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Domain and Range of Graphs worksheet with eight plotted functions on coordinate grids.

Worksheet titled "Domain and Range of Graphs" with eight numbered graphs on coordinate planes, each requiring identification of domain, range, and function type.

Worksheet titled "Domain and Range of Graphs" with eight numbered graphs on coordinate planes, each requiring identification of domain, range, and function type.

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Show Answer Key & Explanations Step-by-step solution for: Algebra 1 Worksheets | Domain and Range Worksheets
Let's solve each of the 8 problems on the worksheet step by step. For each graph, we will determine:

1. Domain: The set of all possible x-values (horizontal extent).
2. Range: The set of all possible y-values (vertical extent).
3. Function?: Whether the graph represents a function (use the Vertical Line Test — if any vertical line intersects the graph more than once, it is not a function).

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1) Graph 1


- Graph Description: A single curve from (0, 4) to (2, 0), decreasing, with a solid dot at (0, 4) and an open circle at (2, 0).
- Domain: x-values from 0 to 2 → [0, 2)
- Range: y-values from 0 to 4 → [0, 4]
- Function?: Yes – passes vertical line test.
- Answer:
- Domain: [0, 2)
- Range: [0, 4]
- Function: Yes

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2) Graph 2


- Graph Description: A downward-opening parabola arc from (-3, 0) to (3, 0), peaking at (0, 3). Solid dots at endpoints.
- Domain: x-values from -3 to 3 → [-3, 3]
- Range: y-values from 0 to 3 → [0, 3]
- Function?: Yes – every x has only one y.
- Answer:
- Domain: [-3, 3]
- Range: [0, 3]
- Function: Yes

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3) Graph 3


- Graph Description: A wavy curve starting at (-3, -2), going up to (0, 2), down to (2, -2), then up again. Open circle at (-3, -2), closed at (2, -2), and a closed point at (0, 2).
- Domain: x-values from -3 to 2 → [-3, 2]
- Range: y-values from -2 to 2 → [-2, 2]
- Function?: Yes – no vertical line crosses twice.
- Answer:
- Domain: [-3, 2]
- Range: [-2, 2]
- Function: Yes

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4) Graph 4


- Graph Description: A U-shaped curve opening to the right, from (-2, -2) to (2, 2), but not continuous. It looks like two parts: left side from (-2, -2) to (0, 0), and right side from (0, 0) to (2, 2), but only one part is drawn: from (-2, -2) to (0, 0) with a solid dot at (-2, -2), open at (0, 0); and another segment from (0, 0) to (2, 2), open at (0, 0), solid at (2, 2). So it’s a V-shape opening to the right, but only the left half is shown?
Wait — actually, looking closely: it seems like a parabola opening to the right, with points from (-2, -2) to (2, 2), but only the left half is drawn? No — let's recheck.

Actually, this graph shows two separate curves:
- One from (-2, -2) to (0, 0): solid at (-2, -2), open at (0, 0)
- One from (0, 0) to (2, 2): open at (0, 0), solid at (2, 2)

So it’s like a "V" shape pointing to the right, but split at origin.

But wait — each x-value has two y-values? Let's check:

For example, x = 0 appears in both segments, but only at (0,0), which is open in both — so no point at x=0.

But for x = 1, there are two points? Wait, no — the graph shows only one curve: a semicircle or curved path from (-2,-2) to (2,2) passing through (0,0), but drawn as two parts?

Actually, upon closer inspection, it looks like a parabola-like shape symmetric about the origin, but only one branch is drawn: from (-2, -2) to (2, 2) through (0,0), but with open circles at (0,0) on both ends? No — it's a single continuous curve from (-2, -2) to (2, 2), passing through (0,0), with closed dot at (-2,-2), open dot at (2,2), and open dot at (0,0)?

Wait — no. Looking carefully:

It's a curve that starts at (-2, -2) with a solid dot, goes upward to (0, 0) with an open dot, then continues to (2, 2) with a solid dot? But that would be two segments.

But the x-values from -2 to 2 are covered, and for each x, there's only one y — so it could be a function.

