Transformed Figures Worksheet Collection For Teaching & Learning - Free Printable
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Step-by-step solution for: Transformed Figures Worksheet Collection For Teaching & Learning
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Step-by-step solution for: Transformed Figures Worksheet Collection For Teaching & Learning
Let's solve each of the four problems on the worksheet step by step. We are to determine if the two figures in each coordinate plane are congruent, and if so, describe the congruence transformations (such as translations, reflections, rotations) that map Figure 1 onto Figure 2.
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Figures:
- Figure 1: Green L-shaped figure with vertices at (1,4), (1,2), (3,2), (3,1), (2,1)
- Figure 2: Orange L-shaped figure with vertices at (-3,2), (-3,0), (-1,0), (-1,-1), (-2,-1)
#### ✔ Step 1: Are they congruent?
Both are L-shaped figures made of 5 unit squares. They have the same shape and size — just positioned differently.
✔ Yes, they are congruent.
#### ✔ Step 2: Transformation from Figure 1 to Figure 2
We can compare corresponding points:
- (1,4) → (-3,2): Δx = -4, Δy = -2
- (1,2) → (-3,0): Δx = -4, Δy = -2
- (3,2) → (-1,0): Δx = -4, Δy = -2
- (3,1) → (-1,-1): Δx = -4, Δy = -2
- (2,1) → (-2,-1): Δx = -4, Δy = -2
All points shift by (-4, -2).
👉 So, the transformation is a translation of 4 units left and 2 units down.
> ✔ Answer: The figures are congruent.
> Transformation: Translate Figure 1 by (x – 4, y – 2) to map it onto Figure 2.
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Figures:
- Figure 1: Green triangle with vertices at (-3,-4), (-1,-4), (-2,-2)
- Figure 2: Orange triangle with vertices at (1,5), (2,3), (1,3)
#### ✔ Step 1: Are they congruent?
Let’s check side lengths:
Figure 1:
- A(-3,-4), B(-1,-4), C(-2,-2)
- AB = 2 units (horizontal)
- AC = √[(-2+3)² + (-2+4)²] = √[1 + 4] = √5
- BC = √[(-1+2)² + (-4+2)²] = √[1 + 4] = √5
So it's an isosceles triangle with sides: 2, √5, √5
Figure 2:
- D(1,5), E(2,3), F(1,3)
- DE = √[(2-1)² + (3-5)²] = √[1 + 4] = √5
- DF = 2 units (vertical)
- EF = √[(2-1)² + (3-3)²] = 1? Wait: (2,3) to (1,3) = 1 unit horizontally.
Wait — this seems inconsistent.
Wait! Let's list the correct vertices:
Looking closely:
- Figure 2: (1,5), (2,3), (1,3)
- So: D(1,5), E(2,3), F(1,3)
Now compute:
- DE: √[(2-1)² + (3-5)²] = √[1 + 4] = √5
- DF: |5 - 3| = 2 (vertical)
- EF: |2 - 1| = 1 (horizontal)
But wait — this gives sides: 2, 1, √5 — which is not the same as Figure 1 (which had 2, √5, √5).
But let's double-check the shapes.
Actually, both triangles appear to be right triangles with legs of length 2 and 2?
Wait — let’s re-express:
Figure 1:
- From (-3,-4) to (-1,-4): horizontal leg = 2
- From (-1,-4) to (-2,-2): not vertical or horizontal
Wait — better to plot or calculate distances.
Let me do exact calculations:
Figure 1:
- A(-3,-4), B(-1,-4), C(-2,-2)
- AB: distance = √[(-1+3)² + (-4+4)²] = √[4] = 2
- AC: √[(-2+3)² + (-2+4)²] = √[1 + 4] = √5
- BC: √[(-1+2)² + (-4+2)²] = √[1 + 4] = √5
So sides: 2, √5, √5 → isosceles
Figure 2:
- D(1,5), E(2,3), F(1,3)
- DF: from (1,5) to (1,3): vertical = 2 units
- EF: from (2,3) to (1,3): horizontal = 1 unit
- DE: √[(2-1)² + (3-5)²] = √[1 + 4] = √5
Sides: 2, 1, √5 → different from Figure 1
But wait — this suggests not congruent?
