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Completed Distance and Displacement Lab worksheet with student measurements and calculations.

A student's completed "Distance and Displacement Lab" worksheet, showing handwritten measurements and calculations for two activities involving walking and measuring distances and displacements.

A student's completed "Distance and Displacement Lab" worksheet, showing handwritten measurements and calculations for two activities involving walking and measuring distances and displacements.

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Show Answer Key & Explanations Step-by-step solution for: SOLUTION: Distance and displacement lab - Studypool
Let's go through the Distance and Displacement Lab step by step, analyze the data provided, correct any inconsistencies, and explain how to solve each part properly.

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🔹 Important Notes:


- The lab asks to round all measurements to the nearest meter, but many values are in centimeters (cm). We’ll convert them to meters (m) for consistency.
- Distance = total path traveled (scalar quantity).
- Displacement = straight-line distance from start to end point (vector quantity), including direction.

---

## Activity #1

Step-by-step:



1. Origin: Marked with tape.

2. Walk 10 steps forward:
- Measured distance: 325 cm = 3.25 m → Rounded to 3 m
*(Note: The instruction says round to nearest meter, so we'll use 3 m)*

3. Turn 180°, walk 5 steps backward:
- Measured distance: 165 cm = 1.65 m → Rounded to 2 m

4. Turn 180° again, walk 20 steps forward:
- Measured distance: 638 cm = 6.38 m → Rounded to 6 m

5. Final measured displacement from origin:
- Measured: 225 cm = 2.25 m → Rounded to 2 m

6. Now calculate:

#### ➤ Total Distance Traveled:
Add all distances walked:
- Forward: 3 m + 6 m = 9 m
- Backward: 2 m
- Total distance = 3 + 2 + 6 = 11 m

> But the student wrote 1.128 cm — this is clearly a mistake (units and magnitude).
> Likely they meant 1128 cm = 11.28 m, which rounds to 11 m.

So, Distance = 11 m

#### ➤ Calculated Displacement:
We consider direction:
- Forward: +3 m
- Then back: –2 m
- Then forward again: +6 m

Total displacement = 3 – 2 + 6 = 7 m forward

But the student wrote 792 cm = 7.92 m → This is close, but not matching our calculation.

Wait — let’s check their numbers:
- 325 cm = 3.25 m
- 165 cm = 1.65 m
- 638 cm = 6.38 m

So actual displacement:
- Forward: 3.25 m
- Backward: –1.65 m
- Forward again: +6.38 m

Net displacement = 3.25 – 1.65 + 6.38 = 7.98 m ≈ 8 m

But measured displacement was 225 cm = 2.25 m → That doesn’t match!

⚠️ Problem: There’s a huge discrepancy between calculated displacement (~8 m) and measured displacement (2.25 m).

This suggests either:
- Measurement error,
- Or misunderstanding of directions.

Let’s re-analyze the path:

- Start at origin.
- Walk 10 steps forward → 3.25 m
- Turn 180° → now facing opposite direction
- Walk 5 steps → 1.65 m backward → position: 3.25 – 1.65 = 1.60 m from origin
- Turn 180° again → now facing original direction
- Walk 20 steps → 6.38 m forward → new position: 1.60 + 6.38 = 7.98 m from origin

So final position should be about 8 m forward.

But the student measured only 2.25 m from origin? That can't be right unless the path wasn't straight or there was a directional error.

➡️ Conclusion: The measured displacement (2.25 m) does not match the calculated displacement (~8 m).

So answer to “Did your measured displacement match?” → No (correct)

But the student's calculated displacement was written as 792 cm = 7.92 m, which matches our calculation. So that's correct.

And distance = 3.25 + 1.65 + 6.38 = 11.28 m → rounded to 11 m

So corrections:
- Distance: 11 m
- Calculated displacement: 7.92 m → 8 m
- Measured displacement: 2.25 m → likely incorrect due to measurement error

---

## Activity #2

Now, this one involves directions: North, West, South, East.

