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Step-by-step solution for: A Comprehensive Collection Of Balancing Chemical Equations ...
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Show Answer Key & Explanations
Step-by-step solution for: A Comprehensive Collection Of Balancing Chemical Equations ...
To balance the chemical equations, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here are the balanced equations with explanations:
---
- Step 1: Start with the unbalanced equation.
\[
\text{CH}_4 + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O}
\]
- Step 2: Balance carbon (C).
- There is 1 C atom on both sides, so it is already balanced.
- Step 3: Balance hydrogen (H).
- There are 4 H atoms in CH₄ and 2 H atoms in H₂O. To balance H, place a coefficient of 2 in front of H₂O:
\[
\text{CH}_4 + \text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O}
\]
- Step 4: Balance oxygen (O).
- There are 2 O atoms in CO₂ and 2 O atoms in 2H₂O, totaling 4 O atoms on the right side. There are 2 O atoms in O₂ on the left side. To balance O, place a coefficient of 2 in front of O₂:
\[
\text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O}
\]
Balanced Equation:
\[
\boxed{\text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O}}
\]
---
- Step 1: Start with the unbalanced equation.
\[
\text{Na}^+ + \text{Cl}^- \rightarrow \text{NaCl}
\]
- Step 2: Balance sodium (Na) and chlorine (Cl).
- There is 1 Na⁺ and 1 Cl⁻ on the left side, and 1 Na and 1 Cl in NaCl on the right side. The equation is already balanced.
Balanced Equation:
\[
\boxed{\text{Na}^+ + \text{Cl}^- \rightarrow \text{NaCl}}
\]
---
- Step 1: Start with the unbalanced equation.
\[
\text{Al} + \text{O}_2 \rightarrow \text{Al}_2\text{O}_3
\]
- Step 2: Balance aluminum (Al).
- There are 2 Al atoms in Al₂O₃ on the right side. To balance Al, place a coefficient of 2 in front of Al:
\[
2\text{Al} + \text{O}_2 \rightarrow \text{Al}_2\text{O}_3
\]
- Step 3: Balance oxygen (O).
- There are 3 O atoms in Al₂O₃ on the right side and 2 O atoms in O₂ on the left side. To balance O, place a coefficient of 1.5 in front of O₂. Since coefficients must be whole numbers, multiply the entire equation by 2:
\[
4\text{Al} + 3\text{O}_2 \rightarrow 2\text{Al}_2\text{O}_3
\]
Balanced Equation:
\[
\boxed{4\text{Al} + 3\text{O}_2 \rightarrow 2\text{Al}_2\text{O}_3}
\]
---
- Step 1: Start with the unbalanced equation.
\[
\text{N}_2 + \text{H}_2 \rightarrow \text{NH}_3
\]
- Step 2: Balance nitrogen (N).
- There are 2 N atoms in N₂ on the left side and 1 N atom in NH₃ on the right side. To balance N, place a coefficient of 2 in front of NH₃:
\[
\text{N}_2 + \text{H}_2 \rightarrow 2\text{NH}_3
\]
- Step 3: Balance hydrogen (H).
- There are 6 H atoms in 2NH₃ on the right side and 2 H atoms in H₂ on the left side. To balance H, place a coefficient of 3 in front of H₂:
\[
\text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3
\]
Balanced Equation:
\[
\boxed{\text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3}
\]
---
- Step 1: Start with the unbalanced equation.
\[
\text{CO}(g) + \text{H}_2(g) \rightarrow \text{C}_2\text{H}_6(l) + \text{H}_2\text{O}
\]
- Step 2: Balance carbon (C).
- There is 1 C atom in CO on the left side and 2 C atoms in C₂H₆ on the right side. To balance C, place a coefficient of 2 in front of CO:
\[
2\text{CO}(g) + \text{H}_2(g) \rightarrow \text{C}_2\text{H}_6(l) + \text{H}_2\text{O}
\]
- Step 3: Balance hydrogen (H).
- There are 6 H atoms in C₂H₆ and 2 H atoms in H₂O, totaling 8 H atoms on the right side. There are 2 H atoms in H₂ on the left side. To balance H, place a coefficient of 5 in front of H₂:
\[
2\text{CO}(g) + 5\text{H}_2(g) \rightarrow \text{C}_2\text{H}_6(l) + \text{H}_2\text{O}
\]
- Step 4: Balance oxygen (O).
