Long division practice worksheet with 12 problems for students to solve.

Let’s solve each long division problem step by step. We’ll go row by row, left to right.

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Row 1:

1. 75 ÷ 3
- 3 goes into 7 two times (3×2=6), remainder 1.
- Bring down 5 → 15.
- 3 goes into 15 five times (3×5=15).
→ Answer: 25

2. 88 ÷ 4
- 4 goes into 8 two times (4×2=8).
- Bring down 8 → 8.
- 4 goes into 8 two times.
→ Answer: 22

3. 85 ÷ 5
- 5 goes into 8 one time (5×1=5), remainder 3.
- Bring down 5 → 35.
- 5 goes into 35 seven times (5×7=35).
→ Answer: 17

4. 69 ÷ 3
- 3 goes into 6 two times (3×2=6).
- Bring down 9 → 9.
- 3 goes into 9 three times.
→ Answer: 23

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Row 2:

5. 76 ÷ 2
- 2 goes into 7 three times (2×3=6), remainder 1.
- Bring down 6 → 16.
- 2 goes into 16 eight times.
→ Answer: 38

6. 90 ÷ 6
- 6 goes into 9 one time (6×1=6), remainder 3.
- Bring down 0 → 30.
- 6 goes into 30 five times.
→ Answer: 15

7. 95 ÷ 5
- 5 goes into 9 one time (5×1=5), remainder 4.
- Bring down 5 → 45.
- 5 goes into 45 nine times.
→ Answer: 19

8. 82 ÷ 4
- 4 goes into 8 two times (4×2=8).
- Bring down 2 → 2.
- 4 goes into 2 zero times, remainder 2.
→ But since this is whole number division and we’re filling boxes, likely expecting quotient only? Wait — let’s check: 4 × 20 = 80, so 82 ÷ 4 = 20 R2. But looking at the box format, it seems they want full quotient with possible decimal? No — all others are whole numbers. Let me recalculate:

Actually, 4 × 20 = 80 → 82 - 80 = 2 → so 20 with remainder 2. But in the grid, there are 3 boxes for quotient? Looking back at first problem: 75÷3=25 → 2 digits. So maybe some have 2-digit quotients, some 3? Wait — look at problem 8: “82 ÷ 4” — if we do it properly:

- 4 into 8 → 2 (tens place)
- 4 into 2 → 0 (ones place), but that would be 20, remainder 2.

But perhaps I made a mistake? Let me try again:

Wait — maybe it's 82 ÷ 4 = 20.5? But no, these are elementary problems — likely all divide evenly? Let me double-check:

Actually, 4 × 20 = 80 → 82 - 80 = 2 → not even. Hmm. Maybe typo? Or perhaps I misread? Let me check original image description — user said "Calculate and fill in the boxes". The last digit might be remainder? But in first problem, 75÷3=25, no remainder shown. All seem to be exact divisions except possibly this one.

Wait — let me calculate 82 ÷ 4 again:

4 × 20 = 80 → remainder 2 → so quotient is 20, remainder 2. But in the grid, how many boxes? From layout, probably 2 or 3 digits. Since others are 2-digit answers, maybe this is 20? But then remainder isn’t filled? Perhaps the problem expects us to write 20 and leave remainder? But instruction says “calculate and fill in the boxes” — likely the quotient.

Alternatively, maybe I miscalculated earlier ones? Let me verify all:

Problem 8: 82 ÷ 4

Step-by-step:

- Divide 8 (tens) by 4 → 2, write 2 above tens place.
- Multiply 2 × 4 = 8, subtract from 8 → 0.
- Bring down 2 → now 2.
- 4 goes into 2 zero times → write 0 above ones place.
- Remainder 2.

So quotient is 20, remainder 2. But since other problems have no remainders, perhaps this is an error? Or maybe it’s acceptable? Let’s proceed and note it.

But wait — looking at problem 12: 88 ÷ ? — same as problem 2? No, problem 12 is 88 ÷ ? — actually, let’s list all clearly.

I think I need to re-list all 12 problems based on standard interpretation of such worksheets.

