Division worksheets for kids to practice dividing numbers, including a sample problem and multiple exercises.

Let’s solve each division problem step by step. We’ll go one at a time, using long division or mental math where possible.

---

First row (left page):

1. 20 ÷ 10
→ 10 goes into 20 exactly 2 times.
✔ Answer: 2

2. 45 ÷ 5
→ 5 × 9 = 45
✔ Answer: 9

3. 36 ÷ 11
→ 11 × 3 = 33, remainder 3
But since this is likely expecting whole number answers (as per sample), we write quotient and remainder if needed. However, looking at the sample, it shows full division with remainder 0 — so maybe only exact divisions? Wait — let’s check all problems.

Actually, looking again — some of these won’t divide evenly. Let’s do them properly as long division, writing quotient and remainder if needed. But in elementary worksheets like this, sometimes they expect just the quotient (whole number part) or maybe remainders are allowed. Since the sample showed “7” with remainder 0, and no remainder written, perhaps we should assume only exact divisions? But that can’t be — for example, 13 ÷ 7 is not exact.

Wait — let me recheck the image description. The user said “solve the problem accurately”. So we must compute each correctly.

But note: In many such worksheets, especially for younger students, they may expect the answer as “quotient R remainder” or just the quotient. Looking at the layout — there’s space under each problem, similar to the sample which wrote “7” above and then subtracted. So probably, we’re to perform long division and write the quotient (and possibly remainder).

However, since the instruction says “solve accurately”, I will compute each as integer division with remainder, but present the answer as “quotient” if it divides evenly, or “quotient R remainder” if not — BUT wait, looking at the format of the worksheet, in the sample, they wrote:

```
7
12)84
84
0
```

So they show the full process. But for our purpose, since we’re giving final answers, and the student is to fill in the blank above the dividend, we should give the quotient (the number on top). If there’s a remainder, it might be expected to write it too — but in many cases, especially at this level, if it doesn’t divide evenly, they might still want the quotient and note the remainder separately. However, looking at the problems, several do not divide evenly.

Let me list all problems and solve them carefully.

---

Left Page Problems:

#### Row 1:
- 20 ÷ 10 = 2 (exact)
- 45 ÷ 5 = 9 (exact)
- 36 ÷ 11 → 11×3=33, remainder 3 → Quotient = 3, Remainder = 3

But how to present? Since the sample didn’t have remainder, and the box was only for quotient, perhaps we only write the quotient? But that would be inaccurate for non-exact divisions.

Wait — let’s look at the right page — same thing. Maybe the worksheet expects only the quotient (integer part), ignoring remainder? That’s common in early grades.

Alternatively, perhaps I misread — let me double-check the numbers.

Actually, let’s calculate every single one precisely.

I think the safest way is to provide the quotient (how many times the divisor fits completely), and if there’s a remainder, mention it — but since the response format asks for “Final Answer” as a list, perhaps we list quotients only? Or include remainders?

Looking back at the user’s request: “Solve the problem accurately.” And the sample shows full division with remainder 0. So for accuracy, we should indicate if there’s a remainder.

But in the context of filling out the worksheet, the child would write the quotient above the dividend, and perhaps write the remainder below or beside. Since we’re providing answers, I’ll give both quotient and remainder where applicable, formatted as “Q R R”.

However, to match typical worksheet expectations, and since the sample only showed the quotient (7), I suspect they want only the quotient — even if there’s a remainder. But that would be misleading.

Wait — let’s test one: 13 ÷ 7. 7×1=7, 13-7=6, so quotient 1, remainder 6. If we only write 1, it’s incomplete.

Perhaps the worksheet is designed so that all problems divide evenly? Let me verify each.

Left page:

Row 1:
- 20 ÷ 10 = 2 ✔️
- 45 ÷ 5 = 9 ✔️
- 36 ÷ 11 = 3.27... → Not integer. 11*3=33, rem 3.

Row 2:
- 13 ÷ 7 = 1 rem 6
- 54 ÷ 18 = 3 ✔️ (18*3=54)
- 49 ÷ 7 = 7 ✔️
- 69 ÷ 3 = 23 ✔️ (3*23=69)

Row 3:
- 51 ÷ 9 = 5 rem 6 (9*5=45, 51-45=6)
- 17 ÷ 12 = 1 rem 5
- 70 ÷ 14 = 5 ✔️ (14*5=70)
- 96 ÷ 16 = 6 ✔️ (16*6=96)

Right page:

Row 1:
- 80 ÷ 10 = 8 ✔️
- 45 ÷ 15 = 3 ✔️
- 88 ÷ 13 = 6 rem 10 (13*6=78, 88-78=10)
- 96 ÷ 12 = 8 ✔️

Row 2:
- 38 ÷ 19 = 2 ✔️
- 55 ÷ 20 = 2 rem 15 (20*2=40, 55-40=15)
- 115 ÷ 15 = 7 rem 10 (15*7=105, 115-105=10)
- 60 ÷ 12 = 5 ✔️

Row 3:
- 85 ÷ 17 = 5 ✔️ (17*5=85)
- 91 ÷ 11 = 8 rem 3 (11*8=88, 91-88=3)
- 64 ÷ 16 = 4 ✔️
- 38 ÷ 19 = 2 ✔️

So many have remainders. Therefore, to be accurate, we must report quotient and remainder.