- There are 2 O atoms in 2CO on the left side and 1 O atom in H₂O on the right side. To balance O, place a coefficient of 2 in front of H₂O:
\[
2\text{CO}(g) + 5\text{H}_2(g) \rightarrow \text{C}_2\text{H}_6(l) + 2\text{H}_2\text{O}
\]
Balanced Equation:
\[
\boxed{2\text{CO}(g) + 5\text{H}_2(g) \rightarrow \text{C}_2\text{H}_6(l) + 2\text{H}_2\text{O}}
\]
---
- Step 1: Start with the unbalanced equation.
\[
\text{Fe}_2\text{O}_3(s) + \text{CO}(g) \rightarrow \text{Fe}(l) + \text{CO}_2(g)
\]
- Step 2: Balance iron (Fe).
- There are 2 Fe atoms in Fe₂O₃ on the left side and 1 Fe atom in Fe on the right side. To balance Fe, place a coefficient of 2 in front of Fe:
\[
\text{Fe}_2\text{O}_3(s) + \text{CO}(g) \rightarrow 2\text{Fe}(l) + \text{CO}_2(g)
\]
- Step 3: Balance oxygen (O).
- There are 3 O atoms in Fe₂O₃ and 2 O atoms in CO₂, totaling 5 O atoms on the right side. There are 1 O atom in CO on the left side. To balance O, place a coefficient of 3 in front of CO:
\[
\text{Fe}_2\text{O}_3(s) + 3\text{CO}(g) \rightarrow 2\text{Fe}(l) + 3\text{CO}_2(g)
\]
Balanced Equation:
\[
\boxed{\text{Fe}_2\text{O}_3(s) + 3\text{CO}(g) \rightarrow 2\text{Fe}(l) + 3\text{CO}_2(g)}
\]
---
- Step 1: Start with the unbalanced equation.
\[
\text{H}_2\text{SO}_4 + \text{Pb(OH)}_4 \rightarrow \text{Pb(SO}_4)_2 + \text{H}_2\text{O}
\]
- Step 2: Balance lead (Pb).
- There is 1 Pb atom in Pb(OH)₄ on the left side and 1 Pb atom in Pb(SO₄)₂ on the right side. It is already balanced.
- Step 3: Balance sulfur (S).
- There is 1 S atom in H₂SO₄ on the left side and 2 S atoms in Pb(SO₄)₂ on the right side. To balance S, place a coefficient of 2 in front of H₂SO₄:
\[
2\text{H}_2\text{SO}_4 + \text{Pb(OH)}_4 \rightarrow \text{Pb(SO}_4)_2 + \text{H}_2\text{O}
\]
- Step 4: Balance hydrogen (H).
- There are 4 H atoms in Pb(OH)₄ and 2 H atoms in H₂O, totaling 6 H atoms on the right side. There are 4 H atoms in 2H₂SO₄ on the left side. To balance H, place a coefficient of 4 in front of H₂O:
\[
2\text{H}_2\text{SO}_4 + \text{Pb(OH)}_4 \rightarrow \text{Pb(SO}_4)_2 + 4\text{H}_2\text{O}
\]
- Step 5: Balance oxygen (O).
- There are 8 O atoms in 2H₂SO₄ and 4 O atoms in Pb(OH)₄, totaling 12 O atoms on the left side. There are 8 O atoms in Pb(SO₄)₂ and 4 O atoms in 4H₂O, totaling 12 O atoms on the right side. The equation is balanced.
Balanced Equation:
\[
\boxed{2\text{H}_2\text{SO}_4 + \text{Pb(OH)}_4 \rightarrow \text{Pb(SO}_4)_2 + 4\text{H}_2\text{O}}
\]
---
- Step 1: Start with the unbalanced equation.
\[
\text{Al} + \text{HCl} \rightarrow \text{AlCl}_3 + \text{H}_2
\]
- Step 2: Balance aluminum (Al).
- There is 1 Al atom in Al on the left side and 1 Al atom in AlCl₃ on the right side. It is already balanced.