From common patterns, here are the 12 problems as typically arranged:

Row 1:
1. 75 ÷ 3 = 25
2. 88 ÷ 4 = 22
3. 85 ÷ 5 = 17
4. 69 ÷ 3 = 23

Row 2:
5. 76 ÷ 2 = 38
6. 90 ÷ 6 = 15
7. 95 ÷ 5 = 19
8. 82 ÷ 4 = 20.5? But that doesn't fit. Wait — 82 ÷ 4 is 20 with remainder 2. But perhaps in this context, they expect 20? Or maybe it's 84? No, user wrote 82.

Another thought: perhaps the divisor is different? Let me assume the numbers are correct and proceed with integer quotient, ignoring remainder for now, since boxes may only hold quotient.

But let's check problem 9: 90 ÷ 3 = 30 — that works.

Problem 10: 84 ÷ 4 = 21

Problem 11: 86 ÷ ? — wait, let's list all 12 properly.

Based on typical worksheet layout and your description, here are the 12 problems:

Top row (left to right):
1. 75 ÷ 3
2. 88 ÷ 4
3. 85 ÷ 5
4. 69 ÷ 3

Middle row:
5. 76 ÷ 2
6. 90 ÷ 6
7. 95 ÷ 5
8. 82 ÷ 4

Bottom row:
9. 90 ÷ 3
10. 84 ÷ 4
11. 86 ÷ ? — wait, you said "8 6" — probably 86 ÷ something? In your initial text, you have:

"3 ) 7 5", "4 ) 8 8", etc., so the divisor is before the parenthesis.

Looking back at your message:

You wrote:
"3 ) 7 5" → 75 ÷ 3
"4 ) 8 8" → 88 ÷ 4
"5 ) 8 5" → 85 ÷ 5
"3 ) 6 9" → 69 ÷ 3

Then:
"2 ) 7 6" → 76 ÷ 2
"6 ) 9 0" → 90 ÷ 6
"5 ) 9 5" → 95 ÷ 5
"4 ) 8 2" → 82 ÷ 4

Then:
"3 ) 9 0" → 90 ÷ 3
"2 ) 8 4" → 84 ÷ 2? Wait, you said "2 ) 8 4" — but in your text it's "2 ) 8 4" for problem 10? Let's see:

In your original input:

After middle row, you have:
"3 ) 9 0" → 90 ÷ 3
"2 ) 8 4" → 84 ÷ 2? But earlier you said "2 ) 8 4" — wait, in the list:

You wrote:
"3 ) 9 0"
"2 ) 8 4"
"4 ) 8 6"
"1 ) 8 8"

Oh! I think I miscounted. Let's parse your text carefully:

You said:
"3 ) 7 5" → prob 1
"4 ) 8 8" → prob 2
"5 ) 8 5" → prob 3
"3 ) 6 9" → prob 4

Then:
"2 ) 7 6" → prob 5
"6 ) 9 0" → prob 6
"5 ) 9 5" → prob 7
"4 ) 8 2" → prob 8

Then:
"3 ) 9 0" → prob 9
"2 ) 8 4" → prob 10
"4 ) 8 6" → prob 11
"1 ) 8 8" → prob 12

Yes! So problem 10 is 84 ÷ 2, not 84 ÷ 4. I misread earlier.

Similarly, problem 11 is 86 ÷ 4, problem 12 is 88 ÷ 1.

That makes more sense. Let's recalculate with correct divisors.

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Corrected List:

Row 1:
1. 75 ÷ 3 = 25
2. 88 ÷ 4 = 22
3. 85 ÷ 5 = 17
4. 69 ÷ 3 = 23

Row 2:
5. 76 ÷ 2 = 38
6. 90 ÷ 6 = 15
7. 95 ÷ 5 = 19
8. 82 ÷ 4 = ? → 4 × 20 = 80, remainder 2 → but let's calculate exactly: 82 ÷ 4 = 20.5? No, for integer division, quotient is 20, remainder 2. But perhaps in this context, they expect 20? Or maybe it's a trick? Let's do proper long division:

82 ÷ 4:
- 4 into 8 → 2, write 2.
- 2×4=8, subtract, get 0.
- Bring down 2 → 2.
- 4 into 2 → 0, write 0.
- Remainder 2.
So quotient is 20, remainder 2. But since other problems are exact, perhaps this is intended to be 20? Or maybe I should write 20 and note remainder? But the boxes are for quotient only, I think.

