Division Word Problems: Stretch (Year 6) | CGP Plus - Free Printable

Let's solve each of the word problems step by step using long division.

---

Problem 1:

There are 620 stickers which are shared between 48 pupils so everyone gets an equal amount. How many stickers does each pupil get? How many are left over?

#### Solution:
We need to divide 620 by 48 using long division.

1. Set up the division:
```
____
48 | 620
```

2. Divide the first two digits (62) by 48:
- 48 goes into 62 once (since \(48 \times 1 = 48\)).
- Write 1 above the line.
- Subtract \(48\) from \(62\):
```
1
____
48 | 620
-48
----
14
```

3. Bring down the next digit (0):
- Now, we have 140.
- Divide 140 by 48:
- 48 goes into 140 twice (since \(48 \times 2 = 96\)).
- Write 2 above the line.
- Subtract \(96\) from \(140\):
```
12
____
48 | 620
-48
----
140
- 96
------
44
```

4. Result:
- The quotient is 12, and the remainder is 44.

So, each pupil gets 12 stickers, and there are 44 stickers left over.

Answer for Problem 1:
$$
\boxed{12 \text{ stickers per pupil, 44 stickers left over}}
$$

---

Problem 2:

There are 1234 birds in a sanctuary and each enclosure should only contain 3 birds. How many enclosures are needed?

#### Solution:
We need to divide 1234 by 3 using long division.

1. Set up the division:
```
____
3 | 1234
```

2. Divide the first digit (1) by 3:
- 3 does not go into 1. So, consider the first two digits (12).
- 3 goes into 12 four times (since \(3 \times 4 = 12\)).
- Write 4 above the line.
- Subtract \(12\) from \(12\):
```
4
____
3 | 1234
-12
----
03
```

3. Bring down the next digit (3):
- Now, we have 3.
- 3 goes into 3 once (since \(3 \times 1 = 3\)).
- Write 1 above the line.
- Subtract \(3\) from \(3\):
```
41
____
3 | 1234
-12
----
03
- 3
------
04
```

4. Bring down the next digit (4):
- Now, we have 4.
- 3 goes into 4 once (since \(3 \times 1 = 3\)).
- Write 1 above the line.
- Subtract \(3\) from \(4\):
```
411
____
3 | 1234
-12
----
03
- 3
------
04
- 3
------
1
```

5. Result:
- The quotient is 411, and the remainder is 1.
- Since we cannot leave any birds out, we need an additional enclosure for the remaining bird.
- Therefore, the total number of enclosures needed is \(411 + 1 = 412\).

Answer for Problem 2:
$$
\boxed{412 \text{ enclosures}}
$$

---

Problem 3:

There are 755 people on a train which has 5 carriages. How many people would there be in each carriage if they divide themselves equally between the carriages?

#### Solution:
We need to divide 755 by 5 using long division.

1. Set up the division:
```
____
5 | 755
```

2. Divide the first digit (7) by 5:
- 5 goes into 7 once (since \(5 \times 1 = 5\)).
- Write 1 above the line.
- Subtract \(5\) from \(7\):
```
1
____
5 | 755
-5
----
25
```

3. Bring down the next digit (5):
- Now, we have 25.
- 5 goes into 25 five times (since \(5 \times 5 = 25\)).
- Write 5 above the line.
- Subtract \(25\) from \(25\):
```
15
____
5 | 755
-5
----
25
- 25
------
05
```

4. Bring down the next digit (5):
- Now, we have 5.
- 5 goes into 5 once (since \(5 \times 1 = 5\)).
- Write 1 above the line.
- Subtract \(5\) from \(5\):
```
151
____
5 | 755
-5
----
25
- 25
------
05
- 5
------
0
```

5. Result:
- The quotient is 151, and the remainder is 0.

So, there are 151 people in each carriage.

Answer for Problem 3:
$$
\boxed{151 \text{ people per carriage}}
$$

---

Problem 4:

There are 342 pieces of cake at a picnic with 32 people. If everyone eats the same amount of cake, what is the maximum number of pieces everyone could have? How many pieces would be left over?

#### Solution:
We need to divide 342 by 32 using long division.

1. Set up the division:
```
____
32 | 342
```

2. Divide the first two digits (34) by 32:
- 32 goes into 34 once (since \(32 \times 1 = 32\)).
- Write 1 above the line.
- Subtract \(32\) from \(34\):
```
1
____
32 | 342
-32
----
22
```

3. Bring down the next digit (2):
- Now, we have 22.
- 32 does not go into 22.
- The quotient is 10, and the remainder is 22.

So, each person can have 10 pieces of cake, and there will be 22 pieces left over.

Answer for Problem 4:
$$
\boxed{10 \text{ pieces per person, 22 pieces left over}}
$$

---

Problem 5:

There are 842 apples collected in an orchard. Each crate can hold 64 apples. How many crates are needed to box up all the apples?

#### Solution:
We need to divide 842 by 64 using long division.

1. Set up the division:
```
____
64 | 842
```

2. Divide the first two digits (84) by 64:
- 64 goes into 84 once (since \(64 \times 1 = 64\)).
- Write 1 above the line.
- Subtract \(64\) from \(84\):
```
1
____
64 | 842
-64
----
202
```

3. Bring down the next digit (2):
- Now, we have 202.
- 64 goes into 202 three times (since \(64 \times 3 = 192\)).
- Write 3 above the line.
- Subtract \(192\) from \(202\):
```
13
____
64 | 842
-64
----
202
- 192
------
10
```

4. Result:
- The quotient is 13, and the remainder is 10.
- Since we cannot leave any apples out, we need an additional crate for the remaining apples.
- Therefore, the total number of crates needed is \(13 + 1 = 14\).

Answer for Problem 5:
$$
\boxed{14 \text{ crates}}
$$

---

Final Answers:

1. \( \boxed{12 \text{ stickers per pupil, 44 stickers left over}} \)
2. \( \boxed{412 \text{ enclosures}} \)
3. \( \boxed{151 \text{ people per carriage}} \)
4. \( \boxed{10 \text{ pieces per person, 22 pieces left over}} \)
5. \( \boxed{14 \text{ crates}} \)