- Step 3: Balance chlorine (Cl).
- There are 3 Cl atoms in AlCl₃ on the right side and 1 Cl atom in HCl on the left side. To balance Cl, place a coefficient of 3 in front of HCl:
\[
\text{Al} + 3\text{HCl} \rightarrow \text{AlCl}_3 + \text{H}_2
\]
- Step 4: Balance hydrogen (H).
- There are 3 H atoms in 3HCl on the left side and 2 H atoms in H₂ on the right side. To balance H, place a coefficient of 1.5 in front of H₂. Since coefficients must be whole numbers, multiply the entire equation by 2:
\[
2\text{Al} + 6\text{HCl} \rightarrow 2\text{AlCl}_3 + 3\text{H}_2
\]
Balanced Equation:
\[
\boxed{2\text{Al} + 6\text{HCl} \rightarrow 2\text{AlCl}_3 + 3\text{H}_2}
\]
---
- Step 1: Start with the unbalanced equation.
\[
\text{Ca}_3(\text{PO}_4)_2 + \text{H}_2\text{SO}_4 \rightarrow \text{CaSO}_4 + \text{Ca(H}_2\text{PO}_4)_2
\]
- Step 2: Balance calcium (Ca).
- There are 3 Ca atoms in Ca₃(PO₄)₂ on the left side and 1 Ca atom in CaSO₄ and 1 Ca atom in Ca(H₂PO₄)₂ on the right side. To balance Ca, place a coefficient of 3 in front of CaSO₄:
\[
\text{Ca}_3(\text{PO}_4)_2 + \text{H}_2\text{SO}_4 \rightarrow 3\text{CaSO}_4 + \text{Ca(H}_2\text{PO}_4)_2
\]
- Step 3: Balance phosphorus (P).
- There are 2 P atoms in Ca₃(PO₄)₂ on the left side and 2 P atoms in Ca(H₂PO₄)₂ on the right side. It is already balanced.
- Step 4: Balance sulfur (S).
- There is 1 S atom in H₂SO₄ on the left side and 3 S atoms in 3CaSO₄ on the right side. To balance S, place a coefficient of 3 in front of H₂SO₄:
\[
\text{Ca}_3(\text{PO}_4)_2 + 3\text{H}_2\text{SO}_4 \rightarrow 3\text{CaSO}_4 + \text{Ca(H}_2\text{PO}_4)_2
\]
- Step 5: Balance hydrogen (H).
- There are 6 H atoms in 3H₂SO₄ on the left side and 4 H atoms in Ca(H₂PO₄)₂ on the right side. The equation is balanced for H as well.
Balanced Equation:
\[
\boxed{\text{Ca}_3(\text{PO}_4)_2 + 3\text{H}_2\text{SO}_4 \rightarrow 3\text{CaSO}_4 + \text{Ca(H}_2\text{PO}_4)_2}
\]
---
- Step 1: Start with the unbalanced equation.
\[
\text{H}_3\text{PO}_4 + \text{HCl} \rightarrow \text{PCl}_5 + \text{H}_2\text{O}
\]
- Step 2: Balance phosphorus (P).
- There is 1 P atom in H₃PO₄ on the left side and 1 P atom in PCl₅ on the right side. It is already balanced.
- Step 3: Balance chlorine (Cl).
- There is 1 Cl atom in HCl on the left side and 5 Cl atoms in PCl₅ on the right side. To balance Cl, place a coefficient of 5 in front of HCl:
\[
\text{H}_3\text{PO}_4 + 5\text{HCl} \rightarrow \text{PCl}_5 + \text{H}_2\text{O}
\]
- Step 4: Balance hydrogen (H).
- There are 3 H atoms in H₃PO₄ and 5 H atoms in 5HCl, totaling 8 H atoms on the left side. There are 2 H atoms in H₂O on the right side. To balance H, place a coefficient of 4 in front of H₂O:
\[
\text{H}_3\text{PO}_4 + 5\text{HCl} \rightarrow \text{PCl}_5 + 4\text{H}_2\text{O}
\]
- Step 5: Balance oxygen (O).
- There are 4 O atoms in H₃PO₄ on the left side and 4 O atoms in 4H₂O on the right side. The equation is balanced for O.
