Evaluate Expressions worksheet with 12 algebra problems requiring substitution of given variable values.

Let's solve each expression step by step, substituting the given values for the variables and simplifying.

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1. $ 9y + 3 $ for $ y = 3 $

$$
9(3) + 3 = 27 + 3 = \boxed{30}
$$

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2. $ 9m^4 $ for $ m = 8 $

First calculate $ m^4 = 8^4 = 8 \times 8 \times 8 \times 8 = 4096 $

Then:
$$
9 \times 4096 = \boxed{36,864}
$$

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3. $ d^2 - 2d + d $ for $ d = 3 $

Simplify the expression first:
$ d^2 - 2d + d = d^2 - d $

Now substitute $ d = 3 $:
$$
3^2 - 3 = 9 - 3 = \boxed{6}
$$

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4. $ 6q + 30 $ for $ q = 5 $

$$
6(5) + 30 = 30 + 30 = \boxed{60}
$$

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5. $ 6v^3 $ for $ v = 8 $

First find $ v^3 = 8^3 = 512 $

Then:
$$
6 \times 512 = \boxed{3,072}
$$

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6. $ j^3 + 11j - 4 $ for $ j = 8 $

Calculate each term:
- $ j^3 = 8^3 = 512 $
- $ 11j = 11 \times 8 = 88 $

Now:
$$
512 + 88 - 4 = 596 - 4 = \boxed{592}
$$

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7. $ 2k^2 + 5k + 1 $ for $ k = 10 $

- $ k^2 = 10^2 = 100 $
- $ 2k^2 = 2 \times 100 = 200 $
- $ 5k = 5 \times 10 = 50 $

Add:
$$
200 + 50 + 1 = \boxed{251}
$$

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8. $ 3n + n^2 $ for $ n = 18 $

- $ n^2 = 18^2 = 324 $
- $ 3n = 3 \times 18 = 54 $

Add:
$$
54 + 324 = \boxed{378}
$$

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9. $ 12v - 6^2 $ for $ v = 24 $

Note: $ 6^2 = 36 $

So:
$$
12(24) - 36 = 288 - 36 = \boxed{252}
$$

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10. $ 4(11 + p) + 10^1 $ for $ p = 90 $

- $ 11 + p = 11 + 90 = 101 $
- $ 4 \times 101 = 404 $
- $ 10^1 = 10 $

Add:
$$
404 + 10 = \boxed{414}
$$

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11. $ h^3 - 2h^2 $ for $ h = 2 $

- $ h^3 = 2^3 = 8 $
- $ h^2 = 2^2 = 4 $
- $ 2h^2 = 2 \times 4 = 8 $

Now:
$$
8 - 8 = \boxed{0}
$$

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12. $ 14z - 1264 + 1,494^0 $ for $ z = 95 $

Note: Any non-zero number to the power of 0 is 1 → $ 1,494^0 = 1 $

Now:
- $ 14z = 14 \times 95 = 1,330 $
- So: $ 1,330 - 1,264 + 1 = 66 + 1 = \boxed{67} $

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✔ Final Answers:

1. $ \boxed{30} $
2. $ \boxed{36,864} $
3. $ \boxed{6} $
4. $ \boxed{60} $
5. $ \boxed{3,072} $
6. $ \boxed{592} $
7. $ \boxed{251} $
8. $ \boxed{378} $
9. $ \boxed{252} $
10. $ \boxed{414} $
11. $ \boxed{0} $
12. $ \boxed{67} $

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