhang of the top rectangle beyond the bottom rectangle on the right.

Yes.

So area:
Bottom: 5 * 2 = 10 cm²
Top: 9 * 6 = 54 cm²
Total area = 10 + 54 = 64 cm²

Perimeter: trace outer edges.

Start at top-left (0,8):
→ right to (9,8) : 9cm (top of top rectangle)
↓ down to (9,6) : 2cm? From y=8 to y=6, but the top rectangle is from y=2 to y=8? Let's set coordinates.

Set bottom-left as (0,0)

Bottom rectangle: from (0,0) to (5,2)
Top rectangle: from (0,2) to (9,8) — since height 6cm, from y=2 to y=8.

Then the shape is the union.

Outer perimeter:

Start at (0,8):
→ right to (9,8) : 9cm
↓ down to (9,2) : 6cm (since from y=8 to y=2)
← left to (5,2) : 4cm (this is the inner horizontal, but it's outer boundary? At y=2, from x=9 to x=5, but below that is the bottom rectangle from x=0 to x=5, so from (5,2) we go down to (5,0)? No.

At (9,2), we are at the bottom-right of the top rectangle. Below that, there is no material, so we go down? But the bottom rectangle is only up to x=5.

So from (9,2), since there's no shape below, we go down to (9,0)? But that would be outside.

I think I have the orientation wrong.

Typically in such figures, the L-shape has the short leg on the bottom right.

From the label: "4cm" is on the inner horizontal, which is likely the top of the bottom part.

Assume the figure is:

- A large rectangle 9cm wide, 8cm high, but with a rectangle cut out from bottom-left or something.

From the labels: left side 8cm, bottom 5cm, right side 6cm, and a horizontal segment of 4cm inside.

Probably, the shape is:

From bottom-left (0,0) to (5,0) to (5,2) to (9,2) to (9,8) to (0,8) to (0,0)? But then the left side is 8cm, bottom is 5cm, but from (5,0) to (5,2) is up, then to (9,2), then to (9,8), then to (0,8), then to (0,0).

But then the right side from (9,2) to (9,8) is 6cm, good.

The bottom from (0,0) to (5,0) is 5cm.

The inner horizontal from (5,2) to (9,2) is 4cm, good.

And the left side from (0,0) to (0,8) is 8cm.

Perfect.

So vertices in order for perimeter: start at (0,0):
→ to (5,0) : 5cm
↑ to (5,2) : 2cm
→ to (9,2) : 4cm
↑ to (9,8) : 6cm
← to (0,8) : 9cm
↓ to (0,0) : 8cm

Sum: 5 + 2 + 4 + 6 + 9 + 8 = let's add: 5+2=7; +4=11; +6=17; +9=26; +8=34 cm

Area: we can calculate as the area of the polygon.

Or split into two rectangles:
- Bottom: 5cm x 2cm = 10 cm²
- Top: 9cm x 6cm = 54 cm², but they overlap? No, the top rectangle is from y=2 to y=8, x=0 to x=9, bottom is x=0 to x=5, y=0 to y=2, so no overlap.

But the top rectangle includes the area above the bottom, so total area = area of bottom rect + area of top rect = 10 + 54 = 64 cm²

We can also see it as a large rectangle 9x8 = 72 cm² minus the missing part. What is missing? From x=5 to x=9, y=0 to y=2, which is 4cm x 2cm = 8 cm², so 72 - 8 = 64 cm² — same.

So area 64 cm², perimeter 34 cm.

Now, summarize all:

Problem 1:
Area: 50 cm²
Perimeter: 34 cm

Problem 2:
Area: 0.72 cm² (since 72 mm² = 0.72 cm²)
Perimeter: 3.6 cm (36 mm = 3.6 cm)

Problem 3:
Area: 690,000 cm² (69 m² * 10,000)
Perimeter: 4,400 cm (44 m * 100)

Problem 4:
Area: 64 cm²
Perimeter: 34 cm

But for problem 2 and 3, the numbers are large or decimal, while others are nice. Perhaps the worksheet has a typo, and for problem 2, the units should be mm, and for problem 3, meters, but the answer boxes specify cm.

Since the instruction is to type in the boxes as per the worksheet, we must use the units specified in the boxes.

So I'll go with that.

Now, to box the answers.

Final Answer:

1) Area: 50, Perimeter: 34
2) Area: 0.72, Perimeter: 3.6
3) Area: 690000, Perimeter: 4400
4) Area: 64, Perimeter: 34

But for problem 3, 690,000 is 690000 without comma.

