Measuring volume using water displacement with graduated cylinders and various objects.

To solve the problem, we need to determine the scale of each graduated cylinder, record the volumes without and with the object, and then calculate the volume of each object using the water displacement method. Let's go through each set of graduated cylinders step by step.

First Row of Graduated Cylinders

#### 1. Dinosaur
- Scale: The markings are every 1 mL.
- Volume without object: The water level is at 4 mL.
- With object: The water level rises to 5 mL.
- Object volume: \( 5 \, \text{mL} - 4 \, \text{mL} = 1 \, \text{mL} \).

#### 2. Fish
- Scale: The markings are every 10 mL.
- Volume without object: The water level is at 30 mL.
- With object: The water level rises to 40 mL.
- Object volume: \( 40 \, \text{mL} - 30 \, \text{mL} = 10 \, \text{mL} \).

#### 3. Person
- Scale: The markings are every 1 mL.
- Volume without object: The water level is at 5 mL.
- With object: The water level rises to 6 mL.
- Object volume: \( 6 \, \text{mL} - 5 \, \text{mL} = 1 \, \text{mL} \).

Second Row of Graduated Cylinders

#### 4. Hammer
- Scale: The markings are every 5 mL.
- Volume without object: The water level is at 65 mL.
- With object: The water level rises to 70 mL.
- Object volume: \( 70 \, \text{mL} - 65 \, \text{mL} = 5 \, \text{mL} \).

#### 5. Shark
- Scale: The markings are every 10 mL.
- Volume without object: The water level is at 50 mL.
- With object: The water level rises to 60 mL.
- Object volume: \( 60 \, \text{mL} - 50 \, \text{mL} = 10 \, \text{mL} \).

#### 6. SpongeBob
- Scale: The markings are every 10 mL.
- Volume without object: The water level is at 40 mL.
- With object: The water level rises to 50 mL.
- Object volume: \( 50 \, \text{mL} - 40 \, \text{mL} = 10 \, \text{mL} \).

Final Answers

1. Dinosaur:
- Scale: 1 mL
- Volume without object: 4 mL
- With object: 5 mL
- Object volume: 1 mL

2. Fish:
- Scale: 10 mL
- Volume without object: 30 mL
- With object: 40 mL
- Object volume: 10 mL

3. Person:
- Scale: 1 mL
- Volume without object: 5 mL
- With object: 6 mL
- Object volume: 1 mL

4. Hammer:
- Scale: 5 mL
- Volume without object: 65 mL
- With object: 70 mL
- Object volume: 5 mL

5. Shark:
- Scale: 10 mL
- Volume without object: 50 mL
- With object: 60 mL
- Object volume: 10 mL

6. SpongeBob:
- Scale: 10 mL
- Volume without object: 40 mL
- With object: 50 mL
- Object volume: 10 mL

Boxed Final Answer

\[
\boxed{
\begin{array}{|c|c|c|c|}
\hline
\text{Object} & \text{Scale} & \text{Volume without object} & \text{With object} & \text{Object volume} \\
\hline
\text{Dinosaur} & 1 \, \text{mL} & 4 \, \text{mL} & 5 \, \text{mL} & 1 \, \text{mL} \\
\hline
\text{Fish} & 10 \, \text{mL} & 30 \, \text{mL} & 40 \, \text{mL} & 10 \, \text{mL} \\
\hline
\text{Person} & 1 \, \text{mL} & 5 \, \text{mL} & 6 \, \text{mL} & 1 \, \text{mL} \\
\hline
\text{Hammer} & 5 \, \text{mL} & 65 \, \text{mL} & 70 \, \text{mL} & 5 \, \text{mL} \\
\hline
\text{Shark} & 10 \, \text{mL} & 50 \, \text{mL} & 60 \, \text{mL} & 10 \, \text{mL} \\
\hline
\text{SpongeBob} & 10 \, \text{mL} & 40 \, \text{mL} & 50 \, \text{mL} & 10 \, \text{mL} \\
\hline
\end{array}
}
\]