49 Balancing Chemical Equations Worksheets [with Answers] - Free Printable
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Step-by-step solution for: 49 Balancing Chemical Equations Worksheets [with Answers]
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Step-by-step solution for: 49 Balancing Chemical Equations Worksheets [with Answers]
To solve the balancing equations worksheet, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Here are the balanced equations for each problem:
- Balance Li: \(1 \times 3 = 3\), so we need 3 LiOH.
- Balance Na: \(1 \times 3 = 3\), so we need 3 NaOH.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{Li}_3\text{PO}_4 + 3 \text{NaOH} \rightarrow 3 \text{LiOH} + 1 \text{Na}_3\text{PO}_4} \]
- Balance Mg: \(1 \times 1 = 1\), so we need 1 MgCO₃.
- Balance Li: \(1 \times 2 = 2\), so we need 2 LiF.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{MgF}_2 + 1 \text{Li}_2\text{CO}_3 \rightarrow 1 \text{MgCO}_3 + 2 \text{LiF}} \]
- Balance P: \(1 \times 4 = 4\), so we need 2 P₂O₃.
- Balance O: \(2 \times 3 = 6\), so we need 3 O₂.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{P}_4 + 3 \text{O}_2 \rightarrow 2 \text{P}_2\text{O}_3} \]
- Balance Mg: \(1 \times 1 = 1\), so we need 1 Mg(NO₃)₂.
- Balance Rb: \(1 \times 2 = 2\), so we need 2 RbNO₃ and 2 RbF.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{RbNO}_3 + 1 \text{MgF}_2 \rightarrow 1 \text{Mg(NO}_3)_2 + 2 \text{RbF}} \]
- Balance Cu: \(1 \times 1 = 1\), so we need 1 Cu(NO₃)₂.
- Balance Ag: \(1 \times 2 = 2\), so we need 2 AgNO₃ and 2 Ag.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{AgNO}_3 + 1 \text{Cu} \rightarrow 1 \text{Cu(NO}_3)_2 + 2 \text{Ag}} \]
- Balance C: \(1 \times 1 = 1\), so we need 1 CBr₄.
- Balance F: \(1 \times 4 = 4\), so we need 2 F₂.
- Balance Br: \(1 \times 4 = 4\), so we need 2 Br₂.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{CF}_4 + 2 \text{Br}_2 \rightarrow 1 \text{CBr}_4 + 2 \text{F}_2} \]
- Balance H: \(1 \times 2 = 2\), so we need 2 HCN.
- Balance Cu: \(1 \times 1 = 1\), so we need 1 CuSO₄ and 1 Cu(CN)₂.
- Balance S: \(1 \times 1 = 1\), so we need 1 H₂SO₄.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{HCN} + 1 \text{CuSO}_4 \rightarrow 1 \text{H}_2\text{SO}_4 + 1 \text{Cu(CN)}_2} \]
- Balance Ga: \(1 \times 1 = 1\), so we need 1 GaF₃ and 1 Ga.
- Balance Cs: \(1 \times 3 = 3\), so we need 3 Cs and 3 CsF.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{GaF}_3 + 3 \text{Cs} \rightarrow 3 \text{CsF} + 1 \text{Ga}} \]
- Balance Sr: \(1 \times 1 = 1\), so we need 1 SrF₂.
- Balance Pt: \(1 \times 1 = 1\), so we need 1 PtS.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{SrS} + 1 \text{PtF}_2 \rightarrow 1 \text{SrF}_2 + 1 \text{PtS}} \]
- Balance N: \(1 \times 2 = 2\), so we need 2 NH₃.
- Balance H: \(3 \times 2 = 6\), so we need 3 H₂.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{N}_2 + 3 \text{H}_2 \rightarrow 2 \text{NH}_3} \]
- Balance Li: \(1 \times 1 = 1\), so we need 2 LiF and 2 LiBr.
- Balance F: \(1 \times 2 = 2\), so we need 1 F₂.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{LiF} + 1 \text{Br}_2 \rightarrow 2 \text{LiBr} + 1 \text{F}_2} \]
- Balance Pb: \(1 \times 1 = 1\), so we need 1 PbCl₂.
