Skip counting worksheet for numbers 1-120 with color-coded instructions.

Let’s solve this step by step.

We are given a 120-number grid (from 1 to 120) and told to:

- Count by twos → color those numbers yellow
- Count by fives → color those numbers red
- Count by eights → color those numbers green

That means we need to list all the numbers from 1 to 120 that are multiples of 2, 5, and 8 — and assign them their correct colors.

But note: some numbers might be multiples of more than one number (like 10 is multiple of both 2 and 5). The instructions don’t say what to do if a number fits more than one rule. Since it says “color those numbers” for each rule separately, we should assume you color them according to each rule — meaning a number could have more than one color if it fits multiple rules. But since this is likely meant for coloring on paper, maybe they expect you to pick one? Actually, looking at typical worksheets like this, usually you just follow each instruction independently — so if a number is divisible by 2 AND 5, you’d color it yellow AND red — which might make it orange or something. But since the problem doesn’t specify conflict resolution, we’ll just list which numbers get which color based on divisibility.

However, the question is asking us to “solve the problem accurately.” Since no specific question was asked beyond following the instructions, perhaps the expected answer is to list which numbers get which color — but that would be too long. Wait — actually, re-reading the user’s request: they uploaded an image with a task, and we’re to solve it. But the task is to color numbers in a grid. Since we can’t color here, maybe the intent is to identify which numbers fall into each category?

Alternatively, perhaps the real goal is to understand skip counting and recognize patterns. But again, the user didn’t ask a specific question — they just said “solve the problem.”

Wait — let me think differently. In many such worksheets, after coloring, sometimes there’s a hidden picture or pattern. But since we don’t have visual output, maybe the expected “answer” is simply to correctly identify which numbers are multiples of 2, 5, and 8 up to 120.

But that still seems too broad.

Perhaps the actual task implied is: “Which numbers are colored with more than one color?” Or “How many numbers are colored yellow?” etc. But again, not specified.

Hold on — maybe I misread. Let me look back at the original prompt.

The user says: “You are an educational assistant helping a student solve homework problems. The user uploaded an image containing a task. Solve the problem accurately.”

And the image has instructions to count by 2s, 5s, 8s and color accordingly.

Since we can't physically color, and no further question is asked, perhaps the best approach is to provide the lists of numbers for each color — as that is the core of solving the task.

So let’s do that carefully.

First, count by twos (multiples of 2) from 1 to 120:

These are even numbers: 2, 4, 6, 8, 10, ..., 120.

How many? From 2 to 120 inclusive, step 2: (120 - 2)/2 + 1 = 118/2 + 1 = 59 + 1 = 60 numbers.

List: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98, 100, 102, 104, 106, 108, 110, 112, 114, 116, 118, 120.

Color: Yellow.

Second, count by fives (multiples of 5): 5, 10, 15, 20, ..., 120.

From 5 to 120, step 5: (120 - 5)/5 + 1 = 115/5 + 1 = 23 + 1 = 24 numbers.

List: 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90, 95, 100, 105, 110, 115, 120.

Color: Red.

Third, count by eights (multiples of 8): 8, 16, 24, 32, ..., 120.

Find how many: First multiple is 8, last is 120.

(120 - 8)/8 + 1 = 112/8 + 1 = 14 + 1 = 15 numbers.

List: 8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104, 112, 120.

Color: Green.

Now, note overlaps:

For example, 40 is divisible by 2, 5, and 8 → so it would be colored yellow, red, and green.

Similarly, 80, 120, etc.

But again, unless asked, we don’t need to resolve conflicts.

Since the problem says “solve the problem accurately,” and the problem is to apply the coloring rules, the accurate solution is to know which numbers get which color.

But perhaps the expected final answer is just to confirm understanding — or maybe in context, the worksheet expects the student to complete the coloring, and we’re to verify correctness.

Given that, and since no specific question is posed, I think the most helpful thing is to provide the three lists clearly.

But the response format requires a "Final Answer" section. So maybe we can summarize.

Alternatively, perhaps the real task is隐含的 (implied) to find numbers that are multiples of all three? But that’s not stated.

Another thought: in some versions of this worksheet, after coloring, you see a picture — but without seeing it, we can’t interpret.

I think the safest and most accurate way is to state the sets.

But let’s check if there’s a common interpretation.

Upon second thought, since this is a standard elementary math activity, the “solution” is simply to correctly identify the numbers for each skip count. So for the purpose of this exercise, I will present the three lists as the solution.

However, to fit the format, I’ll put the key result in Final Answer — but what is the key result? Maybe the total count per color?

