4th Grade Division Worksheets - Math Monks - Free Printable
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Step-by-step solution for: 4th Grade Division Worksheets - Math Monks
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Show Answer Key & Explanations
Step-by-step solution for: 4th Grade Division Worksheets - Math Monks
Let’s solve each division problem step by step. We’ll go one at a time, carefully checking our work.
---
1. 588 ÷ 3
- 3 goes into 5 once → 1 × 3 = 3 → subtract: 5 - 3 = 2
- Bring down 8 → 28
- 3 goes into 28 nine times → 9 × 3 = 27 → subtract: 28 - 27 = 1
- Bring down 8 → 18
- 3 goes into 18 six times → 6 × 3 = 18 → subtract: 0
✔ Answer: 196
---
2. 3,490 ÷ 15
We can do long division:
- 15 into 34 → 2 times (2×15=30) → 34-30=4
- Bring down 9 → 49
- 15 into 49 → 3 times (3×15=45) → 49-45=4
- Bring down 0 → 40
- 15 into 40 → 2 times (2×15=30) → 40-30=10 → remainder 10
But wait — let’s check if we did it right. Maybe better to think:
15 × 232 = ?
15 × 200 = 3000
15 × 30 = 450 → total 3450
15 × 2 = 30 → total 3480
3490 - 3480 = 10 → so yes, 232 R10
But maybe the problem expects exact? Let me recalculate:
Actually, 3490 ÷ 15:
Divide both by 5 first: 3490 ÷ 5 = 698; 15 ÷ 5 = 3 → now 698 ÷ 3
698 ÷ 3:
3 into 6 → 2
3 into 9 → 3
3 into 8 → 2 with remainder 2 → so 232 R2? Wait no — that was after dividing by 5.
Wait — I messed up. Better to do direct long division.
Long division of 3490 ÷ 15:
15 ) 3490
15 × 200 = 3000 → subtract from 3490 → 490 left
15 × 30 = 450 → too big for 490? No, 450 < 490 → 490 - 450 = 40
15 × 2 = 30 → 40 - 30 = 10 → so total 200 + 30 + 2 = 232, remainder 10
So answer is 232 R10, but since this is a practice sheet, maybe they want decimal or just quotient? Looking at other problems, some may have remainders.
But let’s see — perhaps I should write as mixed number or just quotient and remainder. Since it's elementary level, probably quotient and remainder.
But let me double-check with calculator-style:
15 × 232 = 3480 → 3490 - 3480 = 10 → yes.
✔ Answer: 232 R10
Wait — but in many school sheets, they might expect you to continue to decimals? But looking at the numbers, most are whole numbers or clean divisions. Let me check problem 3.
Actually, let’s hold on — maybe I made a mistake. Let me try again.
Alternative way: 3490 ÷ 15
Divide numerator and denominator by 5: 698 ÷ 3
Now 698 ÷ 3:
3 × 232 = 696 → remainder 2 → so 232 R2 for 698÷3, which means original is 232 R10? Because we divided by 5 earlier? No — when you divide dividend and divisor by same number, quotient stays same, remainder scales.
Actually, if A ÷ B = Q R R, then (A/k) ÷ (B/k) = Q R (R/k) only if k divides R.
This is getting messy. Better stick to long division.
I think 232 R10 is correct.
But let’s move on and come back if needed.
---
Actually, let me use a different approach for accuracy.
I'll calculate each using multiplication to verify.
But to save time, I’ll do careful long division for each.
Let me restart with all, systematically.
---
Problem 1: 588 ÷ 3
As above: 196 → verified.
Problem 2: 3490 ÷ 15
Do long division:
232
_______
15 | 3490
-30 (15×2)
----
49
-45 (15×3)
----
40
-30 (15×2)
----
10 ← remainder
So quotient 232, remainder 10.
✔ 232 R10
---
Problem 3: 7892 ÷ 15
Long division:
15 into 78 → 5 times (5×15=75) → 78-75=3
Bring down 9 → 39
15 into 39 → 2 times (30) → 39-30=9
Bring down 2 → 92
15 into 92 → 6 times (90) → 92-90=2
So quotient 526, remainder 2.
