Division Facts by a Fixed Divisor (3, 4 and 6) and Quotients from ... - Free Printable

The task involves calculating quotients for division problems where the divisors are 3, 4, or 6. Below is the solution to each problem, along with an explanation of how to solve them.

Problem Set and Solutions:

#### Row 1:
1. \( 6 \div 30 \)
- Solution: \( 30 \div 6 = 5 \)
2. \( 6 \div 36 \)
- Solution: \( 36 \div 6 = 6 \)
3. \( 6 \div 24 \)
- Solution: \( 24 \div 6 = 4 \)
4. \( 4 \div 20 \)
- Solution: \( 20 \div 4 = 5 \)
5. \( 3 \div 30 \)
- Solution: \( 30 \div 3 = 10 \)

#### Row 2:
1. \( 3 \div 27 \)
- Solution: \( 27 \div 3 = 9 \)
2. \( 6 \div 42 \)
- Solution: \( 42 \div 6 = 7 \)
3. \( 4 \div 32 \)
- Solution: \( 32 \div 4 = 8 \)
4. \( 4 \div 40 \)
- Solution: \( 40 \div 4 = 10 \)
5. \( 4 \div 16 \)
- Solution: \( 16 \div 4 = 4 \)

#### Row 3:
1. \( 6 \div 48 \)
- Solution: \( 48 \div 6 = 8 \)
2. \( 6 \div 18 \)
- Solution: \( 18 \div 6 = 3 \)
3. \( 4 \div 36 \)
- Solution: \( 36 \div 4 = 9 \)
4. \( 3 \div 12 \)
- Solution: \( 12 \div 3 = 4 \)
5. \( 6 \div 60 \)
- Solution: \( 60 \div 6 = 10 \)

#### Row 4:
1. \( 3 \div 21 \)
- Solution: \( 21 \div 3 = 7 \)
2. \( 3 \div 18 \)
- Solution: \( 18 \div 3 = 6 \)
3. \( 3 \div 24 \)
- Solution: \( 24 \div 3 = 8 \)
4. \( 3 \div 15 \)
- Solution: \( 15 \div 3 = 5 \)
5. \( 6 \div 12 \)
- Solution: \( 12 \div 6 = 2 \)

#### Row 5:
1. \( 3 \div 9 \)
- Solution: \( 9 \div 3 = 3 \)
2. \( 4 \div 8 \)
- Solution: \( 8 \div 4 = 2 \)
3. \( 4 \div 28 \)
- Solution: \( 28 \div 4 = 7 \)
4. \( 6 \div 54 \)
- Solution: \( 54 \div 6 = 9 \)
5. \( 4 \div 12 \)
- Solution: \( 12 \div 4 = 3 \)

#### Row 6:
1. \( 6 \div 6 \)
- Solution: \( 6 \div 6 = 1 \)
2. \( 3 \div 6 \)
- Solution: \( 6 \div 3 = 2 \)
3. \( 4 \div 4 \)
- Solution: \( 4 \div 4 = 1 \)
4. \( 4 \div 24 \)
- Solution: \( 24 \div 4 = 6 \)
5. \( 3 \div 3 \)
- Solution: \( 3 \div 3 = 1 \)

#### Row 7:
1. \( 4 \div 36 \)
- Solution: \( 36 \div 4 = 9 \)
2. \( 4 \div 24 \)
- Solution: \( 24 \div 4 = 6 \)
3. \( 6 \div 48 \)
- Solution: \( 48 \div 6 = 8 \)
4. \( 3 \div 21 \)
- Solution: \( 21 \div 3 = 7 \)
5. \( 6 \div 36 \)
- Solution: \( 36 \div 6 = 6 \)

#### Row 8:
1. \( 3 \div 30 \)
- Solution: \( 30 \div 3 = 10 \)
2. \( 6 \div 60 \)
- Solution: \( 60 \div 6 = 10 \)
3. \( 3 \div 18 \)
- Solution: \( 18 \div 3 = 6 \)
4. \( 6 \div 54 \)
- Solution: \( 54 \div 6 = 9 \)
5. \( 6 \div 42 \)
- Solution: \( 42 \div 6 = 7 \)

#### Row 9:
1. \( 4 \div 32 \)
- Solution: \( 32 \div 4 = 8 \)
2. \( 3 \div 27 \)
- Solution: \( 27 \div 3 = 9 \)
3. \( 3 \div 24 \)
- Solution: \( 24 \div 3 = 8 \)
4. \( 3 \div 15 \)
- Solution: \( 15 \div 3 = 5 \)
5. \( 3 \div 12 \)
- Solution: \( 12 \div 3 = 4 \)

#### Row 10:
1. \( 4 \div 40 \)
- Solution: \( 40 \div 4 = 10 \)
2. \( 6 \div 30 \)
- Solution: \( 30 \div 6 = 5 \)
3. \( 6 \div 12 \)
- Solution: \( 12 \div 6 = 2 \)
4. \( 4 \div 12 \)
- Solution: \( 12 \div 4 = 3 \)
5. \( 6 \div 18 \)
- Solution: \( 18 \div 6 = 3 \)

Final Answer:

\[
\boxed{
\begin{array}{ccccc}
5 & 6 & 4 & 5 & 10 \\
9 & 7 & 8 & 10 & 4 \\
8 & 3 & 9 & 4 & 10 \\
7 & 6 & 8 & 5 & 2 \\
3 & 2 & 7 & 9 & 3 \\
1 & 2 & 1 & 6 & 1 \\
9 & 6 & 8 & 7 & 6 \\
10 & 10 & 6 & 9 & 7 \\
8 & 9 & 8 & 5 & 4 \\
10 & 5 & 2 & 3 & 3 \\
\end{array}
}
\]

Each quotient is calculated by dividing the dividend by the divisor as indicated in the problem set. The solutions are straightforward applications of basic division principles.