Balanced Equation:
\[
\boxed{\text{H}_3\text{PO}_4 + 5\text{HCl} \rightarrow \text{PCl}_5 + 4\text{H}_2\text{O}}
\]
---
\[
\boxed{
\begin{aligned}
1. & \quad \text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O} \\
2. & \quad \text{Na}^+ + \text{Cl}^- \rightarrow \text{NaCl} \\
3. & \quad 4\text{Al} + 3\text{O}_2 \rightarrow 2\text{Al}_2\text{O}_3 \\
4. & \quad \text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3 \\
5. & \quad 2\text{CO}(g) + 5\text{H}_2(g) \rightarrow \text{C}_2\text{H}_6(l) + 2\text{H}_2\text{O} \\
6. & \quad \text{Fe}_2\text{O}_3(s) + 3\text{CO}(g) \rightarrow 2\text{Fe}(l) + 3\text{CO}_2(g) \\
7. & \quad 2\text{H}_2\text{SO}_4 + \text{Pb(OH)}_4 \rightarrow \text{Pb(SO}_4)_2 + 4\text{H}_2\text{O} \\
8. & \quad 2\text{Al} + 6\text{HCl} \rightarrow 2\text{AlCl}_3 + 3\text{H}_2 \\
9. & \quad \text{Ca}_3(\text{PO}_4)_2 + 3\text{H}_2\text{SO}_4 \rightarrow 3\text{CaSO}_4 + \text{Ca(H}_2\text{PO}_4)_2 \\
10. & \quad \text{H}_3\text{PO}_4 + 5\text{HCl} \rightarrow \text{PCl}_5 + 4\text{H}_2\text{O}
\end{aligned}
}
\]
---
1. CH₄ + O₂ → CO₂ + H₂O
- Step 1: Start with the unbalanced equation.
\[
\text{CH}_4 + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O}
\]
- Step 2: Balance carbon (C).
- There is 1 C atom on both sides, so it is already balanced.
- Step 3: Balance hydrogen (H).
- There are 4 H atoms in CH₄ and 2 H atoms in H₂O. To balance H, place a coefficient of 2 in front of H₂O:
\[
\text{CH}_4 + \text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O}
\]
- Step 4: Balance oxygen (O).
- There are 2 O atoms in CO₂ and 2 O atoms in 2H₂O, totaling 4 O atoms on the right side. There are 2 O atoms in O₂ on the left side. To balance O, place a coefficient of 2 in front of O₂:
\[
\text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O}
\]
Balanced Equation:
\[
\boxed{\text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O}}
\]
---
2. Na⁺ + Cl⁻ → NaCl
- Step 1: Start with the unbalanced equation.
\[
\text{Na}^+ + \text{Cl}^- \rightarrow \text{NaCl}
\]
- Step 2: Balance sodium (Na) and chlorine (Cl).
- There is 1 Na⁺ and 1 Cl⁻ on the left side, and 1 Na and 1 Cl in NaCl on the right side. The equation is already balanced.
Balanced Equation:
\[
\boxed{\text{Na}^+ + \text{Cl}^- \rightarrow \text{NaCl}}
\]
---
3. Al + O₂ → Al₂O₃
- Step 1: Start with the unbalanced equation.
\[
\text{Al} + \text{O}_2 \rightarrow \text{Al}_2\text{O}_3
\]
- Step 2: Balance aluminum (Al).
- There are 2 Al atoms in Al₂O₃ on the right side. To balance Al, place a coefficient of 2 in front of Al:
\[
2\text{Al} + \text{O}_2 \rightarrow \text{Al}_2\text{O}_3
\]
- Step 3: Balance oxygen (O).
- There are 3 O atoms in Al₂O₃ on the right side and 2 O atoms in O₂ on the left side. To balance O, place a coefficient of 1.5 in front of O₂. Since coefficients must be whole numbers, multiply the entire equation by 2:
\[
4\text{Al} + 3\text{O}_2 \rightarrow 2\text{Al}_2\text{O}_3
\]
Balanced Equation:
\[
\boxed{4\text{Al} + 3\text{O}_2 \rightarrow 2\text{Al}_2\text{O}_3}
\]
---
4. N₂ + H₂ → NH₃
- Step 1: Start with the unbalanced equation.
\[
\text{N}_2 + \text{H}_2 \rightarrow \text{NH}_3
\]
- Step 2: Balance nitrogen (N).
