Printable worksheet featuring ten discount word problems for practicing percentage calculations.
A worksheet titled "Discount Word Problems" with ten math problems involving calculating selling prices after discounts on various items.
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Show Answer Key & Explanations
Step-by-step solution for: Remedial Discount/Interest Word Problems — The Davidson Group
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Show Answer Key & Explanations
Step-by-step solution for: Remedial Discount/Interest Word Problems — The Davidson Group
Discount Word Problems Solution
The problems involve calculating the selling price of items after applying a discount. The general formula to calculate the selling price after a discount is:
\[
\text{Selling Price} = \text{Original Price} - (\text{Original Price} \times \text{Discount Rate})
\]
Alternatively, you can use:
\[
\text{Selling Price} = \text{Original Price} \times (1 - \text{Discount Rate})
\]
Let's solve each problem step by step.
---
#### Problem 1:
The usual price of a DVD player is \$200. At a sale, it was sold at a discount of 10%. What was its selling price?
- Original Price = \$200
- Discount Rate = 10% = 0.10
Using the formula:
\[
\text{Selling Price} = \text{Original Price} \times (1 - \text{Discount Rate})
\]
\[
\text{Selling Price} = 200 \times (1 - 0.10) = 200 \times 0.90 = 180
\]
Answer: \$180
---
#### Problem 2:
A \$50 shirt was sold at a 10% discount. What was the selling price of the shirt?
- Original Price = \$50
- Discount Rate = 10% = 0.10
Using the formula:
\[
\text{Selling Price} = \text{Original Price} \times (1 - \text{Discount Rate})
\]
\[
\text{Selling Price} = 50 \times (1 - 0.10) = 50 \times 0.90 = 45
\]
Answer: \$45
---
#### Problem 3:
The usual price of a TV is \$1000. At a sale, it was sold at a discount of 10%. What was its selling price?
- Original Price = \$1000
- Discount Rate = 10% = 0.10
Using the formula:
\[
\text{Selling Price} = \text{Original Price} \times (1 - \text{Discount Rate})
\]
\[
\text{Selling Price} = 1000 \times (1 - 0.10) = 1000 \times 0.90 = 900
\]
Answer: \$900
---
#### Problem 4:
A \$200 NFL ticket was sold at a discount of 8%. What was the ticket sold for?
- Original Price = \$200
- Discount Rate = 8% = 0.08
Using the formula:
\[
\text{Selling Price} = \text{Original Price} \times (1 - \text{Discount Rate})
\]
\[
\text{Selling Price} = 200 \times (1 - 0.08) = 200 \times 0.92 = 184
\]
Answer: \$184
---
#### Problem 5:
The usual price of a pair of jeans was \$60. On sale, they were 5% off. What was the selling price of the jeans?
- Original Price = \$60
- Discount Rate = 5% = 0.05
Using the formula:
\[
\text{Selling Price} = \text{Original Price} \times (1 - \text{Discount Rate})
\]
\[
\text{Selling Price} = 60 \times (1 - 0.05) = 60 \times 0.95 = 57
\]
Answer: \$57
---
#### Problem 6:
A \$20 book bag was on sale for 20%. What was the book bag being sold for?
- Original Price = \$20
- Discount Rate = 20% = 0.20
Using the formula:
\[
\text{Selling Price} = \text{Original Price} \times (1 - \text{Discount Rate})
\]
\[
\text{Selling Price} = 20 \times (1 - 0.20) = 20 \times 0.80 = 16
\]
Answer: \$16
---
#### Problem 7:
The usual price of a textbook is \$25. It was sold at a 4% discount. How much was it sold for?
- Original Price = \$25
- Discount Rate = 4% = 0.04
Using the formula:
\[
\text{Selling Price} = \text{Original Price} \times (1 - \text{Discount Rate})
\]
\[
\text{Selling Price} = 25 \times (1 - 0.04) = 25 \times 0.96 = 24
\]
Answer: \$24
---
#### Problem 8:
A \$700 computer was sold at a 15% discount. What was the selling price of the computer?
- Original Price = \$700
- Discount Rate = 15% = 0.15
Using the formula:
\[
\text{Selling Price} = \text{Original Price} \times (1 - \text{Discount Rate})
\]
\[
\text{Selling Price} = 700 \times (1 - 0.15) = 700 \times 0.85 = 595
\]
Answer: \$595
---
#### Problem 9:
The usual price of a microwave is \$30. It was sold at an 11% discount. How much was it sold for?
- Original Price = \$30
- Discount Rate = 11% = 0.11
Using the formula:
\[
\text{Selling Price} = \text{Original Price} \times (1 - \text{Discount Rate})
\]
\[
\text{Selling Price} = 30 \times (1 - 0.11) = 30 \times 0.89 = 26.70
\]
Answer: \$26.70
---
#### Problem 10:
A \$3,000 used car was sold at a 15% discount. How much money did its buyer pay?
- Original Price = \$3,000
- Discount Rate = 15% = 0.15
Using the formula:
\[
\text{Selling Price} = \text{Original Price} \times (1 - \text{Discount Rate})
\]
\[
\text{Selling Price} = 3000 \times (1 - 0.15) = 3000 \times 0.85 = 2550
\]
Answer: \$2550
---
Final Answers:
1. \$180
2. \$45
3. \$900
4. \$184
5. \$57
6. \$16
7. \$24
8. \$595
9. \$26.70
10. \$2550
\boxed{180, 45, 900, 184, 57, 16, 24, 595, 26.70, 2550}
Parent Tip: Review the logic above to help your child master the concept of discount word problems worksheet.