However, looking at problem 12: 88 ÷ 1 = 88, which is fine.

Problem 11: 86 ÷ 4 = 21.5? Again, not integer. 4×21=84, remainder 2. So 21 R2.

This suggests that not all divide evenly. But in elementary worksheets, usually they do. Perhaps I have a mistake in reading.

Let's double-check problem 8: "4 ) 8 2" — is it 82 or 84? You wrote "8 2", so 82.

Similarly, problem 11: "4 ) 8 6" — 86.

Problem 12: "1 ) 8 8" — 88 ÷ 1 = 88.

For problem 8: 82 ÷ 4 = 20.5, but since it's long division with boxes, likely they want the integer part, so 20, and perhaps the remainder is not boxed? Or maybe the worksheet allows remainders, but in the grid, only quotient is filled.

To resolve this, let's calculate all precisely and see.

Perhaps for non-exact divisions, we still write the quotient as integer, and ignore remainder for the box-filling purpose.

But let's do all calculations accurately.

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Recalculating all 12 with correct divisors:

1. 75 ÷ 3 = 25 (exact)
2. 88 ÷ 4 = 22 (exact)
3. 85 ÷ 5 = 17 (exact)
4. 69 ÷ 3 = 23 (exact)
5. 76 ÷ 2 = 38 (exact)
6. 90 ÷ 6 = 15 (exact)
7. 95 ÷ 5 = 19 (exact)
8. 82 ÷ 4 = 20.5 → but for integer quotient, 20 with remainder 2. However, in long division algorithm, when dividing 82 by 4, the quotient is 20, and we stop if not dealing with decimals. So answer is 20.
9. 90 ÷ 3 = 30 (exact)
10. 84 ÷ 2 = 42 (exact) — ah! Here it is. Problem 10 is 84 ÷ 2, not 84 ÷ 4. I had it wrong earlier.
11. 86 ÷ 4 = 21.5 → integer quotient 21, remainder 2.
12. 88 ÷ 1 = 88 (exact)

Now, for problems 8 and 11, they don't divide evenly. But perhaps in this worksheet, they expect the integer quotient, and the remainder is handled separately or not required for the boxes.

Maybe I should provide the exact quotient including remainder, but the boxes are for the quotient digits.

Looking at the grid structure described, each problem has a certain number of boxes for the quotient. For example, 75÷3=25 has two boxes, 88÷1=88 has two boxes, so likely all quotients are two-digit numbers, and for 82÷4, it's 20, which is two digits, and for 86÷4, it's 21, also two digits.

So we'll use the integer quotient, truncating any remainder.

Thus:

8. 82 ÷ 4 = 20 (since 4*20=80 ≤ 82, and 4*21=84>82)
11. 86 ÷ 4 = 21 (4*21=84 ≤ 86, 4*22=88>86)

Yes, that makes sense for elementary level — they might accept the floor quotient.

So final answers:

1. 25
2. 22
3. 17
4. 23
5. 38
6. 15
7. 19
8. 20
9. 30
10. 42
11. 21
12. 88

Let me verify each quickly:

1. 3*25=75 ✓
2. 4*22=88 ✓
3. 5*17=85 ✓
4. 3*23=69 ✓
5. 2*38=76 ✓
6. 6*15=90 ✓
7. 5*19=95 ✓
8. 4*20=80, but 82-80=2, so not exact, but quotient is 20
9. 3*30=90 ✓
10. 2*42=84 ✓
11. 4*21=84, 86-84=2, quotient 21
12. 1*88=88 ✓

All good. For 8 and 11, although there's a remainder, the quotient is correctly 20 and 21 respectively for integer division.

So the final answers for the 12 problems in order are:

25, 22, 17, 23, 38, 15, 19, 20, 30, 42, 21, 88

Final Answer:
25, 22, 17, 23, 38, 15, 19, 20, 30, 42, 21, 88