But visually, they look similar.
Wait — maybe I misread the coordinates.
Look again:
Figure 2 has points:
- (1,5), (2,3), (1,3)
Wait — (1,5) to (1,3) = 2 units down
- (1,3) to (2,3) = 1 unit right
- (2,3) to (1,5): diagonal
But Figure 1:
- (-3,-4) to (-1,-4): 2 units right
- (-1,-4) to (-2,-2): up-left
- (-2,-2) to (-3,-4): down-left
Wait — actually, let’s see if there's a rotation or reflection.
Try comparing angles.
Alternatively, try to see if one is a rotation/reflection of the other.
Let’s suppose we rotate Figure 1 90° clockwise around origin.
But better: let's consider possible transformation.
Wait — notice that both seem to be right triangles?
Let’s check angles.
In Figure 1:
- At point B(-1,-4): vectors BA = (-2,0), BC = (-1,2)
- Dot product: (-2)(-1) + (0)(2) = 2 ≠ 0 → not right angle
Wait — maybe not.
Alternatively, perhaps I should count grid squares.
But here's a better idea: compare areas and side lengths.
Figure 1:
- It's a triangle with base 2 (from x=-3 to -1 at y=-4), height 2 (up to y=-2), but not a right triangle?
Wait — actually, plotting:
- Points: (-3,-4), (-1,-4), (-2,-2)
This forms a triangle where:
- From (-3,-4) to (-1,-4): 2 units right
- From (-1,-4) to (-2,-2): 1 left, 2 up
- From (-2,-2) to (-3,-4): 1 left, 2 down
Wait — no, it's not symmetric.
But let’s calculate area using shoelace formula.
Shoelace for Figure 1:
Points: (-3,-4), (-1,-4), (-2,-2), back to (-3,-4)
Sum1 = (-3)(-4) + (-1)(-2) + (-2)(-4) = 12 + 2 + 8 = 22
Sum2 = (-4)(-1) + (-4)(-2) + (-2)(-3) = 4 + 8 + 6 = 18
Area = |22 - 18| / 2 = 4/2 = 2 square units
Figure 2:
Points: (1,5), (2,3), (1,3)
Shoelace:
(1,5), (2,3), (1,3), (1,5)
Sum1 = 1×3 + 2×3 + 1×5 = 3 + 6 + 5 = 14
Sum2 = 5×2 + 3×1 + 3×1 = 10 + 3 + 3 = 16
Area = |14 - 16| / 2 = 2/2 = 1 square unit
✘ Area of Figure 1 = 2, Figure 2 = 1 → Not congruent
But wait — that can't be. Visually, they look the same size.
Wait — did I make a mistake?
Let’s recompute Figure 2:
Points: (1,5), (2,3), (1,3)
List in order:
- (1,5)
- (2,3)
- (1,3)
- back to (1,5)
Shoelace:
Sum1 = (1)(3) + (2)(3) + (1)(5) = 3 + 6 + 5 = 14
Sum2 = (5)(2) + (3)(1) + (3)(1) = 10 + 3 + 3 = 16
Area = |14 - 16| / 2 = 1 → 1 square unit
Figure 1: earlier I got 2.
But let’s recalculate Figure 1:
Points: (-3,-4), (-1,-4), (-2,-2)
Sum1 = (-3)(-4) + (-1)(-2) + (-2)(-4) = 12 + 2 + 8 = 22
Sum2 = (-4)(-1) + (-4)(-2) + (-2)(-3) = 4 + 8 + 6 = 18
Area = |22 - 18| / 2 = 4/2 = 2
But Figure 2 has area 1 → not congruent
But wait — visually, both triangles appear to have the same size?
Wait — let's count the grid.
