Math worksheet for practicing polynomial division by monomials.
Worksheet titled "Dividing Polynomials by a Monomial (Single Term)" with 13 algebraic division problems.
JPG
400×516
44.9 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #191975
⭐
Show Answer Key & Explanations
Step-by-step solution for: Pre-Algebra Worksheets | Monomials and Polynomials Worksheets
▼
Show Answer Key & Explanations
Step-by-step solution for: Pre-Algebra Worksheets | Monomials and Polynomials Worksheets
Problem: Dividing Polynomials by a Monomial (Single Term)
The task involves dividing each polynomial by the given monomial. The general approach is to divide each term of the polynomial by the monomial and simplify the result.
Let's solve each problem step by step.
---
1. \( (6x^3 + 30x^2 + 24x) \div 12 \)
#### Step 1: Divide each term by 12.
- \( \frac{6x^3}{12} = \frac{6}{12} \cdot x^3 = \frac{1}{2}x^3 \)
- \( \frac{30x^2}{12} = \frac{30}{12} \cdot x^2 = \frac{5}{2}x^2 \)
- \( \frac{24x}{12} = \frac{24}{12} \cdot x = 2x \)
#### Final Answer:
\[ \frac{1}{2}x^3 + \frac{5}{2}x^2 + 2x \]
---
2. \( (15x^4 + 20x^3 + 5x) \div 5 \)
#### Step 1: Divide each term by 5.
- \( \frac{15x^4}{5} = \frac{15}{5} \cdot x^4 = 3x^4 \)
- \( \frac{20x^3}{5} = \frac{20}{5} \cdot x^3 = 4x^3 \)
- \( \frac{5x}{5} = \frac{5}{5} \cdot x = x \)
#### Final Answer:
\[ 3x^4 + 4x^3 + x \]
---
3. \( (14x^3 + 10x^2 + 6x) \div 6x \)
#### Step 1: Divide each term by \( 6x \).
- \( \frac{14x^3}{6x} = \frac{14}{6} \cdot \frac{x^3}{x} = \frac{7}{3}x^2 \)
- \( \frac{10x^2}{6x} = \frac{10}{6} \cdot \frac{x^2}{x} = \frac{5}{3}x \)
- \( \frac{6x}{6x} = \frac{6}{6} \cdot \frac{x}{x} = 1 \)
#### Final Answer:
\[ \frac{7}{3}x^2 + \frac{5}{3}x + 1 \]
---
4. \( (17x^2 + 81x^{17} + 9x) \div 9x \)
#### Step 1: Divide each term by \( 9x \).
- \( \frac{17x^2}{9x} = \frac{17}{9} \cdot \frac{x^2}{x} = \frac{17}{9}x \)
- \( \frac{81x^{17}}{9x} = \frac{81}{9} \cdot \frac{x^{17}}{x} = 9x^{16} \)
- \( \frac{9x}{9x} = \frac{9}{9} \cdot \frac{x}{x} = 1 \)
#### Final Answer:
\[ 9x^{16} + \frac{17}{9}x + 1 \]
---
5. \( (60x^{17} + 60x^{10} + 30x^9) \div 30x \)
#### Step 1: Divide each term by \( 30x \).
- \( \frac{60x^{17}}{30x} = \frac{60}{30} \cdot \frac{x^{17}}{x} = 2x^{16} \)
- \( \frac{60x^{10}}{30x} = \frac{60}{30} \cdot \frac{x^{10}}{x} = 2x^9 \)
- \( \frac{30x^9}{30x} = \frac{30}{30} \cdot \frac{x^9}{x} = x^8 \)
#### Final Answer:
\[ 2x^{16} + 2x^9 + x^8 \]
---
6. \( (60x^{17} + 24x^{10} + 24x^7) \div 12x^7 \)