- Balance Cl: \(1 \times 2 = 2\), so we need 2 HCl.
- Balance H: \(1 \times 2 = 2\), so we need 2 H₂O.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{Pb(OH)}_2 + 2 \text{HCl} \rightarrow 2 \text{H}_2\text{O} + 1 \text{PbCl}_2} \]
- Balance Ga: \(1 \times 2 = 2\), so we need 2 GaBr₃ and 1 Ga₂(CO₃)₃.
- Balance Br: \(3 \times 2 = 6\), so we need 6 NaBr.
- Balance Na: \(2 \times 3 = 6\), so we need 3 Na₂CO₃.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{GaBr}_3 + 3 \text{Na}_2\text{CO}_3 \rightarrow 6 \text{NaBr} + 1 \text{Ga}_2(\text{CO}_3)_3} \]
- Balance C: \(1 \times 1 = 1\), so we need 1 CO₂.
- Balance H: \(1 \times 4 = 4\), so we need 2 H₂O.
- Balance O: \(2 \times 2 = 4\) (from CO₂) + \(1 \times 2 = 2\) (from H₂O) = 6, so we need 2 O₂.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{CH}_4 + 2 \text{O}_2 \rightarrow 1 \text{CO}_2 + 2 \text{H}_2\text{O}} \]
- Balance Li: \(1 \times 3 = 3\), so we need 6 LiCl.
- Balance Ca: \(1 \times 3 = 3\), so we need 3 CaCl₂ and 1 Ca₃(PO₄)₂.
- Balance P: \(1 \times 2 = 2\), so we need 2 Li₃PO₄.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{Li}_3\text{PO}_4 + 3 \text{CaCl}_2 \rightarrow 6 \text{LiCl} + 1 \text{Ca}_3(\text{PO}_4)_2} \]
- Balance Na: \(1 \times 1 = 1\), so we need 2 NaCl.
- Balance Cl: \(1 \times 2 = 2\), so we need 1 Cl₂.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{Na} + 1 \text{Cl}_2 \rightarrow 2 \text{NaCl}} \]
- Balance Ga: \(1 \times 1 = 1\), so we need 1 GaCl₃.
- Balance H: \(1 \times 2 = 2\), so we need 2 H₂ and 6 HCl.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{Ga} + 6 \text{HCl} \rightarrow 3 \text{H}_2 + 2 \text{GaCl}_3} \]
- Balance N: \(1 \times 2 = 2\), so we need 2 NF₃.
- Balance F: \(3 \times 2 = 6\), so we need 3 F₂.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{N}_2 + 3 \text{F}_2 \rightarrow 2 \text{NF}_3} \]
- Balance S: \(1 \times 1 = 1\), so we need 1 SSe₂.
- Balance Se: \(1 \times 1 = 1\), so we need 1 SO₂ and 1 Li₂Se.
- Balance Li: \(1 \times 2 = 2\), so we need 1 Li₂O.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{SO}_2 + 1 \text{Li}_2\text{Se} \rightarrow 1 \text{SSe}_2 + 1 \text{Li}_2\text{O}} \]
- Balance N: \(1 \times 2 = 2\), so we need 2 NH₃.
