Math test page with multiple choice questions on patterns, geometry, and multiplication/division.

Let's solve each problem step by step.

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Problem 1:

Question: Football players came out of the tunnel in the pattern shown below. What number belongs on the blank jersey?
```
12, 16, 20, __, 28
```

#### Solution:
The sequence given is: 12, 16, 20, __, 28.

To find the pattern, let's look at the differences between consecutive terms:
- \( 16 - 12 = 4 \)
- \( 20 - 16 = 4 \)

The difference between consecutive terms is consistently 4. Therefore, the next term should be:
\[ 20 + 4 = 24 \]

So, the missing number is 24.

#### Answer:
\[ \boxed{C} \]

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Problem 2:

Question: What are the next three numbers in this pattern?
\[ 6, 5, 3, 1, 6, 5, 3, 1, 6, 5, 3 \]

#### Solution:
The sequence repeats every four numbers: \( 6, 5, 3, 1 \).

The next three numbers in the sequence will be the first three numbers of the repeating pattern:
\[ 6, 5, 3 \]

#### Answer:
\[ \boxed{A} \]

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Problem 3:

Question: What rule can be used to find the number of legs on 7 grasshoppers?

| Number of Grasshoppers | 3 | 5 | 7 | 9 |
|-------------------------|---|---|---|---|
| Number of Legs | 18 | 30 | ? | 54 |

#### Solution:
From the table, we observe the relationship between the number of grasshoppers and the number of legs:
- 3 grasshoppers have 18 legs.
- 5 grasshoppers have 30 legs.
- 9 grasshoppers have 54 legs.

To find the rule, let's determine how many legs one grasshopper has:
\[ \text{Legs per grasshopper} = \frac{\text{Total legs}}{\text{Number of grasshoppers}} \]
- For 3 grasshoppers: \( \frac{18}{3} = 6 \) legs per grasshopper.
- For 5 grasshoppers: \( \frac{30}{5} = 6 \) legs per grasshopper.
- For 9 grasshoppers: \( \frac{54}{9} = 6 \) legs per grasshopper.

Thus, each grasshopper has 6 legs. To find the number of legs for 7 grasshoppers:
\[ \text{Number of legs} = 7 \times 6 = 42 \]

The rule is to multiply the number of grasshoppers by 6.

#### Answer:
\[ \boxed{D} \]

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Problem 4:

Question: Kayla is cutting ribbon to go around cards. Each card is shaped like a triangle with all sides the same length. How many inches of ribbon does she need for a card with each side 7 inches long?

| Side Length in Inches | 2 | 3 | 4 | 7 |
|------------------------|---|---|---|---|
| Inches of Ribbon | 6 | 9 | 12 | ? |

#### Solution:
The table shows the relationship between the side length of the triangle and the total inches of ribbon needed:
- For a side length of 2 inches, the ribbon needed is \( 6 \) inches.
- For a side length of 3 inches, the ribbon needed is \( 9 \) inches.
- For a side length of 4 inches, the ribbon needed is \( 12 \) inches.

The pattern suggests that the total inches of ribbon is three times the side length of the triangle:
\[ \text{Inches of Ribbon} = 3 \times \text{Side Length} \]

For a side length of 7 inches:
\[ \text{Inches of Ribbon} = 3 \times 7 = 21 \]

#### Answer:
\[ \boxed{C} \]

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Problem 5:

Question: Coach Kim needs to form teams that all have the same number of players. The table shows the number of teams formed for different numbers of players. What rule can be used to find how many teams are formed if there are 40 players?

| Number of Players | 24 | 32 | 40 | 72 |
|---------------------|----|----|----|----|
| Number of Teams | 3 | 4 | ? | 9 |

#### Solution:
From the table, we observe the relationship between the number of players and the number of teams:
- 24 players form 3 teams.
- 32 players form 4 teams.
- 72 players form 9 teams.

To find the rule, let's determine how many players are in each team:
\[ \text{Players per team} = \frac{\text{Total players}}{\text{Number of teams}} \]
- For 24 players: \( \frac{24}{3} = 8 \) players per team.
- For 32 players: \( \frac{32}{4} = 8 \) players per team.
- For 72 players: \( \frac{72}{9} = 8 \) players per team.

Thus, each team has 8 players. To find the number of teams for 40 players:
\[ \text{Number of teams} = \frac{\text{Total players}}{\text{Players per team}} = \frac{40}{8} = 5 \]

The rule is to divide the total number of players by 8.

#### Answer:
\[ \boxed{A} \]

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Final Answers:

1. \( \boxed{C} \)
2. \( \boxed{A} \)
3. \( \boxed{D} \)
4. \( \boxed{C} \)
5. \( \boxed{A} \)