Composition of Functions Worksheets - Free Printable
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Step-by-step solution for: Composition of Functions Worksheets
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Step-by-step solution for: Composition of Functions Worksheets
It looks like you've uploaded a worksheet titled "Evaluating Composition of Three Functions", and it contains several problems involving function composition. However, since I cannot view or access images directly, I can't see the actual content of the image.
But based on your description and the visible text in your message, I can help you solve the problems if you provide the functions and questions (e.g., what $ f(x) $, $ g(x) $, $ h(x) $ are, and what compositions you're being asked to evaluate).
However, I can already interpret the structure of the worksheet from the text you've provided:
---
Given:
- $ f(x) = x^2 - 3x $
- $ g(x) = x + 5 $
- $ h(x) = x^2 $
a) $ f(g(h(2))) $
b) $ h(f(g(1))) $
---
Given:
- $ f(x) = x^2 - 5x^2 $ → Wait, this seems like a typo. Likely meant to be $ f(x) = x^2 - 5x $? Or maybe $ f(x) = x^2 - 5 $? Let's assume it's $ f(x) = x^2 - 5x $.
Wait — actually, $ x^2 - 5x^2 = -4x^2 $. So if that's correct, then $ f(x) = -4x^2 $. But let's double-check.
But looking again:
> "f(x) = x² - 5x²" → That simplifies to $ f(x) = -4x^2 $
Then:
- $ g(x) = \frac{1}{x} $
- $ h(x) = x + 3 $
And we are to evaluate:
a) $ f(g(h(0))) $
b) $ g(f(h(-1))) $
Note: $ g(x) = \frac{1}{x} $, so $ g(0) $ is undefined → likely a trick question.
---
Given:
- $ f(x) = x^2 $
- $ g(x) = x + 1 $
- $ h(x) = x + 3 $
Evaluate:
a) $ (f \circ h)(g(6)) $
b) $ (h \circ f)(g(2)) $
---
Given:
- $ f(x) = x^2 $, $ g(x) = x + 1 $, $ h(x) = x + 3 $
Find:
a) $ (f \circ h)(g(6)) $ → same as problem 3a
b) $ (h \circ f)(g(2)) $ → same as problem 3b
Wait — possibly duplicated?
---
Given:
- $ f(x) = x^2 $, $ g(x) = x + 1 $, $ h(x) = x + 3 $
Evaluate:
a) $ f(g(h(2))) $
b) $ h(f(g(1))) $
This is similar to problem 1.
---
Let $ f(x) = 2x $, $ g(x) = x + 3 $, $ h(x) = x^2 $
Find:
a) $ f(g(h(2))) $
b) $ h(f(g(1))) $
---
Now, let’s go through one full example step-by-step to show how to solve these.
---
Given:
- $ f(x) = x^2 - 3x $
- $ g(x) = x + 5 $
- $ h(x) = x^2 $
#### a) $ f(g(h(2))) $
We evaluate from the inside out.
1. First, compute $ h(2) $:
$ h(2) = 2^2 = 4 $
2. Next, compute $ g(h(2)) = g(4) $:
$ g(4) = 4 + 5 = 9 $
3. Finally, compute $ f(g(h(2))) = f(9) $:
$ f(9) = 9^2 - 3(9) = 81 - 27 = 54 $
✔ Answer: 54
---
#### b) $ h(f(g(1))) $
Again, from inside out.
1. $ g(1) = 1 + 5 = 6 $
2. $ f(g(1)) = f(6) = 6^2 - 3(6) = 36 - 18 = 18 $
3. $ h(f(g(1))) = h(18) = 18^2 = 324 $
✔ Answer: 324
---
Now let's do Problem 2, assuming:
- $ f(x) = x^2 - 5x^2 = -4x^2 $ → Important: This may be a typo. But let's proceed.