- Balance H: \(1 \times 8 = 8\), so we need 1 H₂SO₄.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{NH}_3 + 1 \text{H}_2\text{SO}_4 \rightarrow 1 \text{(NH}_4\text{)}_2\text{SO}_4} \]
\[ \boxed{1. 1 \text{Li}_3\text{PO}_4 + 3 \text{NaOH} \rightarrow 3 \text{LiOH} + 1 \text{Na}_3\text{PO}_4} \]
\[ \boxed{2. 1 \text{MgF}_2 + 1 \text{Li}_2\text{CO}_3 \rightarrow 1 \text{MgCO}_3 + 2 \text{LiF}} \]
\[ \boxed{3. 1 \text{P}_4 + 3 \text{O}_2 \rightarrow 2 \text{P}_2\text{O}_3} \]
\[ \boxed{4. 2 \text{RbNO}_3 + 1 \text{MgF}_2 \rightarrow 1 \text{Mg(NO}_3)_2 + 2 \text{RbF}} \]
\[ \boxed{5. 2 \text{AgNO}_3 + 1 \text{Cu} \rightarrow 1 \text{Cu(NO}_3)_2 + 2 \text{Ag}} \]
\[ \boxed{6. 1 \text{CF}_4 + 2 \text{Br}_2 \rightarrow 1 \text{CBr}_4 + 2 \text{F}_2} \]
\[ \boxed{7. 2 \text{HCN} + 1 \text{CuSO}_4 \rightarrow 1 \text{H}_2\text{SO}_4 + 1 \text{Cu(CN)}_2} \]
\[ \boxed{8. 1 \text{GaF}_3 + 3 \text{Cs} \rightarrow 3 \text{CsF} + 1 \text{Ga}} \]
\[ \boxed{9. 1 \text{SrS} + 1 \text{PtF}_2 \rightarrow 1 \text{SrF}_2 + 1 \text{PtS}} \]
\[ \boxed{10. 1 \text{N}_2 + 3 \text{H}_2 \rightarrow 2 \text{NH}_3} \]
\[ \boxed{11. 2 \text{LiF} + 1 \text{Br}_2 \rightarrow 2 \text{LiBr} + 1 \text{F}_2} \]
\[ \boxed{12. 1 \text{Pb(OH)}_2 + 2 \text{HCl} \rightarrow 2 \text{H}_2\text{O} + 1 \text{PbCl}_2} \]
\[ \boxed{13. 2 \text{GaBr}_3 + 3 \text{Na}_2\text{CO}_3 \rightarrow 6 \text{NaBr} + 1 \text{Ga}_2(\text{CO}_3)_3} \]
\[ \boxed{14. 1 \text{CH}_4 + 2 \text{O}_2 \rightarrow 1 \text{CO}_2 + 2 \text{H}_2\text{O}} \]
\[ \boxed{15. 2 \text{Li}_3\text{PO}_4 + 3 \text{CaCl}_2 \rightarrow 6 \text{LiCl} + 1 \text{Ca}_3(\text{PO}_4)_2} \]
\[ \boxed{16. 2 \text{Na} + 1 \text{Cl}_2 \rightarrow 2 \text{NaCl}} \]
\[ \boxed{17. 2 \text{Ga} + 6 \text{HCl} \rightarrow 3 \text{H}_2 + 2 \text{GaCl}_3} \]
\[ \boxed{18. 1 \text{N}_2 + 3 \text{F}_2 \rightarrow 2 \text{NF}_3} \]
\[ \boxed{19. 1 \text{SO}_2 + 1 \text{Li}_2\text{Se} \rightarrow 1 \text{SSe}_2 + 1 \text{Li}_2\text{O}} \]
\[ \boxed{20. 2 \text{NH}_3 + 1 \text{H}_2\text{SO}_4 \rightarrow 1 \text{(NH}_4\text{)}_2\text{SO}_4} \]
1) \( \text{Li}_3\text{PO}_4 + \text{NaOH} \rightarrow \text{LiOH} + \text{Na}_3\text{PO}_4 \)
- Balance Li: \(1 \times 3 = 3\), so we need 3 LiOH.
- Balance Na: \(1 \times 3 = 3\), so we need 3 NaOH.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{Li}_3\text{PO}_4 + 3 \text{NaOH} \rightarrow 3 \text{LiOH} + 1 \text{Na}_3\text{PO}_4} \]
2) \( \text{MgF}_2 + \text{Li}_2\text{CO}_3 \rightarrow \text{MgCO}_3 + \text{LiF} \)
- Balance Mg: \(1 \times 1 = 1\), so we need 1 MgCO₃.
- Balance Li: \(1 \times 2 = 2\), so we need 2 LiF.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{MgF}_2 + 1 \text{Li}_2\text{CO}_3 \rightarrow 1 \text{MgCO}_3 + 2 \text{LiF}} \]
3) \( \text{P}_4 + \text{O}_2 \rightarrow \text{P}_2\text{O}_3 \)
- Balance P: \(1 \times 4 = 4\), so we need 2 P₂O₃.
