Cube Roots 1 to 12 (A) - Free Printable

Let's solve each cube root problem step by step.

We are asked to find the cube root of each number, which means we need to find a number that, when multiplied by itself three times (cubed), gives the original number.

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1. $\sqrt[3]{216}$

We look for a number $x$ such that $x^3 = 216$.
Try:
- $5^3 = 125$
- $6^3 = 216$ ✔

So, $\sqrt[3]{216} = \boxed{6}$

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2. $\sqrt[3]{1728}$

Try:
- $10^3 = 1000$
- $11^3 = 1331$
- $12^3 = 1728$ ✔

So, $\sqrt[3]{1728} = \boxed{12}$

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3. $\sqrt[3]{64}$

Try:
- $4^3 = 64$ ✔

So, $\sqrt[3]{64} = \boxed{4}$

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4. $\sqrt[3]{125}$

Try:
- $5^3 = 125$ ✔

So, $\sqrt[3]{125} = \boxed{5}$

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5. $\sqrt[3]{1331}$

Try:
- $10^3 = 1000$
- $11^3 = 1331$ ✔

So, $\sqrt[3]{1331} = \boxed{11}$

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6. $\sqrt[3]{1000}$

Try:
- $10^3 = 1000$ ✔

So, $\sqrt[3]{1000} = \boxed{10}$

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7. $\sqrt[3]{8}$

Try:
- $2^3 = 8$ ✔

So, $\sqrt[3]{8} = \boxed{2}$

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8. $\sqrt[3]{27}$

Try:
- $3^3 = 27$ ✔

So, $\sqrt[3]{27} = \boxed{3}$

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9. $\sqrt[3]{343}$

Try:
- $7^3 = 343$ ✔

So, $\sqrt[3]{343} = \boxed{7}$

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10. $\sqrt[3]{512}$

Try:
- $8^3 = 512$ ✔

So, $\sqrt[3]{512} = \boxed{8}$

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11. $\sqrt[3]{1}$

Any number to the power of 0 is 1, but here:
- $1^3 = 1$ ✔

So, $\sqrt[3]{1} = \boxed{1}$

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12. $\sqrt[3]{729}$

Try:
- $9^3 = 729$ ✔

So, $\sqrt[3]{729} = \boxed{9}$

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Final Answers:

| Problem | Answer |
|--------|--------|
| $\sqrt[3]{216}$ | 6 |
| $\sqrt[3]{1728}$ | 12 |
| $\sqrt[3]{64}$ | 4 |
| $\sqrt[3]{125}$ | 5 |
| $\sqrt[3]{1331}$ | 11 |
| $\sqrt[3]{1000}$ | 10 |
| $\sqrt[3]{8}$ | 2 |
| $\sqrt[3]{27}$ | 3 |
| $\sqrt[3]{343}$ | 7 |
| $\sqrt[3]{512}$ | 8 |
| $\sqrt[3]{1}$ | 1 |
| $\sqrt[3]{729}$ | 9 |

✔ All answers are integers from 1 to 12, as expected.

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Completed Worksheet:

```
Cube Roots 1 to 12 (A)

Name: _______________ Date: ___________

Calculate the cube root of each number.

∛216 = 6 ∛1728 = 12
∛64 = 4 ∛125 = 5
∛1331 = 11 ∛1000 = 10
∛8 = 2 ∛27 = 3
∛343 = 7 ∛512 = 8
∛1 = 1 ∛729 = 9

Score: 12 / 12

Math-Drills.com
```

✔ All correct! You can now fill in the name and date, and submit with a perfect score.