But wait — if it's a curve from (-2,-2) to (2,2) passing through (0,0), and it's smooth, then it might be a function.

But here’s the key: at x = 0, there is an open circle, meaning the point (0,0) is not included.

But the curve goes from (-2,-2) to (0,0) (open), then from (0,0) (open) to (2,2) (solid). So it's a continuous curve with a gap at (0,0)? That doesn't make sense.

Wait — actually, the graph is likely a function defined piecewise.

Looking at standard interpretations: This graph appears to be a V-shape rotated 45 degrees, but more likely, it's a parabola opening to the right, but only the left half is drawn? No.

Actually, after careful analysis, it looks like a function where:
- From x = -2 to x = 0, y increases from -2 to 0
- From x = 0 to x = 2, y increases from 0 to 2
- But at x = 0, there is an open circle, meaning (0,0) is not included
- However, the curve approaches (0,0) from both sides

But since (0,0) is not included, and the curve is smooth, it's still a function as long as each x has one y.

But wait — if the curve is continuous and increasing from (-2,-2) to (2,2), and (0,0) is not included, then x=0 has no value, so it's not defined at x=0.

But the graph shows a break at x=0.

So:
- Domain: [-2, 0) ∪ (0, 2] → because x=0 is excluded
- Range: [-2, 0) ∪ (0, 2] → same
- But is it a function? Yes — for each x in domain, only one y

Answer:
- Domain: [-2, 0) ∪ (0, 2]
- Range: [-2, 0) ∪ (0, 2]
- Function: Yes

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5) Graph 5


- Graph Description: A line segment from (-4, 2) to (-1, -1), then a horizontal line from (-1, -1) to (0, -1), then a line from (0, -1) to (1, 0). Open circle at (-4,2), closed at (1,0), and closed at (-1,-1), open at (0,-1)? Wait — no.

Actually:
- Starts at (-4, 2) with open circle → not included
- Goes down to (-1, -1) with closed circle → included
- Then horizontal to (0, -1) with open circle → not included
- Then up to (1, 0) with closed circle → included

So:
- Domain: x from -4 to 1, but excluding -4 and 0? Wait — from -4 to -1 (inclusive), then from -1 to 0 (but open at 0), then from 0 to 1 (but 0 is open), so x=0 is missing

Wait — no: the horizontal segment is from (-1, -1) to (0, -1), with open circle at (0,-1) → so x=0 is not included in that segment.

Then the next segment starts at (0, -1) — but that point is open, so no point at (0,-1).

So the graph has:
- From x = -4 to x = -1: line from (-4,2) to (-1,-1), open at (-4), closed at (-1)
- From x = -1 to x = 0: horizontal line from (-1,-1) to (0,-1), closed at (-1), open at (0)
- From x = 0 to x = 1: line from (0,-1) to (1,0), open at (0), closed at (1)

So x=0 is not included in any segment.

Thus:
- Domain: [-4, -1] ∪ [-1, 0) ∪ (0, 1] = [-4, 0) ∪ (0, 1]
- Range: y-values from -1 to 2 → [-1, 2]
- Is it a function? Yes — each x has only one y

Answer:
- Domain: [-4, 0) ∪ (0, 1]
- Range: [-1, 2]
- Function: Yes

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6) Graph 6


- Graph Description: A straight line from (-3, -2) to (3, 4), with solid dots at both ends.
- Domain: x from -3 to 3 → [-3, 3]
- Range: y from -2 to 4 → [-2, 4]
- Function?: Yes — straight line, passes vertical line test
- Answer:
- Domain: [-3, 3]
- Range: [-2, 4]
- Function: Yes

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7) Graph 7


- Graph Description: A diagonal line from (-4, 2) to (0, -2), with open circle at (-4,2), closed at (0,-2)
- Domain: x from -4 to 0 → (-4, 0]
- Range: y from -2 to 2 → [-2, 2)
- Function?: Yes — straight line, one y per x
- Answer:
- Domain: (-4, 0]
- Range: [-2, 2)
- Function: Yes

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8) Graph 8


- Graph Description: A curve that starts at (-3, 0) with open circle, goes up to (0, 3), then down to (3, -3) with open circle. It's a U-shaped curve but inverted — like a parabola opening downward, but only the right half? No — it's not a function.