Check: 15 × 526 = 15×500=7500, 15×26=390 → total 7890 → 7892 - 7890 = 2 → yes.
✔ 526 R2
---
Problem 4: 8921 ÷ 9
9 into 89 → 9 times (81) → 89-81=8
Bring down 2 → 82
9 into 82 → 9 times (81) → 82-81=1
Bring down 1 → 11
9 into 11 → 1 time (9) → 11-9=2
Quotient: 991, remainder 2.
Check: 9×991 = 9×900=8100, 9×91=819 → total 8100+819=8919 → 8921-8919=2 → yes.
✔ 991 R2
---
Problem 5: 9810 ÷ 27
Let me see — 27 × 300 = 8100
9810 - 8100 = 1710
27 × 60 = 1620
1710 - 1620 = 90
27 × 3 = 81
90 - 81 = 9
So total: 300 + 60 + 3 = 363, remainder 9.
Check: 27 × 363 = ?
27×300=8100
27×60=1620 → total 9720
27×3=81 → total 9801
9810 - 9801 = 9 → yes.
✔ 363 R9
---
Problem 6: 1985 ÷ 19
19 into 198 → 10 times? 19×10=190 → 198-190=8
Bring down 5 → 85
19 into 85 → 4 times (76) → 85-76=9
So quotient 104, remainder 9.
Check: 19×104 = 19×100=1900, 19×4=76 → total 1976 → 1985-1976=9 → yes.
✔ 104 R9
---
Problem 7: 348 ÷ 3
Easy: 3 into 3=1, 3 into 4=1 rem 1, bring down 8→18, 3 into 18=6 → 116
Check: 3×116=348 → yes.
✔ 116
---
Problem 8: 1489 ÷ 4
4 into 14 → 3 (12) → rem 2
Bring down 8 → 28 → 4×7=28 → rem 0
Bring down 9 → 9 → 4×2=8 → rem 1
Quotient 372, remainder 1.
Check: 4×372=1488 → 1489-1488=1 → yes.
✔ 372 R1
---
Problem 9: 5489 ÷ 28
28 into 54 → 1 (28) → 54-28=26
Bring down 8 → 268
28 into 268 → 9 times? 28×9=252 → 268-252=16
Bring down 9 → 169
28 into 169 → 6 times (168) → rem 1
Quotient: 196, remainder 1.
Check: 28×196 = 28×200=5600 minus 28×4=112 → 5600-112=5488 → 5489-5488=1 → yes.
✔ 196 R1
---
Problem 10: 234 ÷ 16
16 into 23 → 1 (16) → rem 7
Bring down 4 → 74
16 into 74 → 4 times (64) → rem 10
Quotient 14, remainder 10.
Check: 16×14=224 → 234-224=10 → yes.
✔ 14 R10
---
Problem 11: 5679 ÷ 11
11 into 56 → 5 (55) → rem 1
Bring down 7 → 17 → 11×1=11 → rem 6
Bring down 9 → 69 → 11×6=66 → rem 3
Quotient 516, remainder 3.
Check: 11×516 = 11×500=5500, 11×16=176 → total 5676 → 5679-5676=3 → yes.
✔ 516 R3
---
Problem 12: 2892 ÷ 5
5 into 28 → 5 (25) → rem 3
Bring down 9 → 39 → 5×7=35 → rem 4
Bring down 2 → 42 → 5×8=40 → rem 2
Quotient 578, remainder 2.
Check: 5×578=2890 → 2892-2890=2 → yes.
✔ 578 R2
---
Problem 13: 2982 ÷ 36
36 into 298 → 8 times? 36×8=288 → 298-288=10
Bring down 2 → 102
36 into 102 → 2 times (72) → rem 30? Wait 36×2=72, 102-72=30
But 36×2=72, yes.
Quotient 82, remainder 30.