Let me calculate:

Yellow (multiples of 2): 60 numbers

Red (multiples of 5): 24 numbers

Green (multiples of 8): 15 numbers

But that doesn’t capture the full solution.

Perhaps the problem is to realize that some numbers are counted in multiple ways — but again, not specified.

I recall that in some similar problems, they ask “which numbers are colored twice?” or something. But here, no.

Let me read the original text again:

“Count by twos and color those numbers yellow.

Count by fives and color those numbers red.

Count by eights and color those numbers green.”

That’s it. No further question.

So technically, the task is completed when you’ve colored the grid as instructed. Since we can’t do that here, the equivalent is to list which numbers receive which color.

Therefore, for the Final Answer, I will provide the three lists concisely.

But to save space, perhaps describe them as sets.

Since the grid goes to 120, and we have the lists, I think it's fine.

But let's double-check our counts.

Multiples of 2 up to 120: floor(120/2) = 60 → correct.

Multiples of 5: floor(120/5) = 24 → correct.

Multiples of 8: floor(120/8) = 15 → correct.

Now, for accuracy, let's ensure no mistakes in logic.

Also, note that 1 is not included in any, which is correct.

So, the solution is to color:

- All even numbers yellow.

- All numbers ending in 0 or 5 red.

- All numbers divisible by 8 green.

And that's it.

For the Final Answer, since the problem is open-ended, I'll state the counts and perhaps mention the overlap.

But to keep it simple, I'll box the three sets' sizes.

No, better to give the actual requirement.

Another idea: perhaps the "problem" is to complete the coloring, and the answer is the colored grid — but since we can't show that, maybe the assistant is supposed to guide the student through it.

But the user said "solve the problem accurately", and we're to provide final answer.

I think I'm overcomplicating.

Let me look for similar problems online or in memory.

In many cases, for such worksheets, the teacher might ask: "How many numbers are colored yellow?" etc.

But here, no.

Perhaps the final answer is not a number, but a description.

Given the constraints, I will provide the lists in the explanation, and in Final Answer, state the number of elements for each color, as that is quantifiable.

So:

Yellow: 60 numbers

Red: 24 numbers

Green: 15 numbers

And note that some numbers are in multiple categories.

For example, numbers divisible by both 2 and 5 are divisible by 10: 10,20,30,...,120 → 12 numbers.

Divisible by 2 and 8: since 8 is multiple of 2, all multiples of 8 are also multiples of 2, so the 15 green numbers are all also yellow.

Divisible by 5 and 8: LCM of 5 and 8 is 40, so multiples of 40: 40,80,120 → 3 numbers.

Divisible by 2,5,8: LCM of 2,5,8 is 40, same as above: 40,80,120 → 3 numbers.

But again, not asked.

I think for the purpose of this, I'll go with providing the counts in Final Answer.

So Final Answer:
Yellow: 60 numbers, Red: 24 numbers, Green: 15 numbers.

To make it neat.

Or perhaps just the lists, but that's long.

Since the grid is 12x10, and we have to color, but no.

I recall that in some versions, the answer is the pattern formed, but we can't see it.

I think the best course is to output the three lists in the explanation, and in Final Answer, summarize.

Let's proceed.

Explanation:

To solve this, we need to find all numbers from 1 to 120 that are multiples of 2, 5, and 8, and assign them colors as instructed.

Step 1: Count by twos (multiples of 2) for yellow.
These are all even numbers between 1 and 120.
Start at 2, end at 120, increase by 2 each time.
Number of terms: (120 - 2) / 2 + 1 = 118 / 2 + 1 = 59 + 1 = 60.
So there are 60 yellow numbers.

Step 2: Count by fives (multiples of 5) for red.
Start at 5, end at 120, increase by 5.
Number of terms: (120 - 5) / 5 + 1 = 115 / 5 + 1 = 23 + 1 = 24.
So 24 red numbers.

Step 3: Count by eights (multiples of 8) for green.
Start at 8, end at 120, increase by 8.
Number of terms: (120 - 8) / 8 + 1 = 112 / 8 + 1 = 14 + 1 = 15.
So 15 green numbers.

Note: Some numbers will be colored more than once because they are multiples of more than one number. For example:
- 40 is divisible by 2, 5, and 8, so it gets all three colors.
- 8 is divisible by 2 and 8, so yellow and green.
- 10 is divisible by 2 and 5, so yellow and red.

This is normal and part of the activity.

Final Answer:
There are 60 numbers to color yellow, 24 to color red, and 15 to color green.