- Balance O: \(2 \times 3 = 6\), so we need 3 O₂.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{P}_4 + 3 \text{O}_2 \rightarrow 2 \text{P}_2\text{O}_3} \]
4) \( \text{RbNO}_3 + \text{MgF}_2 \rightarrow \text{Mg(NO}_3)_2 + \text{RbF} \)
- Balance Mg: \(1 \times 1 = 1\), so we need 1 Mg(NO₃)₂.
- Balance Rb: \(1 \times 2 = 2\), so we need 2 RbNO₃ and 2 RbF.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{RbNO}_3 + 1 \text{MgF}_2 \rightarrow 1 \text{Mg(NO}_3)_2 + 2 \text{RbF}} \]
5) \( \text{AgNO}_3 + \text{Cu} \rightarrow \text{Cu(NO}_3)_2 + \text{Ag} \)
- Balance Cu: \(1 \times 1 = 1\), so we need 1 Cu(NO₃)₂.
- Balance Ag: \(1 \times 2 = 2\), so we need 2 AgNO₃ and 2 Ag.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{AgNO}_3 + 1 \text{Cu} \rightarrow 1 \text{Cu(NO}_3)_2 + 2 \text{Ag}} \]
6) \( \text{CF}_4 + \text{Br}_2 \rightarrow \text{CBr}_4 + \text{F}_2 \)
- Balance C: \(1 \times 1 = 1\), so we need 1 CBr₄.
- Balance F: \(1 \times 4 = 4\), so we need 2 F₂.
- Balance Br: \(1 \times 4 = 4\), so we need 2 Br₂.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{CF}_4 + 2 \text{Br}_2 \rightarrow 1 \text{CBr}_4 + 2 \text{F}_2} \]
7) \( \text{HCN} + \text{CuSO}_4 \rightarrow \text{H}_2\text{SO}_4 + \text{Cu(CN)}_2 \)
- Balance H: \(1 \times 2 = 2\), so we need 2 HCN.
- Balance Cu: \(1 \times 1 = 1\), so we need 1 CuSO₄ and 1 Cu(CN)₂.
- Balance S: \(1 \times 1 = 1\), so we need 1 H₂SO₄.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{HCN} + 1 \text{CuSO}_4 \rightarrow 1 \text{H}_2\text{SO}_4 + 1 \text{Cu(CN)}_2} \]
8) \( \text{GaF}_3 + \text{Cs} \rightarrow \text{CsF} + \text{Ga} \)
- Balance Ga: \(1 \times 1 = 1\), so we need 1 GaF₃ and 1 Ga.
- Balance Cs: \(1 \times 3 = 3\), so we need 3 Cs and 3 CsF.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{GaF}_3 + 3 \text{Cs} \rightarrow 3 \text{CsF} + 1 \text{Ga}} \]
9) \( \text{SrS} + \text{PtF}_2 \rightarrow \text{SrF}_2 + \text{PtS} \)
- Balance Sr: \(1 \times 1 = 1\), so we need 1 SrF₂.
- Balance Pt: \(1 \times 1 = 1\), so we need 1 PtS.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{SrS} + 1 \text{PtF}_2 \rightarrow 1 \text{SrF}_2 + 1 \text{PtS}} \]
10) \( \text{N}_2 + \text{H}_2 \rightarrow \text{NH}_3 \)
- Balance N: \(1 \times 2 = 2\), so we need 2 NH₃.
- Balance H: \(3 \times 2 = 6\), so we need 3 H₂.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{N}_2 + 3 \text{H}_2 \rightarrow 2 \text{NH}_3} \]
11) \( \text{LiF} + \text{Br}_2 \rightarrow \text{LiBr} + \text{F}_2 \)
- Balance Li: \(1 \times 1 = 1\), so we need 2 LiF and 2 LiBr.
- Balance F: \(1 \times 2 = 2\), so we need 1 F₂.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{LiF} + 1 \text{Br}_2 \rightarrow 2 \text{LiBr} + 1 \text{F}_2} \]
12) \( \text{Pb(OH)}_2 + \text{HCl} \rightarrow \text{H}_2\text{O} + \text{PbCl}_2 \)
- Balance Pb: \(1 \times 1 = 1\), so we need 1 PbCl₂.
- Balance Cl: \(1 \times 2 = 2\), so we need 2 HCl.