Check: 36×82 = 36×80=2880, 36×2=72 → total 2952 → 2982-2952=30 → yes.
✔ 82 R30
---
Problem 14: 5290 ÷ 42
42 into 52 → 1 (42) → rem 10
Bring down 9 → 109
42 into 109 → 2 times (84) → rem 25
Bring down 0 → 250
42 into 250 → 5 times (210) → rem 40
Quotient 125, remainder 40.
Check: 42×125 = 42×100=4200, 42×25=1050 → total 5250 → 5290-5250=40 → yes.
✔ 125 R40
---
Problem 15: 4928 ÷ 27
27 into 49 → 1 (27) → rem 22
Bring down 2 → 222
27 into 222 → 8 times? 27×8=216 → rem 6
Bring down 8 → 68
27 into 68 → 2 times (54) → rem 14
Quotient 182, remainder 14.
Check: 27×182 = 27×180=4860, 27×2=54 → total 4914 → 4928-4914=14 → yes.
✔ 182 R14
---
Problem 16: 380 ÷ 17
17 into 38 → 2 (34) → rem 4
Bring down 0 → 40
17 into 40 → 2 times (34) → rem 6
Quotient 22, remainder 6.
Check: 17×22=374 → 380-374=6 → yes.
✔ 22 R6
---
Now, compiling all answers:
1. 196
2. 232 R10
3. 526 R2
4. 991 R2
5. 363 R9
6. 104 R9
7. 116
8. 372 R1
9. 196 R1
10. 14 R10
11. 516 R3
12. 578 R2
13. 82 R30
14. 125 R40
15. 182 R14
16. 22 R6
Note: For problems without remainder, I wrote just the quotient. For others, quotient and remainder.
In some contexts, they might write as "quotient R remainder" or as mixed numbers, but since it's a practice sheet for division, remainder form is standard.
Final Answer:
1. 196
2. 232 R10
3. 526 R2
4. 991 R2
5. 363 R9
6. 104 R9
7. 116
8. 372 R1
9. 196 R1
10. 14 R10
11. 516 R3
12. 578 R2
13. 82 R30
14. 125 R40
15. 182 R14
16. 22 R6
---
1. 588 ÷ 3
- 3 goes into 5 once → 1 × 3 = 3 → subtract: 5 - 3 = 2
- Bring down 8 → 28
- 3 goes into 28 nine times → 9 × 3 = 27 → subtract: 28 - 27 = 1
- Bring down 8 → 18
- 3 goes into 18 six times → 6 × 3 = 18 → subtract: 0
✔ Answer: 196
---
2. 3,490 ÷ 15
We can do long division:
- 15 into 34 → 2 times (2×15=30) → 34-30=4
- Bring down 9 → 49
- 15 into 49 → 3 times (3×15=45) → 49-45=4
- Bring down 0 → 40
- 15 into 40 → 2 times (2×15=30) → 40-30=10 → remainder 10
But wait — let’s check if we did it right. Maybe better to think:
15 × 232 = ?
15 × 200 = 3000
15 × 30 = 450 → total 3450
15 × 2 = 30 → total 3480
3490 - 3480 = 10 → so yes, 232 R10
But maybe the problem expects exact? Let me recalculate:
Actually, 3490 ÷ 15:
Divide both by 5 first: 3490 ÷ 5 = 698; 15 ÷ 5 = 3 → now 698 ÷ 3
698 ÷ 3:
3 into 6 → 2
3 into 9 → 3
3 into 8 → 2 with remainder 2 → so 232 R2? Wait no — that was after dividing by 5.
Wait — I messed up. Better to do direct long division.
Long division of 3490 ÷ 15:
15 ) 3490
15 × 200 = 3000 → subtract from 3490 → 490 left
15 × 30 = 450 → too big for 490? No, 450 < 490 → 490 - 450 = 40
15 × 2 = 30 → 40 - 30 = 10 → so total 200 + 30 + 2 = 232, remainder 10
So answer is 232 R10, but since this is a practice sheet, maybe they want decimal or just quotient? Looking at other problems, some may have remainders.
