Find the slope from the given linear equations on this math worksheet.

To solve the problem of finding the slope from the given equations, we need to rewrite each equation in the slope-intercept form, which is:

\[
y = mx + b
\]

where:
- \( m \) is the slope,
- \( b \) is the y-intercept.

Let's solve each equation step by step.

---

1) \( 5x + 3y + 12 = 0 \)

1. Start with the given equation:
\[
5x + 3y + 12 = 0
\]

2. Isolate \( y \):
\[
3y = -5x - 12
\]

3. Divide through by 3:
\[
y = -\frac{5}{3}x - 4
\]

4. The slope \( m \) is the coefficient of \( x \):
\[
\text{slope} = -\frac{5}{3}
\]

---

2) \( 7x - 9 = y \)

1. The equation is already solved for \( y \):
\[
y = 7x - 9
\]

2. The slope \( m \) is the coefficient of \( x \):
\[
\text{slope} = 7
\]

---

3) \( -10 = 8x - y \)

1. Start with the given equation:
\[
-10 = 8x - y
\]

2. Isolate \( y \):
\[
y = 8x + 10
\]

3. The slope \( m \) is the coefficient of \( x \):
\[
\text{slope} = 8
\]

---

4) \( 4y - 15 = -3x \)

1. Start with the given equation:
\[
4y - 15 = -3x
\]

2. Isolate \( y \):
\[
4y = -3x + 15
\]

3. Divide through by 4:
\[
y = -\frac{3}{4}x + \frac{15}{4}
\]

4. The slope \( m \) is the coefficient of \( x \):
\[
\text{slope} = -\frac{3}{4}
\]

---

5) \( x = 3 + 7y \)

1. Start with the given equation:
\[
x = 3 + 7y
\]

2. Isolate \( y \):
\[
7y = x - 3
\]

3. Divide through by 7:
\[
y = \frac{1}{7}x - \frac{3}{7}
\]

4. The slope \( m \) is the coefficient of \( x \):
\[
\text{slope} = \frac{1}{7}
\]

---

6) \( 6x + 2y = -1 \)

1. Start with the given equation:
\[
6x + 2y = -1
\]

2. Isolate \( y \):
\[
2y = -6x - 1
\]

3. Divide through by 2:
\[
y = -3x - \frac{1}{2}
\]

4. The slope \( m \) is the coefficient of \( x \):
\[
\text{slope} = -3
\]

---

7) \( 10x + 2y = -9 \)

1. Start with the given equation:
\[
10x + 2y = -9
\]

2. Isolate \( y \):
\[
2y = -10x - 9
\]

3. Divide through by 2:
\[
y = -5x - \frac{9}{2}
\]

4. The slope \( m \) is the coefficient of \( x \):
\[
\text{slope} = -5
\]

---

8) \( 5y - 8x + 16 = 0 \)

1. Start with the given equation:
\[
5y - 8x + 16 = 0
\]

2. Isolate \( y \):
\[
5y = 8x - 16
\]

3. Divide through by 5:
\[
y = \frac{8}{5}x - \frac{16}{5}
\]

4. The slope \( m \) is the coefficient of \( x \):
\[
\text{slope} = \frac{8}{5}
\]

---

9) Find the slope of the line whose equation is \( 5x = -6y + 9 \)

1. Start with the given equation:
\[
5x = -6y + 9
\]

2. Isolate \( y \):
\[
-6y = -5x + 9
\]

3. Divide through by -6:
\[
y = \frac{5}{6}x - \frac{3}{2}
\]

4. The slope \( m \) is the coefficient of \( x \):
\[
\text{slope} = \frac{5}{6}
\]

---

Final Answers:

1. \( \text{slope} = -\frac{5}{3} \)
2. \( \text{slope} = 7 \)
3. \( \text{slope} = 8 \)
4. \( \text{slope} = -\frac{3}{4} \)
5. \( \text{slope} = \frac{1}{7} \)
6. \( \text{slope} = -3 \)
7. \( \text{slope} = -5 \)
8. \( \text{slope} = \frac{8}{5} \)
9. \( \text{slope} = \frac{5}{6} \)

\[
\boxed{-\frac{5}{3}, 7, 8, -\frac{3}{4}, \frac{1}{7}, -3, -5, \frac{8}{5}, \frac{5}{6}}
\]