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Calculate the area of compound shapes made with rectangles.

Compound shapes made of rectangles with labeled dimensions, showing shaded areas to calculate area and perimeter.

Compound shapes made of rectangles with labeled dimensions, showing shaded areas to calculate area and perimeter.

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Show Answer Key & Explanations Step-by-step solution for: area of compound shapes worksheet Archives - Mr-Mathematics.com

Problem: Calculate the shaded areas of the compound shapes provided.



#### Step-by-Step Solution:

We will calculate the shaded area for each shape (a, b, c, d, e) step by step.

---

Shape (a):


The shape consists of two rectangles:
1. A larger rectangle with dimensions \(8 \, \text{cm} \times 5 \, \text{cm}\).
2. A smaller rectangle with dimensions \(4 \, \text{cm} \times 3 \, \text{cm}\) (since the total width is 8 cm and the left part is 5 cm, the right part is \(8 - 5 = 3 \, \text{cm}\)).

#### Calculation:
- Area of the larger rectangle:
\[
\text{Area}_{\text{large}} = 8 \times 5 = 40 \, \text{cm}^2
\]
- Area of the smaller rectangle:
\[
\text{Area}_{\text{small}} = 4 \times 3 = 12 \, \text{cm}^2
\]
- Total shaded area:
\[
\text{Shaded Area} = \text{Area}_{\text{large}} + \text{Area}_{\text{small}} = 40 + 12 = 52 \, \text{cm}^2
\]

#### Answer for (a):
\[
\boxed{52 \, \text{cm}^2}
\]

---

Shape (b):


The shape consists of two rectangles:
1. A larger rectangle with dimensions \(7 \, \text{cm} \times 5 \, \text{cm}\).
2. A smaller rectangle with dimensions \(4 \, \text{cm} \times 3 \, \text{cm}\) (since the total height is 7 cm and the top part is 4 cm, the bottom part is \(7 - 4 = 3 \, \text{cm}\)).

#### Calculation:
- Area of the larger rectangle:
\[
\text{Area}_{\text{large}} = 7 \times 5 = 35 \, \text{cm}^2
\]
- Area of the smaller rectangle:
\[
\text{Area}_{\text{small}} = 4 \times 3 = 12 \, \text{cm}^2
\]
- Total shaded area:
\[
\text{Shaded Area} = \text{Area}_{\text{large}} + \text{Area}_{\text{small}} = 35 + 12 = 47 \, \text{cm}^2
\]

#### Answer for (b):
\[
\boxed{47 \, \text{cm}^2}
\]

---

Shape (c):


The shape is a large rectangle with a smaller rectangle removed from its center.
1. Dimensions of the large rectangle: \(13 \, \text{m} \times 4 \, \text{m}\).
2. Dimensions of the smaller rectangle: \(7 \, \text{m} \times 1 \, \text{m}\).

#### Calculation:
- Area of the large rectangle:
\[
\text{Area}_{\text{large}} = 13 \times 4 = 52 \, \text{m}^2
\]
- Area of the smaller rectangle:
\[
\text{Area}_{\text{small}} = 7 \times 1 = 7 \, \text{m}^2
\]
- Shaded area (subtract the smaller rectangle from the larger rectangle):
\[
\text{Shaded Area} = \text{Area}_{\text{large}} - \text{Area}_{\text{small}} = 52 - 7 = 45 \, \text{m}^2
\]

#### Answer for (c):
\[
\boxed{45 \, \text{m}^2}
\]

---

Shape (d):


The shape is a "T"-shaped figure consisting of two rectangles:
1. A horizontal rectangle with dimensions \(20 \, \text{m} \times 5 \, \text{m}\).
2. A vertical rectangle with dimensions \(4 \, \text{m} \times 20 \, \text{m}\) (since the total height is 25 m and the top part is 5 m, the remaining height is \(25 - 5 = 20 \, \text{m}\)).

#### Calculation:
- Area of the horizontal rectangle:
\[
\text{Area}_{\text{horizontal}} = 20 \times 5 = 100 \, \text{m}^2
\]
- Area of the vertical rectangle:
\[
\text{Area}_{\text{vertical}} = 4 \times 20 = 80 \, \text{m}^2
\]
- Total shaded area:
\[
\text{Shaded Area} = \text{Area}_{\text{horizontal}} + \text{Area}_{\text{vertical}} = 100 + 80 = 180 \, \text{m}^2
\]

#### Answer for (d):
\[
\boxed{180 \, \text{m}^2}
\]

---

Shape (e):


The shape consists of three rectangles:
1. A top rectangle with dimensions \(14 \, \text{m} \times 4.5 \, \text{m}\).
2. A middle rectangle with dimensions \(9 \, \text{m} \times 3 \, \text{m}\).
3. A bottom rectangle with dimensions \(12 \, \text{m} \times 3 \, \text{m}\).

#### Calculation:
- Area of the top rectangle:
\[
\text{Area}_{\text{top}} = 14 \times 4.5 = 63 \, \text{m}^2
\]
- Area of the middle rectangle:
\[
\text{Area}_{\text{middle}} = 9 \times 3 = 27 \, \text{m}^2
\]
- Area of the bottom rectangle:
\[
\text{Area}_{\text{bottom}} = 12 \times 3 = 36 \, \text{m}^2
\]
- Total shaded area:
\[
\text{Shaded Area} = \text{Area}_{\text{top}} + \text{Area}_{\text{middle}} + \text{Area}_{\text{bottom}} = 63 + 27 + 36 = 126 \, \text{m}^2
\]

#### Answer for (e):
\[
\boxed{126 \, \text{m}^2}
\]

---

Final Answers:


\[
\boxed{52 \, \text{cm}^2, 47 \, \text{cm}^2, 45 \, \text{m}^2, 180 \, \text{m}^2, 126 \, \text{m}^2}
\]
Parent Tip: Review the logic above to help your child master the concept of composite figure worksheet.
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