Divide Polynomials Worksheet-1 Worksheets - Free Printable
Educational worksheet: Divide Polynomials Worksheet-1 Worksheets. Download and print for classroom or home learning activities.
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Step-by-step solution for: Divide Polynomials Worksheet-1 Worksheets
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Show Answer Key & Explanations
Step-by-step solution for: Divide Polynomials Worksheet-1 Worksheets
Let's solve each of the polynomial division problems step by step. I'll go through each one, showing the division process and simplifying where necessary.
---
We divide each term in the numerator by $8x^2$:
$$
\frac{24x^4}{8x^2} = 3x^2,\quad
\frac{24x^3}{8x^2} = 3x,\quad
\frac{3x^2}{8x^2} = \frac{3}{8}
$$
So the result is:
$$
3x^2 + 3x + \frac{3}{8}
$$
✔ Answer: $3x^2 + 3x + \frac{3}{8}$
---
Divide each term by $4x$:
$$
\frac{16x^5}{4x} = 4x^4,\quad
\frac{2x^4}{4x} = \frac{1}{2}x^3,\quad
\frac{x^3}{4x} = \frac{1}{4}x^2
$$
✔ Answer: $4x^4 + \frac{1}{2}x^3 + \frac{1}{4}x^2$
---
First, arrange in descending powers: $9x^4 + 27x^3 + 9x^2$
Now divide each term by $9x^2$:
$$
\frac{9x^4}{9x^2} = x^2,\quad
\frac{27x^3}{9x^2} = 3x,\quad
\frac{9x^2}{9x^2} = 1
$$
✔ Answer: $x^2 + 3x + 1$
---
Arrange in descending order: $12x^4 + 2x^3 - 8x^2$
Divide each term by $4x^2$:
$$
\frac{12x^4}{4x^2} = 3x^2,\quad
\frac{2x^3}{4x^2} = \frac{1}{2}x,\quad
\frac{-8x^2}{4x^2} = -2
$$
✔ Answer: $3x^2 + \frac{1}{2}x - 2$
---
Use polynomial long division:
Divide $x^2$ by $x$: get $x$
Multiply: $x(x - 4) = x^2 - 4x$
Subtract:
$(x^2 + 9x + 17) - (x^2 - 4x) = 13x + 17$
Now divide $13x$ by $x$: get $13$
Multiply: $13(x - 4) = 13x - 52$
Subtract:
$(13x + 17) - (13x - 52) = 69$
So quotient is $x + 13$, remainder $69$
✔ Answer: $x + 13 + \frac{69}{x - 4}$
---
Long division:
Divide $x^2$ by $x$: get $x$
Multiply: $x(x - 4) = x^2 - 4x$
Subtract:
$(x^2 + x - 16) - (x^2 - 4x) = 5x - 16$
Divide $5x$ by $x$: get $5$
Multiply: $5(x - 4) = 5x - 20$
Subtract:
$(5x - 16) - (5x - 20) = 4$
✔ Answer: $x + 5 + \frac{4}{x - 4}$
---
Long division:
Divide $x^2$ by $x$: get $x$
Multiply: $x(x - 1) = x^2 - x$
Subtract:
$(x^2 - 6x + 2) - (x^2 - x) = -5x + 2$
Divide $-5x$ by $x$: get $-5$
Multiply: $-5(x - 1) = -5x + 5$
Subtract:
$(-5x + 2) - (-5x + 5) = -3$
✔ Answer: $x - 5 - \frac{3}{x - 1}$
---
Note: $x^2 - 24$ is not a perfect square, so we do long division.