- There are 2 N atoms in N₂ on the left side and 1 N atom in NH₃ on the right side. To balance N, place a coefficient of 2 in front of NH₃:
\[
\text{N}_2 + \text{H}_2 \rightarrow 2\text{NH}_3
\]
- Step 3: Balance hydrogen (H).
- There are 6 H atoms in 2NH₃ on the right side and 2 H atoms in H₂ on the left side. To balance H, place a coefficient of 3 in front of H₂:
\[
\text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3
\]
Balanced Equation:
\[
\boxed{\text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3}
\]
---
5. CO(g) + H₂(g) → C₂H₆(l) + H₂O
- Step 1: Start with the unbalanced equation.
\[
\text{CO}(g) + \text{H}_2(g) \rightarrow \text{C}_2\text{H}_6(l) + \text{H}_2\text{O}
\]
- Step 2: Balance carbon (C).
- There is 1 C atom in CO on the left side and 2 C atoms in C₂H₆ on the right side. To balance C, place a coefficient of 2 in front of CO:
\[
2\text{CO}(g) + \text{H}_2(g) \rightarrow \text{C}_2\text{H}_6(l) + \text{H}_2\text{O}
\]
- Step 3: Balance hydrogen (H).
- There are 6 H atoms in C₂H₆ and 2 H atoms in H₂O, totaling 8 H atoms on the right side. There are 2 H atoms in H₂ on the left side. To balance H, place a coefficient of 5 in front of H₂:
\[
2\text{CO}(g) + 5\text{H}_2(g) \rightarrow \text{C}_2\text{H}_6(l) + \text{H}_2\text{O}
\]
- Step 4: Balance oxygen (O).
- There are 2 O atoms in 2CO on the left side and 1 O atom in H₂O on the right side. To balance O, place a coefficient of 2 in front of H₂O:
\[
2\text{CO}(g) + 5\text{H}_2(g) \rightarrow \text{C}_2\text{H}_6(l) + 2\text{H}_2\text{O}
\]
Balanced Equation:
\[
\boxed{2\text{CO}(g) + 5\text{H}_2(g) \rightarrow \text{C}_2\text{H}_6(l) + 2\text{H}_2\text{O}}
\]
---
6. Fe₂O₃(s) + CO(g) → Fe(l) + CO₂(g)
- Step 1: Start with the unbalanced equation.
\[
\text{Fe}_2\text{O}_3(s) + \text{CO}(g) \rightarrow \text{Fe}(l) + \text{CO}_2(g)
\]
- Step 2: Balance iron (Fe).
- There are 2 Fe atoms in Fe₂O₃ on the left side and 1 Fe atom in Fe on the right side. To balance Fe, place a coefficient of 2 in front of Fe:
\[
\text{Fe}_2\text{O}_3(s) + \text{CO}(g) \rightarrow 2\text{Fe}(l) + \text{CO}_2(g)
\]
- Step 3: Balance oxygen (O).
- There are 3 O atoms in Fe₂O₃ and 2 O atoms in CO₂, totaling 5 O atoms on the right side. There are 1 O atom in CO on the left side. To balance O, place a coefficient of 3 in front of CO:
\[
\text{Fe}_2\text{O}_3(s) + 3\text{CO}(g) \rightarrow 2\text{Fe}(l) + 3\text{CO}_2(g)
\]
Balanced Equation:
\[
\boxed{\text{Fe}_2\text{O}_3(s) + 3\text{CO}(g) \rightarrow 2\text{Fe}(l) + 3\text{CO}_2(g)}
\]
---
7. H₂SO₄ + Pb(OH)₄ → Pb(SO₄)₂ + H₂O
- Step 1: Start with the unbalanced equation.
\[
\text{H}_2\text{SO}_4 + \text{Pb(OH)}_4 \rightarrow \text{Pb(SO}_4)_2 + \text{H}_2\text{O}
\]
- Step 2: Balance lead (Pb).
