Grade 5 Math Worksheets: Divide whole numbers by decimals | Worsheets library... - Free Printable

Let’s solve each problem one by one. We’re dividing whole numbers by decimals, and we need to round the answer to 3 digits if needed.

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Problem 1: 558 ÷ 0.03

To divide by a decimal, move the decimal point in both numbers to make the divisor a whole number.

0.03 → move decimal 2 places right → becomes 3
So move decimal in 558 two places right → 55800

Now do: 55800 ÷ 3 = 18600

✔ Answer: 18600

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Problem 2: 33 ÷ 0.4

Move decimal 1 place right:

0.4 → 4
33 → 330

Now: 330 ÷ 4 = 82.5

We need to round to 3 digits? 82.5 is already fine — it’s 82.500 if we write 3 digits after decimal, but since it says “round to 3 digits if necessary”, and 82.5 has only one digit after decimal, we can leave it as is or write 82.500. But usually, we just keep it simple unless told otherwise. Let’s check: 82.5 is exact.

But let’s see what the instruction means: “Round to 3 digits” probably means 3 significant digits or 3 decimal places? Looking at context, likely 3 decimal places if needed. Since 82.5 is exact, no rounding needed.

Actually, let’s compute exactly:

33 ÷ 0.4 = 330 ÷ 4 = 82.5 → which is 82.500 if written with 3 decimals.

But maybe they want 3 significant figures? 82.5 has 3 significant figures already.

I think for this level, they mean 3 decimal places if the answer is not whole. But 82.5 is fine.

Wait — let me double-check: 0.4 × 82.5 = 33 → yes, correct.

✔ Answer: 82.5

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Problem 3: 773 ÷ 0.06

Move decimal 2 places right:

0.06 → 6
773 → 77300

Now: 77300 ÷ 6

Do division:

6 × 12883 = 77298 → remainder 2

So 77300 ÷ 6 = 12883.333...

Round to 3 decimal places: 12883.333

✔ Answer: 12883.333

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Problem 4: 69 ÷ 0.08

Move decimal 2 places right:

0.08 → 8
69 → 6900

6900 ÷ 8 = ?

8 × 862 = 6896 → remainder 4 → so 862.5

Because 4/8 = 0.5

So 862.5

✔ Answer: 862.5

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Problem 5: 368 ÷ 0.8

Move decimal 1 place right:

0.8 → 8
368 → 3680

3680 ÷ 8 = 460

✔ Answer: 460

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Problem 6: 11 ÷ 0.8

Move decimal 1 place right:

0.8 → 8
11 → 110

110 ÷ 8 = 13.75

That’s exact. If we need 3 decimal places, write 13.750

But 13.75 is fine. Let’s go with 13.750 to match “3 digits” if interpreted as decimal places.

Actually, 13.75 has two decimal places. To have three, add a zero: 13.750

✔ Answer: 13.750

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Problem 7: 904 ÷ 0.03

Move decimal 2 places right:

0.03 → 3
904 → 90400

90400 ÷ 3 = ?

3 × 30133 = 90399 → remainder 1 → so 30133.333...

Round to 3 decimal places: 30133.333

✔ Answer: 30133.333

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Problem 8: 152 ÷ 0.03

Same as above:

0.03 → 3
152 → 15200

15200 ÷ 3 = ?

3 × 5066 = 15198 → remainder 2 → so 5066.666...

Round to 3 decimal places: 5066.667 (since 6 repeats, third decimal is 6, next is 6 → round up? Wait: 5066.666... → to 3 decimals: look at fourth digit, which is 6 ≥ 5 → round up third 6 to 7)

So 5066.667

✔ Answer: 5066.667

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Problem 9: 97 ÷ 0.5

Move decimal 1 place right:

0.5 → 5
97 → 970

970 ÷ 5 = 194

✔ Answer: 194

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Final Answers:

1. 18600
2. 82.5
3. 12883.333
4. 862.5
5. 460
6. 13.750
7. 30133.333
8. 5066.667
9. 194

Note: For problems where the answer is exact and has fewer than 3 decimal places, I added zeros to show 3 decimal places where appropriate (like 82.5 → 82.500? But I didn’t — because 82.5 is acceptable. However, problem 6 I wrote 13.750 to be consistent with “3 digits”. Actually, let’s re-read: “Round to 3 digits if necessary.” It doesn’t specify decimal places or significant digits. In grade 5, likely they mean 3 decimal places if the answer isn’t whole.

But looking at common practice, for example:

- 82.5 → if they want 3 decimal places, write 82.500
- 862.5 → 862.500
- 460 → 460.000
- 194 → 194.000

But that seems excessive. Maybe “3 digits” means 3 significant figures? Let’s check:

Problem 2: 82.5 → 3 sig figs → good
Problem 4: 862.5 → 4 sig figs → too many? But it’s exact.

Actually, I think the safest is to provide the exact answer, and if it’s repeating or long, round to 3 decimal places.

In problem 2: 82.5 is exact → no need to change
Problem 4: 862.5 → exact
Problem 5: 460 → exact
Problem 9: 194 → exact

For those, we don’t need to add decimals.

Only when the decimal goes on, like problem 3,7,8, we round to 3 decimal places.

Problem 6: 13.75 is exact → but if we interpret “3 digits” as 3 decimal places, then 13.750

I think for consistency, since the instruction says “round to 3 digits if necessary”, and for exact answers with less than 3 decimals, we can leave them as is. But to be safe, let’s follow the pattern: if the answer has a decimal part, show up to 3 decimal places, adding zeros if needed.

So:

Problem 2: 82.5 → 82.500
Problem 4: 862.5 → 862.500
Problem 6: 13.75 → 13.750
Problem 5: 460 → 460.000? But that might be overkill.

Actually, looking back at the worksheet title: “Whole numbers divided by decimals” — and it’s grade 5. They probably expect the answer as calculated, and round only if it’s non-terminating.

In many curricula, “round to 3 digits” means 3 decimal places.

Let me adjust:

For any answer that is not a whole number, express it with up to 3 decimal places, rounding if needed.

So:

1. 18600 → whole → 18600
2. 82.5 → 82.500
3. 12883.333... → 12883.333
4. 862.5 → 862.500
5. 460 → 460
6. 13.75 → 13.750
7. 30133.333... → 30133.333
8. 5066.666... → 5066.667 (rounded)
9. 194 → 194

Yes, this makes sense.

So final answers adjusted:

1. 18600
2. 82.500
3. 12883.333
4. 862.500
5. 460
6. 13.750
7. 30133.333
8. 5066.667
9. 194

Now, let’s verify problem 8 again:

152 ÷ 0.03 = 15200 ÷ 3 = 5066.666...

To 3 decimal places: look at the fourth decimal — it’s 6, so round up the third 6 to 7 → 5066.667 ✔️

All others are correct.

Final Answer:
1. 18600
2. 82.500
3. 12883.333
4. 862.500
5. 460
6. 13.750
7. 30133.333
8. 5066.667
9. 194