Given:


1. North: 10 steps → 312 cm = 3.12 m → 3 m
2. West: 15 steps → 484 cm = 4.84 m → 5 m
3. South: 10 steps → 306 cm = 3.06 m → 3 m
4. East: 20 steps → 685 cm = 6.85 m → 7 m

Step 5: Measured displacement from origin: 200 cm = 2 m



Step 6: Calculate total distance:


Add all segments:
- North: 3 m
- West: 5 m
- South: 3 m
- East: 7 m

→ Total distance = 3 + 5 + 3 + 7 = 18 m

But the student wrote Distance = 207 → probably meant 207 cm = 2.07 m, which is wrong.

Error here — they may have added centimeters incorrectly.

Let’s check:
- 312 + 484 + 306 + 685 = ?

Calculate:
- 312 + 484 = 796
- 796 + 306 = 1102
- 1102 + 685 = 1787 cm = 17.87 m → rounded to 18 m

So Distance = 18 m

---

Now, calculate displacement:



Use vector components.

Let’s define:
- North/South as y-axis (N = +, S = –)
- East/West as x-axis (E = +, W = –)

| Direction | Distance (m) | x-component | y-component |
|----------|---------------|-------------|-------------|
| North | 3 | 0 | +3 |
| West | 5 | –5 | 0 |
| South | 3 | 0 | –3 |
| East | 7 | +7 | 0 |

Now sum:
- Net x = –5 + 7 = +2 m (East)
- Net y = +3 – 3 = 0 m

So displacement = √(x² + y²) = √(2² + 0²) = 2 m East

Measured displacement was 200 cm = 2 m → matches!

So the measured displacement matches the calculated displacement.

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## Final Answers & Corrections:

🟩 Activity #1 Summary



- Distance walked:
325 cm + 165 cm + 638 cm = 1128 cm = 11.28 m → 11 m
→ Student had 1.128 cm Wrong units! Should be 11 m

- Calculated displacement:
Forward: 3.25 + 6.38 = 9.63 m
Backward: 1.65 m
Net: 9.63 – 1.65 = 7.98 m → 8 m
→ Student wrote 792 cm = 7.92 m → close enough, acceptable

- Measured displacement: 225 cm = 2.25 m Does NOT match (should be ~8 m)

- Did it match? → No (Correct)

---

🟩 Activity #2 Summary



- Distance:
312 + 484 + 306 + 685 = 1787 cm = 17.87 m → 18 m
→ Student wrote 207 Incorrect
Likely meant 1787 cm or 18 m

- Measured displacement: 200 cm = 2 m Correct

- Calculated displacement:
Net x = –5 + 7 = +2 m
Net y = +3 – 3 = 0 m
→ Displacement = 2 m East → matches measured value

---

## Final Answer Box

Activity #1


- Distance: 11 m
- Calculated displacement: 8 m
- Measured displacement: 2.25 m
- Match? No

Activity #2


- Distance: 18 m
- Measured displacement: 2 m
- Calculated displacement: 2 m east
- Match? Yes

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## Explanation of Key Concepts

- Distance is scalar (only magnitude): total path length.
- Displacement is vector (magnitude + direction): straight line from start to finish.

In Activity #1, you moved forward, then back, then forward again — so net displacement is forward, not zero.

In Activity #2, you went North, West, South, East — and ended up 2 m east of origin because:
- North and South canceled (3 m vs 3 m)
- West and East: 5 m west, 7 m east → net 2 m east

That’s why displacement is 2 m east.

---

## Conclusion

The student made two major errors:
1. Units confusion: Wrote "1.128 cm" instead of 11.28 m
2. Misread distance: Wrote "207" instead of 1787 cm → 18 m

With corrected calculations:
- Activity #1: Distance = 11 m, Displacement = 8 m (measured 2.25 m → mismatch)
- Activity #2: Distance = 18 m, Displacement = 2 m (matches measured)

These results make sense physically.

Let me know if you'd like a diagram or visual explanation!
Parent Tip: Review the logic above to help your child master the concept of distance and displacement worksheet with answers.
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