- There is 1 Pb atom in Pb(OH)₄ on the left side and 1 Pb atom in Pb(SO₄)₂ on the right side. It is already balanced.
- Step 3: Balance sulfur (S).
- There is 1 S atom in H₂SO₄ on the left side and 2 S atoms in Pb(SO₄)₂ on the right side. To balance S, place a coefficient of 2 in front of H₂SO₄:
\[
2\text{H}_2\text{SO}_4 + \text{Pb(OH)}_4 \rightarrow \text{Pb(SO}_4)_2 + \text{H}_2\text{O}
\]
- Step 4: Balance hydrogen (H).
- There are 4 H atoms in Pb(OH)₄ and 2 H atoms in H₂O, totaling 6 H atoms on the right side. There are 4 H atoms in 2H₂SO₄ on the left side. To balance H, place a coefficient of 4 in front of H₂O:
\[
2\text{H}_2\text{SO}_4 + \text{Pb(OH)}_4 \rightarrow \text{Pb(SO}_4)_2 + 4\text{H}_2\text{O}
\]
- Step 5: Balance oxygen (O).
- There are 8 O atoms in 2H₂SO₄ and 4 O atoms in Pb(OH)₄, totaling 12 O atoms on the left side. There are 8 O atoms in Pb(SO₄)₂ and 4 O atoms in 4H₂O, totaling 12 O atoms on the right side. The equation is balanced.
Balanced Equation:
\[
\boxed{2\text{H}_2\text{SO}_4 + \text{Pb(OH)}_4 \rightarrow \text{Pb(SO}_4)_2 + 4\text{H}_2\text{O}}
\]
---
8. Al + HCl → AlCl₃ + H₂
- Step 1: Start with the unbalanced equation.
\[
\text{Al} + \text{HCl} \rightarrow \text{AlCl}_3 + \text{H}_2
\]
- Step 2: Balance aluminum (Al).
- There is 1 Al atom in Al on the left side and 1 Al atom in AlCl₃ on the right side. It is already balanced.
- Step 3: Balance chlorine (Cl).
- There are 3 Cl atoms in AlCl₃ on the right side and 1 Cl atom in HCl on the left side. To balance Cl, place a coefficient of 3 in front of HCl:
\[
\text{Al} + 3\text{HCl} \rightarrow \text{AlCl}_3 + \text{H}_2
\]
- Step 4: Balance hydrogen (H).
- There are 3 H atoms in 3HCl on the left side and 2 H atoms in H₂ on the right side. To balance H, place a coefficient of 1.5 in front of H₂. Since coefficients must be whole numbers, multiply the entire equation by 2:
\[
2\text{Al} + 6\text{HCl} \rightarrow 2\text{AlCl}_3 + 3\text{H}_2
\]
Balanced Equation:
\[
\boxed{2\text{Al} + 6\text{HCl} \rightarrow 2\text{AlCl}_3 + 3\text{H}_2}
\]
---
9. Ca₃(PO₄)₂ + H₂SO₄ → CaSO₄ + Ca(H₂PO₄)₂
- Step 1: Start with the unbalanced equation.
\[
\text{Ca}_3(\text{PO}_4)_2 + \text{H}_2\text{SO}_4 \rightarrow \text{CaSO}_4 + \text{Ca(H}_2\text{PO}_4)_2
\]
- Step 2: Balance calcium (Ca).
- There are 3 Ca atoms in Ca₃(PO₄)₂ on the left side and 1 Ca atom in CaSO₄ and 1 Ca atom in Ca(H₂PO₄)₂ on the right side. To balance Ca, place a coefficient of 3 in front of CaSO₄:
\[
\text{Ca}_3(\text{PO}_4)_2 + \text{H}_2\text{SO}_4 \rightarrow 3\text{CaSO}_4 + \text{Ca(H}_2\text{PO}_4)_2
\]
- Step 3: Balance phosphorus (P).
- There are 2 P atoms in Ca₃(PO₄)₂ on the left side and 2 P atoms in Ca(H₂PO₄)₂ on the right side. It is already balanced.
- Step 4: Balance sulfur (S).
