Division practice worksheet with multiple problems for math exercises.

Problem Description:

The task involves solving a series of division problems where each problem is in the format \( \text{divisor} \sqrt{\text{dividend}} \). This notation implies that we need to divide the dividend by the divisor.

Solution Approach:

1. Understand the Notation: The notation \( \text{divisor} \sqrt{\text{dividend}} \) means we are dividing the dividend by the divisor.
2. Perform Division: For each entry in the table, divide the number under the square root (the dividend) by the number before the square root (the divisor).
3. Simplify: Ensure that the result is simplified if possible.

Step-by-Step Solution:

#### First Row:
1. \( 2 \sqrt{18} \):
\[
\frac{18}{2} = 9
\]

2. \( 3 \sqrt{24} \):
\[
\frac{24}{3} = 8
\]

3. \( 4 \sqrt{32} \):
\[
\frac{32}{4} = 8
\]

4. \( 5 \sqrt{40} \):
\[
\frac{40}{5} = 8
\]

5. \( 6 \sqrt{48} \):
\[
\frac{48}{6} = 8
\]

#### Second Row:
1. \( 7 \sqrt{49} \):
\[
\frac{49}{7} = 7
\]

2. \( 2 \sqrt{12} \):
\[
\frac{12}{2} = 6
\]

3. \( 3 \sqrt{27} \):
\[
\frac{27}{3} = 9
\]

4. \( 4 \sqrt{28} \):
\[
\frac{28}{4} = 7
\]

5. \( 5 \sqrt{30} \):
\[
\frac{30}{5} = 6
\]

#### Third Row:
1. \( 8 \sqrt{56} \):
\[
\frac{56}{8} = 7
\]

2. \( 7 \sqrt{63} \):
\[
\frac{63}{7} = 9
\]

3. \( 2 \sqrt{14} \):
\[
\frac{14}{2} = 7
\]

4. \( 3 \sqrt{18} \):
\[
\frac{18}{3} = 6
\]

5. \( 4 \sqrt{36} \):
\[
\frac{36}{4} = 9
\]

#### Fourth Row:
1. \( 9 \sqrt{72} \):
\[
\frac{72}{9} = 8
\]

2. \( 8 \sqrt{72} \):
\[
\frac{72}{8} = 9
\]

3. \( 7 \sqrt{56} \):
\[
\frac{56}{7} = 8
\]

4. \( 2 \sqrt{16} \):
\[
\frac{16}{2} = 8
\]

5. \( 3 \sqrt{21} \):
\[
\frac{21}{3} = 7
\]

#### Fifth Row:
1. \( 6 \sqrt{54} \):
\[
\frac{54}{6} = 9
\]

2. \( 9 \sqrt{81} \):
\[
\frac{81}{9} = 9
\]

3. \( 8 \sqrt{48} \):
\[
\frac{48}{8} = 6
\]

4. \( 7 \sqrt{42} \):
\[
\frac{42}{7} = 6
\]

5. \( 2 \sqrt{10} \):
\[
\frac{10}{2} = 5
\]

#### Sixth Row:
1. \( 9 \sqrt{45} \):
\[
\frac{45}{9} = 5
\]

2. \( 6 \sqrt{42} \):
\[
\frac{42}{6} = 7
\]

3. \( 9 \sqrt{63} \):
\[
\frac{63}{9} = 7
\]

4. \( 8 \sqrt{64} \):
\[
\frac{64}{8} = 8
\]

5. \( 7 \sqrt{35} \):
\[
\frac{35}{7} = 5
\]

Final Answer:

\[
\boxed{
\begin{array}{ccccc}
9 & 8 & 8 & 8 & 8 \\
7 & 6 & 9 & 7 & 6 \\
7 & 9 & 7 & 6 & 9 \\
8 & 9 & 8 & 8 & 7 \\
9 & 9 & 6 & 6 & 5 \\
5 & 7 & 7 & 8 & 5 \\
\end{array}
}
\]