Also, ensure no space, as per instruction.

So write as numbers.

For problem 2, 0.72 and 3.6 are fine.

Perhaps they expect fractions, but decimals are acceptable.

Another thought: in problem 2, if we keep in mm, but the box says cm, so must convert.

Similarly for problem 3.

So I think it's correct.

Let me double-check problem 3 perimeter.

In problem 3, with meters:

Vertices:
(0,0) -> (5,0) : 5m
-> (5,9) : 9m? No.

Earlier I had:

From bottom-left (0,0):
→ to (5,0) : 5m (bottom of left part)
↑ to (5,9) : 9m? But the left part is 5m wide, 9m high, but then the bottom extension is from (5,0) to (13,0) to (13,3) to (5,3)? I think I messed up.

Let's redefine problem 3.

Figure 3:
- Left side labeled 6m (vertical)
- Top labeled 5m (horizontal)
- Then a horizontal segment labeled 8m (to the right)
- Then down 3m on the right.

So typically, it's an L-shape with the long leg on bottom.

So:
- The vertical part on left: width 5m, height 6m + 3m = 9m? But the 6m is labeled on the vertical side of the top part.

Standard: the shape has:
- A rectangle on top: 5m wide, 6m high
- A rectangle on bottom: extending right, 8m wide, 3m high, attached to the bottom of the top rectangle.

But then the total width at bottom is 5m + 8m = 13m, height on left is 6m + 3m = 9m, on right is 3m.

The left side is from bottom to top: 9m, but labeled as 6m on the upper part? The label "6m" is on the right side of the top rectangle, I think.

In the text: "3) 5m" on top, "6m" on the right side of the top part, "8m" on the bottom horizontal, "3m" on the right vertical of the bottom part.

So yes, as I had earlier.

So vertices:
Start at top-left (0,9) if we set y=0 at bottom.

Set (0,0) at bottom-left.

Then:
- Bottom-left (0,0)
- Bottom-right of bottom part: (13,0) since 5+8=13m wide at bottom
- But the bottom part is only 3m high, so from (0,0) to (13,0) to (13,3) to (5,3) to (5,9) to (0,9) to (0,0)? Let's see.

From (0,0) to (13,0) : bottom
to (13,3) : right side of bottom part, height 3m
to (5,3) : left along the top of the bottom part, distance 8m (since 13-5=8)
to (5,9) : up the right side of the top part, height 6m (9-3=6)
to (0,9) : left along top, 5m
to (0,0) : down left side, 9m

Yes.

So perimeter: 13 (bottom) + 3 (right) + 8 (inner horizontal) + 6 (inner vertical) + 5 (top) + 9 (left) = 13+3=16; +8=24; +6=30; +5=35; +9=44 m — same as before.

Area: bottom rectangle 13m * 3m = 39 m²? But that includes the part under the top rectangle.

Better to split as:
- Left rectangle: 5m wide, 9m high = 45 m²
- Bottom-right rectangle: 8m wide, 3m high = 24 m²
But the bottom-right is from x=5 to x=13, y=0 to y=3, and left rectangle is x=0 to x=5, y=0 to y=9, so they share the line x=5, but no area overlap.

Total area = 45 + 24 = 69 m² — correct.

If we do large rectangle 13x9 = 117 m² minus the missing part: from x=5 to x=13, y=3 to y=9, which is 8m x 6m = 48 m², so 117 - 48 = 69 m² — same.

So correct.

Now for final answer.

I think we have to go with the conversions.

So:

Final Answer:
1) Area: 50, Perimeter: 34
2) Area: 0.72, Perimeter: 3.6
3) Area: 690000, Perimeter: 4400
4) Area: 64, Perimeter: 34

But for problem 2, 0.72 might be written as .72, but usually 0.72 is fine.

Perhaps they expect 72/100, but decimal is ok.

For problem 3, 690000 is correct.

Now, to present in the box.

The instruction is to type in the boxes, so for each, area and perimeter.

So for the response, list them.

Since the user will fill in, we provide the numbers.

So Final Answer:

1) Area: 50, Perimeter: 34
2) Area: 0.72, Perimeter: 3.6
3) Area: 690000, Perimeter: 4400
4) Area: 64, Perimeter: 34

But to match the format, perhaps write as:

For 1: Area 50, Perimeter 34
etc.

Since the boxes are separate, but in text, we can list.

I think it's clear.

So I'll box the final answer as per the problems.

Note: In problem 2, if the worksheet intended mm, but since the box says cm, we must convert.

Similarly for problem 3.

So I think it's correct.