Figure 2:
- From (1,5) to (2,3): down 2, right 1
- From (2,3) to (1,3): left 1
- From (1,3) to (1,5): up 2
So it's a triangle with base 1 and height 2 → area = (1 × 2)/2 = 1
Figure 1:
- Base from (-3,-4) to (-1,-4): length 2
- Height from y=-4 to y=-2: 2 units, but apex is at (-2,-2), which is above the base
So it's a triangle with base 2, height 2 → area = (2 × 2)/2 = 2
So yes — areas differ: 2 vs 1 → not congruent
But wait — that can’t be right because the green triangle looks larger than orange?
Wait — actually, looking at the image:
- Figure 1 (green): bottom at y=-4, top at y=-2 → height 2
- Width: from x=-3 to x=-1 → width 2
- But it's not a full triangle; it's a triangle with vertices at (-3,-4), (-1,-4), (-2,-2)
This is a triangle with base 2 and height 2, but the apex is centered → area = (base × height)/2 = (2 × 2)/2 = 2
Figure 2 (orange): points (1,5), (2,3), (1,3)
- This is a triangle with base from (1,3) to (2,3): length 1
- Height from y=3 to y=5: 2 units → area = (1 × 2)/2 = 1
So areas are different → not congruent
But wait — the orange triangle looks like it might be the same size?
Wait — let’s measure the sides.
Figure 1:
- AB = 2
- AC = √[(−2+3)² + (−2+4)²] = √[1 + 4] = √5
- BC = √[(−1+2)² + (−4+2)²] = √[1 + 4] = √5
So sides: 2, √5, √5
Figure 2:
- DF = 2 (vertical)
- EF = 1 (horizontal)
- DE = √[(2−1)² + (3−5)²] = √[1 + 4] = √5
So sides: 2, 1, √5 → different from Figure 1
So not congruent
But wait — could it be rotated?
No, because side lengths don't match.
Therefore:
> ✘ Not congruent — different side lengths and areas.
But wait — maybe I misidentified the vertices?
Let’s double-check the orange triangle.
From the image: Figure 2 is a triangle pointing upward-right, with:
- Top vertex at (1,5)
- Bottom-left at (1,3)
- Bottom-right at (2,3)
So yes — it's a right triangle with legs 2 (vertical) and 1 (horizontal) → area = 1
Green triangle: base 2, height 2, but not a right triangle — it's isosceles with two equal sides of √5 and base 2 → area = 2
So not congruent
> ✔ Answer: The figures are not congruent because they have different sizes (different areas and side lengths). Figure 1 has area 2, Figure 2 has area 1.
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Figures:
- Figure 1: Green triangle with vertices at (1,5), (3,5), (2,2)
- Figure 2: Orange triangle with vertices at (-2,-3), (-1,-5), (-3,-5)
#### ✔ Step 1: Are they congruent?
Let’s compute side lengths.
Figure 1:
- A(1,5), B(3,5), C(2,2)
- AB = 2 units (horizontal)
- AC = √[(2-1)² + (2-5)²] = √[1 + 9] = √10
- BC = √[(3-2)² + (5-2)²] = √[1 + 9] = √10
So: sides 2, √10, √10 → isosceles
Figure 2:
- D(-2,-3), E(-1,-5), F(-3,-5)
- DE = √[(-1+2)² + (-5+3)²] = √[1 + 4] = √5
- DF = √[(-3+2)² + (-5+3)²] = √[1 + 4] = √5
- EF = |-1 - (-3)| = 2 units
So sides: 2, √5, √5 → different from Figure 1
Wait — not matching.
But wait — maybe I have the wrong points.
Let’s look carefully:
Figure 2: orange triangle at bottom left
- Left vertex: (-3,-5)
- Right vertex: (-1,-5)
- Top vertex: (-2,-3)
So:
- D(-3,-5), E(-1,-5), F(-2,-3)
Now:
- DE = 2 units (horizontal)
- DF = √[(-2+3)² + (-3+5)²] = √[1 + 4] = √5
- EF = √[(-1+2)² + (-5+3)²] = √[1 + 4] = √5
So sides: 2, √5, √5
But Figure 1 has sides: 2, √10, √10
→ Not the same → not congruent
But wait — areas?
Figure 1: base 2, height 3 → area = (2 × 3)/2 = 3
Figure 2: base 2, height 2 → area = (2 × 2)/2 = 2 → different
So not congruent
Wait — but visually, they look similar?
