Dihybrid cross worksheet: Fill out & sign online | DocHub - Free Printable
Educational worksheet: Dihybrid cross worksheet: Fill out & sign online | DocHub. Download and print for classroom or home learning activities.
PNG
770×1024
21.4 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #1705198
⭐
Show Answer Key & Explanations
Step-by-step solution for: Dihybrid cross worksheet: Fill out & sign online | DocHub
▼
Show Answer Key & Explanations
Step-by-step solution for: Dihybrid cross worksheet: Fill out & sign online | DocHub
Let's solve this Dihybrid Cross Worksheet step by step.
---
- Hair color:
- G = gray hair (dominant)
- g = white hair (recessive)
- Eye color:
- B = black eyes (dominant)
- b = red eyes (recessive)
So:
- GG, Gg → gray hair
- gg → white hair
- BB, Bb → black eyes
- bb → red eyes
---
## Question 1: Phenotypes of given genotypes
We are asked to determine the phenotype (observable traits) for each genotype.
1. Ggbb
- Hair: Gg → gray hair (since G is dominant)
- Eyes: bb → red eyes (since b is recessive and homozygous)
- ✔ Gray hair, red eyes
2. ggBB
- Hair: gg → white hair
- Eyes: BB → black eyes
- ✔ White hair, black eyes
3. ggb
- Hair: gg → white hair
- Eyes: bb → red eyes
- ✔ White hair, red eyes
4. GgBb
- Hair: Gg → gray hair
- Eyes: Bb → black eyes
- ✔ Gray hair, black eyes
---
- Ggbb: Gray hair, red eyes
- ggBB: White hair, black eyes
- ggb: White hair, red eyes
- GgBb: Gray hair, black eyes
---
## Question 2: Cross between male GGbb × female ggBb
- Male: GGbb
- Gametes: Since both genes are homozygous, only one type: Gb
- G from hair gene, b from eye gene
- So all sperm: Gb
- Female: ggBb
- Hair: gg → only g
- Eyes: Bb → can be B or b
- So gametes: gB and gb (each with 50% chance)
But since we're doing a Punnett square with 4 boxes, we need to write all possible combinations:
Actually, the male produces only one type of gamete: Gb
The female produces two types: gB and gb, but we must use four boxes as shown in the grid.
Wait — the square has 4 columns labeled Gb, Gb, Gb, Gb → that means the male contributes Gb in all cases.
And rows: gB, gB, gb, gb → so female contributes gB twice and gb twice (to make 4 total).
So we fill the square:
| | Gb | Gb | Gb | Gb |
|-------|--------|--------|--------|--------|
| gB | GgBb | GgBb | GgBb | GgBb |
| gB | GgBb | GgBb | GgBb | GgBb |
| gb | Ggbb | Ggbb | Ggbb | Ggbb |
| gb | Ggbb | Ggbb | Ggbb | Ggbb |
Now let’s count:
- GgBb: appears 8 times → gray fur, black eyes
- Ggbb: appears 8 times → gray fur, red eyes
Wait! But the question asks "How many out of 16" — so we have 16 boxes.
Let’s count:
- GgBb: 8 boxes → gray fur, black eyes
- Ggbb: 8 boxes → gray fur, red eyes
No white fur (because all offspring have G from father, so Gg → gray)
So:
- Gray fur & black eyes: 8/16
- Gray fur & red eyes: 8/16
- White fur & black eyes: 0/16
- White fur & red eyes: 0/16
✔ Answer for Question 2:
- How many out of 16 have gray fur and black eyes? → 8
- How many out of 16 have gray fur and red eyes? → 8
- How many out of 16 have white fur and black eyes? → 0
- How many out of 16 have white fur and red eyes? → 0
---
## Question 3: Cross between GgBb × GgBb
This is a classic dihybrid cross.
Each parent: GgBb
Gametes: All combinations of alleles:
- GB, Gb, gB, gb — each with equal probability (25%)
So we set up a 4×4 Punnett square.
Columns: GB, Gb, gB, gb (from male)
Rows: GB, Gb, gB, gb (from female)
Let’s fill it in:
| | GB | Gb | gB | gb |
|--------|------------|------------|------------|------------|
| GB | GGBB | GGBb | GgBB | GgBb |
| Gb | GGBb | GGbb | GgBb | Ggbb |
| gB | GgBB | GgBb | ggBB | ggBb |
| gb | GgBb | Ggbb | ggBb | ggbb |
Now let’s analyze phenotypes.