But let’s see — perhaps I should write as mixed number or just quotient and remainder. Since it's elementary level, probably quotient and remainder.
But let me double-check with calculator-style:
15 × 232 = 3480 → 3490 - 3480 = 10 → yes.
✔ Answer: 232 R10
Wait — but in many school sheets, they might expect you to continue to decimals? But looking at the numbers, most are whole numbers or clean divisions. Let me check problem 3.
Actually, let’s hold on — maybe I made a mistake. Let me try again.
Alternative way: 3490 ÷ 15
Divide numerator and denominator by 5: 698 ÷ 3
Now 698 ÷ 3:
3 × 232 = 696 → remainder 2 → so 232 R2 for 698÷3, which means original is 232 R10? Because we divided by 5 earlier? No — when you divide dividend and divisor by same number, quotient stays same, remainder scales.
Actually, if A ÷ B = Q R R, then (A/k) ÷ (B/k) = Q R (R/k) only if k divides R.
This is getting messy. Better stick to long division.
I think 232 R10 is correct.
But let’s move on and come back if needed.
---
Actually, let me use a different approach for accuracy.
I'll calculate each using multiplication to verify.
But to save time, I’ll do careful long division for each.
Let me restart with all, systematically.
---
Problem 1: 588 ÷ 3
As above: 196 → verified.
Problem 2: 3490 ÷ 15
Do long division:
232
_______
15 | 3490
-30 (15×2)
----
49
-45 (15×3)
----
40
-30 (15×2)
----
10 ← remainder
So quotient 232, remainder 10.
✔ 232 R10
---
Problem 3: 7892 ÷ 15
Long division:
15 into 78 → 5 times (5×15=75) → 78-75=3
Bring down 9 → 39
15 into 39 → 2 times (30) → 39-30=9
Bring down 2 → 92
15 into 92 → 6 times (90) → 92-90=2
So quotient 526, remainder 2.
Check: 15 × 526 = 15×500=7500, 15×26=390 → total 7890 → 7892 - 7890 = 2 → yes.
✔ 526 R2
---
Problem 4: 8921 ÷ 9
9 into 89 → 9 times (81) → 89-81=8
Bring down 2 → 82
9 into 82 → 9 times (81) → 82-81=1
Bring down 1 → 11
9 into 11 → 1 time (9) → 11-9=2
Quotient: 991, remainder 2.
Check: 9×991 = 9×900=8100, 9×91=819 → total 8100+819=8919 → 8921-8919=2 → yes.
✔ 991 R2
---
Problem 5: 9810 ÷ 27
Let me see — 27 × 300 = 8100
9810 - 8100 = 1710
27 × 60 = 1620
1710 - 1620 = 90
27 × 3 = 81
90 - 81 = 9
So total: 300 + 60 + 3 = 363, remainder 9.
Check: 27 × 363 = ?
27×300=8100
27×60=1620 → total 9720
27×3=81 → total 9801
9810 - 9801 = 9 → yes.
✔ 363 R9
---
Problem 6: 1985 ÷ 19
19 into 198 → 10 times? 19×10=190 → 198-190=8
Bring down 5 → 85
19 into 85 → 4 times (76) → 85-76=9
So quotient 104, remainder 9.
Check: 19×104 = 19×100=1900, 19×4=76 → total 1976 → 1985-1976=9 → yes.
✔ 104 R9
---
Problem 7: 348 ÷ 3
Easy: 3 into 3=1, 3 into 4=1 rem 1, bring down 8→18, 3 into 18=6 → 116
Check: 3×116=348 → yes.
✔ 116
---
Problem 8: 1489 ÷ 4
4 into 14 → 3 (12) → rem 2
Bring down 8 → 28 → 4×7=28 → rem 0
Bring down 9 → 9 → 4×2=8 → rem 1
Quotient 372, remainder 1.
Check: 4×372=1488 → 1489-1488=1 → yes.
