Multiplication and Division Worksheets with Answer Key - Free Printable

Problem Overview:

The task involves solving multiplication and division problems. Let's break it down into two sections:

1. Multiplication Problems (a–f):
- Perform the multiplication of the given pairs of numbers.

2. Division Problems (g–l):
- Perform the division of the given pairs of numbers.

---

Solution:

#### Section 1: Multiplication Problems

##### Problem (a): \( 127 \times 13 \)
\[
\begin{aligned}
127 \times 13 &= 127 \times (10 + 3) \\
&= (127 \times 10) + (127 \times 3) \\
&= 1270 + 381 \\
&= 1651
\end{aligned}
\]
Answer: \( \boxed{1651} \)

##### Problem (b): \( 228 \times 18 \)
\[
\begin{aligned}
228 \times 18 &= 228 \times (10 + 8) \\
&= (228 \times 10) + (228 \times 8) \\
&= 2280 + 1824 \\
&= 4104
\end{aligned}
\]
Answer: \( \boxed{4104} \)

##### Problem (c): \( 325 \times 14 \)
\[
\begin{aligned}
325 \times 14 &= 325 \times (10 + 4) \\
&= (325 \times 10) + (325 \times 4) \\
&= 3250 + 1300 \\
&= 4550
\end{aligned}
\]
Answer: \( \boxed{4550} \)

##### Problem (d): \( 236 \times 14 \)
\[
\begin{aligned}
236 \times 14 &= 236 \times (10 + 4) \\
&= (236 \times 10) + (236 \times 4) \\
&= 2360 + 944 \\
&= 3304
\end{aligned}
\]
Answer: \( \boxed{3304} \)

##### Problem (e): \( 139 \times 13 \)
\[
\begin{aligned}
139 \times 13 &= 139 \times (10 + 3) \\
&= (139 \times 10) + (139 \times 3) \\
&= 1390 + 417 \\
&= 1807
\end{aligned}
\]
Answer: \( \boxed{1807} \)

##### Problem (f): \( 243 \times 17 \)
\[
\begin{aligned}
243 \times 17 &= 243 \times (10 + 7) \\
&= (243 \times 10) + (243 \times 7) \\
&= 2430 + 1701 \\
&= 4131
\end{aligned}
\]
Answer: \( \boxed{4131} \)

---

#### Section 2: Division Problems

##### Problem (g): \( 108 \div 18 \)
\[
\begin{aligned}
108 \div 18 &= 6 \quad \text{(since } 18 \times 6 = 108\text{)}
\end{aligned}
\]
Answer: \( \boxed{6} \)

##### Problem (h): \( 102 \div 17 \)
\[
\begin{aligned}
102 \div 17 &= 6 \quad \text{(since } 17 \times 6 = 102\text{)}
\end{aligned}
\]
Answer: \( \boxed{6} \)

##### Problem (i): \( 91 \div 13 \)
\[
\begin{aligned}
91 \div 13 &= 7 \quad \text{(since } 13 \times 7 = 91\text{)}
\end{aligned}
\]
Answer: \( \boxed{7} \)

##### Problem (j): \( 98 \div 14 \)
\[
\begin{aligned}
98 \div 14 &= 7 \quad \text{(since } 14 \times 7 = 98\text{)}
\end{aligned}
\]
Answer: \( \boxed{7} \)

##### Problem (k): \( 255 \div 15 \)
\[
\begin{aligned}
255 \div 15 &= 17 \quad \text{(since } 15 \times 17 = 255\text{)}
\end{aligned}
\]
Answer: \( \boxed{17} \)

##### Problem (l): \( 90 \div 15 \)
\[
\begin{aligned}
90 \div 15 &= 6 \quad \text{(since } 15 \times 6 = 90\text{)}
\end{aligned}
\]
Answer: \( \boxed{6} \)

---

Final Answers:

\[
\begin{aligned}
&\text{(a)} \, \boxed{1651}, \quad \text{(b)} \, \boxed{4104}, \quad \text{(c)} \, \boxed{4550}, \quad \text{(d)} \, \boxed{3304}, \quad \text{(e)} \, \boxed{1807}, \quad \text{(f)} \, \boxed{4131}, \\
&\text{(g)} \, \boxed{6}, \quad \text{(h)} \, \boxed{6}, \quad \text{(i)} \, \boxed{7}, \quad \text{(j)} \, \boxed{7}, \quad \text{(k)} \, \boxed{17}, \quad \text{(l)} \, \boxed{6}.
\end{aligned}
\]

Final Boxed Answer:
\[
\boxed{1651, 4104, 4550, 3304, 1807, 4131, 6, 6, 7, 7, 17, 6}
\]