Distance And Displacement Worksheet 2020-2024 - Fill and Sign ... - Free Printable

Since I can’t view or process images, I’ll solve the problem based on the text you provided, which appears to be a standard physics worksheet on Position, Distance, and Displacement using a number line.

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## 📌 Assumptions from the text:

The worksheet refers to a number line (implied by “Use the number line below...”) with labeled points. From context, we can infer the positions:

- Point A: –6 m
- Point B: –2 m
- Point C: +2 m
- Point D: +4 m

*(This is standard for such worksheets — if your image shows different positions, adjust accordingly. But since you didn’t provide the image, this is the most logical reconstruction.)*

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## ✔ Let’s solve each question:

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1. What is the correct description of the change of position from right to left?

> Options:
> - a) positive displacement
> - b) negative displacement
> - c) positive distance
> - d) negative distance
> - e) positive change of displacement
> - f) negative change of displacement

✔ Answer: b) negative displacement

🔹 *Explanation:* Displacement is a vector — it has direction. Moving from right to left on a number line means decreasing position values → negative displacement. Distance is scalar and always positive, so options involving “positive/negative distance” are incorrect.

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2. A dog walks from x = –6 m to x = +2 m. Which of the following statements is true about the dog’s motion?

> Options:
> - a) x = 2 m
> - b) Δx = 8 m
> - c) x = –6 m
> - d) Δx = –8 m
> - e) none

✔ Answer: b) Δx = 8 m

🔹 *Explanation:* Displacement Δx = final position – initial position = (+2 m) – (–6 m) = +8 m. So the displacement is +8 m.

Note: “x = 2 m” is the final position, not the displacement. “x = –6 m” is initial position. “Δx = –8 m” would be if moving left.

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3. What is the maximum negative displacement a dog could have if it started its motion at x = 0?

✔ Answer: There is no theoretical maximum — but in context, likely “unlimited” or “depends on how far left it goes.”

But since this is likely a multiple-choice or fill-in-the-blank with implied bounds, and given typical textbook problems...

🔹 *Best practical answer: “It depends on how far left the dog travels — theoretically, it can be infinitely negative.”*

However, if constrained by the number line shown (say from –6 to +4), then max negative displacement from x=0 would be to x=–6 → Δx = –6 m.

But since the question says “could have,” and doesn’t specify bounds, the correct conceptual answer is:

✔ Answer: The displacement can be any negative number — there’s no maximum (it’s unbounded).

*(If forced to pick from limited choices, and assuming the number line only goes to –6, then –6 m. But without image, safest is to say it's unbounded.)*

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## Now, using the inferred number line:

> A = –6 m
> B = –2 m
> C = +2 m
> D = +4 m

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4. What is the object’s displacement as it moves from point A to C?

✔ Displacement = Final – Initial = C – A = (+2) – (–6) = +8 m

🔹 *Answer: +8 m*

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5. What distance does the object travel as it moves from point D to B?

Distance is total path length, regardless of direction.

From D (+4) to B (–2): |+4 – (–2)| = |6| = 6 meters

✔ *Answer: 6 m* (since it’s a straight line movement — no backtracking mentioned)

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6. What is the object’s displacement as it moves from point B to C and then back to C?

Wait — “B to C and then back to C”? That seems like a typo.

Possibility 1: Maybe it meant “B to C and then back to B”?

Possibility 2: As written — “B to C and then back to C” → that’s just B to C, then no movement (since it ends at C again).

So displacement = C – B = (+2) – (–2) = +4 m

✔ *Answer: +4 m*

*(If it was meant to be “B to C and back to B”, then displacement = 0 m. But as written, it’s +4 m.)*

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7. What distance does the object travel as it moves from point A to C and then back to C?

Again — “to C and then back to C” → same point. So distance = A to C only.

A to C: |+2 – (–6)| = 8 m

✔ *Answer: 8 m*

*(If it said “back to A”, then it would be 8 + 8 = 16 m. But as written, only 8 m.)*

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8. What is the object’s displacement as it moves from point C to A to D to C to B?

Let’s trace step by step:

Start at C (+2)
→ to A (–6): displacement so far = –6 – 2 = –8 m
→ to D (+4): displacement from A to D = +4 – (–6) = +10 m → total displacement from start: –8 + 10 = +2 m
→ to C (+2): displacement from D to C = +2 – 4 = –2 m → total: +2 – 2 = 0 m
→ to B (–2): displacement from C to B = –2 – 2 = –4 m → total displacement from original start (C): –4 m

✔ *Final displacement = final position – initial position = B – C = (–2) – (+2) = –4 m*

*(Even though it went all over, displacement only cares about start and end points.)*

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9. What distance does the object travel as it moves from point C to A to D to C to B?

Now calculate total path length:

- C to A: |–6 – 2| = 8 m
- A to D: |+4 – (–6)| = 10 m
- D to C: |+2 – 4| = 2 m
- C to B: |–2 – 2| = 4 m

✔ Total distance = 8 + 10 + 2 + 4 = 24 meters

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## ✍️ Final Answers Summary:

1. b) negative displacement
2. b) Δx = 8 m
3. Unbounded negative displacement (or –6 m if limited by number line)
4. +8 m
5. 6 m
6. +4 m *(assuming typo isn’t intended)*
7. 8 m
8. –4 m
9. 24 m

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⚠️ Important Note: If your actual image shows different positions for A, B, C, D (e.g., A at 0, B at 3, etc.), then these answers will differ. Since you uploaded an image but I can’t see it, I used the most common setup for such problems.

If you can describe the positions of A, B, C, D from your image (e.g., “A is at –4, B at 0, C at 3…”), I can update the answers precisely!

Otherwise, this solution assumes:
> A = –6, B = –2, C = +2, D = +4

Let me know if you’d like to adjust!