We’ll count how many of each phenotype appear.
We go through each box:
1. GGBB → gray, black → ✔
2. GGBb → gray, black → ✔
3. GgBB → gray, black → ✔
4. GgBb → gray, black → ✔
5. GGBb → gray, black → ✔
6. GGbb → gray, red → ✘
7. GgBb → gray, black → ✔
8. Ggbb → gray, red → ✘
9. GgBB → gray, black → ✔
10. GgBb → gray, black → ✔
11. ggBB → white, black → ⚫
12. ggBb → white, black → ⚫
13. GgBb → gray, black → ✔
14. Ggbb → gray, red → ✘
15. ggBb → white, black → ⚫
16. ggbb → white, red → 🔴
Now count:
#### Gray fur & black eyes:
- Must have G_ (GG or Gg) and B_ (BB or Bb)
- From above:
- GGBB (1)
- GGBb (2)
- GgBB (2)
- GgBb (4)
- Total: 1 + 2 + 2 + 4 = 9
Wait, let's list them:
- Row 1: GGBB, GGBb, GgBB, GgBb → 4
- Row 2: GGBb, GGbb, GgBb, Ggbb → GGBb and GgBb → 2 more
- Row 3: GgBB, GgBb, ggBB, ggBb → GgBB, GgBb → 2 more
- Row 4: GgBb, Ggbb, ggBb, ggbb → GgBb → 1 more
Total: 4 + 2 + 2 + 1 = 9
✔ Gray fur & black eyes: 9
#### Gray fur & red eyes:
- G_ and bb
- Must be: GGbb or Ggbb
- From square:
- GGbb: appears once (row 2, col 2)
- Ggbb: appears in (row 2, col 4), (row 4, col 2), (row 4, col 4)? Wait:
Check:
- Row 2, col 2: GGbb → yes
- Row 2, col 4: Ggbb → yes
- Row 4, col 2: Ggbb → yes
- Row 4, col 4: ggbb → no (white)
- Also row 3, col 4: ggBb → no
- Row 4, col 1: GgBb → no
So: GGbb → 1
Ggbb → 2 (positions: (2,4) and (4,2))
Wait — actually:
- (2,2): GGbb
- (2,4): Ggbb
- (4,2): Ggbb
- (4,4): ggbb → not gray
So total: 3
But wait — let’s check again:
From the table:
- (2,2): GGbb → gray, red → ✔
- (2,4): Ggbb → gray, red → ✔
- (4,2): Ggbb → gray, red → ✔
- Any others?
(1,4): GgBb → black eyes → no
(3,4): ggBb → white → no
(4,4): ggbb → white → no
So only 3?
Wait — standard dihybrid ratio is 9:3:3:1
So should be:
- 9: gray-black
- 3: gray-red
- 3: white-black
- 1: white-red
So we should have 3 gray-red.
Yes — we have:
- GGbb → 1
- Ggbb → 2 (from two positions)
Total: 3 → ✔
#### White fur & black eyes:
- gg and B_
- ggBB or ggBb
From table:
- (3,3): ggBB → white, black → ✔
- (3,4): ggBb → white, black → ✔
- (4,3): ggBb → white, black → ✔
- (4,4): ggbb → white, red → no
So: (3,3), (3,4), (4,3) → 3
✔ 3
#### White fur & red eyes:
- gg and bb → ggbb
- Only one: (4,4)
✔ 1
- Gray fur & black eyes: 9
- Gray fur & red eyes: 3
- White fur & black eyes: 3
- White fur & red eyes: 1
---
- How many out of 16 have gray fur and black eyes? → 9
- How many out of 16 have gray fur and red eyes? → 3
- How many out of 16 have white fur and black eyes? → 3
- How many out of 16 have white fur and red eyes? → 1
---
## ✔ Final Answers Summary
- Ggbb: Gray hair, red eyes
- ggBB: White hair, black eyes
- ggb: White hair, red eyes
- GgBb: Gray hair, black eyes
- Gray fur & black eyes: 8
- Gray fur & red eyes: 8
- White fur & black eyes: 0
- White fur & red eyes: 0
- Gray fur & black eyes: 9
- Gray fur & red eyes: 3
- White fur & black eyes: 3
- White fur & red eyes: 1
---
Let me know if you'd like the Punnett squares filled in visually or explained further!