Wait — look at x = 0: it has two y-values — one at (0,3) and possibly others?

No — the curve goes from (-3,0) to (0,3), then from (0,3) to (3,-3). But at x=0, there is only one point — (0,3) — so maybe it's a function?

Wait — no: the graph shows a loop or non-function.

Actually, it's a parabola opening to the right, but with a double curve — like a sideways parabola.

But more precisely: it looks like a function — from x=-3 to x=3, but at x=0, only one point.

Wait — no: the curve goes from (-3,0) to (0,3), then from (0,3) to (3,-3). So it's a V-shape pointing downward? Or a zigzag?

But at x=1, there is only one y-value? Let's see.

Actually, the graph shows a single continuous curve from (-3,0) to (3,-3), passing through (0,3). But does it go back?

Wait — the curve from (-3,0) to (0,3) is increasing, then from (0,3) to (3,-3) is decreasing — but that’s fine.

But is it a function? Yes — for each x, only one y.

But wait — the shape suggests it may be a function.

However, upon closer inspection, it looks like a sideways parabola — but no, it’s a piecewise linear curve.

But the issue is: does it pass the vertical line test?

At x=1, there is only one point — yes.

But the curve goes from (-3,0) to (0,3), then from (0,3) to (3,-3). So it’s a single path — a broken line.

But at x=0, it’s (0,3) — only one point.

So it is a function.

But wait — the graph shows a loop? No — it's a smooth curve from left to right.

Wait — actually, looking at the graph, it might be a parabola opening to the right, but with two branches — but in this case, it’s not.

Alternatively, it might be a function with a cusp or turn.

But the key is: does any vertical line cross it more than once?

From the description: it goes from (-3,0) to (0,3), then down to (3,-3). So it's a single path — a V-shape turned.

But it's not a function because at some x-values, there are two y-values?

Wait — no — it’s a continuous curve from left to right — so it’s a function.

But let’s think: if it goes from (-3,0) to (0,3), then from (0,3) to (3,-3), that’s fine — it’s a function.

But the problem is: the graph shows a loop — no, it doesn’t.

Wait — actually, upon close inspection, it might be a sideways parabola — but the way it's drawn, it’s not.

Alternatively, it could be a function — but let's check the vertical line test.

If I draw a vertical line at x=1, it hits only one point — yes.

So it is a function.

But wait — the graph has a sharp turn at (0,3), but that’s okay.

So:
- Domain: x from -3 to 3 → [-3, 3]
- Range: y from -3 to 3 → [-3, 3]
- Function: Yes

Wait — but the endpoints:
- At (-3,0): open circle → not included
- At (3,-3): open circle → not included
- So domain: (-3, 3)
- Range: (-3, 3) — but y reaches 3 at (0,3), which is closed → so y=3 is included

So:
- Domain: (-3, 3)
- Range: [-3, 3]
- Function: Yes

Answer:
- Domain: (-3, 3)
- Range: [-3, 3]
- Function: Yes

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Final Answers:



| # | Domain | Range | Function? |
|---|--------|-------|----------|
| 1 | [0, 2) | [0, 4] | Yes |
| 2 | [-3, 3] | [0, 3] | Yes |
| 3 | [-3, 2] | [-2, 2] | Yes |
| 4 | [-2, 0) ∪ (0, 2] | [-2, 0) ∪ (0, 2] | Yes |
| 5 | [-4, 0) ∪ (0, 1] | [-1, 2] | Yes |
| 6 | [-3, 3] | [-2, 4] | Yes |
| 7 | (-4, 0] | [-2, 2) | Yes |
| 8 | (-3, 3) | [-3, 3] | Yes |

> Note: All graphs appear to be functions based on the vertical line test.

Let me know if you'd like a visual explanation or correction for any specific graph!
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