Wait — Figure 1 has height from y=2 to y=5 → 3 units
Figure 2 has height from y=-5 to y=-3 → 2 units
So different sizes → not congruent
> ✔ Answer: The figures are not congruent because they have different sizes (different side lengths and areas).
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Figures:
- Figure 1: Green L-shape at bottom right: vertices at (1,-5), (1,-3), (2,-3), (2,-1), (3,-1), (3,-2), (1,-2)? Wait — better to trace.
From image:
- Figure 1: green shape with blocks at:
- (1,-5), (2,-5), (3,-5)
- (1,-4), (2,-4)
- (1,-3), (2,-3)
- (1,-2), (2,-2)
- (1,-1), (2,-1)
- (3,-1)
Wait — actually, looking at the image:
- Vertical column from (1,-5) to (1,-1): 5 units
- Then at (2,-5), (2,-4), (2,-3), (2,-2), (2,-1): 5 units
- Then at (3,-1): one block
So total: 5 + 5 + 1 = 11 squares?
Wait — let’s count:
- Column at x=1: y=-5 to -1 → 5 blocks
- Column at x=2: y=-5 to -1 → 5 blocks
- Block at (3,-1) → 1 block
Total: 11 blocks
But Figure 2: orange shape at top left
- x=-5 to -2: y=4 to 5
- Blocks:
- (-5,4), (-4,4), (-3,4), (-2,4)
- (-5,5), (-4,5), (-3,5), (-2,5)
- (-3,5) already counted
- And (-3,4) etc.
Wait — let’s count:
- Row y=5: x=-5 to -2 → 4 blocks
- Row y=4: x=-5 to -2 → 4 blocks
- Row y=3: only x=-3 → 1 block
Total: 4 + 4 + 1 = 9 blocks
But Figure 1 has more blocks.
Wait — no, let’s recount Figure 1:
From image:
- Figure 1: green shape
- Vertical line at x=1: y=-5, -4, -3, -2, -1 → 5 blocks
- Vertical line at x=2: y=-5, -4, -3, -2, -1 → 5 blocks
- One block at (3,-1)
Total: 5 + 5 + 1 = 11 blocks
Figure 2: orange shape
- Row y=5: x=-5, -4, -3, -2 → 4
- Row y=4: x=-5, -4, -3, -2 → 4
- Row y=3: x=-3 → 1
- Total: 9 blocks
So different number of blocks → not congruent
But wait — maybe I miscounted.
Wait — Figure 2 has:
- ( -5,5), (-4,5), (-3,5), (-2,5) → 4
- ( -5,4), (-4,4), (-3,4), (-2,4) → 4
- ( -3,3) → 1
- Total: 9
Figure 1:
- (1,-5), (1,-4), (1,-3), (1,-2), (1,-1) → 5
- (2,-5), (2,-4), (2,-3), (2,-2), (2,-1) → 5
- (3,-1) → 1
- Total: 11
So not congruent due to different sizes.
But wait — perhaps they are supposed to be the same?
Wait — maybe Figure 1 is missing something.
Wait — no, based on the image, Figure 1 has 11 blocks, Figure 2 has 9 → not congruent
But let’s double-check the image.
Wait — actually, in Figure 1, is (3,-1) the only extra? Yes.
But in Figure 2, is there a block at (-3,3)? Yes.
So 9 vs 11 → not congruent
> ✔ Answer: The figures are not congruent because they have different numbers of unit squares (11 vs 9), so they are not the same size.
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Problem 1 (Top Left):
- Congruent? Yes
- Transformation: Translate Figure 1 by (x – 4, y – 2)
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Problem 2 (Top Right):
- Congruent? No
- Reason: Different side lengths and areas (2 vs 1). Figure 1 has sides 2, √5, √5; Figure 2 has sides 2, 1, √5.
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Problem 3 (Bottom Left):
- Congruent? No
- Reason: Different side lengths and areas. Figure 1 has sides 2, √10, √10; Figure 2 has sides 2, √5, √5.
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Problem 4 (Bottom Right):
- Congruent? No
- Reason: Different numbers of unit squares (11 vs 9), so not the same size.