But how to format the final answer? The user said “provide only the final correct answer” after reasoning. And it’s a list of problems.

Perhaps we can list them in order, with quotient and remainder where needed.

Since the worksheet has spaces for the quotient above, and possibly remainder below, but for our answer, I'll write each as "quotient" if exact, or "quotient R remainder" if not.

Let me compile all answers in order, left to right, top to bottom for each page.

---

Left Page Answers (in order):

1. 20 ÷ 10 = 2
2. 45 ÷ 5 = 9
3. 36 ÷ 11 = 3 R 3
4. 13 ÷ 7 = 1 R 6
5. 54 ÷ 18 = 3
6. 49 ÷ 7 = 7
7. 69 ÷ 3 = 23
8. 51 ÷ 9 = 5 R 6
9. 17 ÷ 12 = 1 R 5
10. 70 ÷ 14 = 5
11. 96 ÷ 16 = 6

Wait, left page has 3 rows of 4 problems? Let me count:

From image description:

Left page:
- First row: 10)20, 5)45, 11)36 → 3 problems? No, earlier I thought 4, but let's see:

In the text:
"10)20 5)45 11)36" — that's three in first row? But then next line: "7)13 18)54 7)49 3)69" — four? Inconsistent.

Looking back at user's input:

For left page:
After sample, it says:
"10)20 5)45 11)36" — that's three
Then "7)13 18)54 7)49 3)69" — four
Then "9)51 12)17 14)70 16)96" — four

That's 3+4+4=11 problems? But typically worksheets are symmetric. Perhaps I miscounted.

Actually, in the initial description, it might be formatted as:

Left page:
- Top row: three problems? But let's read carefully:

User wrote:
"10)20 5)45 11)36" — likely three
Then below: "7)13 18)54 7)49 3)69" — four
Then: "9)51 12)17 14)70 16)96" — four

Total 11 on left? But right page:

"10)80 15)45 13)88 12)96" — four
"19)38 20)55 15)115 12)60" — four
"17)85 11)91 16)64 19)38" — four

Total 12 on right? That doesn't make sense. Probably a formatting issue in the user's message.

Looking at the actual image description (though I can't see it, based on standard worksheets), it's likely that each page has 12 problems arranged in 3 rows of 4.

In the user's text for left page:
After sample, it says:
"10)20 5)45 11)36" — but that might be missing one? Or perhaps it's "10)20, 5)45, 11)36" and then the next line starts with "7)13" etc.

To resolve, let's assume each page has 12 problems, as is standard.

From common practice, and to match the right page having 4 per row, likely left page also has 4 per row.

In the user's message for left page:
It says:
"10)20 5)45 11)36" — perhaps this is incomplete, or maybe it's three, but then "7)13 18)54 7)49 3)69" is four, so total 7, then "9)51 12)17 14)70 16)96" is four more, total 11. Missing one?

Perhaps the first row is "10)20, 5)45, 11)36" and that's it for row 1, but usually it's symmetric. Another possibility: the "Sample" is separate, and the problems start after.

Let's list all problems mentioned for left page from user's text:

- 10)20
- 5)45
- 11)36
- 7)13
- 18)54
- 7)49
- 3)69
- 9)51
- 12)17
- 14)70
- 16)96

That's 11. But 12 is expected. Perhaps I missed one. In the text: "10)20 5)45 11)36" — maybe it's "10)20, 5)45, 11)36" and then the next is "7)13" etc., but no fourth in first row.

For the sake of completing, I'll use the problems as listed in the user's message, and for right page, it's clear: 12 problems.

Right page from user:
"10)80 15)45 13)88 12)96" — 4
"19)38 20)55 15)115 12)60" — 4
"17)85 11)91 16)64 19)38" — 4
Total 12.

Left page has 11 listed, but perhaps it's a typo, and it's meant to be 12. To be safe, I'll solve the ones listed.

But let's proceed with the calculations for all mentioned.

Perhaps in the left page, the first row is three problems, but that's unusual. Another idea: in the user's message, for left page, after "Sample", it says "10)20 5)45 11)36" — but maybe it's "10)20, 5)45, 11)36" and then the next line is "7)13, 18)54, 7)49, 3)69" — so first row has 3, second has 4, third has 4, total 11. Okay, we'll go with that.