- Balance H: \(1 \times 2 = 2\), so we need 2 H₂O.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{Pb(OH)}_2 + 2 \text{HCl} \rightarrow 2 \text{H}_2\text{O} + 1 \text{PbCl}_2} \]
13) \( \text{GaBr}_3 + \text{Na}_2\text{CO}_3 \rightarrow \text{NaBr} + \text{Ga}_2(\text{CO}_3)_3 \)
- Balance Ga: \(1 \times 2 = 2\), so we need 2 GaBr₃ and 1 Ga₂(CO₃)₃.
- Balance Br: \(3 \times 2 = 6\), so we need 6 NaBr.
- Balance Na: \(2 \times 3 = 6\), so we need 3 Na₂CO₃.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{GaBr}_3 + 3 \text{Na}_2\text{CO}_3 \rightarrow 6 \text{NaBr} + 1 \text{Ga}_2(\text{CO}_3)_3} \]
14) \( \text{CH}_4 + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} \)
- Balance C: \(1 \times 1 = 1\), so we need 1 CO₂.
- Balance H: \(1 \times 4 = 4\), so we need 2 H₂O.
- Balance O: \(2 \times 2 = 4\) (from CO₂) + \(1 \times 2 = 2\) (from H₂O) = 6, so we need 2 O₂.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{CH}_4 + 2 \text{O}_2 \rightarrow 1 \text{CO}_2 + 2 \text{H}_2\text{O}} \]
15) \( \text{Li}_3\text{PO}_4 + \text{CaCl}_2 \rightarrow \text{LiCl} + \text{Ca}_3(\text{PO}_4)_2 \)
- Balance Li: \(1 \times 3 = 3\), so we need 6 LiCl.
- Balance Ca: \(1 \times 3 = 3\), so we need 3 CaCl₂ and 1 Ca₃(PO₄)₂.
- Balance P: \(1 \times 2 = 2\), so we need 2 Li₃PO₄.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{Li}_3\text{PO}_4 + 3 \text{CaCl}_2 \rightarrow 6 \text{LiCl} + 1 \text{Ca}_3(\text{PO}_4)_2} \]
16) \( \text{Na} + \text{Cl}_2 \rightarrow \text{NaCl} \)
- Balance Na: \(1 \times 1 = 1\), so we need 2 NaCl.
- Balance Cl: \(1 \times 2 = 2\), so we need 1 Cl₂.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{Na} + 1 \text{Cl}_2 \rightarrow 2 \text{NaCl}} \]
17) \( \text{Ga} + \text{HCl} \rightarrow \text{H}_2 + \text{GaCl}_3 \)
- Balance Ga: \(1 \times 1 = 1\), so we need 1 GaCl₃.
- Balance H: \(1 \times 2 = 2\), so we need 2 H₂ and 6 HCl.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{Ga} + 6 \text{HCl} \rightarrow 3 \text{H}_2 + 2 \text{GaCl}_3} \]
18) \( \text{N}_2 + \text{F}_2 \rightarrow \text{NF}_3 \)
- Balance N: \(1 \times 2 = 2\), so we need 2 NF₃.
- Balance F: \(3 \times 2 = 6\), so we need 3 F₂.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{N}_2 + 3 \text{F}_2 \rightarrow 2 \text{NF}_3} \]
19) \( \text{SO}_2 + \text{Li}_2\text{Se} \rightarrow \text{SSe}_2 + \text{Li}_2\text{O} \)
- Balance S: \(1 \times 1 = 1\), so we need 1 SSe₂.
- Balance Se: \(1 \times 1 = 1\), so we need 1 SO₂ and 1 Li₂Se.
- Balance Li: \(1 \times 2 = 2\), so we need 1 Li₂O.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{1 \text{SO}_2 + 1 \text{Li}_2\text{Se} \rightarrow 1 \text{SSe}_2 + 1 \text{Li}_2\text{O}} \]
20) \( \text{NH}_3 + \text{H}_2\text{SO}_4 \rightarrow \text{(NH}_4\text{)}_2\text{SO}_4 \)
- Balance N: \(1 \times 2 = 2\), so we need 2 NH₃.