✔ 372 R1
---
Problem 9: 5489 ÷ 28
28 into 54 → 1 (28) → 54-28=26
Bring down 8 → 268
28 into 268 → 9 times? 28×9=252 → 268-252=16
Bring down 9 → 169
28 into 169 → 6 times (168) → rem 1
Quotient: 196, remainder 1.
Check: 28×196 = 28×200=5600 minus 28×4=112 → 5600-112=5488 → 5489-5488=1 → yes.
✔ 196 R1
---
Problem 10: 234 ÷ 16
16 into 23 → 1 (16) → rem 7
Bring down 4 → 74
16 into 74 → 4 times (64) → rem 10
Quotient 14, remainder 10.
Check: 16×14=224 → 234-224=10 → yes.
✔ 14 R10
---
Problem 11: 5679 ÷ 11
11 into 56 → 5 (55) → rem 1
Bring down 7 → 17 → 11×1=11 → rem 6
Bring down 9 → 69 → 11×6=66 → rem 3
Quotient 516, remainder 3.
Check: 11×516 = 11×500=5500, 11×16=176 → total 5676 → 5679-5676=3 → yes.
✔ 516 R3
---
Problem 12: 2892 ÷ 5
5 into 28 → 5 (25) → rem 3
Bring down 9 → 39 → 5×7=35 → rem 4
Bring down 2 → 42 → 5×8=40 → rem 2
Quotient 578, remainder 2.
Check: 5×578=2890 → 2892-2890=2 → yes.
✔ 578 R2
---
Problem 13: 2982 ÷ 36
36 into 298 → 8 times? 36×8=288 → 298-288=10
Bring down 2 → 102
36 into 102 → 2 times (72) → rem 30? Wait 36×2=72, 102-72=30
But 36×2=72, yes.
Quotient 82, remainder 30.
Check: 36×82 = 36×80=2880, 36×2=72 → total 2952 → 2982-2952=30 → yes.
✔ 82 R30
---
Problem 14: 5290 ÷ 42
42 into 52 → 1 (42) → rem 10
Bring down 9 → 109
42 into 109 → 2 times (84) → rem 25
Bring down 0 → 250
42 into 250 → 5 times (210) → rem 40
Quotient 125, remainder 40.
Check: 42×125 = 42×100=4200, 42×25=1050 → total 5250 → 5290-5250=40 → yes.
✔ 125 R40
---
Problem 15: 4928 ÷ 27
27 into 49 → 1 (27) → rem 22
Bring down 2 → 222
27 into 222 → 8 times? 27×8=216 → rem 6
Bring down 8 → 68
27 into 68 → 2 times (54) → rem 14
Quotient 182, remainder 14.
Check: 27×182 = 27×180=4860, 27×2=54 → total 4914 → 4928-4914=14 → yes.
✔ 182 R14
---
Problem 16: 380 ÷ 17
17 into 38 → 2 (34) → rem 4
Bring down 0 → 40
17 into 40 → 2 times (34) → rem 6
Quotient 22, remainder 6.
Check: 17×22=374 → 380-374=6 → yes.
✔ 22 R6
---
Now, compiling all answers:
1. 196
2. 232 R10
3. 526 R2
4. 991 R2
5. 363 R9
6. 104 R9
7. 116
8. 372 R1
9. 196 R1
10. 14 R10
11. 516 R3
12. 578 R2
13. 82 R30
14. 125 R40
15. 182 R14
16. 22 R6
Note: For problems without remainder, I wrote just the quotient. For others, quotient and remainder.
In some contexts, they might write as "quotient R remainder" or as mixed numbers, but since it's a practice sheet for division, remainder form is standard.
Final Answer:
1. 196
2. 232 R10
3. 526 R2
4. 991 R2
5. 363 R9
6. 104 R9
7. 116
8. 372 R1
9. 196 R1
10. 14 R10
11. 516 R3
12. 578 R2
13. 82 R30
14. 125 R40
15. 182 R14
16. 22 R6
Parent Tip: Review the logic above to help your child master the concept of division for 4th grade.