Educational worksheet for identifying and fixing electrical circuit problems.

Let’s go through each circuit one by one. We’re looking for why the bulb won’t light — and how to fix it.

Remember: For a bulb to light, there must be a complete loop (circuit) from the battery’s positive end, through the bulb, and back to the battery’s negative end. If anything is missing or broken in that path, the bulb won’t light.

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Circuit 1:
- The switch is open (not closed). That means electricity can’t flow.
→ Fault: Switch is open.
→ Fix: Close the switch so current can flow.

Circuit 2:
- The battery is drawn upside down? Actually, no — look closely: the battery symbol has the long line (positive) on top, short line (negative) on bottom — that’s fine. But wait — the wires don’t connect properly to the battery! One wire is floating near the battery but not touching either terminal.
→ Fault: Wire not connected to battery terminals.
→ Fix: Connect both ends of the wire to the battery’s + and - terminals.

Actually, let me double-check Circuit 2:
Looking again — the battery is shown with two lines: long (+) and short (-). The wire goes from the switch to the bulb, then from the bulb to... nothing? It doesn’t connect back to the battery. So the circuit is incomplete — it’s an open loop.
→ Fault: No connection from bulb back to battery.
→ Fix: Add a wire from the bulb back to the other side of the battery.

Wait — actually, in standard diagrams, if you see a break like this, it’s usually meant to show a disconnected part. Let’s assume the diagram shows the wire ending without connecting to the battery. So yes — incomplete circuit.

But hold on — maybe I’m overcomplicating. Let’s compare all circuits carefully.

Actually, let’s re-analyze each using simple rules:

Rule 1: Battery must have both terminals connected.
Rule 2: Bulb must have both sides connected.
Rule 3: Switch must be closed (if present).
Rule 4: All parts must form one continuous loop.

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Circuit 1:
Switch is open → breaks the loop → bulb off.
✔ Fault: Open switch.
✔ Fix: Close the switch.

Circuit 2:
Battery is connected to switch, switch to bulb, bulb to... nowhere? The wire stops before reaching the other battery terminal. So it’s not a complete loop.
✔ Fault: Missing wire to complete the circuit back to battery.
✔ Fix: Draw a wire from the bulb back to the negative terminal of the battery.

Circuit 3:
No battery at all! Just a bulb in a rectangle. No power source.
✔ Fault: No battery.
✔ Fix: Add a battery in the circuit.

Circuit 4:
Has a battery, but no bulb! Just wires and battery. Nothing to light up.
✔ Fault: No bulb.
✔ Fix: Add a bulb in the circuit.

Circuit 5:
Two switches, both open. Even if one were closed, the other would still block the flow. Both need to be closed for current to pass.
✔ Fault: Both switches are open.
✔ Fix: Close both switches.

Circuit 6:
One bulb is lit (has a circle with X), one is not (just a circle). Wait — actually, in circuit diagrams, a bulb that’s “lit” isn’t drawn differently — we infer based on whether the circuit works. Here, both bulbs are drawn the same way? Wait — looking again: the top bulb has an “X” inside, which might mean it’s supposed to be lit? Or maybe it’s just a drawing style.

Actually — in many worksheets, they draw the bulb with an “X” to represent the filament, and it’s always drawn that way. So probably both bulbs are identical symbols.

But here’s the real issue: There are two bulbs in series, and two switches — both switches are open. So even though there are two bulbs, neither will light because the switches are open.

Wait — but the question says “Will the bulb light?” — singular. Maybe it’s asking about each bulb? Or perhaps it’s a trick.

Actually, looking at the table header: “Will the bulb light? yes/no” — it says “bulb”, singular. But in circuits 5 and 6, there are multiple components.

Perhaps in circuit 6, since both switches are open, no current flows, so no bulb lights.

But also — notice: in circuit 6, the two bulbs are connected in parallel? Let’s trace:

From battery + → splits to two paths: one goes through top switch and top bulb, other goes through bottom switch and bottom bulb → then joins back to battery -.

So if both switches are open, neither bulb lights.

But the fault is: switches are open.

However — wait! In circuit 6, are the switches really open? They’re drawn as open (like in circuit 1). Yes.

So same as circuit 5? Not exactly — circuit 5 has two switches in series, circuit 6 has them in parallel branches.

But for the purpose of this worksheet, likely the expected answer is:

For circuit 6: Switches are open → bulbs won’t light.

But let’s check if there’s another fault.

Another possibility: in some diagrams, if a bulb is drawn with a different symbol, it might indicate it’s burnt out — but here, both bulbs look the same except one has an “X”? Actually, upon closer inspection — in circuit 6, the top bulb has an “X” inside, the bottom one does not? Or is it just my screen?

Assuming standard representation: all bulbs are drawn with an “X” to show the filament. Probably a rendering thing.

I think the intended fault for circuit 6 is: switches are open.

But let’s confirm with common textbook problems.

Actually, I recall a similar worksheet where circuit 6 has two bulbs in parallel, but one bulb is missing its connection or something — but here, it looks symmetric.

Wait — perhaps the problem is that in circuit 6, even if switches were closed, both bulbs would light — but since switches are open, they don’t.

So fault: switches open.

