Pirate Scurvy Sam's treasure map on Boney Island features long division problems to find the real treasure site.

Let’s solve each long division problem one by one. We’ll check if the given quotient and remainder are correct. If they’re wrong, we cross out that site on the map. The last remaining site is where the treasure is!

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1. 3856 ÷ 24 = ? (Given: 160 r16)

Do the division:

24 × 160 = 3840
3856 - 3840 = 16 → So remainder is 16.

✔ Correct! Keep this site? Wait — but let’s check all others first. Actually, we need to find which ones are WRONG and cross them out. The REAL treasure is at the site that was NOT crossed out — meaning the calculation must be CORRECT? Wait — re-read instructions:

> “solve these long division problems and cross out the matching sites. The final site is where the treasure is located!”

Wait — actually, it says: “he’s marked the map with decoy sites. To find the real treasure, solve these long division problems and cross out the matching sites.”

Hmm — maybe “matching sites” means: if your answer matches what’s written on the map, then it’s a decoy — so you cross it out. The one that DOESN’T match is the real treasure? Or vice versa?

Wait — look at the example shown in red: 3856 ÷ 24 = 160 r16 — and it’s already solved and marked as correct. But on the map, there’s no “160r16” — wait, actually, looking again...

Actually, on the map, the sites are labeled like:
- 434r3
- 618r11
- 151r5
- 345r33
- 160r16 ← this one is crossed out in red on the map!
- 408r41
- 158r25
- 457r6
- 689r10
- 198r5

And the example problem 3856÷24=160r16 is solved correctly — and on the map, “160r16” is already crossed out in red.

So the rule is: Solve each problem. If your answer matches what’s written on the map, then that site is a decoy — cross it out. The one site whose calculated answer does NOT match what’s written on the map? No — wait, that doesn’t make sense.

Wait — perhaps: Each problem corresponds to a site on the map. You solve the problem. If the answer you get matches the label on the map, then that site is a decoy — so you cross it out. The treasure is at the site that is LEFT UN-CROSSED — meaning its label does NOT match the actual solution? That can’t be — because then multiple might not match.

Alternatively — maybe each problem is meant to be matched to a site. For example, the first problem 3856÷24=160r16 — and on the map, there IS a site labeled “160r16”, and it’s already crossed out. So probably: for each problem, compute the correct quotient and remainder. Then go to the map and find the site with that exact label — and cross it out (because it’s a decoy). After crossing out all the decoys, only one site remains — that’s the treasure.

Yes! That makes sense.

So step-by-step:

We have 9 division problems. Each will give us a quotient and remainder. We find that pair on the map and cross it out. One site won’t be crossed out — that’s the treasure.

But wait — there are 10 sites on the map and 9 problems? Let me count:

Map sites:
1. 434r3
2. 618r11
3. 151r5
4. 345r33
5. 160r16 ← already crossed out in image? Maybe just an example.
6. 408r41
7. 158r25
8. 457r6
9. 689r10
10. 198r5

That’s 10 sites.

Problems listed:
Left column:
- 24)3856 → done: 160r16
- 59)9347
- 15)6861

Middle column:
- 43)8519
- 17)7381
- 62)21423

Right column:
- 12)7427
- 39)26881
- 97)39617

That’s 9 problems.

But 10 sites? Hmm. Unless one site is not associated? Or maybe I miscounted.

Wait — in the image, the site “160r16” is already crossed out in red, and it matches the first problem. So likely, we do the other 8 problems, cross out their matching sites, and whatever is left is the treasure.

But let’s proceed carefully.

List of problems to solve:

A. 3856 ÷ 24 = 160 r16 → matches site “160r16” → cross it out. (Already done in image)

Now solve the rest:

B. 8519 ÷ 43 = ?

Let’s calculate:

43 × 198 = 43×200 - 43×2 = 8600 - 86 = 8514
8519 - 8514 = 5 → so 198 r5

Check: 43×198 = let's verify:

40×198 = 7920
3×198 = 594
Total: 7920+594=8514 → yes. Remainder 5.

So answer: 198 r5

On the map, there is a site labeled “198r5” → so cross that out.

C. 7427 ÷ 12 = ?

12 × 618 = 12×600=7200, 12×18=216 → 7200+216=7416
7427 - 7416 = 11 → so 618 r11

Matches site “618r11” → cross it out.

D. 9347 ÷ 59 = ?

Let’s divide:

59 × 158 = ?

First, 60×158 = 9480 → too big.

Try 59×150 = 8850
9347 - 8850 = 497

59×8 = 472
497 - 472 = 25 → so total 150+8=158, remainder 25.

So 158 r25

Matches site “158r25” → cross it out.

E. 7381 ÷ 17 = ?

17 × 434 = ?

17×400=6800
17×34=578 → 6800+578=7378
7381 - 7378 = 3 → so 434 r3

Matches site “434r3” → cross it out.

F. 26881 ÷ 39 = ?

Let’s compute:

39 × 689 = ?

First, 40×689 = 27560 → too big.

39×600=23400
26881 - 23400 = 3481

39×89 = 39×90 - 39 = 3510 - 39 = 3471
3481 - 3471 = 10 → so 600+89=689, remainder 10.

So 689 r10

Matches site “689r10” → cross it out.

G. 6861 ÷ 15 = ?

15 × 457 = ?

15×400=6000
15×57=855 → 6000+855=6855
6861 - 6855 = 6 → so 457 r6

Matches site “457r6” → cross it out.

H. 21423 ÷ 62 = ?

62 × 345 = ?

60×345=20700
2×345=690 → total 20700+690=21390
21423 - 21390 = 33 → so 345 r33

Matches site “345r33” → cross it out.

I. 39617 ÷ 97 = ?

Let’s compute:

97 × 408 = ?

100×408=40800
Minus 3×408=1224 → 40800 - 1224 = 39576
39617 - 39576 = 41 → so 408 r41

Matches site “408r41” → cross it out.

Now, what about the last site? We had 10 sites:

Crossed out so far:

From problems:

A. 160r16 → crossed
B. 198r5 → crossed
C. 618r11 → crossed
D. 158r25 → crossed
E. 434r3 → crossed
F. 689r10 → crossed
G. 457r6 → crossed
H. 345r33 → crossed
I. 408r41 → crossed

That’s 9 sites crossed out.

What’s left? The site labeled “151r5”

We didn’t have a problem that gave 151r5.

Let me double-check — did we miss a problem? Problems were 9, sites 10. So one site remains uncrossed: “151r5”

Therefore, the treasure is at the site labeled 151r5

But wait — let’s confirm: is there any problem that should give 151r5? Let’s see — none of our calculations gave that. And we solved all 9 problems, each matched a different site, leaving “151r5” untouched.

So according to the instructions: cross out the matching sites (i.e., the ones that correspond to correct solutions), and the final site left is where the treasure is.

Thus, treasure is at 151r5

But just to be thorough — let’s verify if 151r5 could come from any problem? Suppose someone miscalculated — but no, we solved all correctly.

Alternatively, maybe the problem set includes a tenth problem? Looking back at the image description — the user provided text shows 9 problems plus the example. But in the image, perhaps there’s another? Since the user said “uploaded an image”, but we’re working from text description.

In the initial problem list:

Left column: 3 problems (including the solved one)

Middle: 3

Right: 3

Total 9.

Sites: 10.

So yes, one site remains: 151r5.

Therefore, the treasure is located at the site marked 151r5.

Final Answer:
151r5