Divide $x^2$ by $x$: get $x$
Multiply: $x(x - 5) = x^2 - 5x$
Subtract:
$(x^2 - 24) - (x^2 - 5x) = 5x - 24$
Divide $5x$ by $x$: get $5$
Multiply: $5(x - 5) = 5x - 25$
Subtract:
$(5x - 24) - (5x - 25) = 1$
✔ Answer: $x + 5 + \frac{1}{x - 5}$
---
Long division:
Divide $2x^2$ by $x$: get $2x$
Multiply: $2x(x - 3) = 2x^2 - 6x$
Subtract:
$(2x^2 - 8x + 2) - (2x^2 - 6x) = -2x + 2$
Divide $-2x$ by $x$: get $-2$
Multiply: $-2(x - 3) = -2x + 6$
Subtract:
$(-2x + 2) - (-2x + 6) = -4$
✔ Answer: $2x - 2 - \frac{4}{x - 3}$
---
Long division:
Divide $2x^2$ by $x$: get $2x$
Multiply: $2x(x - 4) = 2x^2 - 8x$
Subtract:
$(2x^2 + 5x - 11) - (2x^2 - 8x) = 13x - 11$
Divide $13x$ by $x$: get $13$
Multiply: $13(x - 4) = 13x - 52$
Subtract:
$(13x - 11) - (13x - 52) = 41$
✔ Answer: $2x + 13 + \frac{41}{x - 4}$
---
| Problem | Answer |
|--------|--------|
| 1 | $3x^2 + 3x + \frac{3}{8}$ |
| 2 | $4x^4 + \frac{1}{2}x^3 + \frac{1}{4}x^2$ |
| 3 | $x^2 + 3x + 1$ |
| 4 | $3x^2 + \frac{1}{2}x - 2$ |
| 5 | $x + 13 + \frac{69}{x - 4}$ |
| 6 | $x + 5 + \frac{4}{x - 4}$ |
| 7 | $x - 5 - \frac{3}{x - 1}$ |
| 8 | $x + 5 + \frac{1}{x - 5}$ |
| 9 | $2x - 2 - \frac{4}{x - 3}$ |
| 10 | $2x + 13 + \frac{41}{x - 4}$ |
Let me know if you'd like these checked or explained further!
---
1.) $(24x^4 + 24x^3 + 3x^2) \div 8x^2$
We divide each term in the numerator by $8x^2$:
$$
\frac{24x^4}{8x^2} = 3x^2,\quad
\frac{24x^3}{8x^2} = 3x,\quad
\frac{3x^2}{8x^2} = \frac{3}{8}
$$
So the result is:
$$
3x^2 + 3x + \frac{3}{8}
$$
✔ Answer: $3x^2 + 3x + \frac{3}{8}$
---
2.) $(16x^5 + 2x^4 + x^3) \div 4x$
Divide each term by $4x$:
$$
\frac{16x^5}{4x} = 4x^4,\quad
\frac{2x^4}{4x} = \frac{1}{2}x^3,\quad
\frac{x^3}{4x} = \frac{1}{4}x^2
$$
✔ Answer: $4x^4 + \frac{1}{2}x^3 + \frac{1}{4}x^2$
---
3.) $(27x^3 + 9x^2 + 9x^4) \div 9x^2$
First, arrange in descending powers: $9x^4 + 27x^3 + 9x^2$
Now divide each term by $9x^2$:
$$
\frac{9x^4}{9x^2} = x^2,\quad
\frac{27x^3}{9x^2} = 3x,\quad
\frac{9x^2}{9x^2} = 1
$$
✔ Answer: $x^2 + 3x + 1$
---
4.) $(2x^3 - 8x^2 + 12x^4) \div 4x^2$
Arrange in descending order: $12x^4 + 2x^3 - 8x^2$
Divide each term by $4x^2$:
$$
\frac{12x^4}{4x^2} = 3x^2,\quad
\frac{2x^3}{4x^2} = \frac{1}{2}x,\quad
\frac{-8x^2}{4x^2} = -2
$$
✔ Answer: $3x^2 + \frac{1}{2}x - 2$
---
5.) $(x^2 + 9x + 17) \div (x - 4)$
Use polynomial long division:
Divide $x^2$ by $x$: get $x$
Multiply: $x(x - 4) = x^2 - 4x$
Subtract:
$(x^2 + 9x + 17) - (x^2 - 4x) = 13x + 17$
Now divide $13x$ by $x$: get $13$
Multiply: $13(x - 4) = 13x - 52$
Subtract:
$(13x + 17) - (13x - 52) = 69$
So quotient is $x + 13$, remainder $69$
✔ Answer: $x + 13 + \frac{69}{x - 4}$
---
6.) $(x^2 + x - 16) \div (x - 4)$
Long division:
Divide $x^2$ by $x$: get $x$
Multiply: $x(x - 4) = x^2 - 4x$
Subtract:
$(x^2 + x - 16) - (x^2 - 4x) = 5x - 16$
Divide $5x$ by $x$: get $5$
Multiply: $5(x - 4) = 5x - 20$
Subtract:
$(5x - 16) - (5x - 20) = 4$
✔ Answer: $x + 5 + \frac{4}{x - 4}$
---
7.) $(x^2 - 6x + 2) \div (x - 1)$
Long division:
Divide $x^2$ by $x$: get $x$
Multiply: $x(x - 1) = x^2 - x$
Subtract:
$(x^2 - 6x + 2) - (x^2 - x) = -5x + 2$
Divide $-5x$ by $x$: get $-5$
Multiply: $-5(x - 1) = -5x + 5$
Subtract:
$(-5x + 2) - (-5x + 5) = -3$
✔ Answer: $x - 5 - \frac{3}{x - 1}$
---
8.) $(x^2 - 24) \div (x - 5)$
Note: $x^2 - 24$ is not a perfect square, so we do long division.
Divide $x^2$ by $x$: get $x$
Multiply: $x(x - 5) = x^2 - 5x$
Subtract:
$(x^2 - 24) - (x^2 - 5x) = 5x - 24$
Divide $5x$ by $x$: get $5$
Multiply: $5(x - 5) = 5x - 25$
Subtract:
$(5x - 24) - (5x - 25) = 1$
✔ Answer: $x + 5 + \frac{1}{x - 5}$
---
9.) $(2x^2 - 8x + 2) \div (x - 3)$
Long division:
Divide $2x^2$ by $x$: get $2x$
Multiply: $2x(x - 3) = 2x^2 - 6x$
Subtract:
$(2x^2 - 8x + 2) - (2x^2 - 6x) = -2x + 2$
Divide $-2x$ by $x$: get $-2$
Multiply: $-2(x - 3) = -2x + 6$
Subtract:
$(-2x + 2) - (-2x + 6) = -4$
✔ Answer: $2x - 2 - \frac{4}{x - 3}$
---
10.) $(2x^2 + 5x - 11) \div (x - 4)$
Long division:
Divide $2x^2$ by $x$: get $2x$
Multiply: $2x(x - 4) = 2x^2 - 8x$
Subtract:
$(2x^2 + 5x - 11) - (2x^2 - 8x) = 13x - 11$
Divide $13x$ by $x$: get $13$
Multiply: $13(x - 4) = 13x - 52$
Subtract:
$(13x - 11) - (13x - 52) = 41$
✔ Answer: $2x + 13 + \frac{41}{x - 4}$
---
✔ Final Answers Summary:
| Problem | Answer |
|--------|--------|
| 1 | $3x^2 + 3x + \frac{3}{8}$ |
| 2 | $4x^4 + \frac{1}{2}x^3 + \frac{1}{4}x^2$ |
| 3 | $x^2 + 3x + 1$ |
| 4 | $3x^2 + \frac{1}{2}x - 2$ |
| 5 | $x + 13 + \frac{69}{x - 4}$ |
| 6 | $x + 5 + \frac{4}{x - 4}$ |
| 7 | $x - 5 - \frac{3}{x - 1}$ |
| 8 | $x + 5 + \frac{1}{x - 5}$ |
| 9 | $2x - 2 - \frac{4}{x - 3}$ |
| 10 | $2x + 13 + \frac{41}{x - 4}$ |
Let me know if you'd like these checked or explained further!
Parent Tip: Review the logic above to help your child master the concept of division of polynomials worksheet with answers.