#### Step 1: Divide each term by \( 12x^7 \).
- \( \frac{60x^{17}}{12x^7} = \frac{60}{12} \cdot \frac{x^{17}}{x^7} = 5x^{10} \)
- \( \frac{24x^{10}}{12x^7} = \frac{24}{12} \cdot \frac{x^{10}}{x^7} = 2x^3 \)
- \( \frac{24x^7}{12x^7} = \frac{24}{12} \cdot \frac{x^7}{x^7} = 2 \)
#### Final Answer:
\[ 5x^{10} + 2x^3 + 2 \]
---
7. \( (33x^7 + 99x^5 + 11x^4) \div 33x \)
#### Step 1: Divide each term by \( 33x \).
- \( \frac{33x^7}{33x} = \frac{33}{33} \cdot \frac{x^7}{x} = x^6 \)
- \( \frac{99x^5}{33x} = \frac{99}{33} \cdot \frac{x^5}{x} = 3x^4 \)
- \( \frac{11x^4}{33x} = \frac{11}{33} \cdot \frac{x^4}{x} = \frac{1}{3}x^3 \)
#### Final Answer:
\[ x^6 + 3x^4 + \frac{1}{3}x^3 \]
---
8. \( (18x^{12} + 21x^7 + 24x^5) \div 6x^2 \)
#### Step 1: Divide each term by \( 6x^2 \).
- \( \frac{18x^{12}}{6x^2} = \frac{18}{6} \cdot \frac{x^{12}}{x^2} = 3x^{10} \)
- \( \frac{21x^7}{6x^2} = \frac{21}{6} \cdot \frac{x^7}{x^2} = \frac{7}{2}x^5 \)
- \( \frac{24x^5}{6x^2} = \frac{24}{6} \cdot \frac{x^5}{x^2} = 4x^3 \)
#### Final Answer:
\[ 3x^{10} + \frac{7}{2}x^5 + 4x^3 \]
---
9. \( (28x^{12} - 42x^7 - 28x^5) \div 21x^2 \)
#### Step 1: Divide each term by \( 21x^2 \).
- \( \frac{28x^{12}}{21x^2} = \frac{28}{21} \cdot \frac{x^{12}}{x^2} = \frac{4}{3}x^{10} \)
- \( \frac{-42x^7}{21x^2} = \frac{-42}{21} \cdot \frac{x^7}{x^2} = -2x^5 \)
- \( \frac{-28x^5}{21x^2} = \frac{-28}{21} \cdot \frac{x^5}{x^2} = -\frac{4}{3}x^3 \)
#### Final Answer:
\[ \frac{4}{3}x^{10} - 2x^5 - \frac{4}{3}x^3 \]
---
10. \( (-24x^9 + 42x^7 + 42x^5) \div 18x \)
#### Step 1: Divide each term by \( 18x \).
- \( \frac{-24x^9}{18x} = \frac{-24}{18} \cdot \frac{x^9}{x} = -\frac{4}{3}x^8 \)
- \( \frac{42x^7}{18x} = \frac{42}{18} \cdot \frac{x^7}{x} = \frac{7}{3}x^6 \)
- \( \frac{42x^5}{18x} = \frac{42}{18} \cdot \frac{x^5}{x} = \frac{7}{3}x^4 \)
#### Final Answer:
\[ -\frac{4}{3}x^8 + \frac{7}{3}x^6 + \frac{7}{3}x^4 \]
---
11. \( (-40x^{12} + 30x^{10} - 10x^7 + 30x^5 + 80x^3) \div 20x^2 \)