- There is 1 S atom in H₂SO₄ on the left side and 3 S atoms in 3CaSO₄ on the right side. To balance S, place a coefficient of 3 in front of H₂SO₄:
\[
\text{Ca}_3(\text{PO}_4)_2 + 3\text{H}_2\text{SO}_4 \rightarrow 3\text{CaSO}_4 + \text{Ca(H}_2\text{PO}_4)_2
\]
- Step 5: Balance hydrogen (H).
- There are 6 H atoms in 3H₂SO₄ on the left side and 4 H atoms in Ca(H₂PO₄)₂ on the right side. The equation is balanced for H as well.
Balanced Equation:
\[
\boxed{\text{Ca}_3(\text{PO}_4)_2 + 3\text{H}_2\text{SO}_4 \rightarrow 3\text{CaSO}_4 + \text{Ca(H}_2\text{PO}_4)_2}
\]
---
10. H₃PO₄ + HCl → PCl₅ + H₂O
- Step 1: Start with the unbalanced equation.
\[
\text{H}_3\text{PO}_4 + \text{HCl} \rightarrow \text{PCl}_5 + \text{H}_2\text{O}
\]
- Step 2: Balance phosphorus (P).
- There is 1 P atom in H₃PO₄ on the left side and 1 P atom in PCl₅ on the right side. It is already balanced.
- Step 3: Balance chlorine (Cl).
- There is 1 Cl atom in HCl on the left side and 5 Cl atoms in PCl₅ on the right side. To balance Cl, place a coefficient of 5 in front of HCl:
\[
\text{H}_3\text{PO}_4 + 5\text{HCl} \rightarrow \text{PCl}_5 + \text{H}_2\text{O}
\]
- Step 4: Balance hydrogen (H).
- There are 3 H atoms in H₃PO₄ and 5 H atoms in 5HCl, totaling 8 H atoms on the left side. There are 2 H atoms in H₂O on the right side. To balance H, place a coefficient of 4 in front of H₂O:
\[
\text{H}_3\text{PO}_4 + 5\text{HCl} \rightarrow \text{PCl}_5 + 4\text{H}_2\text{O}
\]
- Step 5: Balance oxygen (O).
- There are 4 O atoms in H₃PO₄ on the left side and 4 O atoms in 4H₂O on the right side. The equation is balanced for O.
Balanced Equation:
\[
\boxed{\text{H}_3\text{PO}_4 + 5\text{HCl} \rightarrow \text{PCl}_5 + 4\text{H}_2\text{O}}
\]
---
Final Answer:
\[
\boxed{
\begin{aligned}
1. & \quad \text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O} \\
2. & \quad \text{Na}^+ + \text{Cl}^- \rightarrow \text{NaCl} \\
3. & \quad 4\text{Al} + 3\text{O}_2 \rightarrow 2\text{Al}_2\text{O}_3 \\
4. & \quad \text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3 \\
5. & \quad 2\text{CO}(g) + 5\text{H}_2(g) \rightarrow \text{C}_2\text{H}_6(l) + 2\text{H}_2\text{O} \\
6. & \quad \text{Fe}_2\text{O}_3(s) + 3\text{CO}(g) \rightarrow 2\text{Fe}(l) + 3\text{CO}_2(g) \\
7. & \quad 2\text{H}_2\text{SO}_4 + \text{Pb(OH)}_4 \rightarrow \text{Pb(SO}_4)_2 + 4\text{H}_2\text{O} \\
8. & \quad 2\text{Al} + 6\text{HCl} \rightarrow 2\text{AlCl}_3 + 3\text{H}_2 \\
9. & \quad \text{Ca}_3(\text{PO}_4)_2 + 3\text{H}_2\text{SO}_4 \rightarrow 3\text{CaSO}_4 + \text{Ca(H}_2\text{PO}_4)_2 \\
10. & \quad \text{H}_3\text{PO}_4 + 5\text{HCl} \rightarrow \text{PCl}_5 + 4\text{H}_2\text{O}
\end{aligned}
}
\]
Parent Tip: Review the logic above to help your child master the concept of easy balancing equations worksheet.
![49 Balancing Chemical Equations Worksheets [with Answers]](/images2/easy-balancing-equations-worksheet/easy-balancing-equations-worksheet-3.jpg)