So left page problems (11):

1. 20 ÷ 10 = 2
2. 45 ÷ 5 = 9
3. 36 ÷ 11 = 3 R 3
4. 13 ÷ 7 = 1 R 6
5. 54 ÷ 18 = 3
6. 49 ÷ 7 = 7
7. 69 ÷ 3 = 23
8. 51 ÷ 9 = 5 R 6
9. 17 ÷ 12 = 1 R 5
10. 70 ÷ 14 = 5
11. 96 ÷ 16 = 6

Right page problems (12):

1. 80 ÷ 10 = 8
2. 45 ÷ 15 = 3
3. 88 ÷ 13 = 6 R 10 (since 13*6=78, 88-78=10)
4. 96 ÷ 12 = 8
5. 38 ÷ 19 = 2
6. 55 ÷ 20 = 2 R 15 (20*2=40, 55-40=15)
7. 115 ÷ 15 = 7 R 10 (15*7=105, 115-105=10)
8. 60 ÷ 12 = 5
9. 85 ÷ 17 = 5
10. 91 ÷ 11 = 8 R 3 (11*8=88, 91-88=3)
11. 64 ÷ 16 = 4
12. 38 ÷ 19 = 2

Now, for the final answer, since the user wants the answers to the problems, and to be accurate, I'll list them in order, with remainder if applicable.

But to match the worksheet style, where the quotient is written above, and remainder might be noted, but for simplicity in text, I'll write each as "quotient" or "quotient R remainder".

Also, for the left page, there are 11 problems, right page 12, so total 23 answers.

But perhaps the user expects only the quotients, as in the sample. However, the sample had no remainder, so for consistency, maybe they want only the integer quotient, discarding remainder. But that would be inaccurate for problems like 36÷11.

Given the instruction "solve accurately", I think we must include remainders.

So for Final Answer, I'll list all answers in sequence.

Let me write them clearly.

---

Left Page Answers (in order as listed):

1. 20 ÷ 10 = 2
2. 45 ÷ 5 = 9
3. 36 ÷ 11 = 3 R 3
4. 13 ÷ 7 = 1 R 6
5. 54 ÷ 18 = 3
6. 49 ÷ 7 = 7
7. 69 ÷ 3 = 23
8. 51 ÷ 9 = 5 R 6
9. 17 ÷ 12 = 1 R 5
10. 70 ÷ 14 = 5
11. 96 ÷ 16 = 6

Right Page Answers (in order):

1. 80 ÷ 10 = 8
2. 45 ÷ 15 = 3
3. 88 ÷ 13 = 6 R 10
4. 96 ÷ 12 = 8
5. 38 ÷ 19 = 2
6. 55 ÷ 20 = 2 R 15
7. 115 ÷ 15 = 7 R 10
8. 60 ÷ 12 = 5
9. 85 ÷ 17 = 5
10. 91 ÷ 11 = 8 R 3
11. 64 ÷ 16 = 4
12. 38 ÷ 19 = 2

Now, for the Final Answer section, since it should be concise, I'll list them as a sequence, separating left and right pages.

But the user might expect a single list. To be clear, I'll state:

Final Answer:
Left page: 2, 9, 3 R 3, 1 R 6, 3, 7, 23, 5 R 6, 1 R 5, 5, 6
Right page: 8, 3, 6 R 10, 8, 2, 2 R 15, 7 R 10, 5, 5, 8 R 3, 4, 2

But to make it neat, perhaps write each with its problem, but that might be too long.

Since the worksheet has the problems in order, and we're to provide answers, I think listing the answers in order is fine.

Another way: since the sample showed only the quotient, and for educational purposes at this level, sometimes they teach to write the quotient and ignore remainder initially, but that's not accurate.

I recall that in some curricula, for division with remainder, they write "q r r", so I'll stick with that.

For the Final Answer, I'll box the list.

But the instruction says "provide only the final correct answer" after reasoning, so I'll summarize.

Perhaps the user intends for us to recognize that all problems are meant to be solved with quotient only, but that contradicts "accurately".

Let's double-check one: 36 ÷ 11. If we do long division, 11 into 36 is 3, since 11*3=33, and 36-33=3, so quotient 3, remainder 3. Accurate answer is 3 with remainder 3.

Similarly for others.

So I think it's correct.

For the response, since ExplainAnswer is false, etc., I'll go directly to Final Answer after this reasoning.

In the Final Answer section, I'll list all answers in order for both pages.

To save space, I can write:

Left page answers: 2, 9, 3R3, 1R6, 3, 7, 23, 5R6, 1R5, 5, 6
Right page answers: 8, 3, 6R10, 8, 2, 2R15, 7R10, 5, 5, 8R3, 4, 2

Using "R" for remainder.

Now, for the very last part, ensure no mistakes.

Let me verify a few:

- 54 ÷ 18: 18*3=54, yes, 3.
- 69 ÷ 3: 3*23=69, yes.
- 96 ÷ 16: 16*6=96, yes.
- 88 ÷ 13: 13*6=78, 88-78=10, so 6R10.
- 115 ÷ 15: 15*7=105, 115-105=10, so 7R10.
- 91 ÷ 11: 11*8=88, 91-88=3, so 8R3.

All good.

So Final Answer is as above.