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Step-by-step solution for: Square & Cube Roots - Go Teach Maths: Handcrafted Resources for
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Step-by-step solution for: Square & Cube Roots - Go Teach Maths: Handcrafted Resources for
Let's solve each question from the worksheet "Cubes and Cube Roots" step by step with clear explanations.
---
To find the cube of a number, we multiply it by itself three times.
$$
\left(-\frac{2}{3}\right)^3 = \left(-\frac{2}{3}\right) \times \left(-\frac{2}{3}\right) \times \left(-\frac{2}{3}\right)
$$
First:
$$
\left(-\frac{2}{3}\right) \times \left(-\frac{2}{3}\right) = \frac{4}{9}
$$
Then:
$$
\frac{4}{9} \times \left(-\frac{2}{3}\right) = -\frac{8}{27}
$$
✔ Answer: $-\frac{8}{27}$
---
We compute each cube:
$$
\left(\frac{3}{5}\right)^3 = \frac{27}{125}, \quad \left(\frac{1}{5}\right)^3 = \frac{1}{125}
$$
Now subtract:
$$
\frac{27}{125} - \frac{1}{125} = \frac{26}{125}
$$
✔ Answer: $\frac{26}{125}$
---
Convert decimals to fractions:
- $0.5 = \frac{1}{2}$ → $(0.5)^3 = \left(\frac{1}{2}\right)^3 = \frac{1}{8}$
- $0.2 = \frac{1}{5}$ → $(0.2)^3 = \left(\frac{1}{5}\right)^3 = \frac{1}{125}$
Now add:
$$
\frac{1}{8} + \frac{1}{125}
$$
Find LCM of 8 and 125: $LCM(8, 125) = 1000$
$$
\frac{1}{8} = \frac{125}{1000}, \quad \frac{1}{125} = \frac{8}{1000}
$$
$$
\frac{125}{1000} + \frac{8}{1000} = \frac{133}{1000} = 0.133
$$
✔ Answer: $0.133$ or $\frac{133}{1000}$
---
Volume of a cube = $side^3$
$$
6^3 = 6 \times 6 \times 6 = 216 \text{ cm}^3
$$
✔ Answer: $216 \text{ cm}^3$
---
A unit cube has side 1 cm.
Volume of original cube = $5^3 = 125 \text{ cm}^3$
Each unit cube has volume $1 \text{ cm}^3$, so number of unit cubes = $125$
✔ Answer: $125$
---
We already know:
$$
\left(\frac{3}{5}\right)^3 = \frac{27}{125}
$$
So:
$$
1 + \frac{27}{125} = \frac{125}{125} + \frac{27}{125} = \frac{152}{125}
$$
✔ Answer: $\frac{152}{125}$
---
First, write in prime factorization form:
$$
3 \times 3 \times 3 \times 5 \times 5 \times 7 \times 7 = 3^3 \times 5^2 \times 7^2
$$
For a perfect cube, all exponents must be multiples of 3.
- $3^3$: already good (exponent 3)
- $5^2$: need one more 5 → $5^3$
- $7^2$: need one more 7 → $7^3$
So, multiply by $5 \times 7 = 35$
✔ Answer: $35$
---
Group the factors:
$$
5 \times 5 \times 5 \times 7 \times 7 \times 7 = 5^3 \times 7^3
$$
Now take cube root:
$$
\sqrt[3]{5^3 \times 7^3} = 5 \times 7 = 35
$$
✔ Answer: $35$
---
$$
0.3 = \frac{3}{10}, \quad \left(\frac{3}{10}\right)^3 = \frac{27}{1000} = 0.027
$$
✔ Answer: $0.027$
---
Note: $0.064 = \frac{64}{1000}$
$$
\sqrt[3]{\frac{64}{1000}} = \frac{\sqrt[3]{64}}{\sqrt[3]{1000}} = \frac{4}{10} = 0.4
$$
Because $4^3 = 64$, $10^3 = 1000$
✔ Answer: $0.4$
---
$$
\sqrt[3]{-216} = -6 \quad (\text{since } (-6)^3 = -216)
$$
$$
\sqrt[3]{125} = 5 \quad (\text{since } 5^3 = 125)
$$
So:
$$
-6 - 5 = -11
$$
✔ Answer: $-11$
---
Positive numbers raised to any odd power (like 3) remain positive.
Example: $2^3 = 8 > 0$, $(-2)^3 = -8 < 0$
So cubes of positive numbers are always positive.
✔ Answer: positive
---
Cube root of a positive number is always positive.
Example: $\sqrt[3]{8} = 2$, $\sqrt[3]{27} = 3$
Even for non-perfect cubes, like $\sqrt[3]{10} \approx 2.15$, still positive.
✔ Answer: positive
---
| Q | Answer |
|---|--------|
| 1 | $-\frac{8}{27}$ |
| 2 | $\frac{26}{125}$ |
| 3 | $0.133$ or $\frac{133}{1000}$ |
| 4 | $216 \text{ cm}^3$ |
| 5 | $125$ |
| 6 | $\frac{152}{125}$ |
| 7 | $35$ |
| 8 | $35$ |
| 9 | $0.027$ |
| 10 | $0.4$ |
| 11 | $-11$ |
| 12 | positive |
| 13 | positive |
Let me know if you'd like these explained further!