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Let me know if you'd like this formatted for printing or want diagrams added.
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🔷 Problem 1 (Top Left)
Figures:
- Figure 1: Green L-shaped figure with vertices at (1,4), (1,2), (3,2), (3,1), (2,1)
- Figure 2: Orange L-shaped figure with vertices at (-3,2), (-3,0), (-1,0), (-1,-1), (-2,-1)
#### ✔ Step 1: Are they congruent?
Both are L-shaped figures made of 5 unit squares. They have the same shape and size — just positioned differently.
✔ Yes, they are congruent.
#### ✔ Step 2: Transformation from Figure 1 to Figure 2
We can compare corresponding points:
- (1,4) → (-3,2): Δx = -4, Δy = -2
- (1,2) → (-3,0): Δx = -4, Δy = -2
- (3,2) → (-1,0): Δx = -4, Δy = -2
- (3,1) → (-1,-1): Δx = -4, Δy = -2
- (2,1) → (-2,-1): Δx = -4, Δy = -2
All points shift by (-4, -2).
👉 So, the transformation is a translation of 4 units left and 2 units down.
> ✔ Answer: The figures are congruent.
> Transformation: Translate Figure 1 by (x – 4, y – 2) to map it onto Figure 2.
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🔷 Problem 2 (Top Right)
Figures:
- Figure 1: Green triangle with vertices at (-3,-4), (-1,-4), (-2,-2)
- Figure 2: Orange triangle with vertices at (1,5), (2,3), (1,3)
#### ✔ Step 1: Are they congruent?
Let’s check side lengths:
Figure 1:
- A(-3,-4), B(-1,-4), C(-2,-2)
- AB = 2 units (horizontal)
- AC = √[(-2+3)² + (-2+4)²] = √[1 + 4] = √5
- BC = √[(-1+2)² + (-4+2)²] = √[1 + 4] = √5
So it's an isosceles triangle with sides: 2, √5, √5
Figure 2:
- D(1,5), E(2,3), F(1,3)
- DE = √[(2-1)² + (3-5)²] = √[1 + 4] = √5
- DF = 2 units (vertical)
- EF = √[(2-1)² + (3-3)²] = 1? Wait: (2,3) to (1,3) = 1 unit horizontally.
Wait — this seems inconsistent.
Wait! Let's list the correct vertices:
Looking closely:
- Figure 2: (1,5), (2,3), (1,3)
- So: D(1,5), E(2,3), F(1,3)
Now compute:
- DE: √[(2-1)² + (3-5)²] = √[1 + 4] = √5
- DF: |5 - 3| = 2 (vertical)
- EF: |2 - 1| = 1 (horizontal)
But wait — this gives sides: 2, 1, √5 — which is not the same as Figure 1 (which had 2, √5, √5).
But let's double-check the shapes.
Actually, both triangles appear to be right triangles with legs of length 2 and 2?
Wait — let’s re-express:
Figure 1:
- From (-3,-4) to (-1,-4): horizontal leg = 2
- From (-1,-4) to (-2,-2): not vertical or horizontal
Wait — better to plot or calculate distances.
Let me do exact calculations:
Figure 1:
- A(-3,-4), B(-1,-4), C(-2,-2)
- AB: distance = √[(-1+3)² + (-4+4)²] = √[4] = 2
- AC: √[(-2+3)² + (-2+4)²] = √[1 + 4] = √5
- BC: √[(-1+2)² + (-4+2)²] = √[1 + 4] = √5
So sides: 2, √5, √5 → isosceles
Figure 2:
- D(1,5), E(2,3), F(1,3)
- DF: from (1,5) to (1,3): vertical = 2 units
- EF: from (2,3) to (1,3): horizontal = 1 unit
- DE: √[(2-1)² + (3-5)²] = √[1 + 4] = √5
Sides: 2, 1, √5 → different from Figure 1
But wait — this suggests not congruent?
But visually, they look similar.
Wait — maybe I misread the coordinates.