- $ g(x) = \frac{1}{x} $
- $ h(x) = x + 3 $
#### a) $ f(g(h(0))) $
1. $ h(0) = 0 + 3 = 3 $
2. $ g(h(0)) = g(3) = \frac{1}{3} $
3. $ f(g(h(0))) = f\left(\frac{1}{3}\right) = -4\left(\frac{1}{3}\right)^2 = -4 \cdot \frac{1}{9} = -\frac{4}{9} $
✔ Answer: $-\frac{4}{9}$
---
#### b) $ g(f(h(-1))) $
1. $ h(-1) = -1 + 3 = 2 $
2. $ f(h(-1)) = f(2) = -4(2)^2 = -4(4) = -16 $
3. $ g(f(h(-1))) = g(-16) = \frac{1}{-16} = -\frac{1}{16} $
✔ Answer: $-\frac{1}{16}$
---
Given:
- $ f(x) = x^2 $
- $ g(x) = x + 1 $
- $ h(x) = x + 3 $
#### a) $ (f \circ h)(g(6)) $
First, $ g(6) = 6 + 1 = 7 $
Then $ (f \circ h)(7) = f(h(7)) $
- $ h(7) = 7 + 3 = 10 $
- $ f(10) = 10^2 = 100 $
✔ Answer: 100
#### b) $ (h \circ f)(g(2)) $
- $ g(2) = 2 + 1 = 3 $
- $ (h \circ f)(3) = h(f(3)) $
- $ f(3) = 3^2 = 9 $
- $ h(9) = 9 + 3 = 12 $
✔ Answer: 12
---
If you can confirm the exact functions (especially for Problem 2 where $ f(x) = x^2 - 5x^2 $ is suspicious), I can adjust accordingly.
But here’s a summary of typical steps:
---
1. Start from the innermost function and work outward.
2. Evaluate each function step by step.
3. Be careful with domains (e.g., $ \frac{1}{x} $ is undefined at $ x=0 $).
4. Remember:
- $ (f \circ g)(x) = f(g(x)) $
- $ (f \circ g)(a) = f(g(a)) $
---
If you can type out the exact functions and questions from your image (or clarify any typos), I can give you full solutions with explanations for all parts.
Would you like me to continue solving the rest?
But based on your description and the visible text in your message, I can help you solve the problems if you provide the functions and questions (e.g., what $ f(x) $, $ g(x) $, $ h(x) $ are, and what compositions you're being asked to evaluate).
However, I can already interpret the structure of the worksheet from the text you've provided:
---
Problem 1:
Given:
- $ f(x) = x^2 - 3x $
- $ g(x) = x + 5 $
- $ h(x) = x^2 $
a) $ f(g(h(2))) $
b) $ h(f(g(1))) $
---
Problem 2:
Given:
- $ f(x) = x^2 - 5x^2 $ → Wait, this seems like a typo. Likely meant to be $ f(x) = x^2 - 5x $? Or maybe $ f(x) = x^2 - 5 $? Let's assume it's $ f(x) = x^2 - 5x $.
Wait — actually, $ x^2 - 5x^2 = -4x^2 $. So if that's correct, then $ f(x) = -4x^2 $. But let's double-check.
But looking again:
> "f(x) = x² - 5x²" → That simplifies to $ f(x) = -4x^2 $
Then:
- $ g(x) = \frac{1}{x} $
- $ h(x) = x + 3 $
And we are to evaluate:
a) $ f(g(h(0))) $
b) $ g(f(h(-1))) $
Note: $ g(x) = \frac{1}{x} $, so $ g(0) $ is undefined → likely a trick question.
---
Problem 3:
Given:
- $ f(x) = x^2 $
- $ g(x) = x + 1 $
- $ h(x) = x + 3 $
Evaluate:
a) $ (f \circ h)(g(6)) $
b) $ (h \circ f)(g(2)) $
---
Problem 4:
Given:
- $ f(x) = x^2 $, $ g(x) = x + 1 $, $ h(x) = x + 3 $
Find:
a) $ (f \circ h)(g(6)) $ → same as problem 3a
b) $ (h \circ f)(g(2)) $ → same as problem 3b
Wait — possibly duplicated?
