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7 2MomentumConservationProblemsCP.pdf - Name Date Period Worksheet ... - Free Printable

7 2MomentumConservationProblemsCP.pdf - Name Date Period Worksheet ...

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Show Answer Key & Explanations Step-by-step solution for: 7 2MomentumConservationProblemsCP.pdf - Name Date Period Worksheet ...
Let’s solve each problem step by step.

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Problem 1:
Two trains (one freight, one passenger) collide and couple. Find final velocity.

Given:
- Freight train: mass = 5000 kg, velocity = +2 m/s (let’s say to the right is positive)
- Passenger train: mass = 3000 kg, velocity = -4 m/s (to the left)

They stick together → inelastic collision → use conservation of momentum.

Total initial momentum = total final momentum

Initial momentum:
= (mass_freight × velocity_freight) + (mass_passenger × velocity_passenger)
= (5000 × 2) + (3000 × (-4))
= 10,000 – 12,000
= -2000 kg·m/s

Final combined mass = 5000 + 3000 = 8000 kg

Let final velocity = v

So:
8000 × v = -2000
→ v = -2000 / 8000 = -0.25 m/s

Negative means they move to the left after collision.

Final Answer for Problem 1: -0.25 m/s

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Problem 2:
A 2 kg object moving at 6 m/s hits a stationary 4 kg object. After collision, first object moves at 2 m/s. What’s speed of second object?

This is also conservation of momentum.

Initial momentum:
= (2 kg × 6 m/s) + (4 kg × 0 m/s) = 12 kg·m/s

After collision:
First object: 2 kg × 2 m/s = 4 kg·m/s
Second object: let its velocity be v → 4 kg × v

Total final momentum = 4 + 4v

Set equal to initial:
4 + 4v = 12
→ 4v = 8
→ v = 2 m/s

Final Answer for Problem 2: 2 m/s

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Problem 3:
Football player (80 kg) running at 5 m/s tackles referee (70 kg) standing still. They fall together. What’s their velocity?

Again, conservation of momentum — inelastic collision.

Initial momentum:
= (80 × 5) + (70 × 0) = 400 kg·m/s

Combined mass = 80 + 70 = 150 kg

Final velocity = v

150 × v = 400
→ v = 400 / 150 ≈ 2.666... m/s

We can write as fraction: 400 ÷ 150 = 8/3 ≈ 2.67 m/s (rounded to two decimals)

But since the problem says “round to nearest tenth”, we do:

400 ÷ 150 = 2.666... → rounds to 2.7 m/s

Wait — let me check rounding rule:
2.666... → look at hundredths place (6), which is ≥5 → round up tenths place from 6 to 7 → yes, 2.7 m/s

Final Answer for Problem 3: 2.7 m/s

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Final Answer:
Problem 1: -0.25 m/s
Problem 2: 2 m/s
Problem 3: 2.7 m/s
Parent Tip: Review the logic above to help your child master the concept of conservation of momentum worksheet.
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