But let’s list all clearly:

After careful review:

Circuit 1:
Fault: Switch is open.
Fix: Close the switch.

Circuit 2:
Fault: The circuit is not complete — the wire from the bulb does not connect back to the battery.
Fix: Add a wire from the bulb to the negative terminal of the battery.

Circuit 3:
Fault: No battery.
Fix: Add a battery.

Circuit 4:
Fault: No bulb.
Fix: Add a bulb.

Circuit 5:
Fault: Both switches are open.
Fix: Close both switches.

Circuit 6:
Fault: Both switches are open (so no current flows to either bulb).
Fix: Close both switches.

But wait — in circuit 6, if you close only one switch, one bulb would light. But the question is “will the bulb light?” — probably meaning any bulb. Since both switches are open, no bulb lights.

Alternatively, maybe the diagram intends that one bulb is faulty — but I don’t see evidence of that.

Another thought: in some versions of this worksheet, circuit 6 has a broken wire or a gap — but here, it seems intact except for open switches.

I think we’ll go with switches being open.

Now, for the “Draw the correct circuit” column — we’d sketch the fixed version, but since we’re text-based, we’ll describe.

And “Describe how you fixed” — explain what you changed.

Let’s compile the answers row by row.

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Final Answers per Row:

Row 1:
- Will bulb light? No
- Fault: Switch is open
- Correct circuit: Same as given, but with switch closed (drawn as a solid line instead of gap)
- How fixed: Closed the switch to complete the circuit

Row 2:
- Will bulb light? No
- Fault: Wire not connected back to battery (incomplete circuit)
- Correct circuit: Add a wire from the bulb to the negative terminal of the battery
- How fixed: Connected the loose end of the wire to the battery’s negative terminal

Row 3:
- Will bulb light? No
- Fault: No battery
- Correct circuit: Add a battery in the loop
- How fixed: Inserted a battery between the wires to provide power

Row 4:
- Will bulb light? No
- Fault: No bulb
- Correct circuit: Add a bulb in the circuit
- How fixed: Placed a bulb in the wire path so current can flow through it

Row 5:
- Will bulb light? No
- Fault: Both switches are open
- Correct circuit: Close both switches (draw them as connected lines)
- How fixed: Closed both switches to allow current to flow through the entire circuit

Row 6:
- Will bulb light? No
- Fault: Both switches are open (preventing current from reaching either bulb)
- Correct circuit: Close both switches
- How fixed: Closed both switches so that current can flow through at least one branch (actually both, if both closed)

Note: In circuit 6, closing either switch would light one bulb, but since the question likely expects all faults addressed, we close both.

Also, in some interpretations, circuit 6 might have a different fault — but based on standard analysis, open switches are the issue.

Let me verify circuit 2 once more.

In circuit 2: Battery on left, wire to switch, switch to bulb, bulb to... and then the wire ends. It doesn't return to battery. So yes, incomplete circuit.

Similarly, circuit 3: just a rectangle with a bulb — no battery.

Circuit 4: battery and wires, no bulb.

All seem correct.

So final tabular answer:

| Fault Finding Circuit Number | Will the bulb light? yes/no | Where is the fault on the circuit? Circle the fault. | Draw the correct circuit that will light the bulb. | Describe how you fixed the fault to light the bulb |
|------------------------------|-----------------------------|------------------------------------------------------|----------------------------------------------------|--------------------------------------------------|
| 1 | No | Switch is open | [Diagram with switch closed] | Closed the switch |
| 2 | No | Wire not connected to battery | [Add wire from bulb to battery - terminal] | Connected the wire to the battery's negative terminal |
| 3 | No | No battery | [Add battery in the circuit] | Added a battery to provide power |
| 4 | No | No bulb | [Add bulb in the circuit] | Added a bulb so current has something to light |
| 5 | No | Both switches open | [Close both switches] | Closed both switches to complete the circuit |
| 6 | No | Both switches open | [Close both switches] | Closed both switches to allow current to flow |

Since we can't draw, in the "Draw" column, we'd sketch the corrected diagram, but for text, we describe.

For the student, they would draw the fixes on their paper.

Now, for the Final Answer section — since the task is to fill the table, and we've reasoned each row, we'll present the completed table in text form as the final answer.

But note: the instruction says "Final Answer: [Provide only the final correct answer]"

So we need to output the filled table concisely.

Let’s write it as:

Final Answer:

1. No; switch open; close switch; closed the switch
2. No; wire not connected to battery; add wire to battery; connected wire to battery negative terminal
3. No; no battery; add battery; added battery
4. No; no bulb; add bulb; added bulb
5. No; both switches open; close both switches; closed both switches
6. No; both switches open; close both switches; closed both switches

To make it clearer, perhaps list per row.

Since the original has columns, we can do:

Row 1: No | Switch is open | [draw closed switch] | Closed the switch
Row 2: No | Wire not connected to battery | [add wire to battery] | Connected wire to battery
Row 3: No | No battery | [add battery] | Added battery
Row 4: No | No bulb | [add bulb] | Added bulb
Row 5: No | Both switches open | [close both switches] | Closed both switches
Row 6: No | Both switches open | [close both switches] | Closed both switches

Yes.

I think that's accurate.