- Balance H: \(1 \times 8 = 8\), so we need 1 H₂SO₄.
- The equation is now balanced.
Balanced Equation:
\[ \boxed{2 \text{NH}_3 + 1 \text{H}_2\text{SO}_4 \rightarrow 1 \text{(NH}_4\text{)}_2\text{SO}_4} \]
Final Answer:
\[ \boxed{1. 1 \text{Li}_3\text{PO}_4 + 3 \text{NaOH} \rightarrow 3 \text{LiOH} + 1 \text{Na}_3\text{PO}_4} \]
\[ \boxed{2. 1 \text{MgF}_2 + 1 \text{Li}_2\text{CO}_3 \rightarrow 1 \text{MgCO}_3 + 2 \text{LiF}} \]
\[ \boxed{3. 1 \text{P}_4 + 3 \text{O}_2 \rightarrow 2 \text{P}_2\text{O}_3} \]
\[ \boxed{4. 2 \text{RbNO}_3 + 1 \text{MgF}_2 \rightarrow 1 \text{Mg(NO}_3)_2 + 2 \text{RbF}} \]
\[ \boxed{5. 2 \text{AgNO}_3 + 1 \text{Cu} \rightarrow 1 \text{Cu(NO}_3)_2 + 2 \text{Ag}} \]
\[ \boxed{6. 1 \text{CF}_4 + 2 \text{Br}_2 \rightarrow 1 \text{CBr}_4 + 2 \text{F}_2} \]
\[ \boxed{7. 2 \text{HCN} + 1 \text{CuSO}_4 \rightarrow 1 \text{H}_2\text{SO}_4 + 1 \text{Cu(CN)}_2} \]
\[ \boxed{8. 1 \text{GaF}_3 + 3 \text{Cs} \rightarrow 3 \text{CsF} + 1 \text{Ga}} \]
\[ \boxed{9. 1 \text{SrS} + 1 \text{PtF}_2 \rightarrow 1 \text{SrF}_2 + 1 \text{PtS}} \]
\[ \boxed{10. 1 \text{N}_2 + 3 \text{H}_2 \rightarrow 2 \text{NH}_3} \]
\[ \boxed{11. 2 \text{LiF} + 1 \text{Br}_2 \rightarrow 2 \text{LiBr} + 1 \text{F}_2} \]
\[ \boxed{12. 1 \text{Pb(OH)}_2 + 2 \text{HCl} \rightarrow 2 \text{H}_2\text{O} + 1 \text{PbCl}_2} \]
\[ \boxed{13. 2 \text{GaBr}_3 + 3 \text{Na}_2\text{CO}_3 \rightarrow 6 \text{NaBr} + 1 \text{Ga}_2(\text{CO}_3)_3} \]
\[ \boxed{14. 1 \text{CH}_4 + 2 \text{O}_2 \rightarrow 1 \text{CO}_2 + 2 \text{H}_2\text{O}} \]
\[ \boxed{15. 2 \text{Li}_3\text{PO}_4 + 3 \text{CaCl}_2 \rightarrow 6 \text{LiCl} + 1 \text{Ca}_3(\text{PO}_4)_2} \]
\[ \boxed{16. 2 \text{Na} + 1 \text{Cl}_2 \rightarrow 2 \text{NaCl}} \]
\[ \boxed{17. 2 \text{Ga} + 6 \text{HCl} \rightarrow 3 \text{H}_2 + 2 \text{GaCl}_3} \]
\[ \boxed{18. 1 \text{N}_2 + 3 \text{F}_2 \rightarrow 2 \text{NF}_3} \]
\[ \boxed{19. 1 \text{SO}_2 + 1 \text{Li}_2\text{Se} \rightarrow 1 \text{SSe}_2 + 1 \text{Li}_2\text{O}} \]
\[ \boxed{20. 2 \text{NH}_3 + 1 \text{H}_2\text{SO}_4 \rightarrow 1 \text{(NH}_4\text{)}_2\text{SO}_4} \]
Parent Tip: Review the logic above to help your child master the concept of equation balancing worksheet.
![49 Balancing Chemical Equations Worksheets [with Answers]](/images2/equation-balancing-worksheet/equation-balancing-worksheet-22.jpg)