Look again:
Figure 2 has points:
- (1,5), (2,3), (1,3)
Wait — (1,5) to (1,3) = 2 units down
- (1,3) to (2,3) = 1 unit right
- (2,3) to (1,5): diagonal
But Figure 1:
- (-3,-4) to (-1,-4): 2 units right
- (-1,-4) to (-2,-2): up-left
- (-2,-2) to (-3,-4): down-left
Wait — actually, let’s see if there's a rotation or reflection.
Try comparing angles.
Alternatively, try to see if one is a rotation/reflection of the other.
Let’s suppose we rotate Figure 1 90° clockwise around origin.
But better: let's consider possible transformation.
Wait — notice that both seem to be right triangles?
Let’s check angles.
In Figure 1:
- At point B(-1,-4): vectors BA = (-2,0), BC = (-1,2)
- Dot product: (-2)(-1) + (0)(2) = 2 ≠ 0 → not right angle
Wait — maybe not.
Alternatively, perhaps I should count grid squares.
But here's a better idea: compare areas and side lengths.
Figure 1:
- It's a triangle with base 2 (from x=-3 to -1 at y=-4), height 2 (up to y=-2), but not a right triangle?
Wait — actually, plotting:
- Points: (-3,-4), (-1,-4), (-2,-2)
This forms a triangle where:
- From (-3,-4) to (-1,-4): 2 units right
- From (-1,-4) to (-2,-2): 1 left, 2 up
- From (-2,-2) to (-3,-4): 1 left, 2 down
Wait — no, it's not symmetric.
But let’s calculate area using shoelace formula.
Shoelace for Figure 1:
Points: (-3,-4), (-1,-4), (-2,-2), back to (-3,-4)
Sum1 = (-3)(-4) + (-1)(-2) + (-2)(-4) = 12 + 2 + 8 = 22
Sum2 = (-4)(-1) + (-4)(-2) + (-2)(-3) = 4 + 8 + 6 = 18
Area = |22 - 18| / 2 = 4/2 = 2 square units
Figure 2:
Points: (1,5), (2,3), (1,3)
Shoelace:
(1,5), (2,3), (1,3), (1,5)
Sum1 = 1×3 + 2×3 + 1×5 = 3 + 6 + 5 = 14
Sum2 = 5×2 + 3×1 + 3×1 = 10 + 3 + 3 = 16
Area = |14 - 16| / 2 = 2/2 = 1 square unit
✘ Area of Figure 1 = 2, Figure 2 = 1 → Not congruent
But wait — that can't be. Visually, they look the same size.
Wait — did I make a mistake?
Let’s recompute Figure 2:
Points: (1,5), (2,3), (1,3)
List in order:
- (1,5)
- (2,3)
- (1,3)
- back to (1,5)
Shoelace:
Sum1 = (1)(3) + (2)(3) + (1)(5) = 3 + 6 + 5 = 14
Sum2 = (5)(2) + (3)(1) + (3)(1) = 10 + 3 + 3 = 16
Area = |14 - 16| / 2 = 1 → 1 square unit
Figure 1: earlier I got 2.
But let’s recalculate Figure 1:
Points: (-3,-4), (-1,-4), (-2,-2)
Sum1 = (-3)(-4) + (-1)(-2) + (-2)(-4) = 12 + 2 + 8 = 22
Sum2 = (-4)(-1) + (-4)(-2) + (-2)(-3) = 4 + 8 + 6 = 18
Area = |22 - 18| / 2 = 4/2 = 2
But Figure 2 has area 1 → not congruent
But wait — visually, both triangles appear to have the same size?
Wait — let's count the grid.
Figure 2:
- From (1,5) to (2,3): down 2, right 1
- From (2,3) to (1,3): left 1
- From (1,3) to (1,5): up 2
So it's a triangle with base 1 and height 2 → area = (1 × 2)/2 = 1
Figure 1:
- Base from (-3,-4) to (-1,-4): length 2
- Height from y=-4 to y=-2: 2 units, but apex is at (-2,-2), which is above the base
So it's a triangle with base 2, height 2 → area = (2 × 2)/2 = 2
So yes — areas differ: 2 vs 1 → not congruent
But wait — that can’t be right because the green triangle looks larger than orange?