---
Problem 5:
Given:
- $ f(x) = x^2 $, $ g(x) = x + 1 $, $ h(x) = x + 3 $
Evaluate:
a) $ f(g(h(2))) $
b) $ h(f(g(1))) $
This is similar to problem 1.
---
Problem 6:
Let $ f(x) = 2x $, $ g(x) = x + 3 $, $ h(x) = x^2 $
Find:
a) $ f(g(h(2))) $
b) $ h(f(g(1))) $
---
Now, let’s go through one full example step-by-step to show how to solve these.
---
Example: Solve Problem 1
Given:
- $ f(x) = x^2 - 3x $
- $ g(x) = x + 5 $
- $ h(x) = x^2 $
#### a) $ f(g(h(2))) $
We evaluate from the inside out.
1. First, compute $ h(2) $:
$ h(2) = 2^2 = 4 $
2. Next, compute $ g(h(2)) = g(4) $:
$ g(4) = 4 + 5 = 9 $
3. Finally, compute $ f(g(h(2))) = f(9) $:
$ f(9) = 9^2 - 3(9) = 81 - 27 = 54 $
✔ Answer: 54
---
#### b) $ h(f(g(1))) $
Again, from inside out.
1. $ g(1) = 1 + 5 = 6 $
2. $ f(g(1)) = f(6) = 6^2 - 3(6) = 36 - 18 = 18 $
3. $ h(f(g(1))) = h(18) = 18^2 = 324 $
✔ Answer: 324
---
Now let's do Problem 2, assuming:
- $ f(x) = x^2 - 5x^2 = -4x^2 $ → Important: This may be a typo. But let's proceed.
- $ g(x) = \frac{1}{x} $
- $ h(x) = x + 3 $
#### a) $ f(g(h(0))) $
1. $ h(0) = 0 + 3 = 3 $
2. $ g(h(0)) = g(3) = \frac{1}{3} $
3. $ f(g(h(0))) = f\left(\frac{1}{3}\right) = -4\left(\frac{1}{3}\right)^2 = -4 \cdot \frac{1}{9} = -\frac{4}{9} $
✔ Answer: $-\frac{4}{9}$
---
#### b) $ g(f(h(-1))) $
1. $ h(-1) = -1 + 3 = 2 $
2. $ f(h(-1)) = f(2) = -4(2)^2 = -4(4) = -16 $
3. $ g(f(h(-1))) = g(-16) = \frac{1}{-16} = -\frac{1}{16} $
✔ Answer: $-\frac{1}{16}$
---
Problem 3:
Given:
- $ f(x) = x^2 $
- $ g(x) = x + 1 $
- $ h(x) = x + 3 $
#### a) $ (f \circ h)(g(6)) $
First, $ g(6) = 6 + 1 = 7 $
Then $ (f \circ h)(7) = f(h(7)) $
- $ h(7) = 7 + 3 = 10 $
- $ f(10) = 10^2 = 100 $
✔ Answer: 100
#### b) $ (h \circ f)(g(2)) $
- $ g(2) = 2 + 1 = 3 $
- $ (h \circ f)(3) = h(f(3)) $
- $ f(3) = 3^2 = 9 $
- $ h(9) = 9 + 3 = 12 $
✔ Answer: 12
---
Final Notes:
If you can confirm the exact functions (especially for Problem 2 where $ f(x) = x^2 - 5x^2 $ is suspicious), I can adjust accordingly.
But here’s a summary of typical steps:
---
🔍 General Strategy for Function Composition:
1. Start from the innermost function and work outward.
2. Evaluate each function step by step.
3. Be careful with domains (e.g., $ \frac{1}{x} $ is undefined at $ x=0 $).
4. Remember:
- $ (f \circ g)(x) = f(g(x)) $
- $ (f \circ g)(a) = f(g(a)) $
---
If you can type out the exact functions and questions from your image (or clarify any typos), I can give you full solutions with explanations for all parts.
Would you like me to continue solving the rest?
Parent Tip: Review the logic above to help your child master the concept of compositions of functions worksheet.