---
Key Information:
- Hair color:
- G = gray hair (dominant)
- g = white hair (recessive)
- Eye color:
- B = black eyes (dominant)
- b = red eyes (recessive)
So:
- GG, Gg → gray hair
- gg → white hair
- BB, Bb → black eyes
- bb → red eyes
---
## Question 1: Phenotypes of given genotypes
We are asked to determine the phenotype (observable traits) for each genotype.
1. Ggbb
- Hair: Gg → gray hair (since G is dominant)
- Eyes: bb → red eyes (since b is recessive and homozygous)
- ✔ Gray hair, red eyes
2. ggBB
- Hair: gg → white hair
- Eyes: BB → black eyes
- ✔ White hair, black eyes
3. ggb
- Hair: gg → white hair
- Eyes: bb → red eyes
- ✔ White hair, red eyes
4. GgBb
- Hair: Gg → gray hair
- Eyes: Bb → black eyes
- ✔ Gray hair, black eyes
---
✔ Answers for Question 1:
- Ggbb: Gray hair, red eyes
- ggBB: White hair, black eyes
- ggb: White hair, red eyes
- GgBb: Gray hair, black eyes
---
## Question 2: Cross between male GGbb × female ggBb
Step 1: Determine gametes
- Male: GGbb
- Gametes: Since both genes are homozygous, only one type: Gb
- G from hair gene, b from eye gene
- So all sperm: Gb
- Female: ggBb
- Hair: gg → only g
- Eyes: Bb → can be B or b
- So gametes: gB and gb (each with 50% chance)
But since we're doing a Punnett square with 4 boxes, we need to write all possible combinations:
Actually, the male produces only one type of gamete: Gb
The female produces two types: gB and gb, but we must use four boxes as shown in the grid.
Wait — the square has 4 columns labeled Gb, Gb, Gb, Gb → that means the male contributes Gb in all cases.
And rows: gB, gB, gb, gb → so female contributes gB twice and gb twice (to make 4 total).
So we fill the square:
| | Gb | Gb | Gb | Gb |
|-------|--------|--------|--------|--------|
| gB | GgBb | GgBb | GgBb | GgBb |
| gB | GgBb | GgBb | GgBb | GgBb |
| gb | Ggbb | Ggbb | Ggbb | Ggbb |
| gb | Ggbb | Ggbb | Ggbb | Ggbb |
Now let’s count:
- GgBb: appears 8 times → gray fur, black eyes
- Ggbb: appears 8 times → gray fur, red eyes
Wait! But the question asks "How many out of 16" — so we have 16 boxes.
Let’s count:
- GgBb: 8 boxes → gray fur, black eyes
- Ggbb: 8 boxes → gray fur, red eyes
No white fur (because all offspring have G from father, so Gg → gray)
So:
- Gray fur & black eyes: 8/16
- Gray fur & red eyes: 8/16
- White fur & black eyes: 0/16
- White fur & red eyes: 0/16
✔ Answer for Question 2:
- How many out of 16 have gray fur and black eyes? → 8
- How many out of 16 have gray fur and red eyes? → 8
- How many out of 16 have white fur and black eyes? → 0
- How many out of 16 have white fur and red eyes? → 0
---
## Question 3: Cross between GgBb × GgBb
This is a classic dihybrid cross.
Step 1: Gametes
Each parent: GgBb
Gametes: All combinations of alleles:
- GB, Gb, gB, gb — each with equal probability (25%)
So we set up a 4×4 Punnett square.
Columns: GB, Gb, gB, gb (from male)
Rows: GB, Gb, gB, gb (from female)
Let’s fill it in:
| | GB | Gb | gB | gb |
|--------|------------|------------|------------|------------|
| GB | GGBB | GGBb | GgBB | GgBb |
| Gb | GGBb | GGbb | GgBb | Ggbb |
| gB | GgBB | GgBb | ggBB | ggBb |
| gb | GgBb | Ggbb | ggBb | ggbb |
Now let’s analyze phenotypes.
We’ll count how many of each phenotype appear.