Wait — actually, looking at the image:
- Figure 1 (green): bottom at y=-4, top at y=-2 → height 2
- Width: from x=-3 to x=-1 → width 2
- But it's not a full triangle; it's a triangle with vertices at (-3,-4), (-1,-4), (-2,-2)
This is a triangle with base 2 and height 2, but the apex is centered → area = (base × height)/2 = (2 × 2)/2 = 2
Figure 2 (orange): points (1,5), (2,3), (1,3)
- This is a triangle with base from (1,3) to (2,3): length 1
- Height from y=3 to y=5: 2 units → area = (1 × 2)/2 = 1
So areas are different → not congruent
But wait — the orange triangle looks like it might be the same size?
Wait — let’s measure the sides.
Figure 1:
- AB = 2
- AC = √[(−2+3)² + (−2+4)²] = √[1 + 4] = √5
- BC = √[(−1+2)² + (−4+2)²] = √[1 + 4] = √5
So sides: 2, √5, √5
Figure 2:
- DF = 2 (vertical)
- EF = 1 (horizontal)
- DE = √[(2−1)² + (3−5)²] = √[1 + 4] = √5
So sides: 2, 1, √5 → different from Figure 1
So not congruent
But wait — could it be rotated?
No, because side lengths don't match.
Therefore:
> ✘ Not congruent — different side lengths and areas.
But wait — maybe I misidentified the vertices?
Let’s double-check the orange triangle.
From the image: Figure 2 is a triangle pointing upward-right, with:
- Top vertex at (1,5)
- Bottom-left at (1,3)
- Bottom-right at (2,3)
So yes — it's a right triangle with legs 2 (vertical) and 1 (horizontal) → area = 1
Green triangle: base 2, height 2, but not a right triangle — it's isosceles with two equal sides of √5 and base 2 → area = 2
So not congruent
> ✔ Answer: The figures are not congruent because they have different sizes (different areas and side lengths). Figure 1 has area 2, Figure 2 has area 1.
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🔷 Problem 3 (Bottom Left)
Figures:
- Figure 1: Green triangle with vertices at (1,5), (3,5), (2,2)
- Figure 2: Orange triangle with vertices at (-2,-3), (-1,-5), (-3,-5)
#### ✔ Step 1: Are they congruent?
Let’s compute side lengths.
Figure 1:
- A(1,5), B(3,5), C(2,2)
- AB = 2 units (horizontal)
- AC = √[(2-1)² + (2-5)²] = √[1 + 9] = √10
- BC = √[(3-2)² + (5-2)²] = √[1 + 9] = √10
So: sides 2, √10, √10 → isosceles
Figure 2:
- D(-2,-3), E(-1,-5), F(-3,-5)
- DE = √[(-1+2)² + (-5+3)²] = √[1 + 4] = √5
- DF = √[(-3+2)² + (-5+3)²] = √[1 + 4] = √5
- EF = |-1 - (-3)| = 2 units
So sides: 2, √5, √5 → different from Figure 1
Wait — not matching.
But wait — maybe I have the wrong points.
Let’s look carefully:
Figure 2: orange triangle at bottom left
- Left vertex: (-3,-5)
- Right vertex: (-1,-5)
- Top vertex: (-2,-3)
So:
- D(-3,-5), E(-1,-5), F(-2,-3)
Now:
- DE = 2 units (horizontal)
- DF = √[(-2+3)² + (-3+5)²] = √[1 + 4] = √5
- EF = √[(-1+2)² + (-5+3)²] = √[1 + 4] = √5
So sides: 2, √5, √5
But Figure 1 has sides: 2, √10, √10
→ Not the same → not congruent
But wait — areas?
Figure 1: base 2, height 3 → area = (2 × 3)/2 = 3
Figure 2: base 2, height 2 → area = (2 × 2)/2 = 2 → different
So not congruent
Wait — but visually, they look similar?
Wait — Figure 1 has height from y=2 to y=5 → 3 units
Figure 2 has height from y=-5 to y=-3 → 2 units
So different sizes → not congruent
> ✔ Answer: The figures are not congruent because they have different sizes (different side lengths and areas).
