Let's solve each problem step by step using the density formula and the information provided.
---
Problem 1: Platinum Bar
Given:
- Length = 5.0 cm
- Width = 4.0 cm
- Thickness (height) = 1.5 cm
- Mass = 700.0 grams
####
a. Calculate the volume of the platinum bar.
The platinum bar is a rectangular prism, so its volume is calculated as:
$$
V = \text{length} \times \text{width} \times \text{thickness}
$$
$$
V = 5.0\, \text{cm} \times 4.0\, \text{cm} \times 1.5\, \text{cm}
$$
$$
V = 30.0\, \text{cm}^3
$$
✔ Volume = 30.0 cm³
---
####
b. Calculate the density of the platinum bar.
Use the density formula:
$$
\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{m}{V}
$$
$$
d = \frac{700.0\, \text{g}}{30.0\, \text{cm}^3} = 23.33\, \text{g/cm}^3
$$
✔ Density = 23.3 g/cm³ (rounded to one decimal place)
---
Problem 2: Lead Cylinder
Given:
- Mass = 540 grams
- Density = 2.70 g/mL
We need to find the
volume.
Use the rearranged density formula:
$$
V = \frac{m}{d}
$$
$$
V = \frac{540\, \text{g}}{2.70\, \text{g/mL}} = 200\, \text{mL}
$$
✔ Volume = 200 mL
> Note: 1 mL = 1 cm³, so this is also 200 cm³.
---
✔ Final Answers:
1a. Volume of platinum bar =
30.0 cm³
1b. Density of platinum bar =
23.3 g/cm³
2. Volume of lead cylinder =
200 mL
---
🔍 Explanation Summary:
-
Volume of a rectangular solid = length × width × height.
-
Density = mass ÷ volume → use the triangle method (cover what you want).
- For
unknown volume, rearrange: $ V = m/d $
These problems reinforce understanding of the relationship between mass, volume, and density.
Parent Tip: Review the logic above to help your child master the concept of density problems worksheet with answers.