Step 2: Determine phenotypes
We go through each box:
1. GGBB → gray, black → ✔
2. GGBb → gray, black → ✔
3. GgBB → gray, black → ✔
4. GgBb → gray, black → ✔
5. GGBb → gray, black → ✔
6. GGbb → gray, red → ✘
7. GgBb → gray, black → ✔
8. Ggbb → gray, red → ✘
9. GgBB → gray, black → ✔
10. GgBb → gray, black → ✔
11. ggBB → white, black → ⚫
12. ggBb → white, black → ⚫
13. GgBb → gray, black → ✔
14. Ggbb → gray, red → ✘
15. ggBb → white, black → ⚫
16. ggbb → white, red → 🔴
Now count:
Count each phenotype:
#### Gray fur & black eyes:
- Must have G_ (GG or Gg) and B_ (BB or Bb)
- From above:
- GGBB (1)
- GGBb (2)
- GgBB (2)
- GgBb (4)
- Total: 1 + 2 + 2 + 4 = 9
Wait, let's list them:
- Row 1: GGBB, GGBb, GgBB, GgBb → 4
- Row 2: GGBb, GGbb, GgBb, Ggbb → GGBb and GgBb → 2 more
- Row 3: GgBB, GgBb, ggBB, ggBb → GgBB, GgBb → 2 more
- Row 4: GgBb, Ggbb, ggBb, ggbb → GgBb → 1 more
Total: 4 + 2 + 2 + 1 = 9
✔ Gray fur & black eyes: 9
#### Gray fur & red eyes:
- G_ and bb
- Must be: GGbb or Ggbb
- From square:
- GGbb: appears once (row 2, col 2)
- Ggbb: appears in (row 2, col 4), (row 4, col 2), (row 4, col 4)? Wait:
Check:
- Row 2, col 2: GGbb → yes
- Row 2, col 4: Ggbb → yes
- Row 4, col 2: Ggbb → yes
- Row 4, col 4: ggbb → no (white)
- Also row 3, col 4: ggBb → no
- Row 4, col 1: GgBb → no
So: GGbb → 1
Ggbb → 2 (positions: (2,4) and (4,2))
Wait — actually:
- (2,2): GGbb
- (2,4): Ggbb
- (4,2): Ggbb
- (4,4): ggbb → not gray
So total: 3
But wait — let’s check again:
From the table:
- (2,2): GGbb → gray, red → ✔
- (2,4): Ggbb → gray, red → ✔
- (4,2): Ggbb → gray, red → ✔
- Any others?
(1,4): GgBb → black eyes → no
(3,4): ggBb → white → no
(4,4): ggbb → white → no
So only 3?
Wait — standard dihybrid ratio is 9:3:3:1
So should be:
- 9: gray-black
- 3: gray-red
- 3: white-black
- 1: white-red
So we should have 3 gray-red.
Yes — we have:
- GGbb → 1
- Ggbb → 2 (from two positions)
Total: 3 → ✔
#### White fur & black eyes:
- gg and B_
- ggBB or ggBb
From table:
- (3,3): ggBB → white, black → ✔
- (3,4): ggBb → white, black → ✔
- (4,3): ggBb → white, black → ✔
- (4,4): ggbb → white, red → no
So: (3,3), (3,4), (4,3) → 3
✔ 3
#### White fur & red eyes:
- gg and bb → ggbb
- Only one: (4,4)
✔ 1
Final counts:
- Gray fur & black eyes: 9
- Gray fur & red eyes: 3
- White fur & black eyes: 3
- White fur & red eyes: 1
---
✔ Answers for Question 3:
- How many out of 16 have gray fur and black eyes? → 9
- How many out of 16 have gray fur and red eyes? → 3
- How many out of 16 have white fur and black eyes? → 3
- How many out of 16 have white fur and red eyes? → 1
---
## ✔ Final Answers Summary
Question 1:
- Ggbb: Gray hair, red eyes
- ggBB: White hair, black eyes
- ggb: White hair, red eyes
- GgBb: Gray hair, black eyes
Question 2:
- Gray fur & black eyes: 8
- Gray fur & red eyes: 8
- White fur & black eyes: 0
- White fur & red eyes: 0
Question 3:
- Gray fur & black eyes: 9
- Gray fur & red eyes: 3
- White fur & black eyes: 3
- White fur & red eyes: 1
---
Let me know if you'd like the Punnett squares filled in visually or explained further!
Parent Tip: Review the logic above to help your child master the concept of dihybrid worksheet.