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🔷 Problem 4 (Bottom Right)
Figures:
- Figure 1: Green L-shape at bottom right: vertices at (1,-5), (1,-3), (2,-3), (2,-1), (3,-1), (3,-2), (1,-2)? Wait — better to trace.
From image:
- Figure 1: green shape with blocks at:
- (1,-5), (2,-5), (3,-5)
- (1,-4), (2,-4)
- (1,-3), (2,-3)
- (1,-2), (2,-2)
- (1,-1), (2,-1)
- (3,-1)
Wait — actually, looking at the image:
- Vertical column from (1,-5) to (1,-1): 5 units
- Then at (2,-5), (2,-4), (2,-3), (2,-2), (2,-1): 5 units
- Then at (3,-1): one block
So total: 5 + 5 + 1 = 11 squares?
Wait — let’s count:
- Column at x=1: y=-5 to -1 → 5 blocks
- Column at x=2: y=-5 to -1 → 5 blocks
- Block at (3,-1) → 1 block
Total: 11 blocks
But Figure 2: orange shape at top left
- x=-5 to -2: y=4 to 5
- Blocks:
- (-5,4), (-4,4), (-3,4), (-2,4)
- (-5,5), (-4,5), (-3,5), (-2,5)
- (-3,5) already counted
- And (-3,4) etc.
Wait — let’s count:
- Row y=5: x=-5 to -2 → 4 blocks
- Row y=4: x=-5 to -2 → 4 blocks
- Row y=3: only x=-3 → 1 block
Total: 4 + 4 + 1 = 9 blocks
But Figure 1 has more blocks.
Wait — no, let’s recount Figure 1:
From image:
- Figure 1: green shape
- Vertical line at x=1: y=-5, -4, -3, -2, -1 → 5 blocks
- Vertical line at x=2: y=-5, -4, -3, -2, -1 → 5 blocks
- One block at (3,-1)
Total: 5 + 5 + 1 = 11 blocks
Figure 2: orange shape
- Row y=5: x=-5, -4, -3, -2 → 4
- Row y=4: x=-5, -4, -3, -2 → 4
- Row y=3: x=-3 → 1
- Total: 9 blocks
So different number of blocks → not congruent
But wait — maybe I miscounted.
Wait — Figure 2 has:
- ( -5,5), (-4,5), (-3,5), (-2,5) → 4
- ( -5,4), (-4,4), (-3,4), (-2,4) → 4
- ( -3,3) → 1
- Total: 9
Figure 1:
- (1,-5), (1,-4), (1,-3), (1,-2), (1,-1) → 5
- (2,-5), (2,-4), (2,-3), (2,-2), (2,-1) → 5
- (3,-1) → 1
- Total: 11
So not congruent due to different sizes.
But wait — perhaps they are supposed to be the same?
Wait — maybe Figure 1 is missing something.
Wait — no, based on the image, Figure 1 has 11 blocks, Figure 2 has 9 → not congruent
But let’s double-check the image.
Wait — actually, in Figure 1, is (3,-1) the only extra? Yes.
But in Figure 2, is there a block at (-3,3)? Yes.
So 9 vs 11 → not congruent
> ✔ Answer: The figures are not congruent because they have different numbers of unit squares (11 vs 9), so they are not the same size.
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✔ Final Answers Summary:
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Problem 1 (Top Left):
- Congruent? Yes
- Transformation: Translate Figure 1 by (x – 4, y – 2)
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Problem 2 (Top Right):
- Congruent? No
- Reason: Different side lengths and areas (2 vs 1). Figure 1 has sides 2, √5, √5; Figure 2 has sides 2, 1, √5.
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Problem 3 (Bottom Left):
- Congruent? No
- Reason: Different side lengths and areas. Figure 1 has sides 2, √10, √10; Figure 2 has sides 2, √5, √5.
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Problem 4 (Bottom Right):
- Congruent? No
- Reason: Different numbers of unit squares (11 vs 9), so not the same size.
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Parent Tip: Review the logic above to help your child master the concept of congruent transformations worksheet.