Let’s solve each division problem step by step. We’ll find how many times the divisor fits into the dividend (that’s the quotient), and what’s left over (that’s the remainder).
We’ll go one by one:
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12 ÷ 7
7 goes into 12 once (7 × 1 = 7).
Subtract: 12 - 7 = 5 → that’s the remainder.
→
1 R 5
20 ÷ 8
8 goes into 20 twice (8 × 2 = 16).
Subtract: 20 - 16 = 4 → remainder.
→
2 R 4
14 ÷ 3
3 goes into 14 four times (3 × 4 = 12).
Subtract: 14 - 12 = 2 → remainder.
→
4 R 2
16 ÷ 7
7 goes into 16 twice (7 × 2 = 14).
Subtract: 16 - 14 = 2 → remainder.
→
2 R 2
49 ÷ 9
9 goes into 49 five times (9 × 5 = 45).
Subtract: 49 - 45 = 4 → remainder.
→
5 R 4
26 ÷ 4
4 goes into 26 six times (4 × 6 = 24).
Subtract: 26 - 24 = 2 → remainder.
→
6 R 2
36 ÷ 5
5 goes into 36 seven times (5 × 7 = 35).
Subtract: 36 - 35 = 1 → remainder.
→
7 R 1
43 ÷ 6
6 goes into 43 seven times (6 × 7 = 42).
Subtract: 43 - 42 = 1 → remainder.
→
7 R 1
60 ÷ 9
9 goes into 60 six times (9 × 6 = 54).
Subtract: 60 - 54 = 6 → remainder.
→
6 R 6
12 ÷ 5
5 goes into 12 two times (5 × 2 = 10).
Subtract: 12 - 10 = 2 → remainder.
→
2 R 2
22 ÷ 5
5 goes into 22 four times (5 × 4 = 20).
Subtract: 22 - 20 = 2 → remainder.
→
4 R 2
40 ÷ 7
7 goes into 40 five times (7 × 5 = 35).
Subtract: 40 - 35 = 5 → remainder.
→
5 R 5
36 ÷ 7
7 goes into 36 five times (7 × 5 = 35).
Subtract: 36 - 35 = 1 → remainder.
→
5 R 1
25 ÷ 6
6 goes into 25 four times (6 × 4 = 24).
Subtract: 25 - 24 = 1 → remainder.
→
4 R 1
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Final Answer:
12÷7= 1 R 5
20÷8= 2 R 4
14÷3= 4 R 2
16÷7= 2 R 2
49÷9= 5 R 4
26÷4= 6 R 2
36÷5= 7 R 1
43÷6= 7 R 1
60÷9= 6 R 6
12÷5= 2 R 2
22÷5= 4 R 2
40÷7= 5 R 5
36÷7= 5 R 1
25÷6= 4 R 1
Parent Tip: Review the logic above to help your child master the concept of division with remainder worksheet 3 grade.