#### Step 1: Divide each term by \( 20x^2 \).
- \( \frac{-40x^{12}}{20x^2} = \frac{-40}{20} \cdot \frac{x^{12}}{x^2} = -2x^{10} \)
- \( \frac{30x^{10}}{20x^2} = \frac{30}{20} \cdot \frac{x^{10}}{x^2} = \frac{3}{2}x^8 \)
- \( \frac{-10x^7}{20x^2} = \frac{-10}{20} \cdot \frac{x^7}{x^2} = -\frac{1}{2}x^5 \)
- \( \frac{30x^5}{20x^2} = \frac{30}{20} \cdot \frac{x^5}{x^2} = \frac{3}{2}x^3 \)
- \( \frac{80x^3}{20x^2} = \frac{80}{20} \cdot \frac{x^3}{x^2} = 4x \)
#### Final Answer:
\[ -2x^{10} + \frac{3}{2}x^8 - \frac{1}{2}x^5 + \frac{3}{2}x^3 + 4x \]
---
12. \( (77x^{14} + 55x^{13} + 99x^{12} + 88x^{11} + 44x^{10} + 11x^9) \div 11x^9 \)
#### Step 1: Divide each term by \( 11x^9 \).
- \( \frac{77x^{14}}{11x^9} = \frac{77}{11} \cdot \frac{x^{14}}{x^9} = 7x^5 \)
- \( \frac{55x^{13}}{11x^9} = \frac{55}{11} \cdot \frac{x^{13}}{x^9} = 5x^4 \)
- \( \frac{99x^{12}}{11x^9} = \frac{99}{11} \cdot \frac{x^{12}}{x^9} = 9x^3 \)
- \( \frac{88x^{11}}{11x^9} = \frac{88}{11} \cdot \frac{x^{11}}{x^9} = 8x^2 \)
- \( \frac{44x^{10}}{11x^9} = \frac{44}{11} \cdot \frac{x^{10}}{x^9} = 4x \)
- \( \frac{11x^9}{11x^9} = \frac{11}{11} \cdot \frac{x^9}{x^9} = 1 \)
#### Final Answer:
\[ 7x^5 + 5x^4 + 9x^3 + 8x^2 + 4x + 1 \]
---
13. \( (-40x^{12} - 20x^{11} - 25x^9 - 30x^8) \div 15x^8 \)
#### Step 1: Divide each term by \( 15x^8 \).
- \( \frac{-40x^{12}}{15x^8} = \frac{-40}{15} \cdot \frac{x^{12}}{x^8} = -\frac{8}{3}x^4 \)
- \( \frac{-20x^{11}}{15x^8} = \frac{-20}{15} \cdot \frac{x^{11}}{x^8} = -\frac{4}{3}x^3 \)
- \( \frac{-25x^9}{15x^8} = \frac{-25}{15} \cdot \frac{x^9}{x^8} = -\frac{5}{3}x \)
- \( \frac{-30x^8}{15x^8} = \frac{-30}{15} \cdot \frac{x^8}{x^8} = -2 \)
#### Final Answer:
\[ -\frac{8}{3}x^4 - \frac{4}{3}x^3 - \frac{5}{3}x - 2 \]
---
Final Answers:
1. \( \frac{1}{2}x^3 + \frac{5}{2}x^2 + 2x \)
2. \( 3x^4 + 4x^3 + x \)
3. \( \frac{7}{3}x^2 + \frac{5}{3}x + 1 \)
4. \( 9x^{16} + \frac{17}{9}x + 1 \)
5. \( 2x^{16} + 2x^9 + x^8 \)
6. \( 5x^{10} + 2x^3 + 2 \)
7. \( x^6 + 3x^4 + \frac{1}{3}x^3 \)
8. \( 3x^{10} + \frac{7}{2}x^5 + 4x^3 \)
9. \( \frac{4}{3}x^{10} - 2x^5 - \frac{4}{3}x^3 \)
10. \( -\frac{4}{3}x^8 + \frac{7}{3}x^6 + \frac{7}{3}x^4 \)
11. \( -2x^{10} + \frac{3}{2}x^8 - \frac{1}{2}x^5 + \frac{3}{2}x^3 + 4x \)
12. \( 7x^5 + 5x^4 + 9x^3 + 8x^2 + 4x + 1 \)
13. \( -\frac{8}{3}x^4 - \frac{4}{3}x^3 - \frac{5}{3}x - 2 \)
\boxed{\text{See above for detailed solutions and final answers.}}
Parent Tip: Review the logic above to help your child master the concept of dividing polynomials by monomials worksheets.