---
1. Find the cube of $\left(-\frac{2}{3}\right)$.
To find the cube of a number, we multiply it by itself three times.
$$
\left(-\frac{2}{3}\right)^3 = \left(-\frac{2}{3}\right) \times \left(-\frac{2}{3}\right) \times \left(-\frac{2}{3}\right)
$$
First:
$$
\left(-\frac{2}{3}\right) \times \left(-\frac{2}{3}\right) = \frac{4}{9}
$$
Then:
$$
\frac{4}{9} \times \left(-\frac{2}{3}\right) = -\frac{8}{27}
$$
✔ Answer: $-\frac{8}{27}$
---
2. How much is $\left(\frac{3}{5}\right)^3 - \left(\frac{1}{5}\right)^3$?
We compute each cube:
$$
\left(\frac{3}{5}\right)^3 = \frac{27}{125}, \quad \left(\frac{1}{5}\right)^3 = \frac{1}{125}
$$
Now subtract:
$$
\frac{27}{125} - \frac{1}{125} = \frac{26}{125}
$$
✔ Answer: $\frac{26}{125}$
---
3. Simplify and give the answer: $(0.5)^3 + (0.2)^3$
Convert decimals to fractions:
- $0.5 = \frac{1}{2}$ → $(0.5)^3 = \left(\frac{1}{2}\right)^3 = \frac{1}{8}$
- $0.2 = \frac{1}{5}$ → $(0.2)^3 = \left(\frac{1}{5}\right)^3 = \frac{1}{125}$
Now add:
$$
\frac{1}{8} + \frac{1}{125}
$$
Find LCM of 8 and 125: $LCM(8, 125) = 1000$
$$
\frac{1}{8} = \frac{125}{1000}, \quad \frac{1}{125} = \frac{8}{1000}
$$
$$
\frac{125}{1000} + \frac{8}{1000} = \frac{133}{1000} = 0.133
$$
✔ Answer: $0.133$ or $\frac{133}{1000}$
---
4. Find the volume of a cube of side 6 cm.
Volume of a cube = $side^3$
$$
6^3 = 6 \times 6 \times 6 = 216 \text{ cm}^3
$$
✔ Answer: $216 \text{ cm}^3$
---
5. How many unit cubes can be formed by melting a copper cube of side 5 cm?
A unit cube has side 1 cm.
Volume of original cube = $5^3 = 125 \text{ cm}^3$
Each unit cube has volume $1 \text{ cm}^3$, so number of unit cubes = $125$
✔ Answer: $125$
---
6. Simplify $1 + \left(\frac{3}{5}\right)^3$
We already know:
$$
\left(\frac{3}{5}\right)^3 = \frac{27}{125}
$$
So:
$$
1 + \frac{27}{125} = \frac{125}{125} + \frac{27}{125} = \frac{152}{125}
$$
✔ Answer: $\frac{152}{125}$
---
7. If a number is written as $3 \times 3 \times 5 \times 3 \times 5 \times 7 \times 7$, find the smallest number by which this is to be multiplied to form a perfect cube.
First, write in prime factorization form:
$$
3 \times 3 \times 3 \times 5 \times 5 \times 7 \times 7 = 3^3 \times 5^2 \times 7^2
$$
For a perfect cube, all exponents must be multiples of 3.
- $3^3$: already good (exponent 3)
- $5^2$: need one more 5 → $5^3$
- $7^2$: need one more 7 → $7^3$
So, multiply by $5 \times 7 = 35$
✔ Answer: $35$
---
8. Find $\sqrt[3]{5 \times 7 \times 7 \times 5 \times 7 \times 5}$
Group the factors:
$$
5 \times 5 \times 5 \times 7 \times 7 \times 7 = 5^3 \times 7^3
$$
Now take cube root:
$$
\sqrt[3]{5^3 \times 7^3} = 5 \times 7 = 35
$$
✔ Answer: $35$
---
9. $(0.3)^3 = ?$
$$
0.3 = \frac{3}{10}, \quad \left(\frac{3}{10}\right)^3 = \frac{27}{1000} = 0.027
$$
✔ Answer: $0.027$
---
10. Find the value of $\sqrt[3]{0.064}$
Note: $0.064 = \frac{64}{1000}$
$$
\sqrt[3]{\frac{64}{1000}} = \frac{\sqrt[3]{64}}{\sqrt[3]{1000}} = \frac{4}{10} = 0.4
$$
Because $4^3 = 64$, $10^3 = 1000$
✔ Answer: $0.4$
---
11. $\sqrt[3]{-216} - \sqrt[3]{125} = ?$
$$
\sqrt[3]{-216} = -6 \quad (\text{since } (-6)^3 = -216)
$$
$$
\sqrt[3]{125} = 5 \quad (\text{since } 5^3 = 125)
$$
So:
$$
-6 - 5 = -11
$$
✔ Answer: $-11$
---
12. Cubes of positive numbers are always ________.
Positive numbers raised to any odd power (like 3) remain positive.
Example: $2^3 = 8 > 0$, $(-2)^3 = -8 < 0$
So cubes of positive numbers are always positive.
✔ Answer: positive
---
13. Cube roots of positive numbers are always ________.
Cube root of a positive number is always positive.
Example: $\sqrt[3]{8} = 2$, $\sqrt[3]{27} = 3$
Even for non-perfect cubes, like $\sqrt[3]{10} \approx 2.15$, still positive.
✔ Answer: positive
---
✔ Final Answers Summary:
| Q | Answer |
|---|--------|
| 1 | $-\frac{8}{27}$ |
| 2 | $\frac{26}{125}$ |
| 3 | $0.133$ or $\frac{133}{1000}$ |
| 4 | $216 \text{ cm}^3$ |
| 5 | $125$ |
| 6 | $\frac{152}{125}$ |
| 7 | $35$ |
| 8 | $35$ |
| 9 | $0.027$ |
| 10 | $0.4$ |
| 11 | $-11$ |
| 12 | positive |
| 13 | positive |
Let me know if you'd like these explained further!
Parent Tip: Review the logic above to help your child master the concept of cubed roots worksheets.